If we sample from a small finite population without replacement, the binomial distribution should not be used because
the events are not independent. If sampling is done without replacement and the outcomes belong to one of two types,
we can use the hypergeometric distribution. If a population has A objects of one type, while the remaining B objects are
of the other type, and if n objects are sampled without replacement, then the probability of getting x objects of type A and
n-x objects of type B under the hypergeometric distribution is given by the following formula. In a lottery game, a bettor
selects four numbers from 1 to 54 (without repetition), and a winning four-number combination is later randomly
selected. Find the probabilities of getting exactly two winning numbers with one ticket. (Hint: Use A = 4, B = 50, n = 4, and
x=2.)
P(x)=
A!
B!
(A + B)!
(A-x)!x! (B-n+x)!(n-x)! (A+B-n)!n!
+


P(2)=
(Round to four decimal places as needed.)

The area of the quadrilateral is 2 square units

From the question, we have the following parameters that can be used in our computation:

(-3, -3), (-2, -3), (-5, -1), and (-2, -1)

The area of the triangle in square units is calculated as

Area = 1/2 * |x₁y₂ - x₂y₁ + x₂y₃ - x₃y₂ + x₃y₄ - x₄y₃ + x₄y₁ - x₁y₄|

Substitute the known values in the above equation, so, we have the following representation

Area = 1/2 * |-3 * -3 - -3 * -2 + -2 * -1 - -3 * -5 + -5 * -1 - -1 * -2 + -2 * -3 - -3 * -1|

Evaluate the sum and the difference of products

Area = 1/2 * 4

So, we have

Area = 2

Hence, the area of the triangle is 2 square units

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The table should be completed to show different percentages of the questions Rita answered correctly on the pre-test as follows;

Number of questions correct           Percentage

7                                                       350% of the correct pre-test questions.

1                                                        50% of the correct pre-test questions.

2                                                       100% of the correct pre-test questions.

In Mathematics and Statistics, a percentage refers to any numerical value that is expressed as a fraction of hundred (100). This ultimately implies that, a percentage indicates the hundredth parts of any given numerical value.

Based on the information provided about this tape diagram that shows the number of questions Rita answered correctly on the pre-test, we can logically deduce that each of the box represents the number of questions and corresponds to a percentage of 50;

350%  ⇒ 350/50 = 7 questions.

50%  ⇒ 50/50 = 1 question.

100%  ⇒ 100/50 = 2 questions.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Responsible financial plan will take into consideration both short term and long term goals.

Given,

A financial plan is to be made.

A financial plan protects you from life's surprises. A Personal financial plan reduces doubt or uncertainty about your decisions and make adjustments to help overcome obstacles that could alter your lifestyle.

Now,

To make a better financial plan one should consider his/her short term as well long term goals.

Short term goals:

Short term goals include the goals that are needed to be achieved in the time frame 2-4 years.

For example,

One has to buy a car in the coming 3 years than this type of goals are considered short term and financial plan is to be made according to the price of car that is to be paid after 3 years while buying a car.

Long term goals:

Long term goals include the goals that are needed to be achieved in the time frame 10-12 years.

For example,

Retirement can be considered as long term plan for which one has to save a big amount of corpus so that after retirement his/her expenses will be well taken care off.

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The derivative of the function y = -3x + 5t/(1 + t[tex]^3[/tex]) is (-3x + 5)/(1 + x[tex]^3[/tex]).

To find the derivative of the given function using the first part of the Fundamental Theorem of Calculus, we need to evaluate the integral of the function.

The integral of the function f(t) with respect to t, from a constant 'a' to 'x', is denoted as:

∫[a to x] f(t) dt

In this case, the function is y = (-t[tex]^3[/tex] + 5)/(1 + t[tex]^3[/tex]), and we need to find its derivative.

Using the Fundamental Theorem of Calculus, the derivative of y with respect to x is:

d/dx ∫[a to x] (-t[tex]^3[/tex] + 5)/(1 + t[tex]^3[/tex]) dt

Applying the first part of the Fundamental Theorem of Calculus, we can differentiate the integral with respect to x:

d/dx ∫[a to x] (-t[tex]^3[/tex] + 5)/(1 + t[tex]^3[/tex]) dt = (-x[tex]^3[/tex] + 5)/(1 + x[tex]^3[/tex])

The derivative of the given function y = (-t[tex]^3[/tex] + 5)/(1 + t^3) with respect to x is (-x[tex]^3[/tex] + 5)/(1 + x[tex]^3[/tex]).

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]9y-3xy^2-4+x[/tex]

9y-3xy²-4+x

The rate at which the area of the Rectangle is changing at the instant when the other side is 13 cm and increasing at 3 cm per minute is approximately -1.385 cm/min. Note that the negative sign indicates that the width is decreasing

To find how fast the area of the rectangle is changing, we can use the formula for the derivative of the area with respect to time. Let's denote the width of the rectangle as x (in cm) and the length as y (in cm). We are given that x = 6 cm and dy/dt = 3 cm/min. We want to find dx/dt, the rate at which the area is changing.

The area of a rectangle is given by A = x * y. Taking the derivative of both sides with respect to time t, we have:

dA/dt = (d/dt)(x * y)

To solve for dA/dt, we need to express y in terms of x. We know that the length y is increasing at a rate of dy/dt = 3 cm/min. Therefore, we can write:

dy/dt = 3 cm/min

dy = 3 dt

dy/dt = 3

Now, we can differentiate the area equation with respect to time:

dA/dt = x * (dy/dt) + y * (dx/dt)

Substituting the given values:

dA/dt = 6 * 3 + 13 * (dx/dt)

Since we are interested in finding dx/dt, we can rearrange the equation:

dx/dt = (dA/dt - 6 * 3) / 13

Now, let's plug in the given values and calculate the rate at which the area is changing:dx/dt = (dA/dt - 6 * 3) / 13

dx/dt = (0 - 6 * 3) / 13

dx/dt = -18 / 13

Therefore, the rate at which the area of the rectangle is changing at the instant when the other side is 13 cm and increasing at 3 cm per minute is approximately -1.385 cm/min. Note that the negative sign indicates that the width is decreasing

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The area of the rectangle is increasing at a rate of 18 cm^2 per minute when the other side is 13 cm and increasing at 3 cm per minute.

Let's use the formula for the area of a rectangle: A = lw, where A is the area, l is the length, and w is the width.

Since one side of the rectangle is fixed at 6 cm, we can express the area as a function of the other side w: A(w) = 6w.

The rate of change of the area with respect to time is given by the rectangle of A with respect to time t:

dA/dt = d/dt (6w) = 6 dw/dt

We also know that the width is increasing at a rate of 3 cm per minute, so dw/dt = 3 cm/min.

At the instant when the other side is 13 cm, the width of the rectangle is w = 13 cm. Therefore, the rate of change of the area at that instant is:

dA/dt = 6 dw/dt = 6(3) = 18 cm^2/min.

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a. The expression (3x^4)^2 is incorrectly simplified because the exponent 2 must be distributed to both the 3 and the x^4. This means that the expression should be simplified as follows: (3x^4)^2 = 3^2 * (x^4)^2 = 9x^8

b. The expression 4x^0 = 0 is incorrectly simplified because any number raised to the power of 0 equals 1.

This means that the expression should be simplified as follows:
4x^0 = 4 * 1 = 4

c. The expression 5x^2 = 1/5x^2 is incorrectly simplified because the right side of the equation is the reciprocal of 5x^2.

This means that the expression should be simplified as follows:
5x^2 ≠ 1/5x^2

d. The expression 8x/4x^-1 = 2 is incorrectly simplified because the denominator 4x^-1 can be simplified as 4/x, which means that the expression should be simplified as follows:
8x/(4x^-1) = 8x * (4/x) = 32

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The monomers arranged in decreasing order of reactivity towards cationic polymerization are ii > i > iii.

Cationic polymerization is a process where a cationic initiator initiates the polymerization of monomers. In this case, monomer ii is the most reactive towards cationic polymerization, followed by monomer i, and then monomer iii. Monomer ii exhibits the highest reactivity due to its chemical structure, which enables it to readily undergo cationic polymerization. Monomer i has slightly lower reactivity compared to ii, while monomer iii is the least reactive among the three monomers. The arrangement ii > i > iii implies that monomer ii will polymerize the fastest, followed by monomer i, and then monomer iii. This ordering of monomers is based on their relative abilities to undergo cationic polymerization

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It is expected that 300 participants out of the 900 who participate in the survey would receive a coupon for sleigh rides.

To determine the number of participants expected to receive a coupon for sleigh rides, we need to divide the total number of participants (900) by the number of coupon options (3) since each option has an equal chance of being received.

The expected number of participants receiving a coupon for sleigh rides can be calculated as follows:

Total participants / Number of coupon options = Expected number of participants receiving a sleigh ride coupon

900 participants / 3 coupon options = 300 participants.

Therefore, it is expected that 300 participants out of the 900 who participate in the survey would receive a coupon for sleigh rides.

It's important to note that this calculation assumes an equal chance of receiving each type of coupon and does not consider any specific preferences or biases that participants may have.

The calculation is based on the assumption of a random distribution of coupons among the participants.

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To change the order of integration for the given triple integral, we can integrate with respect to one variable at a time.

The original order of integration is: ∫₀¹₆ ∫₀² ∫₃ʸ⁶ ₅cos(x²) ₄z dx dy dz

Let's change the order of integration. We start by integrating with respect to z first:

∫₀¹₆ ∫₀² ∫₃ʸ⁶ ₅cos(x²) ₄z dx dy dz

= ∫₀¹₆ ∫₀² [2z₃ʸ⁶ cos(x²)] dx dy

= ∫₀¹₆ [2z₃ʸ⁶ cos(x²)] x=₀² dy dz

Next, we integrate with respect to x:

∫₀¹₆ [2z₃ʸ⁶ cos(x²)] x=₀² dy dz

= ∫₀¹₆ [2z₃ʸ⁶ (sin(x²))|₀²] dy dz

= ∫₀¹₆ [2z₃ʸ⁶ (sin(4) - sin(0))] dy dz

= ∫₀¹₆ [2z₃ʸ⁶ sin(4)] dy dz

Finally, we integrate with respect to y:

∫₀¹₆ [2z₃ʸ⁶ sin(4)] dy dz

= [z₃ʸ⁷ sin(4)/7] ₀¹₆ dz

= ∫₀¹₆ z₃ sin(4)/7 dz

Now we can integrate with respect to z:

∫₀¹₆ z₃ sin(4)/7 dz

= [(z² sin(4))/14] ₀¹₆

= (16² sin(4))/14 - (0² sin(4))/14

= (256 sin(4))/14

= (128 sin(4))/7

Therefore, by changing the order of integration, the given triple integral becomes (128 sin(4))/7.

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The distance between the points (-7, -3) and (-3, -5) in simplest radical form is 2√5.

The distance formula used in finding the distance between two points is expressed as;

[tex]d = \sqrt{( x_2 - x_1 )^2 + ( y_2 - y_1)^2 }[/tex]

Given the points in the question:

Point 1 (-7,-3)

Point 2 (-3,-5)

Plug the given values into the distance formula and simplify.

[tex]d = \sqrt{( x_2 - x_1 )^2 + ( y_2 - y_1)^2 }\\\\d = \sqrt{( -3 - (-7) )^2 + ( -5 - (-3))^2 }\\\\d = \sqrt{( -3 + 7 )^2 + ( -5 + 3)^2 }\\\\d = \sqrt{( 4 )^2 + ( -2)^2 }\\\\d = \sqrt{16 + 4 }\\\\d = \sqrt{20 }\\\\d = 2\sqrt{5}[/tex]

Therefore, the distance between the points is 2√5 .

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Answer:

Solution is in attached photo.

Step-by-step explanation:

Do take note, when the square is split into 2 diagonal halves, we will see a isosceles triangle, from there, we can use sine rule (there is more than one way) to find the length of one side.

The statement "if the means of two distributions are equal, then the variance must also be equal" is false. While the mean and variance of a distribution are related, they are not always directly proportional to each other.

It is possible for two distributions to have the same mean but different variances. For example, imagine two distributions where one has all of its values clustered tightly around the mean, while the other has a wider range of values spread out more widely from the mean.

In this case, the first distribution would have a lower variance than the second, but both could still have the same mean. In summary, while there may be some cases where equal means correspond with equal variances, this is not always the case.

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S is transitive. Since S is reflexive, symmetric, and transitive, it is an equivalence relation.

To prove that S is an equivalence relation, we need to show that it satisfies three conditions: reflexivity, symmetry, and transitivity.

Reflexivity: For any ordered pair (a, b), we have a + b = b + a. So, (a, b) S (a, b), and S is reflexive.

Symmetry: If (a, b) S (c, d), then a + d = b + c. Rearranging this equation gives us d + a = c + b, which implies that (c, d) S (a, b). Therefore, S is symmetric.

Transitivity: If (a, b) S (c, d) and (c, d) S (e, f), then we have a + d = b + c and c + f = d + e. Adding these two equations gives us a + 2d + f = b + 2c + e. Rearranging this equation, we get (a, b) S (e, f). Hence, S is transitive.

Since S is reflexive, symmetric, and transitive, it is an equivalence relation.

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Similarly, if the consumer's income increases, they may choose to consume more of both function x1 and x2, or they may choose to consume more of one good and less of the other, depending on the relative prices and the marginal utility of each good.

The utility function represents the satisfaction or happiness a consumer derives from consuming two goods, x1 and x2. In this case, the utility function is u(x1, x2) = x1x2^2. This means that the consumer values x1 and x2 positively and that the value the consumer derives from x2 increases at a faster rate than x1 as they consume more of it.

The budget constraint, on the other hand, represents the limited resources or income of the consumer. It is given by p1x1 + p2x2 = w, where p1 and p2 are the prices of x1 and x2, respectively, and w is the consumer's income.

To find the optimal consumption bundle, we need to maximize the utility function subject to the budget constraint. This can be done using the method of Lagrange multipliers.

The Lagrangian function is given by:

L(x1, x2, λ) = x1x2^2 + λ(w - p1x1 - p2x2)

Taking partial derivatives with respect to x1, x2, and λ and setting them equal to zero, we get the following first-order conditions:

∂L/∂x1 = x2^2 - λp1 = 0

∂L/∂x2 = 2x1x2 - λp2 = 0

∂L/∂λ = w - p1x1 - p2x2 = 0

Solving these equations simultaneously, we can find the optimal values of x1 and x2 that maximize the utility function subject to the budget constraint. Once we have the optimal consumption bundle, we can use it to make predictions about how changes in prices or income will affect the consumer's consumption of x1 and x2. For example, if the price of x1 increases, the consumer will consume less of it and more of x2, assuming that the utility-maximizing bundle is still affordable.

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Answer:

Step-by-step explanation:

To simplify the fraction (−4c^−1)^3 / (12c^−8), we can apply the rules of exponents.

First, let's simplify the numerator: (-4c^(-1))^3. To raise a power to a power, we multiply the exponents, so we have:

(-4c^(-1))^3 = (-4)^3 * (c^(-1))^3

= -64 * c^(-3)

Now, let's simplify the denominator: 12c^(-8).

Putting the simplified numerator and denominator together, the fraction becomes:

(-64 * c^(-3)) / (12c^(-8))

To simplify further, we can divide the coefficients and subtract the exponents of the variable:

(-64 / 12) * (c^(-3 - (-8)))

= (-64 / 12) * (c^5)

= -16/3 * c^5

So, the fraction (−4c^−1)^3 / (12c^−8) simplifies to (-16/3) * c^5.

Therefore, the amount of energy (in kJ) needed to ionize 7.5 mol of sodium is 3720 kJ. This is the long answer that contains 250 words

To determine the amount of energy (in kJ) needed to ionize 7.5 mol of sodium (Na(g) + 496 kJ → Na+(g) + e–), we can use dimensional analysis. The balanced chemical equation for the ionization of sodium is:Na(g) + 496 kJ → Na+(g) + e–The energy required to ionize one mole of sodium is 496 kJ/mol.

Therefore, the energy required to ionize 7.5 mol of sodium can be calculated as:7.5 mol × 496 kJ/mol = 3720 kJ Therefore, the amount of energy (in kJ) needed to ionize 7.5 mol of sodium is 3720 kJ. This is the long answer that contains 250 words.

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The function f takes a binary string of length 2, and returns the first bit of that string, which is either 0 or 1.

Therefore, the range of f is {0, 1}.

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If in the circle centered at "A", we have NA ≅ PA, MO⊥NA, and RO⊥PA, then the measure of the the segment PO is (d) 3.5 ft.

From the figure, we observe the triangles OAN and OAP are "right-triangles" where one "common-side" is OA and the two "congruent-sides" NA ≅ PA (given), it follows that they are congruent.

⇒ OP ≅ ON;

We know that, the perpendicular drawn from circle's center on chord divides it in two "congruent-segments",

So, We have;

PO ≅ RP, and NO ≅ MN;

​Which means that, PO = RO/2 and ON = MO/2 = 7/2;

Since, OP ≅ ON, we get:

⇒ PO = 7/2 = 3.5,

Therefore, the correct option is (d).

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Approximately 10.8% of the original amount of Sr-90 will remain in the artifact after 68.8 years.

The decay of a radioactive substance is modeled by the equation:

N(t) = N₀ * (1/2)^(t / T)

where N(t) is the amount of the substance at time t, N₀ is the initial amount, T is the half-life, and t is the time elapsed since the initial measurement.

In this case, we are given that the half-life of Sr-90 is T = 28.1 years, and we want to find the percentage of Sr-90 remaining after 68.8 years, which is t = 68.8 years.

The percentage of Sr-90 remaining at time t can be found by dividing the amount of Sr-90 at time t by the initial amount N₀, and multiplying by 100:

% remaining = (N(t) / N₀) * 100

Substituting the values given, we get:

% remaining = (N₀ * (1/2)^(t/T) / N₀) * 100

= (1/2)^(68.8/28.1) * 100

≈ 10.8%

Therefore, approximately 10.8% of the original amount of Sr-90 will remain in the artifact after 68.8 years.

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The equation of the tangent plane is -x/√2 - y/2 + z = 1/2√2.

To parametrize the surface A, we can use spherical coordinates:

x = cosθ sinϕ

y = sinθ sinϕ / √2

z = cosϕ

where 0 ≤ θ ≤ 2π and 0 ≤ ϕ ≤ π.

Substituting these expressions into the equation of A, we get:

(cosθ sinϕ)^2 + 2(sinθ sinϕ / √2)^2 + cos^2ϕ = 1

Simplifying and rearranging, we get:

sin^2ϕ(cos^2θ + sin^2θ/2) + cos^2ϕ = 1

sin^2ϕ + cos^2ϕ = 1

So this parametrization satisfies the equation of A.

To find the tangent plane at the point (1/√2, 1/2, 0), we need the partial derivatives of x, y, and z with respect to θ and ϕ:

∂x/∂θ = -sinθ sinϕ

∂y/∂θ = cosθ sinϕ / √2

∂z/∂θ = 0

∂x/∂ϕ = cosθ cosϕ

∂y/∂ϕ = sinθ cosϕ / √2

∂z/∂ϕ = -sinϕ

Evaluating these partial derivatives at (1/√2, 1/2, 0), we get:

∂x/∂θ = -1/2

∂y/∂θ = 1/2√2

∂z/∂θ = 0

∂x/∂ϕ = 1/√2

∂y/∂ϕ = 1/2

∂z/∂ϕ = 0

So the normal vector to the tangent plane at (1/√2, 1/2, 0) is given by:

n = (-∂x/∂θ, -∂y/∂θ, ∂x/∂ϕ) × (∂x/∂ϕ, ∂y/∂ϕ, -∂z/∂ϕ)

 = (-1/2, 1/2√2, 0) × (1/√2, 1/2, 0)

 = (-1/2, -1/4√2, 1/2)

So the equation of the tangent plane is:

(-1/2)(x - 1/√2) + (-1/4√2)(y - 1/2) + (1/2)(z - 0) = 0

Simplifying, we get:

-x/√2 - y/2 + z = 1/2√2

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The moment of inertia about the z-axis of a thin spherical shell with equation x² + y² + z² = 2a and constant density 8 is 8.

The moment of inertia of a solid object measures its resistance to rotational motion around a specific axis. For a thin spherical shell, the moment of inertia about the z-axis can be calculated using the formula:

I = ∫(r²) dm

where r is the perpendicular distance from the axis of rotation (z-axis) to an infinitesimally small mass element dm.

In this case, the spherical shell has constant density, so the mass per unit volume is constant. Therefore, dm = ρ dV, where ρ is the density and dV is the volume element.

Since the equation of the spherical shell is x² + y² + z² = 2a, we can rewrite it as r² + z² = 2a, where r is the distance from the z-axis to a point on the shell. The moment of inertia can be calculated by integrating over the volume of the shell:

I = ∫∫∫ (r²) ρ dV

Since the density is constant, ρ can be taken out of the integral:

I = ρ ∫∫∫ (r²) dV

The integral represents the volume of the spherical shell, which is 4πa². Therefore, we have:

I = ρ (4πa²)

Substituting the given density ρ = 8, we get:

I = 8 (4πa²) = 32πa²

So, the moment of inertia about the z-axis of the thin spherical shell is 32πa².

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The number 1.088 x 10¹ is 13.6 times larger than 8 x 10⁻¹

To find how many times larger is (1.088 x 10¹)  than (8 x 10⁻¹), we just need to take the quotient between these two numbers. To do so remember that when we take the quotient between two powerswith the same base, we just need to subtract the exponents.

Then here we will get:

[tex]\frac{1.088*10^1}{8*10^{-1}} = \frac{1.088}{8} *10^{1 - (-1)} = 0.136*10^2[/tex]

We can rewrite that as:

1.36*10 = 13.6

Then the first number is 13.6 times larger than the second one.

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The line integral along the boundary of the triangle C is 32/15.

To apply Green's , we need to find the curl of the vector field F:

∂F₂/∂x - ∂F₁/∂y = (2xy³) - (y)

The boundary of the triangle C, which consists of three-line segments:

C₁: From (0,0) to (1,0)

C₂: From (1,0) to (1,2)

C₃: From (1,2) to (0,0)

Using the parametric equations for each line segment, we can express the line integral as:

∫C F · dr = ∫∫R (∂F₂/∂x - ∂F₁/∂y) dA

R is the region enclosed by C.

Since R is a triangle with vertices (0,0), (1,0), and (1,2), we can use a double integral to compute the area of R:

∫∫R dA = [tex]\int_0^1 \int_0^{y_2} dx dy[/tex] = 1/2

Now we can apply Green's Theorem:

∫C F · dr = ∫∫R (∂F₂/∂x - ∂F₁/∂y) dA

= ∫∫R (2xy³ - y) dA

= [tex]\int_0^1 \int_0^{y_2} (2xy^3 - y) dx dy[/tex]

= [tex]\int_0^2 (4/5)y^5 - (1/2)y^2 dy[/tex]

= 32/15

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[tex]4x^2 + 9y^2 = 36[/tex] is the rectangular form of the curve using parametric equations.

A set of equations known as a parametric equation expresses point coordinates in terms of one or more parameters. In other words, it establishes a connection between one or more variables that specify a point's or an object's location in space. Curves, surfaces, and other geometric shapes are frequently described using parametric equations. Due to their greater versatility in forming complicated shapes than conventional equations, they are excellent for visualising complex shapes and producing computer-generated visuals. In physics, engineering, and mathematics, parametric equations are frequently utilised because they offer a potent tool for modelling and analysing complicated systems.

To eliminate the parameter, we need to solve for the parameter (in this case, theta) in terms of x and y and then substitute that expression into the other equation.

From the first equation, we have cos(theta) = x/3.

From the second equation, we have sin(theta) = y/6.

We can use the Pythagorean identity [tex]sin^2(theta) + cos^2(theta) = 1[/tex]to eliminate theta:

[tex]sin^2(theta) + cos^2(theta) = (y/6)^2 + (x/3)^2 = 1[/tex]

Multiplying both sides by 36:

[tex]4x^2 + 9y^2 = 36[/tex]

This is the rectangular form of the curve using parametric equations.

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Answer:

$36.52

Step-by-step explanation:

To calculate how much each friend will pay, we need to consider the bill amount, sales tax, and tip. Let's break it down step by step:

Bill before tax: $84.62

Sales tax: 7% of the bill before tax

Sales tax = 7/100 * $84.62

= $5.92

Bill after tax: Bill before tax + Sales tax

Bill after tax = $84.62 + $5.92

= $90.54

Tip: 21% of the bill after tax

Tip = 21/100 * $90.54

= $19.01

Total amount per person: Bill after tax + Tip

Total amount per person = $90.54 + $19.01

= $109.55

Finally, to find out how much each friend will pay, we divide the total amount equally among the three friends:

Amount per friend = Total amount per person / Number of friends

= $109.55 / 3

= $36.52 (rounded to the nearest cent)

Each friend will pay approximately $36.52.
Hope this helps ^^

The chi-square test for homogeneity is used if he wants to determine if the distributions are the same.

What is the chi-square test?

Chi-square is a statistical test that looks at how categorical variables from a random sample differ from one another to see if the expected and actual findings match together well.  It is a contrast of two sets of statistical data. Karl Pearson developed this test in 1900 for the analysis and distribution of categorical data.

Here,

We have to determine for which situations should the chi-square test for homogeneity be used.

We concluded from the given option that:

A researcher is trying to determine if salaries for men and women in the tech industry have the same distribution.

He surveys a random sample of men and women in the industry and records the distribution of salaries for each gender.

He wants to determine if the distributions are the same.

Hence, the chi-square test for homogeneity is used if he wants to determine if the distributions are the same.

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The tuition at the local college in 2000, assuming it followed the same growth rate as after 2017, can be estimated to be approximately $4,018. The tuition in 2010, using the same growth rate, would be around $9,049.

To find the tuition in 2000, we need to calculate the value of f(x) when x represents the number of years since 2000. Since the given function models the cost of tuition x years since 2017, we need to determine how many years have passed between 2000 and 2017, which is 17 years. Plugging this value into the function, we get:

f(17) = 15(1.07)^17 ≈ $4,018

Therefore, the estimated tuition in 2000, assuming it followed the same growth rate as after 2017, would be approximately $4,018.

To determine the tuition in 2010, we need to calculate the value of f(x) when x represents the number of years since 2010. Since 2010 is 7 years before 2017, we have:

f(7) = 15(1.07)^7 ≈ $9,049

Hence, the estimated tuition in 2010, using the same growth rate, would be around $9,049. It is important to note that these calculations are based on the assumption that the tuition growth rate before 2017 was consistent with the growth rate after 2017 as provided by the function f(x).

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The maximum velocity of the car is 0 m/s and the time t' when it stops is t' = -10/a when subjected to acceleration.

Given that the jet car is originally traveling at a velocity of 10 m/s and is subjected to acceleration, we need to determine the car's maximum velocity and the time t' when it stops.

We can use the equation of motion:
v = u + at

Where:
v = final velocity
u = initial velocity
a = acceleration
t = time

Let's assume that the car comes to a stop at time t' and the final velocity is 0 m/s.
0 = 10 + at'
t' = -10/a

Now, to determine the maximum velocity, we can use another equation of motion:
[tex]v^2 = u^2 + 2as[/tex]

Where:
s = distance

As the car stops, the distance traveled before coming to a stop will be:
[tex]s = ut' + (1/2)at'^2[/tex]

Substituting the value of t' in the above equation, we get:
[tex]s = 10(-10/a) + (1/2)a(-10/a)^2[/tex]
s = -50/a

Now, substituting the values of s, u, and a in the equation of motion, we get:
[tex]v^2 = 10^2 + 2a(-50/a)[/tex]
[tex]v^2 = 100 - 100\\v^2 = 0[/tex]

v = 0 m/s

Hence, the maximum velocity of the car is 0 m/s and the time t' when it stops is t' = -10/a.

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