if you move point toward point B along BC how does m_ABC change? How do mZBAC and mZACB change? What happens to these
angles if you move point C away from point B along BC?

Answer:

It’s either A or C. However I’m mostly going with C. For C tells us 2 hours and 23 minutes have passed. I hope this helps.

Step-by-step explanation:

Please correct me if I am wrong.

Answer:

2.25

Step-by-step explanation:

Since its a perfect square and you know the area, all you have to do it divide 9 by 4

Answer:2.97 ×10 − 19 J

Answer:

D

Step-by-step explanation:

So it needs to go down because its negative. So B and C are out. Now if you look at the y intercept (4), you just have to look at which graph has a y intercept that's positive. So that's D

Answer:d^4+2d^3+4d^2+6d+3

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

The confidence interval of the percentage of people that favored Mario = number of votes favoring Mario ± Margin of error

The confidence interval = 53.9% ± 4.2% = (49.7%, 58.1%)

This means that between 49.7% to 58.1% of the people would have voted for Mario.

Hence Yin Ling would not have won the election, since there is a probability that 50% would have voted for Mario

Answer:

3%

Step-by-step explanation: 315/325 as a percent would be 96.92%. After finding that, we would do 100 - 96.92, yielding 3.08, 3.08 to the nearest percent would result in 3%

Answer:

the answer to the nearest percent is 3%

Answer:

-9 points

Step-by-step explanation:

Answer:

1847 - 24% decrease

1848 - 68.42% increase

Hope this helps.

Answer:

It will tale 1 hour before they meet and they will meet agin at 9 :00 AM.

Step-by-step explanation:

Speed of Jane, [tex]v_1=3[/tex] mph

and the speed of Jillian, [tex]v_2= 5[/tex] mph.

Length of one complete circle = 8 miles.

Both are moving in the opposite direction, let the starting point is at O, and met at the point P after time, t, as shown in the figure.

Let the length covered by Jane via path OAP= x miles.

[tex]\Rightarrow x= 3t[/tex] [as distance= speed x time]

[tex]\Rightarrow t=x/3 \cdots(i)[/tex]

The length covered by Jillian via path OBP [tex]= 8-x[/tex] miles

[tex]\Rightarrow 8-x= 5t[/tex] [as distance = speed x time]

[tex]\Rightarrow t=(8-x)/5 \cdots(i)[/tex]

Now from equation (i) and (ii),

[tex]\frac{x}{3} = \frac{8-x}{3}[/tex]

[tex]\Rightarrow 5x=3(8-x)[/tex]

[tex]\Rightarrow 5x+3x=24[/tex]

[tex]\Rightarrow x=3[/tex]

So, the distanc covered by Jane = 3 miles and

the distanc covered by Jillian = 8-3=5 miles

From equation (i), time taken, t = 3/3= 1 hour.

So, it will tale 1 hour before they meet.

As the startion time was 8:00 AM, so the will agin meet at 9 :00 AM.

Answer:

Your photo wont show up

Step-by-step explanation:

Answer:

Hello

1.  B. 2.35 * 10^11

2. A. 3 * 10^-2

(Hope that helps (= The given says the height distribution is normally distributed with the mean height equal to 68 inches. In this case, the bell-shaped curve has a vertical symmetry at 68 inches. This means, half of the mean exceeds 68 inches while the other half has height below 68 inches.

The height range out of which only 5% of the young American men (from age 18 to 24) lie is  [63.35, 72.65] (in inches)

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have

[tex]X \sim N(\mu, \sigma)[/tex]

(X is following normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] )

then it can be converted to standard normal distribution as

[tex]Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)[/tex]

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

[tex]P(Z \leq z) = P(Z < z) )[/tex]

Also, know that if we look for Z = z in z tables, the p value we get is

[tex]P(Z \leq z) = \rm p \: value[/tex]

For this case, let we take:

Then, according to the given data, we have:
[tex]X \sim N(\mu = 68, \sigma = 2.5)[/tex]

where [tex]\mu[/tex] is mean value of X and [tex]\sigma[/tex] is standard deviation of X (both in inches).

Also, we can write:

[tex]P(X < a) + P(X > b) = 5\% = 0.05[/tex]

Since normal distribution is symmetric about its mean, we can take a and b equidistant from the mean, so as to get a symmetric range which makes much more sense than taking an asymmetric range which doesn't comply with the nature of values of X.

Thus, we have:

[tex]\mu - a = b - \mu\\b = 2\mu - a[/tex]

From this result and [tex]P(X < a) + P(X > b) = 5\% = 0.05[/tex], we get:
[tex]P(X < a) + P(X > 2\mu -a) = 0.05[/tex]

Converting X to Z(the standard normal distribution), we get;
[tex]Z = \dfrac{X - \mu}{\sigma}[/tex]

[tex]P(X < a) + P(X > 2\mu -a) = 0.05\\\\P(Z < z = \dfrac{x-\mu}{\sigma} = \dfrac{a-68}{2.5}) + P(Z > \dfrac{2(68) - a - 68}{2.5}) = 0.05\\\\P(Z < \dfrac{a-68}{2.5}) + P(Z > \dfrac{68-a}{2.5}) = 0.05\\\\P(Z < \dfrac{a-68}{2.5}) + P(Z > -\dfrac{a-68}{2.5}) = 0.05\\\\P(Z < \dfrac{a-68}{2.5}) + P(Z \leq \dfrac{a-68}{2.5}) = 0.05 \: \: \: \: (\because P(Z > -k) = P(Z \leq k))\\\\2P(Z < \dfrac{a-68}{2.5}) = 0.05\\\\P(Z < \dfrac{a-68}{2.5}) = 0.025[/tex]

Using the z-tables, we get the value of Z for which p-value is 0.025 as

-1.96

Thus, we get:
[tex]\dfrac{a-68}{2.5} = -1.96\\\\a = 68 + (-1.96 \times 2.5)\\a = 63.35[/tex]

Thus, we get: [tex]b = 2\mu - a = 2(68) - 63.35 = 72.65[/tex]

Thus, the range is [a,b] = [63.35, 72.65]

Thus, the height range out of which only 5% of the young American men (from age 18 to 24) lie is  [63.35, 72.65] (in inches)

Learn more about standard normal distribution here:

https://brainly.com/question/10984889

Answer:

(-5, 3)

Step-by-step explanation:

Moving up one will give you (-2, 3) and moving left three brings you to (-5, 3).

Answer:

V= 5 X=6

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the figure attached,

Point X is the midpoint of line AC.

Since coordinates of the midpoint of the segment joining endpoints [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

Therefore, coordinates of the point X will be,

= [tex](\frac{0+2a}{2},\frac{2a+0}{2})[/tex]

= (a, a)

From triangle AXB,

Length of AB = 2a

Length of AX = [tex]\sqrt{(a-0)^2+(a-2a)^2}[/tex]

                      = [tex]a\sqrt{2}[/tex]

Length of BX = [tex]\sqrt{(a-0)^2+(a-0)^2}[/tex]

                      = [tex]a\sqrt{2}[/tex]

Length of AX = BX = [tex]a\sqrt{2}[/tex]

Therefore, triangle AXB is an isosceles triangle.

Answer:

[tex]cos^2\theta + sin^2\theta = 1[/tex]

Step-by-step explanation:

Given

[tex](\frac{b}{r})^2 + (\frac{a}{r})^2[/tex]

Required

Use the expression to prove a trigonometry identity

The given expression is not complete until it is written as:

[tex](\frac{b}{r})^2 + (\frac{a}{r})^2 = (\frac{r}{r})^2[/tex]

Going by the Pythagoras theorem, we can assume the following.

So, we have:

[tex]Sin\theta = \frac{a}{r}[/tex]

[tex]Cos\theta = \frac{b}{r}[/tex]

Having said that:

The expression can be further simplified as:

[tex](\frac{b}{r})^2 + (\frac{a}{r})^2 = 1[/tex]

Substitute values for sin and cos

[tex](\frac{b}{r})^2 + (\frac{a}{r})^2 = 1[/tex] becomes

[tex]cos^2\theta + sin^2\theta = 1[/tex]

Answer:

5

Step-by-step explanation:

you divide 42 by 2,then get 21 so you divide that by 105 and get 5 :))

Answer:

In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number.

Any number that can be written as a fraction with integers is called a rational number . For example, 17 and −34 are rational numbers

Answer:

C. it cannot be a whole number

Step-by-step explanation:

Answer:

x = - 3

Step-by-step explanation:

Solve by isolating x on one side of the equation.

12x+12=8x

     -12    -12

12x=8x-12

      -8x

4x=-12

4x/4=-12/4

x = - 3

Answer:

The total weight of the smaller packages is 84 lb

Answer: Tiffany got 45 questions right! Hope this helped.

Step-by-step explanation:

Answer:

[tex] \sqrt{5} < 2.9 \\ = true \\ \\ 4 > \sqrt{23} \\ = false \\ \\ \frac{ \sqrt{30} }{5} < \frac{7}{5} \\ = true[/tex]

Thank you ☺️☺️

Answer:

Option 1

Step-by-step explanation:

First inequality:

-x/3>=-3 => x<9

Second inequality:

x>=17

Answer:

Wouldn’t y be 4 and x be 1?

Answer:

Y = -1X + 5

Step-by-step explanation:

I just solved it, it was a long problem, I don't wanna talk you through it. I think I'm correct.

Hope this helps! Let me know!

Answer:

54%

Step-by-step explanation:

Getting a head or a tail are two mutually exclusive events. Thus, given that probability of getting a tail is 0.46, the probability of getting a head is 0.54.

Two events are mutually exclusive or disjoint if they cannot both occur at the same time.

P(getting a head) + P(getting a tail) = 1

(Getting a head and getting a tail are mutually exclusive events. This implies that when we toss a coin, we either get a head or a tail.)

P(getting a head) + 0.46 = 1

P(getting a head) = 1 - 0.46 = 0.54

Learn more about mutually exclusive events here

https://brainly.com/question/5492865

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