I’m testing if this app works.What is gravity?

Answers

Answer 1

Answer:

Gravity, or gravitation, is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward one another. On Earth, gravity gives weight to physical objects, and the Moon's gravity causes the ocean tides. 


Related Questions

How does the air pressure inside a tennis ball change when you hit it?​

Answers

When the can is opened and the balls are put into play more air starts to push on the inside of the balls. As the balls get older small amounts of air start to seep out which minimises inside pressure. This reduces the amount of air that pushes on the inside of the ball when it hits the ground, thus reducing bounce.

what are the characteristics of image when object is between f1 and 2f1 for concave lense?​

Answers

Answer:

The required diagram is shown in the figure. When an object is placed in front of the convex lens, i.e., between 2F

1

and F

1

, its image is formed beyond 2F

2

on the other side of the lens. The image is real, inverted and enlarged.

solution

how are frequency and were peroid related?

Answers

Answer:

Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.

Answer:

Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.

Explanation:

What are the 6 uses of electromagnet?​

Answers

I would say x-rays, microwave radiation, radio waves, Ultraviolet radiation, and Gamma rays.

Did the energy you used to lift the notebook get stored in the book as potential energy? Explain your answer with reasons.

Answers

Answer:

Because when you move a object the energy stored in moving objects. As the object moves faster, more energy is stored. Motion energy is the sum of potential and kinetic energy in an object that is used to do work.

Explanation:

answer it please

What is the Central Idea of "Shelter Dog Protects Owner with Epilepsy“

What is the author’s viewpoint?

Do you agree or disagree with that viewpoint?

Why? Explain your answer.

parpgraph 1-2

Answer:

Yes, the energy used to lift the book was stored in the book as potential energy. The book moved when it was let go.

Explanation:

This is what edmentum sample answer says so I hope this helps out!

What do the skull and vertebrae have in common

Answers

Answer: ok

Explanation: ok

If one person is applying an upward force equal to 60 N at one end, at what location on the board is the other person applying an upward force

Answers

Answer:

When one person applies force f1 = 60 N at one end, the other person applies f2 = 160 - 60 = 100 N. The torques about the center must balance. Thus the distances from the center d1 and d2 must be such that f1*d1 = f2*d2, or 60*1.5 = 100*d2, so d2=0.9. Thus f2 must be applied at a point 1.5 + 0.9 = 2.4 m from the end where f1 is applied.

A carriage of 20 kg is pulled with a force of 35 N. How far the carriage will go
doing 95 J work?

Answers

Answer:

2.71 m

Explanation:

Force is the product of mass and acceleration

F=m*a

Work done is the product of force and distance

Work done=F*d

In this case;

F= 35 N

Work done = 95 J

95 =35 * d

95 /35 = d

2.71 m= d

A boy throws a tell ball straight up . disregarding any effects of air resistance, the forces acting 9n the ball untill it returns to the ground is are

Answers

well in my opinion I think that is called gravity but I’m no expert.

matter can be a solid, lquid or gas. but you cannot see the particles or adoms that make up matter because they are

Answers

Answer:

very small...

Explanation:

i guess... but i may be missing something. the question feels too straightforward

WHAT IS CHANGES IN SOLID MATERIALS ​

Answers

Answer: Solid to a Liquid Liquid to a Solid Liquid to a Gas Gas to a Liquid Solid to a Gas Gas to a Solid

Explanation:

A food processor draws 8.47 A of current when connected to a potential difference of 110 V.

a. What is the power consumed by this appliance?

b. How much electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day?

c. Assume that the price of electrical energy is 7.00 $/kWh. What is the monthly cost of using this food processor?

2. The electric meter in a house indicates that the refrigerator consumes 70.0 kWh in a week.

a. What is the power consumption of the refrigerator?

b. Assuming it is connected to a potential difference of 120 V , how much current does the refrigerator draw?

3. The heating element of an electric broiler dissipates 2.8 kW of power when connected to a potential difference of 120 V.

a. What is the resistance of the element?

b. How much current does the broiler draw? Use two ways to find out, and verify your answer.

Answers

Answer:

i want the answer

Explanation:i want the answer

a. The power consumed by this appliance is 931.7W

b. The electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is 4.65kWh

c. The  monthly cost of using this food processor is 32.55 $

What is power?

The rate of consumption of energy is power. it is given by the product of potential difference(V) and current(I)

a. P = VI  

here V  = 110V . I = 8.47 A

P = 110 x 8.47 = 931.7W

hence power consumed is 931.7 W

b. electrical energy  consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is

E = P/t

Here, P = 931.7 W = 0.93kW

t = 10 x 30 = 300 min = 5 h

So, E =0.93 x 5 =  4.65 kWh

hence electrical energy consumed is 4.65kWh

c. The monthly cost of using the food processor is

given ,

Cost of one unit is 7.00$

Cost of 4.65 unit will be  7.0 x 4.65 =  32.55$

monthly cost of using the food processor  is  32.55$

2.

a.  Power consumption of refrigerator is  416 W

P = E/t  

Here, E = 70 kwh . t = 1 week = 168 h

So, P=  70/168 = 0.416 kW = 416 W

b. Current drawn by the refrigerator  is 3.46A

P = VI

Here, V = 120V, P = 416 W

So, I = P/V = 416/120 = 3.46 A

3.

a. The resistance of the element is 5.14 Ω

b. Current drawn by the boiler is 23,33A

What is resistance?

Resistance is the hindrance caused in the flow of current

a. The resistance is given by [tex]R = v^{2} / P[/tex]

here V = 120V , P = 2.8kW = 2800W

R = (120 x 120)/ 2800 = 5.14Ω

Hence Resistance of the boiler is 51.4Ω

b.   V = IR so, I = V /R

Here, V = 120V , R = 5.14Ω

So, I = 120/51.4 = 23.33 A

Hence current drawn by the boiler is 23.33A

The alternate way to find the current is by using formula

P = VI  

I = P/V

Since, P = 2800W,   V = 120V

So, I = 2800/120 =23.33 A

Hence Current comes out to be the same from both the method which verifies the answer .

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according to newton's first law of motion what is the reason for a ball throwing up in the airfall back to earth

Answers

the force of earth's gravitational field is always directed downwards (towards the center of the earth. When the ball is thrown up, it is going against the earth's gravitational field and so, the earth's gravitational force pulls it back down, accelerating it downwards.

Suppose that a brass rod 2.0 m long expands 0.2 cm when its temperature is increased a certain amount. By how much will a brass rod 80 m long expand with the same change in temperature?

Answers

Answer:

0.08 m

Explanation:

Linear expansivity brass = 2 * 10^-5 C

Linear expansivity = change in length / (initial length * θ)

Change in length = 0.2cm = 0.002m

Initial length = 2m

2 * 10^-5 = 0.002 / (2 * θ)

(2 * 10^-5 * 2θ) = 0.002

4 * 10^-5θ = 0.002

θ = 0.002 / 4 * 10^-5

θ = 2 * 10^-3 / 4 * 10^-5

θ = 0.5 * 10^2

θ = 50°C

For a rod of original length 80m at the same temperature of 50°C

Linear expansivity = change in length / (initial length * θ)

Change in length = dL

2 * 10^-5 = dL / (80 * 50)

2 * 10^-5 * 80 * 50 = dL

160 * 10^-5 * 50 = dL

8000 * 10^-5 = dL

0.08 m = dL

Hence, change in length = 0.08m

A 10-turn ideal solenoid has an inductance of 3.5 mH. When the solenoid carries a current of 2.0 A the magnetic flux through each turn is:

Answers

Answer:

7 * 10^-4Wb

Explanation:

The magnetic flux is the product of the inductance and current

Magnetic flux = LI

L is the inductance = 3.5mH

I is the current = 2.0A

Number of turns N = 2A

Since for a 10-turn solenoid, L = 3.5mH

For a one-turn solenoid, L = 3.5/10 = 0.35mH

magnetic flux = 0.35mH * 2

magnetic flux = 0.35 * 10^-3 * 2

magnetic flux = 0.7* 10^-3

Magnetic flux = 7 * 10^-4Wb

Hence the magnetic flux through each turn is 7 * 10^-4Wb

The magnetic flux through each turn is 7 ×10⁻⁴ Wb. The magnetic flux is the product of the inductance and current.

What is megnetic flux?

The surface integral of the normal component of the magnetic field B across a surface is the magnetic flux through that surface. It is commonly indicated by the letters B.

The weber is the SI unit for magnetic flux, while the maxwell is the CGS unit.

The given data in the problem is;

[tex]\rm \phi[/tex] is the magnetic flux =?

L is the inductance = 3.5mH

I is the current = 2.0A

N number of turns of solenoid  = 2A

The inductance for the one turn is found by;

For a 10-turn solenoid, L = 3.5mH

For a one-turn solenoid, L = 3.5/10 = 0.35mH

The megnetic flux through each turn is found by;

[tex]\rm \phi = L \times I \\\\ \rm \phi = 0.35 \times 10^{-3}\times 2\\\\ \rm \phi =7 \times 10^{-4}[/tex]

Hence the magnetic flux through each turn is 7 ×10⁻⁴ Wb.

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80g of kerosene was burned to raise the temperature of 3 l of water to 90c ⁰C. What is the efficiency of the burner?​

Answers

Answer:

363

Explanation:

80g of kerosene was burned to raise the temperature

k = 90+273

= 363

How high of a hill should an 80-kg person climb to expend 40,000 joules of energy?

A. 4.1 km
B. 4.9 km
C. 51 m
D. 500 m

Answers

Answer:

1: 51 m

2: some energy was transformed to other forms

3: 3.24

4: 45j

5: 1020

Explanation:

The required height of hill is 51 m. Hence, option (C) is correct.

Given data:

The mass of person is, m = 80 kg.

The energy expended during climbing is, E = 40,000 J.

The energy possessed by the body by virtue of height is known as potential energy. In the given case, the energy expended by the person will be stored in the form of potential energy. Then,

E = U

E = mgh

here, h is the height of hill and g is the gravitational acceleration.

Solving as,

40000 = 80(9.8) h

h ≈ 51 m

Thus, we can conclude that the required height of hill is 51 m. Hence, option (C) is correct.

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What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N?

Answers

Answer:

What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N? a=2m/s^2 Applying Newton's 2nd law, a=Fnet/m=(400N)/(200kg)=2m/s^2. The acceleration is constant.

Explanation:

The person begins to push a refrigerator with a force of 400 N. So, the acceleration of the refrigerator will be 2 m/s².

What is Acceleration?

In mechanics, acceleration is the measure of how rapidly an object's velocity changes over time. It is a vector quantity. An object's acceleration depends on the direction of the net force exerted on it.

A vector quantity, acceleration is something that has both a magnitude and a direction. As a vector quantity, velocity is also. The ratio of the velocity vector change over a time interval to that interval is the definition of acceleration.

There are several types of acceleration :

Uniform AccelerationNon-Uniform AccelerationAverage Acceleration

According to the question, the given values are :

Force applied to the refrigerator is 400 N.

The mass of the refrigerator is 200 kg.

Use the 2nd law of newton,

[tex]Force= mass*acceleration[/tex]

Acceleration = 400/200

Acceleration = 2 m/s².

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A motobike's tire rotates with a constant angular speed of 62.8 rad/s. The radius of a tire is 30cm. Assuming that no slipping occurs, the number of
revolutions of the tire in one second is:

a.
12.6
b.
20
C.
18.8
d.
10

Answers

Answer:

10

Explanation:

Given that :

Angular speed (w) = 62.8 rad/s

Radius of tire (r) = 30 cm

Number of revolutions per second :

s = 2πr

s = 2π * 0.3 = 1.8849555

The number or revolutions per second :

θ = s / r

θ = 1.884955 / 0.3

θ = 6.283185 rad

Number of revolutions per second :

62.8 / 6.283185

= 9.9949309

= 10

A bird perched in a tree is balanced or unbalanced​

Answers

Answer: Balanced

Explanation: When a bird is perched on a tree it is sitting still will stay still if the forces acting on it are balanced.

sound is faster than light that is why we hear thunder before we see lightning

Answers

Answer:

false

Explanation:

sound travels slower than light. that is why we see lightning before we hear the thunder

How much energy is stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A

Answers

Answer:

The energy stored in the solenoid is 7.078 x 10⁻⁵ J

Explanation:

Given;

diameter of the solenoid, d = 2.80 cm

radius of the solenoid, r = d/2 = 1.4 cm

length of the solenoid, L = 14 cm = 0.14 m

number of turns, N = 200 turns

current in the solenoid, I = 0.8 A

The cross sectional area of the solenoid is given as;

[tex]A = \pi r^2\\\\A = \pi (0.014)^2\\\\A = 6.16*10^{-4} \ m^2[/tex]

The inductance of the solenoid is given by;

[tex]L = \frac{\mu_0 N^2A}{l} \\\\L = \frac{(4\pi*10^{-7})(200^2)(6.16*10^{-4})}{0.14}\\\\L = 2.212*10^{-4} \ H[/tex]

The energy stored in the solenoid is given by;

E = ¹/₂LI²

E = ¹/₂(2.212 x 10⁻⁴)(0.8)²

E = 7.078 x 10⁻⁵ J

Therefore, the energy stored in the solenoid is 7.078 x 10⁻⁵ J

The energy stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A is 7.07 × 10⁻⁵ J.

A solenoid is a type of electromagnet, whose purpose is to generate a controlled magnetic field through a coil wound into a tightly packed helix.

First, given the diameter of the solenoid (d) is 2.80 cm (0.0280 m), we can calculate the cross-sectional area (A) using the following expression.

[tex]A =\pi \times (\frac{d}{2} )^{2} = \pi \times (\frac{0.0280}{2} )^{2} = 6.16 \times 10^{-4} m^{2}[/tex]

Next, we will calculate the inductance (L) of the solenoid using the following expression.

[tex]L = \frac{\mu _0 \times N^{2} \times A}{l} = \frac{(4\pi \times 10^{-7}H/m ) \times 200^{2} \times (6.16 \times 10^{-4}m^{2} )}{0.140m} = 2.21 \times 10^{-4} H[/tex]

where,

μ₀ is the vacuum permeabilityN is the number of turnsl is the length of the solenoid

Finally, for a current (I) of 0.800 A, we can calculate the energy stored (E) using the following expression.

[tex]E = \frac{1}{2} \times L \times I^{2} = \frac{1}{2} \times (2.21 \times 10^{-4}H ) \times (0.800A)^{2} = 7.07 \times 10^{-5} J[/tex]

The energy stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A is 7.07 × 10⁻⁵ J.

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Have you ever written a bio-data or an application letter? Share your experience in the
space below. (e.g. How did you find the experience? What was hard? What was easy?)
Leave the space blank if you have never written any of these.​

Answers

Answer:

I found the experience tasking

Explanation:

I wouldn't say it was hard, neither was it easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. Of course I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.

I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn

The experience of writing a bio-data or an application letter was quite a tasking goal, where proper structure is required.

The given problem is based on the fundamentals of bio-data. Biodata is a document that is used to display the biographical data about the work experience in any organization.

As per my experience it was neither hard nor easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously.

I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.  I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn.

Thus, it is concluded that writing a bio-data or an application letter was quite a tasking goal, where proper structure is required.

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A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If the spider has a mass of 1.27 g, what is the tension in the web

Answers

Answer:

Tension = 0.012 N

Explanation:

If the black widow spider is hanging vertically motionless from the ceiling above. Then, the weight of the spider must be balancing the tension in the spider web. Therefore,

Tension = Weight

Tension = mg

where,

m = mass of spider = 1.27 g = 0.00127 kg

g = acceleration due to gravity = 9.8 m/s²

Therefore,

Tension = (0.00127 kg)(9.8 m/s²)

Tension = 0.012 N

A force of 400-N pushes on a 25-kg box horizontally. The box accelerates at 9 m/s? Find the coefficient of kinetic friction between the box and floor.

Answers

Answer:

0.69

Explanation:

Using the Newtons law of motion;

[tex]\sum Fx = ma_x\\Fm - Ff = ma_x[/tex]

Fm is the moving force = 400N

Ff is the frictional force = μR

μ is the coefficient of kinetic friction

R is the reaction = mg

m is the mass

a is the acceleration

The equation becomes;

[tex]Fm - \mu R = ma_x\\Fm - \mu mg = ma_x\\400- \mu (25)(9.8) = 25(9)\\400 - 254.8 \mu = 225\\- 254.8 \mu = 225 - 400\\- 254.8 \mu = -175\\ \mu = \frac{-175}{- 254.8} \\\mu = 0.69[/tex]

Hence the coefficient of kinetic friction between the box and floor is 0.69

The coefficient of kinetic friction between the box and the floor is 0.714.

Friction: This can be defined as the force that tends to oppose two surfaces in motion.

The question above can be solved using the formula

F-ma = mgμ................. Equation 1

Where F = Force applied to push the box, m = mass of the box, a = acceleration of the box, μ = coefficient of kinetic friction, g = acceleration due to gravity.

make μ the subject of the equation

μ = (F-ma)/mg................ Equation 2

From the question,

Given: F = 400 N, m = 25 kg, a = 9 m/s²,

Constant: g = 9.8 m/s²

Substitute these values into equation 2

μ = [400-(25×9)]/(25×9.8)

μ = (400-225)/245

μ = 175/245

μ = 0.714

Hence, the coefficient of kinetic friction between the box and the floor is 0.714.

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2. An 85.5 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 12.0 m) and spun at a constant angular velocity of 18.4 rpm. Answer the following:
(a) What is the angular velocity of the centrifuge in ?
(b) What is the linear velocity of the astronaut at the outer edge of the centrifuge?
(c) What is the centripetal acceleration of the astronaut at the end of the centrifuge?
(d) How many g’s does the astronaut experience?
(e) What is the centripetal force experienced by the astronaut?

Answers

Answer Expert Verified

Hello here is your answer and also please mark me as brainlest

Since one revolution around a circle is 2 pi radian; hence 1 rpm equals 2 pi radians per minute. And because a minute has 60 seconds, 1 rpm equals 1/60 revolution per second. Therefore, we have 2 pie/60 * 15.3 = 0.2513 rps. The linear velocity v = wr where w is the angular velocity in rad/s and r is the distance. So we have 0.2513 * 10.0 = 2.513 rad/s The centripetal acceleration is given by a = w^2 r = (2.513)^2 * 10 = 63.15 rad/s2 The centripetal force F = mass * centripetal acc = 75 * 63.15 = 4736.25 N The torque = centripetal force * distance = 4736 * 63.15 = 299078.4 Nm Two forces acts on the astronaut. The normal force and acceleration due to gravity.

I hope this help you

brainlest

Rotational kinematics and Newton's second law allow to find the results for the astronaut's movement in the centrifuge are:

       a) The angular velocity is: w = 1.927 rad / s

       b) The linear velocity is: v = 23.1 m / s

       c) The centripetal acceleration is: a = 6.417 10³ m / s²

       d) The centripetal acceleration is: a = 6.548 10² g

       e) The centripetal force F = 5.49 10⁵ N

given parameters

The mass of the astronaut m = 85.5 kg Centrifuge radii r = 12.0 m Angular velocity w = 18.4 rpm (2prad / 1rev) (1min / 60s) = 1.927 rad / s

To find

    a) angular velocity

    b) linear velocity

    c) centripetal acceleration

    d) acceleration in units of gravity (g)

    e) the centripetal force

The angular velocity is defined as the rotated angle in the unit of time.

         [tex]w = \frac{\Delta \theta}{t}[/tex]  

Angular and linear variables are related.

         v = w r

Where w is the angular velocity, θ  is the angle, t the time, v the lienal velocity and R the radius of the cetnrifuga

Let's answer the questions:

a) The angular velocity of the centrifuge and the astronaut are equal

         w = 1.927 rad / s

b) Linear velocity

         v = 1.927 12.0

         v = 23.1 m / s

c) Centripetal acceleration has the formula:

          a = [tex]\frac{v^2}{R}[/tex]  

          a = [tex]\frac{23.1^2}{12.0}[/tex]  

          a = 6.417 10³ m / s²

d) The value of this eceleration as a function of gravity

          [tex]\frac{a}{g}[/tex]  = 6.417 10³ / 9.8

          [tex]\frac{a}{g}[/tex]  = 6.548 10²

          a = 6.548 10² g

e) The centripetal force

           F = ma

           F = 85.5 6.417 10³

           F = 5.49 10⁵ N

In conclusion, using rotational kinematics and Newton's second law we can find the results for the movement of the astronaut in the centrifuge are:

       a) The angular velocity is: w = 1.927 rad / s

       b) The linear velocity is: v = 23.1 m / s

       c) The centripetal acceleration is: a = 6.417 10³ m / s²

       d) The centripetal acceleration is: a = 6.548 10² g

       e) The centripetal force F = 5.49 10⁵ N

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In an RC parallel circuit, Et = 480 V, R = 50ko, and XC = 47 ko. What is the reactive power?

Answers

Correct question is;

In an RC parallel circuit, Et = 480 V, R = 50kΩ, and XC = 47 kΩ. What is the reactive power?

Answer:

P_r = 4.9 VARs

Explanation:

We are given;

Total voltage: Et = 480 V

Resistance; R = 50kΩ = 50000 Ω

Capacitive reactance; XC = 47 kΩ = 47000 Ω

Formula for current across the capacitor is;

Et = I_c • XC

I_c = Et/XC

l_c = 480/47000

I_c = 0.01021 A

Formula for reactive power is;

P_r = (I_c)² × XC

P_r = 0.01021² × 47000

P_r = 4.9 VARs

Four charges are placed on the corners of a rectangle. What is the resultant force on the positive charge (a = 1.1 m, b = 0.9 m, q = 2.3 × 10-9C)?

Answers

Answer:

F = 93.49 × 10^(-9) N

Explanation:

We are given;

Length of rectangle; a = 1.1 m

Width of rectangle; b = 0.9 m

Charge on rectangle; q = 2.3 × 10^(-9) C

Formula for force is;

F = kq²/r²

Where;

k is a constant = 8.99 x 10^(9) N.m²/C²

a) on the width side, we have;

F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/0.9²

F = 58.79 × 10^(-9) N

This is on the y-axis

b) on the length side, we have;

F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/1.1²

F = 39.3 × 10^(-9) N

This is on the x-axis

C) using pythagoras theorem, for the diagonal side, we have c² = a² + b².

Thus;

F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/(1.1² + 0.9²)

F = 23.54 × 10^(-9) N

Using trigonometric ratios, we can find the angle θ.

tan θ = b/a

tan θ = 0.9/1.1

tan θ = 0.8182

θ = tan^(-1) 0.8182

θ = 39.29°

Resolving along x and y axis, we have;

F_x = 23.54 × 10^(-9) × cos 39.29°

F_x = 18.22 × 10^(-9) N

F_y = 23.54 × 10^(-9) × sin 39.29°

F_y = 14.91 × 10^(-9) N

Resultant force will be;

F = √((Σf_x)² + (ΣF_y)²)

F = √[(18.22 × 10^(-9)) + (39.3 × 10^(-9))]² + [(14.91 × 10^(-9)) + (58.79 × 10^(-9))²]

F = √[(33.0855 × 10^(-16)) + (54.317 × 10^(-16))]

F = 93.49 × 10^(-9) N

A light bulb uses 1.2 A when connected across a 120 V source. What is the resistance by the bulb?

Answers

V=iR
R=V/i
R=120/1.2
R ≈ 100Ω

A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°.

a. What is the horizontal component of the velocity?
b. What is the vertical component of the velocity?
c. How long does it take the ball to reach its highest point?
d. What is the maximum height of the ball?
e. What is the total amount of time that the ball is in the air?
f. How far is the ball from the football player when it lands?

I would appreciate any help :)

Answers

Answer:

see explanation

Explanation:

Answer:

a. 13.22 m/s

b. 16.32

c. 1.664 s

d. 13.58

e. 3.328

f. 40.0m

Explanation:

This is basically what the guy said, i dunno if you saw the letters, but he added some at the end of every answer.

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