Imagine holding two identical bricks under water. Brick A is just beneath the surface of the water, while brick B is at a greater depth. What is the force needed to hold brick B in place? (Assume the density of water doesn't change with height.) a) the same as b) larger c) smaller than the force required to hold brick A in place.

Answer:

Explanation:

aver. velocity = distance over time

                      =          500 miles          

                         3 hours + (33 min. x  1 hr.  )

                                                           60 min.

                     =   500 miles

                          3.55 hours

                     = 140.845 ≈ 141  miles / hour

Answer:

Glucose

Explanation:

Answer:

Check in your science textbook

Answer: 18o degrees

Explanation:  :)

The planet should move across the sky when completing one revolution around the Sun is 180 degrees.

Planets are large, spherical celestial objects that are neither stars nor their leftovers. The nebular hypothesis, which states that an interstellar cloud collapses out of a nebula to create a young protostar orbited by a proto-planetary disk, is the best theory currently available for explaining planet formation.

More than 5,000 exoplanets, as they are known, were found as a result of further astronomical advancements. These consist of hot Jupiter's, which are enormous planets that revolve around their parent.

The steady accumulation of matter accelerated by gravity, or accretion, is how planets expand within this disk. There are at least eight planets in the Solar System, including the gigantic planets Jupiter, Saturn, Uranus, and Neptune as well as the terrestrial planets Mercury, Venus, Earth, and Mars.

Therefore, the planet should move across the sky when completing one revolution around the Sun is 180 degrees.

To know more about Planet:

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Explanation:

a fluorine atom has nine protons and electrons so it is electrically neutral

Answer:

no bloody idea

Explanation:

???

Answer:it would probably be C

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 32 × 0.5

We have the final answer as

Hope this helps you

Answer:

that gases are gases

Explanation:

Answer:

A. Some, but not all gases are harmful to humans.

Explanation:

Answer:

Explanation:acceleration

If a baseball was thrown with an initial velocity of 14 m/s at an angle above the horizontal. It remained in the air for 2 seconds, then the acceleration of the object would remain constant while the baseball was in the air.

It can be defined as the motion of any object or body when thrown from the earth's surface and follows any curved path under the effect of the gravitational force of the earth.

As given in the problem a baseball was thrown with an initial velocity of 14 m/s at an angle above the horizontal. It remained in the air for 2 seconds.

Thus, If a baseball was thrown with an initial velocity of 14 m/s at an angle above the horizontal. It remained in the air for 2 seconds, then the acceleration of the object would remain constant while the baseball was in the air.

Learn more about projectile motion here, refer to the link given below ;

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Answer:

The number of turns in the secondary coil is 62,500 turns.

Explanation:

Given;

power of the transformer, P = 460 W

output voltage, V₂ = 15 kV = 15,000 V

input voltage of normal household outlet, V₁ = 120 V

number of turns in the primary coil, N₁ = 500 turns

number of turns in the secondary coil, N₂ = ?

Apply the following the transformer equation;

[tex]\frac{N_2}{N_1} = \frac{V_2}{V_1}\\\\N_2 = \frac{V_2}{V_1}*N_1\\\\N_2 = \frac{15000}{120}*500\\\\N_2 = 62500 \ turns[/tex]

Therefore, the number of turns in the secondary coil is 62,500 turns.

Explanation:

Step one:

given dara

mass of ball m=0.kg

initial velocity u= 10 m/s

final velocity v=10m/s

Required

momentum before and after impact

the expression for momentum P

P=mv

before impact

P=mv

P1=0.5*10

P1=5(kg⋅m/s)

after impact

P=mu

P2=0.5*10

P2=5(kg⋅m/s)

change  in momentum is =P1-P2= 5-5=0

yes, momentum is conserved.

Answer:

Explanation:

read the assignment and use this

Topic sentence

Evidence from the text

Thoughts in your own words

Opinion

Wrap up sentence

T

E

T

O

W

and 2 of those make 2 paragraphs

Answer:

.

Explanation:

Gravitational potential energy is the energy stored in an object as the result of its vertical position or height. It can be calculated as its weight times the height. This is:

[tex]\boxed{U_g=W\cdot h=mgh}[/tex]

Where:

Solving for the h:

[tex]h=\dfrac{U_g}{mg} = \dfrac{35944\;J}{310\;kg\cdot 9.8\;m/s^2} = 11.8\;m[/tex]

Answer:

A)

Explanation:

This is because the longer the wire is, the more resistance there is for the electricity to run through.

The student can increase the resistance by replacing the wire with one that is longer. Thus, option A is correct.

The voltage across a conductor, according to Ohm's law, is precisely proportional to the current that passes through it.

A wire's resistance is inversely correlated with its cross-sectional area and directly correlated with its length. Most conductors have a resistance to the flow of an electric current through them. As the wire's length increases, the resistance in the wire rises.

However, according to Ohms law V=IR, a wire's length increases its resistance while decreasing its current for a given potential difference (voltage).

Therefore, replacing the wire with a longer one will increase resistance if a student plans to modify a circuit.

Thus, option A is correct.

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Answer:

What is the magnitude of the centripetal acceleration of a car following a curve of radius 500 m at a speed of 25.0 m/s (about 90 km/h)? Compare the acceleration with that due to gravity for this fairly gentle curve taken at highway speed. See Figure 2a.

Strategy

Because v and r are given, the first expression in

a

c

=

v

2

r

;

a

c

=

r

ω

2

a

c

=

v

2

r

;

a

c

=

r

ω

2

is the most convenient to use.

Solution

Entering the given values of v = 25.0 m/s and r=500 m into the first expression for ac gives

a

c

=

v

2

r

=

(

25.0

m/s

)

2

500

m

=

1.25

m/s

2

a

c

=

v

2

r

=

(

25.0

m/s

)

2

500

m

=

1.25

m/s

2

.

Discussion

To compare this with the acceleration due to gravity (g = 9.80 m/s2), we take the ratio of

a

c

g

=

(

1.25

m/s

2

)

(

9.80

m/s

2

)

=

0.128

a

c

g

=

(

1.25

m/s

2

)

(

9.80

m/s

2

)

=

0.128

. Thus, ac=0.128 g and is noticeable especially if you were not wearing a seat belt.

Explanation:

Answer:

2613.3 pa

Explanation:

p=F/A

p=ma/A

p=200×9.8/0.75

p=2613.3

Answer:

8.193x10^-21m/s²

Explanation:

We have it that the gravitational force that is acting on this object is equal to the earth's gravitational force.

We start by using this formula

Ma = mg

We make a the subject of formula

a = mg/M

m = 5000kg

g = 9.8

M = 5.98x10^24kg

mg = 5000x9.8

= 49000

49000/5.98x10^24

= 8.193x10^-21m/s²

The magnitude of the earth's acceleration is 8.20 × 10^27

The parameters given in the question are;

mass= 5000 kg

g= 9.81

earth's mass= 5.98 × 10∧ 24

The formula is

= mass × acceleration due to gravity/earth's mass

= 5000 × 9.81/ 5.98^24

= 49,050/5.98 × 10^24

= 8.20 × 10^27

Hence the magnitude of the earth's acceleration just before impact is 8.20 × 10^27

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Answer:

208.08 pounds

Explanation:

Given that,

Mass of a man, m = 75.5 kg

Starting from rest, the elevator ascends, attaining its maximum speed of 1.65 m/s in 0.675 s.

We need to find the value of spring scale during these 0.675 s.

As the elevator ascends, net force will be given by :

F = mg + ma

a can be calculated as follows :

[tex]a=\dfrac{1.65-0}{0.675}\\\\a=2.45\ m/s^2[/tex]

So,

F = 75.5[(9.81) + (2.45)]

F = 925.63  N

We know that,

1 N = 0.224 Pounds

It means, 925.63  N = 208.08 pounds

So, the spring scale will register 208.08 pounds.

Answer:

Explanation:

Step one:

given data

let the mass of the rider be m,=110kg

let the velocity be v=?

let the mass of the car be M,=110kg

let velocity of the car V=6m/s

Step two:

the momentum of an object is given by the expression

P=mv

Step two:

since the two the bicycle rider must have the same momentum as the car,

then we need to equate their momentum

mv=MV

110*v=1400*6

110v=8400

divide both sides by 110 to find v

v=8400/110

v=76.36m/s

The rider is expected to have a speed of 76.36m/s

Answer:

Andromeda galaxy

Explanation:

Answer:

Andromida galaxy

Explanation:

In 4 billion years the milky way and the Andromida galaxy will collide with each other

Answer:

I think

Explanation:

the brain grows more when you learn something new, and less when you practice things you already know. i think- lol

Answer:

[tex]v_{B} = \frac{m_{A}v_{A}}{m_{B}}[/tex]

Explanation:

We can apply the law of conservation of momentum on the nucleus in its initial and final state of nucleus:

Initial Momentum = Final Momentum

momentum of nucleus before bursting = momentum of piece A + momentum of Piece B

[tex](m_{nucleus})(velocity of nucleus) = m_{A}v_{A} + m_{B}v_{B}\\[/tex]

since, nucleus was initially at rest. Therefore,

velocity of nucleus = 0 m/s

and due to opposite direction of forces:

Vb = - Vb

Therefore,

[tex](m_{nucleus})(0) = m_{A}v_{A} - m_{B}v_{B}\\\\m_{A}v_{A} = m_{B}v_{B}\\\\v_{B} = \frac{m_{A}v_{A}}{m_{B}}[/tex]

Answer:

i am in the southern hemisphere

Explanation:

Answer:

its winter ................

Answer:

A- Katie has been conditioned

Explanation:

Katie has associated the ice cream truck music with something positive like ice cream that makes her happy. it's kinda like a dog clicker, whenever a dog hears the click they know that click means a treat, which is the same for Katie, ice cream jingle means treat.

Answer:

Atoms of elements in the same group of the periodic table share the same ELECTRONS

Explanation:

May I have brainliest please? :)

Answer:

a) t = 6.62 s

b) x = 238.6 m

c) H = 53.7 m

Explanation:

a) We can find the time of flight as follows:

[tex] y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} [/tex]

Where:

[tex]y_{f}[/tex] is the final height = 0

[tex]y_{0}[/tex] is the initial height = 0

[tex]v_{0_{y}}[/tex] is the initial vertical velocity of the stone

t: is the time

g: is the gravity = 9.81 m/s²

[tex] v_{0}sin(42)t - \frac{1}{2}gt^{2} = 0 [/tex]      

[tex] 48.5 m/s*sin(42)*t - \frac{1}{2}9.81 m/s^{2}*t^{2} = 0 [/tex]  

By solving the above quadratic equation we have:  

t = 6.62 s

b) The maximum range is:

[tex] x = v_{0_{x}}t = 48.5 m/s*cos(42)*6.62 s = 238.6 m [/tex]

c) The maximum height (H) can be found knowing that at this height the final vertical velocity of the stone is zero:

[tex] v_{f_{y}}^{2} = v_{0_{y}}^{2} - 2gH [/tex]  

[tex] H = \frac{v_{0_{y}}^{2} - v_{f_{y}}^{2}}{2g} = \frac{(48.5 m/s*sin(42))^{2} - 0}{2*9.81 m/s^{2}} = 53.7 m [/tex]

I hope it helps you!

Answer:

44 m

Explanation:

Given that,

Horizontal velocity of the ball, u = 40 m/s

It is 6 m above the level field.

We need to find the distance covered by the ball when move horizontally before striking the ground. Let it is d.

Firstly, we will find time taken for the ball to hit the ground. Using second equation of motion as follows :

[tex]s=ut+\dfrac{1}{2}at^2[/tex]

Put u = 0 and a = g

[tex]s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 6}{9.8}} \\\\t=1.1\ s[/tex]

No finding the horizontal distance as follows :

d = ut

d = 40 m/s × 1.1 s

d = 44 m

So, the ball will move 44 m horizontally before striking the ground.

Answer:

Key components of games are goals, rules, challenge, and interaction.

Explanation:

Hope I helped.

Answer:

the name of the games are goals, rules, challenges and interaction and mabe there can be more.

Explanation:

I hope this helped your day better this is the correct answer i got it correct on the test.

Answer:

v = 47.85 m / s ,   θ = 64.7º

Explanation:

This is a missile throwing exercise.

Let's find the speed to reach the maximum height, at this point the vertical speed is zero

        [tex]v_{y}^{2}[/tex] = v_{oy}^{2} - 2 g y

         0 = v_{oy}^{2} - 2gy

        v_{oy} = √2gy

let's calculate

        v_{oy} = √ (2 9.8 21.3)

        v_{oy} = 20.43 m / s

now we can calculate the time it takes to get to this point

      vy = v_{oy} - g t

       t = v_{oy} / g

       t = 20.43 / 9.8

       t = 2.08 s

in projectile launching, the time it takes for the body to rise is the same as the time it takes to go down, so the total launch time is

     [tex]t_{v}[/tex] = 2 t

     t_{v} = 2 2.08 = 4.16 s

let's use the horizontal throw ratio

      x = v₀ₓ t_{v}

      v₀ₓ = x / t_{v}

      v₀ₓ = 180 / 4.16

      v₀ₓ = 43.27 m / s

initial velocity is

      v = √ (v₀ₓ² + v_{oy}^{2})

      v = √ (20.43² + 43.27²)

      v = 47.85 m / s

with an angle of

      tan θ = I go / vox

      θ = tan⁻¹ (43.27 / 20.43)

      θ = 64.7º