Answer:
$7.80
Step-by-step explanation:
Find the cost to download 1 song. Divide 6 from 4.68
4.68/6 = 0.78
Each song costs $0.78.
Find the amount 10 songs cost. Multiply 0.78 with 10:
10 x 0.78 = 7.80
$7.80 is your answer.
~
Hi
6 = 4.68
10 = X
X = 10*4.68 /6
X = 46.8/6
X = 7.8
Evan and Luke see 8 worms on the path. Luke sees 2 more worms than Evan. Even sees 3 worms.How many worms does Luke see? 10 is my answer. What's yours?
Answer:
Luke saw 5 worms
Step-by-step explanation:
Evan and Luke saw 8 worms on the path.
Evan saw 3 worms while Luke saw 2 Worms more than Evan.
So luke is +2 of Evan
Luke= 3+2
Luke = 5
Luke saw a total of 5 worms while Evan saw a total of 3 worms adding up to a total of 8 worms
Evaluate.
8 x 4 + {15 / [8 - (3 + 2)]}
Answer:
the answer is 37 i believe
37
Step-by-step explanation:
First start with parenthesis 3 + 2=5. Next the brackets
8 - 5=3. Next 15 ÷ 3 = 5. Then Finally, 8 × 4 = 32, and add 5, which 37
Please help me with this is important and I’ll give you a brainless if the answer is right
Answer:
She subtracted 5 and got 6 instead of subtracting -5 which is 16
Step-by-step explanation:
11 - (-5)
Subtracting a negative is like adding
11 +5
16
She subtracted 5 and got 6 instead of subtracting -5 which is 16
y varies inversely with x. If x = 15 and y = 4 , find y when x = 60
Answer:
y=1
Step-by-step explanation:
if x=15
y=4
now what is y when the value of x is 60.
15x4/60
15x4=60
60/60=1
y=1
The solution is : the value of y is: y=1
What is multiplication?In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.
Here, we have,
given that,
y varies inversely with x. If x = 15 and y = 4 ,
now, we have to find y when x = 60
so, we have,
if x=15
y=4
now what is y when the value of x is 60.
15x4/60
15x4=60
60/60=1
y=1
Hence, The solution is : the value of y is: y=1
To learn more on multiplication click:
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I NEED HELP SO BAD MATH
Answer:
13:20
Step-by-step explanation:
Start time:
09:30Trip duration:
3 hr 50 minEnd time= ?
Solution 1Simply adding up the time the family left and time in trip:
09:30 + 03:50 = 13:20Sum of minutes:
30 min + 50 min = 80 min = 1 hr and 20 minSum of hours:
09 hr + 03 hr = 12 hr and add 1 hr from line above = 13 hrSo time arrival is:
13:20 Solution 2Time they left is 09:30 and it will take 2 hr and a half before noon.
Splitting 3 hr and 50 min into two parts, one part being 2 hr and 30 min and the other is:
3 hr 50 min - 2 hr 30 min = 1 hr 20 minAdding 2 hr 30 min and then adding 1 hr 20 min to initial time of 09:30:
09 : 30 + 02:30 = 12:00Then:
12:00 + 01:20 = 13: 20 this is arrival time of familyFind the distance that 5,2 is from the origin
Answer:
Step-by-step explanation:feel pleasure to help u.
Consider P2 with the inner product given by evaluation at -1, 0, and 1. That is < p, q >= p(−1)q(−1) + p(0)q(0) + p(1)q(1).
Let p(t) = 3t − t2 and q(t) = 3 + 2t2 .
A) Compute < p, q >, ||p||, and ||q||.
B) Compute the orthogonal projection of q onto the subspace spanned by p.
(A)
Evaluate [tex]p[/tex] and [tex]q[/tex] at the given values of [tex]t[/tex], then plug them into the inner product:
[tex]p(t)=3t-t^2\implies\begin{cases}p(-1)=-4\\p(0)=0\\p(1)=2\end{cases}[/tex]
[tex]q(t)=3+2t^2\implies\begin{cases}q(-1)=5\\q(0)=3\\q(1)=5\end{cases}[/tex]
Now,
[tex]\langle p,q\rangle=4\cdot5+0\cdot3+2\cdot5=30[/tex]
[tex]\|p\|=\sqrt{\langle p,p\rangle}=(-4)^2+0^2+2^2=20[/tex]
[tex]\|q\|=\sqrt{\langle q,q\rangle}=5^2+3^2+5^2=59[/tex]
(B)
Let [tex]V[/tex] denote the subspace spanned by [tex]p[/tex]. We need an orthonormal basis for [tex]V[/tex]. Since
[tex]p(t)=3t-t^2=3\cdot t+(-1)\cdot t^2[/tex]
we have the basis vectors [tex]\{t,t^2\}[/tex]; normalize these vectors to get the orthonormal basis,
[tex]\left\{\dfrac t{|t|},\dfrac{t^2}{|t^2|}\right\}=\left\{\dfrac t{|t|},1\right\}[/tex]
Then the projection of [tex]q[/tex] onto [tex]V[/tex] is
[tex]\mathrm{proj}_Vq(t)=\left(q(t)\cdot\dfrac t{|t|}\right)\dfrac t{|t|}+\left(q(t)\cdot1\right)1[/tex]
[tex]\mahtrm{proj}_Vq(t)=\dfrac{3t^2+2t^4}{t^2}+(3+2t^2)=\boxed{6+4t^2}[/tex]
A).
[tex]< p, q >=-10\\||p||=9\sqrt{2} \\||q||=3\sqrt{2}[/tex]
B).The orthogonal projection of q onto the subspace spanned by p is[tex]proj_vq(t)=6+4t^2[/tex]
We have [tex]p(t) = 3t - t^2 ,q(t) = 3 + 2t^2[/tex]
And < p, q >= p(−1)q(−1) + p(0)q(0) + p(1)q(1).
Now,
A).
[tex]p(-1) = 3.(-1) - (-1)^2 \\=-4\\p(1)=3.1-1^2\\=2q(-1) = 3 + 2.(-1)^2\\=5\\q(1) = 3 + 2.(1)^2\\=5p(0) = 3.0 - 0^2 \\=0\\q(0) = 3 + 2.0^2\\=3\\< p, q >= p(-1)q(-1) + p(0)q(0) + p(1)q(1)\\< p, q >=-4.5+0.3+2.5\\=-10\\||p||=<p,p>\\=\sqrt{(-4)^2+0+2^2} \\=\sqrt{20} \\=2\sqrt{5} \\||q||=<q,q>\\=\sqrt{5^2+3^2+5^2} \\=\sqrt{59}[/tex]
B)Let V be the subspace spanned by p.
Now, an orthonormal basis for p is[tex](t,t^2)[/tex]
Then the projection of q onto the subspace spanned by p is
[tex]proj_vq(t)=(q(t).\frac{t}{|t|} ).\frac{t}{|t|} +(q(t).1)1\\proj_vq(t)=\frac{3t^2+2t^4}{t^2} +(3+2t^2)\\proj_vq(t)=6+4t^2[/tex]
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A statistics practitioner would like to estimate a population mean to within 50 units with 99% confidence given that the population standard deviation is 250. What sample size should be used? b. Re-do part (a) changing the standard deviation to 50. c. Re-do part (a) using a 95% confidence leve
Answer:
(a) 167
(b) 7
(c) 97
Step-by-step explanation:
The (1 - α)% confidence interval for the population mean μ is:
[tex]CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}[/tex]
The margin of error is:
[tex]MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}[/tex]
Then the formula to estimate the sample size is:
[tex]n=[\frac{z_{\alpha/2}\cdot \sigma }{MOE}]^{2}[/tex]
(a)
For 99% confidence interval the critical value of z is:
z = 2.58.
The standard deviation is, 250.
Compute the sample size as follows:
[tex]n=[\frac{z_{\alpha/2}\cdot \sigma }{MOE}]^{2}[/tex]
[tex]=[\frac{2.58\times 250}{50}]^{2}\\\\=(12.9)^{2}\\\\=166.41\\\\\approx 167[/tex]
The sample size that should be used is 167.
(b)
Now the standard deviation is, 50.
Compute the sample size as follows:
[tex]n=[\frac{z_{\alpha/2}\cdot \sigma }{MOE}]^{2}[/tex]
[tex]=[\frac{2.58\times 50}{50}]^{2}\\\\=(2.58)^{2}\\\\=6.6564\\\\\approx 7[/tex]
The sample size that should be used is 7.
(c)
Now a 95% confidence level is used.
For 95% confidence interval the critical value of z is:
z = 1.96.
Compute the sample size as follows:
[tex]n=[\frac{z_{\alpha/2}\cdot \sigma }{MOE}]^{2}[/tex]
[tex]=[\frac{1.96\times 250}{50}]^{2}\\\\=(9.8)^{2}\\\\=96.04\\\\\approx 97[/tex]
The sample size that should be used is 97.
Jeremy's coach makes him run clockwise around a circular track with radius of 50 meters. Jeremy manages to maintain a constant speed around the track. He takes 48 seconds to finish one lap of the track. From his starting point, it takes him 12 seconds to reach the northernmost point of the track. Answer the following questions below assuming that the center of the track at the origin and the northernmost point is on the y-axis.
a. Give Jeremy's coordinates at his starting point.
b. Give Jeremy's coordinates when he has been running for 4 seconds.
c. Give Jeremy's coordinates when he has been running for 32 seconds.
Answer:
Coordinates of the starting point ( -50 ; 0 )
Coordinates 4 seconds later Q ( - 25*√3 ; 25 )
Coordinates 32 seconds later R ( 25 ; - 25*√3 )
Step-by-step explanation:
a) If Jeremy takes 48 seconds fr a lap then
The length of the lap ( length of the circle ) is:
L = 2*π*r ⇒ L = 100*π
If the time for one lap was 48 seconds at a constant speed, the speed was
v = 100*π / 48 [m/s]
v = 6,54 m/s
12 seconds is 1/4 0f 48 in that time he (she) reach the northernmost point, then he(she) necessarily started on the negative side of the x-axis the coordinates at this point are
( -50 ; 0 )
b) 4 seconds later, at v = 6,54 m/s by rule of three
In 12 seconds 90⁰
In 4 seconds (the third part ) x ??
x = 30⁰
sin 30⁰ = 1/2
cos 30⁰ = (√3)/2
And coordinates for the point are
sin 30⁰ = 1/2 = y/50 ⇒ y = 25
cos 30⁰ = (√3)/2 = x / 50 ⇒ x = 25*√3
coordinates of the point 4 seconds later
Q ( - 25*√3 ; 25 ) she (he) is in the negative part of x-axis
c) 32 seconds later
32 is 12 + 12 + 8
Then she (he) is 8 seconds below the positive side of x-axis
8 is 2/3 of 12 ( negative 60⁰ )
sin 60⁰ = (√3)/2 = y/50 y = 25*√3 negative
cos 60⁰ = 1/2 * 50 = X/50 x = 25
Coordinates of the point R
R ( 25 ; - 25*√3 )
10 points
A student who did not study for a test is left to guess the correct
answers. There are 6 questions, each with 4 answer choices. How many
ways can the test be answered?
A. 9640
B. 6094
C. 9046
D. 4096
Answer:
Hey there!
He can guess in 4x4x4x4x4x4 or 4096 ways.
Let me know if this helps :)
On his fishing trip Justin rides on hist 12 km south. The fish aren’t biting so he changes location and goes 4 km west. What is Justin's displacement?
Answer:
Displacement= 12.65 km S 18.44°W
Step-by-step explanation:
Justin rides on hist 12 km south.
He changes location and goes 4 km west.
The displacement from his current location = X
X²= 12²+4²
X²= 144+16
X²= 160
X= √160
X= 4√10
X= 12.649 km
X= 12.65 km
His total distance covered=12+4
His total distance covered= 16 km
Tan ^-1 12/4= angle
71.56° = angle
90-71.56= 18.44°
Displacement= 12.65 km S 18.44°W
What is the area of this triangle?
Answer:
21 units²
Step-by-step explanation:
A=1/2bh
b=6
h=7
1/2(6)(7)=
1/2(42)=
21 units²
A party planner is going to use an arch of balloons for a parade of recent graduates. The estimated curve the
balloons will create is modeled by the function given in the table, where x represents the distance in feet along
the ground from the start and f(x) represents the height in feet above the ground.
The planner needs a clearance of 9 feet under the arch. Has the planner met the minimum height?
No, because the width of the arch is 8 feet
Yes, because the width of the arch is 9.6 feet
No, because the maximum height of the arch is 8 feet
Yes, because the maximum height of the arch is 9.6
feet
Answer:
Option (4)
Step-by-step explanation:
Party planner has used an arc of balloons for the parade.
This arc starts from x = 0 along the ground and f(x) defines the height of the arch.
From the table attached, it is clear that at x = 4 maximum height of the arch is 9.6 feet.
Therefore, clearance space below the arc is 9.6 feet which is greater than 9 feet, minimum height required for the clearance of the parade.
Option (4) will be the answer.
Answer:
D. yes, because the maximum height of the arch is 9.6 feet
Step-by-step explanation:
EDGE 2020 :)
Which of the following expressions are equivalent to this expression
Answer:
-1 (4 + (-4))
Step-by-step explanation:
Any number multiplied by 0 is equal to 0
in the first option given we should calculate inside the
parenthesis first then multiply which I will give result equal to 0
Answer:
-1[4 + (-4)]
Step-by-step explanation:
So first we need to evaluate the original expression, -1(0) = 0 since this is equivalent to saying negative one times zero is zero.
Now let's look at the options.
-1[4 + (-4)] evaluates using order of operations and the distributive property to -1[0] = 0. Notice this is the same as our original expression.
-1[4 + (4)] evaluates to -1[8] = -8. Note, this is different from the original expression.
1 + [4 + (-4)] evaluates to 1 + [0] = 1. Note this is different from the original expression.
-1[-4 + (-4)] evaluate to -1[-8] = 8. Note this is different from the original expression.
So we want to choose the first option which matches the original expression.
Cheers.
out of every 122 containers of juice bought in a grocery store, 58 are orange juice. What fraction of juice purchased is orange juice?
Hi there! :)
Answer:
[tex]\huge\boxed{\frac{29}{61}}[/tex]
Express the given scenario as a fraction:
[tex]\frac{58}{122}[/tex]
Simplify the fraction by taking out the GCF, or 2:
[tex]\frac{2(29)}{2(61)}[/tex]
Cancel out the 2's:
[tex]\frac{29}{61}[/tex]
Answer: 58/122 I think and if simplified I think it would be 29/61
Step-by-step explanation:
122 containers of juice would be the denominator
and 58 is orange juice would be the numerator
then you can leave it or simplify!
solve for z? 2x-4y+4z-6w=4 6w-4x+4y-4z=-12 6w+4x-2y+6z=64 4z+2w+6y-4x=56
Answer:
z ≈ 9.22
Step-by-step explanation:
Given the equations
2x-4y+4z-6w=4 ................ 1
6w-4x+4y-4z=-12 ...............2
6w+4x-2y+6z=64 ............... 3
4z+2w+6y-4x=56 ................ 4
We will first need to reduce the equation by cancelling out some variables.
Add equations 1 and 2 will give;
(2x-4x)+(-4y+4y)+(4z-4z)+ (-6w+6w) = 4+12
-2x +0 = 16
-2x = 16
x = -8
Also, equation 2 minus 3
6w-6w+(-4x-4x)+4y+2y+(-4z-6z) = 12-64
-8x+6y-10z = -52
-8(-8)+6y-10z = -52
64+6y-10z = -52
6y-10z = -52-64
6y-10z = -116
3y-5z = -58 ... 5
Equation 3 * 1 and eqn 4 * 3
6w+4x-2y+6z=64 ............... 3
4z+2w+6y-4x=56 ................ 4
6w+4x-2y+6z=64
12z+6w+18y-12x= 168
Subtracting both equations;
16x-20y-6z = -104
8x-10y-3z = -52
8(-8)-10y-3z = -52
-64-10y-3z = -52
-10y-3z = -52+64
-10y-3z = 12 ....... 6
equating 5 and 6 and solving simultaneously;
3y-5z = -58 ... 5 * 10
-10y-3z = 12 ....... 6 * 3
30y-50z = -580
-30y-9z = 36
Add both equations
-50z-9z = -580+36
-59z = -544
z = -544/-59
z = 9.22
Hence z ≈ 9.22
4. A recent poll of 1079 adults finds that 55% of Americans support a more stringent immigration law. Construct a 99% confidence interval of the proportion of the population that will support such a law.
Answer:
0.5306[tex]<\mu<[/tex]0.5694
Step-by-step explanation:
USing the formuls for calculating the confidence interval for the population proportion;
CI = p±Z*√[p(1-p)/n]
p is the percentage proportion of the population 55%
Z is the z-score at 99% confidence interval = 2.576
n is the sample size = 1079
CI = 0.55 ± 2.576*[0.55(1-0.55)/√1079]
CI = 0.55 ± 2.576*[0.55(0.45)/√1079]
CI = 0.55 ± 2.576*[0.2475/√1079]
CI = 0.55 ± 2.576*[0.2475/32.85]
CI = 0.55 ± 2.576*[0.00753]
CI = 0.55 ±0.0194
CI =(0.55-0.0194, 0.55+0.0194)
CI = (0.5306, 0.5694)
Hence, a 99% confidence interval of the proportion of the population that will support such a law is 0.5306[tex]<\mu<[/tex]0.5694
The diagonals of a rhombus bisect each other of measures 8cm and 6cm .Find its perimeter. please help !!!!!!!!!!!!!!!!!!!!!!!!
Answer:
20 cm
Step-by-step explanation:
8/2 = 4
6/2 = 3
3 and 4 are the sides of the triangle (four triangles in rhombus)
[tex]a^{2} + b^{2} = c^{2} \\4^{2} + 3^{2} = c^{2}[/tex]
c = 5
5 x 4 = 20
Hope that helped!!! k
(10+i)^2 = (in form a+bi)
Answer:
99+20i
Step-by-step explanation:
(10+i)^2
➡
(10 + i) × (10 + i) = 100 + 10i + 10i + i^2 add like terms
100 + 20i + i^2 since i^2 = -1 we can write the expression like this
99 + 20i
free cus i have 300,000 - 100 = ?
Answer:
Step-by-step explanation:
300,000-100
300,00 + -100
=299900
Answer:
299900
Step-by-step explanation:
Find 1.3x when x=5.7
Answer:
7.41
Step-by-step explanation:
1.3 x 5.7
just use a calculator
Show all work to identify the asymptotes and zero of the function f of x equals 5 x over quantity x squared minus 25.
Answer:
asymptotes: x = -5, x = 5zero: x = 0Step-by-step explanation:
The function of interest is ...
[tex]f(x)=\dfrac{5x}{x^2-25}=\dfrac{5x}{(x-5)(x+5)}[/tex]
The asymptotes are found where the denominator is zero. It will be zero when either factor is zero, so at x = 5 and x = -5
__
The zeros are found where the numerator is zero. It will be zero for x = 0.
The asymptotes are x=-5, x=5; the zero is x=0.
Answer:
The asymptotes are x=-5, x=5; the zero is x=0.
Step-by-step explanation:
Find the value of (-3)4 +(-2)4 +(-1)4
the value of (-3)4+(-2)4×(-1)4 is -24
Answer:
98
Step-by-step explanation:
-3⁴ = -3*-3*-3*-3 = +81 = 81
-2⁴ = -2*-2*-2*-2 = +16 = 16
-1⁴ = -1*-1*-1*-1 = +1 = 1
Then:
(-3)⁴ + (-2)⁴ + (-1)⁴ = 81 + 16 + 1
= 98
Calculate the expected value of X, E(X), for the given probability distribution. E(X):_________
x 0 1 2 3
P(x) 0.5 0.1 0.1 0.3
Answer:
The expected value of X, E(X), for the given probability distribution is 1.2
Step-by-step explanation:
Mathematical hope (also known as hope, expected value, population means or simply means) expresses the average value of a random phenomenon and is denoted as E(x).
Hope is the sum of the product of the probability of each event and the value of that event. That is, it is the sum of the probability of each possible event multiplied by the frequency of said process, this indicates that if you have a discrete quantitative variable X with "n" possible events x₁, x₂, x₃... xₙ and probabilities P (X = xi) = Pi the mathematical expectation is:
E(x)=x₁*P₁ + x₂*P₂ + x₃*P₃ + ... + xₙ*Pₙ
In this case:
E(x)=x₁*P₁ + x₂*P₂ + x₃*P₃ + x₄*P₄
Being:
x₁: 0 P₁: 0.5x₂: 1P₂:0.1 x₃:2P₃:0.1 x₄: 3P₄: 0.3and replacing:
E(x)= 0* 0.5 + 1* 0.1 + 2*0.1 + 3*0.3
you get:
E(x)= 1.2
The expected value of X, E(X), for the given probability distribution is 1.2
you invested $27000 in two account paying 2% and 8% annual interest respectively of the total interest earned for the year was $2100 how much was invested at each rate? the amount invested at 2% is
Answer:2100
Step-by-step explanation:
How much money did Gemma have left in her checking account
Answer:
This can be solved by subtracting 584 from 2,054.
2,054-584
=1470
Step-by-step explanation:
Gemma would have $1470 left in her checking account. hope this helps you :)
Tim has 39 pairs of headphones and 13 music players. Tim wants to sell all of the headphones and music players in identical packages. What is the greatest number of packages Tim can make?
Answer:
13 packages
Step-by-step explanation:
We need to find the highest common factor, in order to solve this problem.
So, we have to find the highest common factor of 39 and 13.
We find the highest common factor of 39 and 13 because it says in the problem” Tim has 39 pairs of headphones and 13 music players.”
And than you just find the highest common factor, after you find the highest common factor... YOU ARE DONE SOLVING THE PROBLEM!
The highest common factor will be 13
13: 1,13
39:1,3,13,39
ANSWER:13
Hope this helps!
Answer:
13
Step-by-step explanation:
Greatest number of packages Tim can make =
H. C. F of 39 and 13
Factors of 39 = 13 * 3 * 1
Factors of 13 = 13 * 1
H.C.F = 13
Therefore, Greatest number of identical packages Tim can make is 13.
The table shows the results of the experiment to determine the 90-day weather forecast. How does the experimental probability compare to the theoretical probability? The theoretical probability for rain is 1/5. The experimental probability for rain is . The actual weather is the theoretical probability.
Answer: 1/6
Approximately the same.
Step-by-step explanation:
Answer:
The first answer was:1/6
The second answer was: approximately the same.
Step-by-step explanation:
Just did it on edge2020
consider the geometric sequence: 1, 3, 9, 27, ...
if n is an integer, which of these functions generate the sequence?
a) a(n)=3^n for n greater than or equal to 0
b) b(n)=3(3)^n for n greater than or equal to 0
c) c(n)=3^n for n greater than or equal to 2
d) d(n)=3^n-1 for n greater than or equal to 2
PLS ANSWER ASAPP!!
Answer:
The answer is option DStep-by-step explanation:
Since the sequence is a geometric sequence
For an nth term in a geometric sequence
[tex]A(n) = a ({r})^{n - 1} [/tex]
where
n is the number of terms
a is the first term
r is the common ratio
To find n we must first find the common ratio
To find the common ratio divide the previous term by the next term
That's
r = 3/1 = 3 or r = 9/3 = 3
a = 1
Substitute the values into the above formula
That's
If n is an integer then
[tex]A(n) = 1 ({3})^{n - 1} [/tex]
[tex]A(n) = {3}^{n - 1} [/tex]
where n is greater than or equal to 2
Hope this helps you
The function that describes the sequence is the first one:
a(n) = 3ⁿ fpr n ≥ 0.
Which function generates the sequence?Here we have the following sequence:
1, 3, 9, 27, ...
We can see that all of these are powers of 3, and the function must behave like:
f(0) = 1
f(1) = 3
f(2) = 9
...
And so on, then the function must be:
a(n) = 3ⁿ
when n = 0 we have:
a(0) = 3⁰ = 1
When n = 1
a(1) = 3¹ = 3
And so on.
Then we can see that the correct option is the first one.
Learn more about sequences at:
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brad walked 2.5 miles in 5/6 of an hour.how fast does he walk per hour
Answer:
Rate or speed=3 Miles per hour
Step-by-step explanation:
Brad walked 2.5 miles in 5/6 of an hour.
Distance covered by Brad = 2.5 miles
Distance covered by Brad= 2 1/2 miles
Distance covered by Brad= 5/2 miles
Time taken to cover the distance = 5/6 of an hour
His rate of walking or how fast he walks is determined by the formula
Rate or speed= distance/time
Rate or speed=( 5/2)/(5/6)
Rate or speed= (5/2)*(6/5)
Rate or speed=6/2
Rate or speed=3 Miles per hour