If you were to solve this inequality,
do you need to flip the Inequality symbol?

The given inequality shows an ellipse with a center at (1,-2)

The major axis will be   [tex]a=\sqrt{\dfrac{26}{9} }[/tex]

The minor axis will be   [tex]b=\sqrt{\dfrac{26}{4} }[/tex]

The equation of an ellipse is written in the form

[tex]\dfrac{(x-h)^2}{a^2} +\dfrac{(y-k)^2}{b^2} =1[/tex]

The center is (h,k) and the larger of a and b is the major radius and the smaller is the minor radius.

Now the given inequality is

[tex]9x^2+18x+4y^2+16y-11 > 0[/tex]

[tex]9x^2+18x+4y^2+16y > 11[/tex]

[tex]9(x^2-2x)+4(y^2+4y) > 11[/tex]

[tex]9(x^2-2x+1)+4(y^2+4y+4) > 11+9+16[/tex]

[tex]9(x^2-2x+1)+4(y^2+4y+4) > 26[/tex]

On further solving

[tex]9(x-1)^2+4(y+2)^2 > 26[/tex]

[tex]\dfrac{(x-1)^2}{\dfrac{26}{9} } + \dfrac{(y+2)^2}{\dfrac{26}{4} } > 1[/tex]

Thus by comparing the equation with the standard form

[tex]\dfrac{(x-h)^2}{a^2} +\dfrac{(y-k)^2}{b^2} =1[/tex]

Thus we can see that the center (h,k) is (1,-2)

The major axis will be [tex]a=\sqrt{\dfrac{26}{9} }[/tex]

The minor axis will be[tex]a=\sqrt{\dfrac{26}{4} }[/tex]

To know more about ellipse follow

https://brainly.com/question/19507943

Answer:

ellipse with a dashed line boundary

(1,-2)

(-2,0)

Step-by-step explanation:

assignment

Answer:

-8

Step-by-step explanation:

Answer:

-8

Step-by-step explanation:

Pull out like factors : 16 + 2x  =   2 • (x + 8)

Solve::x+8 = 0

Subtract  8  from both sides of the equation::x = -8

Answer:

Your answer to your question is FALSE!!!!!!

Answer:

True

Step-by-step explanation:

I hope this helps!

[tex](\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}[/tex]

Answer: 62

Step-by-step explanation:

infinitely many solutions

[tex]m+7=3+m+4[/tex]

Combine like terms

[tex]m+7=7+m[/tex]

Rearrange variables to the left side of the equation

[tex]m-m=7-7[/tex]

Apply the Inverse Property of Addition

[tex]m-m=7-7\\ 0=0[/tex]

Bases on the given conditions, the (system of) equation(s) has

[tex]infinitely\ many\ solutions[/tex]

I hope this helps you

:)

Answer:24 oz at smiths

Step-by-step explanation:

4.40/20 =.22 c per oz

4.80/24=.20 c per oz

Answer:

Your answer is: (a little big) ----> 1175/819

Mixed number form: 1 356/819

Combine the fractions by finding a common denominator.

Step-by-step explanation:

Hope this helped : )

Answer:

1175/819

Step-by-step explanation:

80/91 = 720/819

5/9 = 455/819

720 + 455 = 1175

We will not add the denominators

I hope this helps!

Answer:

x = 61°

y = 29°

Step-by-step explanation:

Since x°+29° is a right angle (90°), you would have to subtract 29 from 90 to get x.

90 - 29 = x

90 - 29 = 61

x = 61°

For y: You can infer that y°+x°=90° as well because the angles are corresponding angles. So to find y°, you would do the same thing as finding x.

90 - x = y

90 - 61 = 29

y = 29°

Hope this helps :)

Answer:

3.2, 3.25, 3 1/2, 3 2/3

Step-by-step explanation:

You can put them on a number line and find out the order. Or, convert to decimals or fractions.

Answer:

1/-9

Step-by-step explanation:

First you need to calculate rise over run with the equation [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex] in this case that would be 6-4 over -8 - 10 this gets you 2/-18. This means the "rise" is 2 and the "run" is -18. This can be simplified to 1/-9.

Answer:

29568 people cheered for the runners at the start of the race

Step-by-step explanation:

From the question, the crowd lined up 5 feet deep on both sides of the street for the first mile.

This lined up crowd could be related to a rectangle that is 1 mile long and 5 feet wide.

First, Convert 1 mile to feet

1 mile = 5280 feet

Hence, the length of the rectangle is 5280 feet and the width is 5 feet.

Now, we will determine how many 5 feet by 5 feet square we can get from the 5280 feet by 5 feet rectangle. To do that, we will divide 5280 feet by 5 feet

5280 feet ÷ 5 feet = 1056

Hence, from the rectangle, we can get 1056 5 feet by 5 feet square.

From the question, you estimate that 14 people can comfortably fit in a square that measures 5 feet by 5 feet,

∴ 14 × 1056 people will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

14 × 1056 = 14784 people

This is the amount of people that will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

Since the crowd lined up on both sides of the street, then

2 × 14784 people will comfortably fit in the crowed lined up 5 feet deep on both sides of the street for the first mile

2 × 14784 = 29568 people

Hence, 29568 people cheered for the runners at the start of the race.

Answer:

65

Step-by-step explanation:

3+5=8

7x8+9

56+9

=65

Please give brainliest!

Answer:

=> 65

Step-by-step explanation:

=> 7(3+5)+9

=> 7(8)+9

=> 56+9

=> 65

We'll need the slope formula which is

[tex]m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\[/tex]

We subtract the y values together, and divide that over the difference in the x values when subtracted in the same order.

Let's find the slope of line DE

[tex]D = (x_1,y_1) = (6,1) \text{ and } E = (x_2,y_2) = (2,3)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{3 - 1}{2 - 6}\\\\m = \frac{2}{-4}\\\\m = -\frac{1}{2}\\\\[/tex]

The slope of line DE is -1/2.

Next, compute the slope of line EF

[tex]E = (x_1,y_1) = (2,3) \text{ and } F = (x_2,y_2) = (-1,-3)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-3 - 3}{-1 - 2}\\\\m = \frac{-6}{-3}\\\\m = 2\\\\[/tex]

The slope of line EF is 2.

Lastly, compute the slope of line FD

[tex]F = (x_1,y_1) = (-1,-3) \text{ and } D = (x_2,y_2) = (6,1)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{1 - (-3)}{6 - (-1)}\\\\m = \frac{1 + 3}{6 + 1}\\\\m = \frac{4}{7}\\\\[/tex]

The slope of line FD is 4/7.

--------------------------

To recap everything so far, we found the following:

The product of the first two slopes gets us (-1/2)*(2) = -1 showing that DE is perpendicular to EF.

Perpendicular slopes multiply to -1 as long as neither line is vertical nor horizontal.

Since DE is perpendicular to EF, this proves we have a 90 degree angle at point E.

Therefore triangle DEF is a right triangle.

Answer:

this is based around your own learning but do something relatively easy to get it over with quickly. for example, in soccer will score a goal by the end of the season.

Step-by-step explanation:

specific, measurable, attainable, realistic, and timely

Answer:

the plain is going 12km in one minute

Step-by-step explanation:

Answer:

7/8 quart

Step-by-step explanation:

Answer:

question 5: 9.6

Step-by-step explanation:

[tex] \frac{ 5.4}{6.3} = \frac{x}{11.2} [/tex]

[tex] \frac{5.4 \times 11.2}{6.3} = 9.6[/tex]

:) Good Luck! You got this, and hope this helps!

Positive correlation = positive association Negative correlation = negative association

Does it say how many of the marbles in the bag are red? Normally you will want to divide the amount of red marbles to the amount total marbles and you will get a percent. It's also note worthy that it states the marble going back into the bag. It would change if it was left out still.

Answer:

26 inches.

Step-by-step explanation:

Lilly: 12 x 2 + 2 = 26

Anita: 12

Answer:

x = 9/5 = 1 4/5

Step-by-step explanation:

5x - 6 = 3

    +6   +6

(add positive 6 to the negative 6 = - 6 + 6 = 0, and to the answer = 3 = 3 + 6 = 9)

5x = 9

÷5   ÷5

x = 9/5 (improper fraction)

= 1 4/5 (mixed numeral)

Hello.

First, let's add 6 to both sides:

[tex]\tt{5x-6+6=3+6}[/tex]

[tex]\tt{5x=9}[/tex]

The next step is to divide both sides by 5:

[tex]\tt{x=\displaystyle\frac{9}{5}[/tex] (Improper fraction)

[tex]\tt{x=\displaystyle1\frac{4}{5}[/tex] (Mixed number)

I hope it helps.

Have a great day.

[tex]\boxed{imperturbability}[/tex]

6840 ÷ 7 = ?

6840  | 7          

63        977          

=54  

  49  

  =50

    49  

    =1

Answer: x = 2

Steps: x + 3= 8x - 11

Subtract three form both sides: x + 3 - 3 = 8x - 11 - 3

Simplify: x = 8x - 14

Subtract 8x from both sides: x - 8x = 8x - 14 - 8x

Simplify:  -7x = -14

Divide both sides by negative seven: -7x ÷ -7   =   -14 ÷ -7

Simplify:  x = 2

Answer:

6, 8, 10.

Step-by-step explanation:

Let n be any integer.

Then our first even integer will be [tex]2n[/tex]

And the consecutive integers will be [tex]2n+2[/tex] and [tex]2n+4[/tex]

We want to find the integers such that the sum of twice the smallest number (2n) and three times the largest number (2n+4) is 42. In other words:

[tex]2(2n)+3(2n+4)=42[/tex]

Solve for n. Distribute:

[tex]4n+6n+12=42[/tex]

Combine like terms:

[tex]10n+12=42[/tex]

Subtract 12 from both sides:

[tex]10n=30[/tex]

Divide both sides by 10:

[tex]n=3[/tex]

So, the value of n is 3.

This means that our first even integer is 2(3) or 6.

So, our sequence of integers is: 6, 8, 10.

And we're done!

Notes:

We use 2n because anything integer multiplied by 2 ensures that the resulting number is even. Starting out, n can be either even or odd, but by multiplying it by 2, we will get an even number.

Answer:

A ≈ 62.8 cm²

Step-by-step explanation:

the area (A) of the triangle is calculated as

A = [tex]\frac{1}{2}[/tex] ab sinC

where a = 10, b = 13 and C = 105° , then

A = [tex]\frac{1}{2}[/tex] × 10 × 13 × sin105° = 65 × sin105° ≈ 62.8 cm² ( to 1 dec. place )

Answer:

Ans of a = 18x

Ans of b = 3.111

The step that Omar should proceed with is given by: Option D: Omar should factor out a negative from one of the groups so the binomials will be the same.

Those polynomials with integer coefficients that cannot be factored further, with factors of lower degree and integer coefficients are called prime polynomials.

(it is necessary that no factors exists having their coefficients are still integers and they're of lower degree)

The polynomial that Omar is dealing with is:

[tex]3x^3 - 15x^2 -4x + 20[/tex]

We see that 3 times 5 = 15 and 4 times 5 = 20, so trying in that way:

[tex]3x^3 - 15x^2 -4x + 20 = 3x^2(x-5) + 4(-x + 5)[/tex]

Taking out a negative factor from second term would make the binomials same, after which we can take that common out, as shown below:

[tex]3x^3 - 15x^2 -4x + 20 = 3x^2(x-5) + 4(-x + 5) \\3x^3 - 15x^2 -4x + 20 = 3x^2(x-5) -4(x-5) \\3x^3 - 15x^2 -4x + 20 = (x-5)(3x^2-4)[/tex]

It successfully got factored, thus not a polynomial.

Thus,the step that Omar should proceed with is given by: Option D: Omar should factor out a negative from one of the groups so the binomials will be the same.

Learn more about prime polynomials here:

https://brainly.com/question/10717989

Answer: Omar should factor out a negative from one of the groups so the binomials will be the same.

Step-by-step explanation: Answer on edge