If you answer these questions i will give you free point's. (Answer all of them pls)


1. I am 50% of a quarter of 32.
2. I am two thirds of 60.
3. I am exactly half-way between 25% of 80 cm and 40% of 120cm.
4. I am one-quarter of 50% of 88kg.
5. I am 3% of half of 600 pounds.
6. I am exactly halfway between one fifth of 25cm and 2% of 300 cm.
7. I am greater that 0.6 kg, less than one-third of 6 kg, and equal to four times 10% of 3kg.

Answer:

y = 5x + 11

Step-by-step explanation:

Step 1:  When two lines are parallel, they have the same slope, as indicated by the following equation as m2 = m1, where

Thus, since the slope of line 1 is 5, the slope of line 2 is also 5.

Step 2:  Now we can plug in (-2, 1) for x and y and 5 for m to solve for b, the y-intercept of the other line:

1 = 5(-2) + b

1 = -10 + b

11 = b

Thus, the equation of the line parallel to y = 5x + 2 and passing through (-2, 1) is y = 5x + 11

The standard deviation of the random variable x is 1.1145

Since the Probability distribution of a random variable is the collection of value and its probability pair for values of that considered random variable.

The probability of a value of x is never neg.

The sum of the probabilities is always 1.

The sum of all values of P(X = x) equals 1, which is, considering n values

There are no negative values of P(X = x).

Since we are given the probability distribution as below, we will go and calculate the mean and standard deviation using the formula:

E(X)= ∑xP(X=x)

Standard deviation = √Variance(x)

Var(x) = E(x²) - [E(x)]²

X           0          1            2        3        4          5

p(x=x)   0.032   0.152   0.316  0.316  0.152  0.032

First we have to find E(x)

E(x) = (0x0.032) + (1x0.152) + (2x0.316) + (3x0.316) + (0.152) + (5x0.032)

The mean E(x) = 2.5

To find variance, we use Var(x) = E(x²) - [E(x)]²

But we have to calculate E(x²) first, since we already have found E(x)

So,

E(x²) = (0²x0.032) + (1²x0.152) + (2²x0.316) + (3²x0.316) + (4²x0.152) + (5²x0.032)

therefore, E(x²) = 7.492

Now we have all the values we can find the variance:

Var(x) = E(x²) - [E(x)]²

=7.492 - [2.5]²

= 1.242

With variance now we can find the standard deviation;

S.D = √Var(x)

= √1.242

= 1.1145

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The triangles are not similar

Given data ,

Let the first triangle be ΔJKL

Let the second triangle be ΔMNP

Now , the corresponding sides are

JK / JL ≠ NM / MP

where the corresponding sides of similar triangles are not in the same ratio

And , the common angle to both the triangles is ∠J = ∠M

So , ∠J = ∠M and JK / JL ≠ NM / MP

Hence , the triangles are not similar

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The value of angle L is 61°

Exterior angle theorem states that the measure of an exterior angle of a triangle is greater than either of the measures of the remote interior angles.

If angle A and B are interior angles and angle C is the exterior angle, what this theorem is saying is that;

A+B = C

Similarly,

angle L and angle E are the interior angles and 113 is the exterior angle, therefore;

113 = L + 52

L = 113 -52

L = 61°

Therefore angle L is 61°

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Answer:

12

Step-by-step explanation:

206

5x10 12x13=206 it may be incorrect but i not sure if it is incorrect

The measure,

⇒∠s = 124 degree

In the given figure of kite,

PQRS,

Measure of angle p = 22 degree

And angle R is a right angle

Therefore,

∠R = 90 degree

Now we know that for a kite PQRS

Angle Q and Angle S are equal

Now consider,

Angle s is equal to x degree

Therefore,

∠S = ∠ Q = x degree

We know that,

For a kite the sum of interior angle is equal to 360 degree.

Therefore,

⇒ ∠P + ∠Q + ∠R + ∠S = 360

⇒ 22 + x + 90 + x = 360

⇒ 22 + x + 90 + x = 360

⇒                     2x  = 248

⇒                        x  = 124 degree.

Thus,

Measure of angle s = 124 degree.

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The complex number in standard form is written as:

Z =  1.99 + i*0.201, so the correct option is a

Remember that a complex number can be written in standard form as:

Z = a + b*i

And in polar form the notation is (R, θ):

[tex]Z = R*e^{i*\theta} = R*cos(\theta) + i*R*sin(\theta)[/tex]

Here we have the complex number:

Z = 2(cos(11pi/6) + i*sin(11pi/6))?

So here we just need to solve these expressions, we will get:

Z = 2*(0.995 + i*0.100)

Z =  1.99 + i*0.201

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Complete question:

"Convert the polar representation of this complex number into its standard form: z = 2(cos 11pi/6+ i sin 11pi/6)? "

The equation of the line that passes through point (-3,-7) and point (-3,10) is x = -3.

The formula for equation of line is expressed as;

y = mx + b

Where m is slope and b is y-intercept.

Given the points through which the line passes: (-3,-7) and (-3,10).

The two given points (-3, -7) and (-3, 10) have the same x-coordinate -3

Hence, the two lines  lie on a vertical line.

since the slope of the vertical line is undefined.

The equation of the line passing through these two points is simply the equation of the vertical line:

x = -3

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The value of tan (A-B) is equal to 715/2052.

To find the value of tan(A - B), we can use the trigonometric identity:

tan(A - B) = (tan(A) - tan(B))/(1 + tan(A)tan(B))

Given that tan(A) = 40/9 and sin(B) = 45/53, we can determine the values of cos(B) and tan(B) using the Pythagorean identity:

sin^2(B) + cos^2(B) = 1

cos(B) = sqrt(1 - sin^2(B))

cos(B) = sqrt(1 - (45/53)^2)

cos(B) = sqrt(1 - 2025/2809)

cos(B) = sqrt(784/2809)

cos(B) = 28/53

tan(B) = sin(B)/cos(B)

tan(B) = (45/53)/(28/53)

tan(B) = 45/28

Now we can substitute the values into the formula for tan(A - B):

tan(A - B) = (tan(A) - tan(B))/(1 + tan(A)tan(B))

tan(A - B) = (40/9 - 45/28)/(1 + (40/9)(45/28))

tan(A - B) = [(1120/252 - 405/252)] / (1 + (1800/252))

tan(A - B) = (715/252) / (2052/252)

tan(A - B) = 715/2052

Therefore, tan(A - B) is equal to 715/2052.

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Answer: 0 , 5

Step-by-step explanation:

Imagine a plane taking off, first it drives to gain speed then flies, thats what you can use for coordinates.

X is the driving and Y is the flight.

The X is at 0, and the Y is at 5.

All the expressions after completing the square each equation are,

⇒ (x - 1/2)² = 5/4

⇒ (x - 5/2)² + 3/4 = 0

⇒ (2x + 3/2)² = 57/4

Given that;

Expressions are,

⇒ 2x² - 2x + 7 = 5

⇒ -2x² + 10x = 14

⇒ 4x² + 6x = 12

Now, We can completing the square each equation as;

⇒ 2x² - 2x + 7 = 5

⇒ x² - x + 7/2 = 5/2

⇒ x² - x + 1/4 - 1/4 + 7/2 = 5/2

⇒ (x - 1/2)² = 1 + 1/4

⇒ (x - 1/2)² = 5/4

⇒ -2x² + 10x = 14

⇒ - x² + 5x = 7

⇒ x² - 5x = - 7

⇒ x² - 5x + 25/4 - 25/4 = - 7

⇒ (x - 5/2)² = - 7 + 25/4

⇒ (x - 5/2)² = - 3/4

⇒ (x - 5/2)² + 3/4 = 0

⇒ 4x² + 6x = 12

⇒ (2x)² + 2×2x×3/2 + 9/4 -9/4 = 12

⇒ (2x + 3/2)² = 12 + 9/4

⇒ (2x + 3/2)² = 57/4

Thus, All the expressions after completing the square each equation are,

⇒ (x - 1/2)² = 5/4

⇒ (x - 5/2)² + 3/4 = 0

⇒ (2x + 3/2)² = 57/4

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The equation of the plane pi is: -6x-7y-9z=0.

To find the equation of the plane that contains the given line L and the origin as well, we first need to find two vectors that lie on the plane. One vector can be the direction vector of the line L, which is (2i - j + 3k). Now to find the second vector, we can take the vector from the origin to any point on the line L, and this vector will lie on the plane.

Let us now take t=0, and find the point on the line L:

r = 3i + 3j - k + 0(2i - j + 3k)

= 3i + 3j - k

So, the vector from the origin to this point is simply (3i + 3j - k). We can just take (3i + 3j - k) as our second vector.

Now, we can find the normal vector of the plane by taking the cross-product of two vectors that we just found, we get:

n = (2i - j + 3k) * (3i + 3j - k)

= -6i - 7j - 9k

Therefore, the equation of the plane pi is: -6x-7y-9z=0.

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t = (6 + 3k)/(k - 2) is the formula for t in the equation k=2(t+3)/t-3.

The given equation is k=2(t+3)/t-3.

We need to isolate t on one side of the equation.

Let's start by cross-multiplying:

k(t - 3) = 2(t + 3)

Expanding the brackets:

kt - 3k = 2t + 6

Now, let's gather all the terms with t on one side and all the constant

terms on the other side:

kt - 2t = 6 + 3k

Factoring out t on the left side:

t(k - 2) = 6 + 3k

Finally, we can solve for t by dividing both sides of the equation by (k - 2):

t = (6 + 3k)/(k - 2)

Therefore, t is the subject of the formula, and it is given by t = (6 + 3k)/(k - 2).

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Solving a system of equations we can see that Gavin worked 7 hours tutoring.

Let's define the variables:

x = number of hours tutoring.

y = number of hours land scaping.

We know that he worked for 10 hours and earned $137, then we can write a system of equations:

x + y = 10

14x + 13y = 137

Isolating y on the first equation we get:

y = 10 - x

Replace that in the second one to get:

14x + 13*(10 - x) = 137

14x + 130 - 13x = 137

x = 137 - 130 = 7

He worked 7 hours tutoring.

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The calculated value of the mode(s) of the data is (a) 1

From the question, we have the following parameters that can be used in our computation:

1, 0, 2, 2, 3, 0, 1, 1, 4, and 5

By definition, the mode of a data is the data that has the highest frequency

Using the above as a guide, we have the following:

The data element 1 has the highest frequency of 3

Other data elements have lesser frequencies

Hence, the mode(s) of the data is (a) 1

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The x-intercepts, in order from least to greatest, are (2.46, 0) and (5.54, 0).

Use the vertex form of a quadratic function, which is [tex]y = a(x-h)^2 + k,[/tex] where (h, k) is the vertex and "a" is the coefficient of the[tex]x^2[/tex]term. Since the vertex is at (4, 8 1/3), the quadratic function's equation is y = a(x-[tex]4)^2 + 8 1/3.[/tex]

Use the y-intercept to find the value of "a".

The y-intercept is (0,3), so when x=0, y=3.

Plugging these values into the equation above, we get: [tex]3 = a(0-4)^2 + 8 1/3[/tex].

Simplifying, we get 3 = 16a + 25/3, or 9/3 = 16a. Therefore, a = 9/48 or a = 3/16.

To obtain the complete equation, enter the value of "a" into the vertex form equation: [tex]y = (3/16)(x-4)^2 + 8 1/3.[/tex]

To find the x-intercepts, set y = 0 and solve for x.

The equation becomes: [tex]0 = (3/16)(x-4)^2 + 8 1/3[/tex].

Subtracting 8 1/3 from both sides, we get: [tex]-8 1/3 = (3/16)(x-4)^2[/tex]. Multiplying both sides by -1, we get: [tex]8 1/3 = (3/16)(x-4)^2.[/tex]

Take the square root of both sides to isolate[tex]x-4: \sqrt{(8 1/3) } = \sqrt{((3/16)(x-4)^2)}[/tex] Simplifying,

we get: [tex]\sqrt{(25/3)} = (3/4)(x-4).[/tex]

Solving for x, we get two solutions: [tex]x = 4 + 4\sqrt{(3)/3 } or x = 4 - 4\sqrt{(3)/3 }[/tex]

Sort the answers in order of best to worst. The x-intercepts are (2.46, 0) and (5.54, 0) because the first answer is around 5.54 and the second solution is roughly 2.46.

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A single log statement from the many log statements to 1 is: [tex]log(7wy^{(-8)}/x^3)[/tex]

The exponent that indicates the power to which a base number is raised to produce a given number are called logarithm.

Use the logarithmic identity:

log[tex](a^n)[/tex] = n*log(a)

to convert the coefficients 2, 3, and 8:

log w + log 7 - 3log x - 8log y

= log w + log 7 - log [tex]x^3[/tex] - log [tex]y^8[/tex]

Combine the terms on the right-hand side using the logarithmic identity:

log(a) + log(b) = log(ab)

log w + log 7 - log[tex]x^3[/tex] - log [tex]y^8[/tex]

= log([tex]7wy^{-8}/x^3[/tex])

Therefore, the single log statement is from the many log statements to 1 is: log[tex](7wy^{-8}/x^3)[/tex]

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The coordinates of vertex D in the parallelogram are (-7, -10).

We have,

To find the coordinates of vertex D of the parallelogram, we need to use the properties of a parallelogram.

One of these properties states that opposite sides of a parallelogram are parallel and have equal lengths.

Given that A = (8, 2), B = (6, -4), and C = (-5, -4), we can find the coordinates of D as follows:

Find the vector representing one of the sides of the parallelogram.

We can use the vector AB.

Vector AB = (x-coordinate of B - x-coordinate of A, y-coordinate of B - y-coordinate of A)

= (6 - 8, -4 - 2)

= (-2, -6)

Add this vector to point C to find the coordinates of D.

Coordinates of D = (x-coordinate of C + x-coordinate of AB, y-coordinate of C + y-coordinate of AB)

= (-5 - 2, -4 - 6)

= (-7, -10)

Therefore,

The coordinates of vertex D are (-7, -10).

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Answer:

  (x +4)²/25 +(y -3)²/16 = 1

Step-by-step explanation:

You want the equation of the ellipse with center (-4, 3) and semi-axes 5 and 4 in the x- and y-directions, respectively.

The standard form equation for an ellipse with center (h, k) and sem-axes 'a' and 'b' in the x- and y-directions, respectively, is ...

  (x -h)²/a² +(y -k)²/b² = 1

Using the given values, we find the equation to be ...

  (x +4)²/25 +(y -3)²/16 = 1

__

Additional comment

The longer of the two axes is the "major" axis, and its end points are the "vertices". For the purpose of an ellipse with center, vertices, and co-vertices specified, the equation is not affected by which axis is longer.

Effectively, this is the equation of a circle with different scale factors in the x- and y-directions.

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Answer:

[tex]m = \frac{1 - ( - 3)}{0 - ( - 4)} = \frac{4}{4} = 1[/tex]

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

The numerical value of the given log expression is -73.

From definitions of logarithms, we know that :

[tex]log(a*b) = log(a) + log(b)\\log(a / b) = log(a) - log(b)[/tex]

[tex]log(a^n) = n*log(a)[/tex]

Therefore,

[tex]log(\frac{\sqrt[3]{b^4}}{a^8c^5 }) = \frac{4}{3}*log(b) - 8*log(a) - 5*log(c)[/tex]

substituting the given values

[tex]log(a) = 10\\log(b) = 9\\log(c) = 1\\[/tex]

we get the value of the given expression

[tex]log(\frac{\sqrt[3]{b^4}}{a^8c^5 }) = \frac{4}{3}*9 - 8*10 - 5*1[/tex]

[tex]log(\frac{\sqrt[3]{b^4}}{a^8c^5 }) = 12 - 80 - 5[/tex]

[tex]log(\frac{\sqrt[3]{b^4}}{a^8c^5 }) = -73[/tex]

Therefore the numerical value of the given log expression is -73.

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Based on the information provided, it seems that you have a rectangular grid with a shaded area, and the grid contains  option D.  48 square units.

To calculate the area of the shaded part, we would need to know the dimensions of the rectangle as well as the specific location and size of the shaded region within it.

If you can provide more details about the dimensions of the rectangular grid and the shaded region, I would be happy to help you calculate the area of the shaded part. Once we have that information, we can apply the formula for calculating the area of a rectangle,

which is Area = length × width. The result will give us the area of the shaded part in square units.

The area in square units, of the shaded part of the rectangle It has 48. Therefore the correct option  D

The Question was Incomplete, Find the full content below :

The grid shown below is in the shape of a rectangle. What is the area, in square units, of the shaded part of the rectangle? a 14 b 24 c 28 d 48

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The equation of the line is y = x/7 - 1/7

The equation of a straight line is y=mx+c . Where m is the gradient or slope and c is the height at which the line crosses the y -axis, also known as the y -intercept.

The equation of a line can be expressed as;

y-y1 = m(x -x1)

where m is the slope

The slope = 1/7

x1 = 8 and y1 = 1

Therefore;

y -1 = 1/7( x -8)

7(y-1) = x-8

7y -7 = x-8

collecting like terms

7y = x - 8+7

7y = x -1

y = x/7 -1/7

The intercept is -1/7 and the slope is 1/7

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Answer:

3



Step-by-step explanation:

Area = 7pi/5

56/360 × pi r² = 7pi/5

Pi is canceled on both sides.

r² = 7/5 ÷ 56/360 = 9

r = root 9 = 3

Answer:

(a) 5 ft^2

Step-by-step explanation:

The formula for area of a triangle is given by the formula,

A = 1/2bh, where

Thus, we can plug in 5 for b and 2 for h in the formula to find the area of the triangle in square feet:

A = 1/2(5)(2)

A = (5/2)(2)

A = 10/2

A = 5

Thus, the area of a triangle whose base is 5 ft and whose height is 2 ft is 5 ft^2

In a rectangle, the value of x is,

⇒ x = 5

We have to given that;

ABCD is a rectangle.

And, AC = 5x + 2

BD = x + 22

Since, We know that;

Diagonal of a rectangle are equal in length.

Hence, We get;

AC = BD

(5x + 2) = (x + 22)

5x - x = 22 - 2

4x = 20

x = 20/4

x = 5

Thus, the value of x is,

⇒ x = 5

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The area of the given figure with rectangle and triangle is 27.5 square centimeters.

The given figure has a rectangle and two triangles.

The area of the rectangle is length times width

Length = 5 cm

Width = 4 cm

Area of rectangle = 5×4

=20 square centimeters

Area of triangle =1/2 base ×height

=1/2×2.5×3

=3.75  square centimeters

As there are two triangles, 2(3.75)=7.5   square centimeters

Total area = 20+7.5

=27.5 square centimeters

Hence, the area of the given figure with rectangle and triangle is 27.5 square centimeters.

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