I'll give brainliest to the right answer!!!
Find three consecutive odd integers such that the difference of twice the second and the first is 11.

Answer:

7, 9, 11

Step-by-step explanation:

question: Find three consecutive odd integers such that the difference of twice the second and the first is 11.

make the 3 consecutive odd intergers x, y, and z.

numbers are consective (come right after another) AND odd, meaning you would add 2 every time. therefore:

x+2=y

y+2=z

given that: "difference of twice the second and the first is 11."

difference means subtraction

second number is the variable y

first number is the variable x

2y-x=11

----------------

3 equations:

2y-x=11

x+2=y

y+2=z

----------solve by substitution

x+2=y

x =y-2 into 2y-x=11

2y-(y-2)=11

2y-y+2=11

y=9

second number is 9

-----

numbers are 7, 9, 11

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