A 15-cm X 15-cm circuit board dissipating 15 W of power uniformly is cooled by air,
which approaches the circuit board at 20°C with a velocity of 5 m/s. Disregarding
any heat transfer from the back surface of the board, determine the surface
temperature of the electronic components (a) at the leading edge and (b) at the end
of the board. Assume the flow to be turbulent since the electronic components are
expected to act as turbulators.
The temperature change at the two conditions will be at the leading edge will be 20°C and at the end of the board will be 45.64°C.
What is Heat transfer?The movement of heat across the border of the system due to a difference in the temperature between the system and the surroundings.
Board size = 15 cm × 15cm,
Power = 15W,
Temperature of cooled Air: 20°C, and velocity is 5 m/sec.
Firstly, take some value from Standard Air table, at pressure. Suppose That The film Temperature of the is 35°, at this temperature. and pressure.
K = 0.0265 w/m²c (Thermal conductivity)
V = 1.655 × 10⁻⁵ m²/sec (kinematic viscosity)
and Pr = 0.7668 ( pr and t' Number)
According To The Nusselt. Number Equation,
NVx = hxX / k
Here, x = heat transfer from the edge distance which is 0, 30
hx = ∞
So, express the Surface Temperature at the end board by using the equation
Q = hx. Ax (Ts, T∞)
Q/ hx. As = (Ts-T∞)
Ts = Q/hx. As + T∞
Put all the values in this equation, like, P = 15W, T= 20°C, hx = ∞
So,
Ts = 15/∞As + 20
Ts = 20°C
The Temperature of surface at the leading edge = 20°C
At the end of the board. Assume The flow to be turbulent since the electronic components. turbulators.
So, firstly determine The Reynolds Number equation, and
Rex = Vx/ u
Re = 5 × 0.15/ 1.655 × 10⁻⁵
Re = 45317.22
which is less than 3x 10⁵, so The flow is laminar flow at the surface.
again from The Relation of pr and t' Number, Reynolds. Nusselt number.
NVx = [tex]0.030s (Re)^(0.8)[/tex] [tex](pr)^(1/3)[/tex]
Put all the values in this equation
NVx = 0.0308 × 5308.97 × 0.90005
NVx = 147.1728
So, determine equation the heat transfer coefficient by using Relation.
here, x = 0.15m, consider.
hx = NVxK/ x
hx = 147.1728 × 0.0265/ 0.15
hx = 26.00
Area = 0.0225 m²
Q = hx. As (Ts - T∞)
Put all the values in equation,
Ts - 20 = 25.64
Ts = 45.64°C
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If Y is grounded while the balloon is still close to X, which of the following will be true?A) Electrons will flow from the sphere to the groundB) Electrons will flow from the ground to the sphereC) Protons will flow from the sphere to the groundD) Protons will flow from the ground to the sphere.
If Y is grounded while the balloon is still close to X, which of the following will be true, Protons will flow from the ground to the sphere.so, option (d) is correct.
What is proton ?
In the nucleus of every atom, there is a proton, a subatomic particle. Though going in the opposite direction from the electron, the particle has a positive electrical charge. The mass of an isolated proton, which is almost equal to that of a neutron, is just 1.673 x 1027 kg.
What is electron ?
It is possible for an atom to have an attached or detached electron, a negatively charged subatomic particle (not bound). The electron, along with protons and neutrons, is one of the three main particle types found inside an atom. Atomic nuclei are composed of protons, neutrons, and electrons.
Therefore, If Y is grounded while the balloon is still close to X, which of the following will be true, Protons will flow from the ground to the sphere.so, option (d) is correct.
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A radiating source at rest with respect to an observer produces a series of wave crests that propagate outward. From this figure, how do the waves detected by Observer A compare to those detected by Observer B?
Based on the given figure, for a radiating source at rest, the way waves detected by Observer A compared to those detected by Observer B is that Observer A detects the same wavelength and the same frequency.
The Doppler effect, also called Doppler shift refers to an apparent change in frequency of a wave in relation to an observer. The principle is named after the Austrian physicist Christian Doppler, who described the phenomenon in 1842.
In the given case, a radiating source at rest with respect to an observer produces a series of wave crests that propagate outward. The waves spread out evenly in all directions as shown in the figure. The crests are separated by a distance, λ, where λ is the wavelength.
The observer located in the at point A will see the waves coming evenly, one wavelength apart. The observers located anywhere else would see the same thing. Hence, Observer A will detect the same wavelength and frequency as Observer B.
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An earthquake 25 km from a city produces P and
S waves that travel outwards at 5000 and
3000 m/s, respectively.
The time taken before S-wave arrives is 3.33 seconds.
What time before the S wave arrives?
The time taken before S wave arrives is calculated by applying the following equation.
Let the time taken for P-wave = t₁
Let the time taken for S-wave = t₂
The time taken for P-wave, t₁ = ( 25,000 m ) / ( 5000 m/s )
t₁ = 5 s
The time taken for S-wave, t₂ = ( 25,000 m ) / ( 3,000 m/s )
t₂ = 8.33 s
The time taken before S-wave arrives = 8.33 s - 5 s = 3.33 s
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The complete question is below:
An earthquake 25 km from a city produces P and
S waves that travel outwards at 5000 and
3000 m/s, respectively. how much time do they have before the S wave arrives?
Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8 km/h.
The football Felipe throws to Lilah will go at a speed of 23 km/h.
What is the relative velocity?The movement of an object in relation to another observer is known as its relative velocity. It is the pace at which one object's close location changes in reference to another object over time.
Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8 km/h.
Then the velocity of the ball is given as,
v = 15 + 8
v = 23 km/h
The velocity of the ball will be 23 km / h.
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a body falls to the ground in vertical direction. its total energy depends only on potential and kinetic energy and is equal to 725 j. give possible values for the potential energy epot ans the kinetic energy ekin for a moment during the falling.
Since the total energy of the body is constant, we can write Epot + Ekin is 725 J
We can express the potential energy of the body as a function of its height, h, relative to some reference point:
Epot = m * g * h
where m is the mass of the body, g is the acceleration due to gravity, and h is the height of the body.
We can express the kinetic energy of the body as a function of its velocity, v:
Ekin = 0.5 * m * v^2
Since the total energy is constant, we can substitute Epot + Ekin = 725 J into the expressions for Epot and Ekin:
m * g * h + 0.5 * m * v^2 = 725 J
For a moment during the falling, both the potential energy and the kinetic energy can have any non-negative value, as long as their sum is equal to 725 J. So, there are infinitely many possible values for the potential energy and the kinetic energy during the falling. For example, one possible set of values could be:
Epot = 500 J
Ekin = 225 J
Another possible set of values could be:
Epot = 700 J
Ekin = 25 J
And so on.
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Can someone answer these questions pls??
5. The density here will be 60/150 = 0.4 g/cm³
How is gravity explained?The force of gravity, often known as gravitation, affects every material thing in the universe. The gravity force tends to draw any two items or particles with nonzero mass toward one another. From subatomic to galaxy clusters, gravity affects things of all sizes.
What does gravitational mean in plain English?Gravitation seems to be the force in physics that draws two masses together. Unbelievably, every subatomic particle of matter with in cosmos attracts every other particle through gravity. The phrases attraction and gravity are sometimes used synonymously to refer to the attraction that exists between anything with mass or energy.
6) a. The weight of water causes this pressure .
b. As the weight of water increases the pressure increases too.
7) a. pascal (represented as Pa) can be used to measure pressure.
b. The number of particles increases.
c. The pressure will compress
8) The affect of drag on an object causes friction
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A worker pushes horizontally on a large crate with a force of 235 N, and the crate is moved 3.3 m. How much work was done?
Answer:
Explanation:
The work done by a force on an object is equal to the product of the magnitude of the force, the distance moved by the object in the direction of the force, and the cosine of the angle between the force and the direction of motion.
In this case, the worker pushes the crate horizontally, so the force and the direction of motion are in the same direction. Therefore, the angle between them is 0 degrees, and the cosine of the angle is 1.
The work done by the worker on the crate is then:
work = force x distance x cos(angle)
= 235 N x 3.3 m x cos(0)
= 773.5 J
So the work done by the worker is 773.5 Joules (J).
Hello,
Answer:
The work done by a force on an object is given by:
Work = Force x Distance x cos(theta)
where Force is the magnitude of the force applied, Distance is the displacement of the object, and theta is the angle between the force and displacement vectors. Since the worker is pushing horizontally on the crate, the angle between the force and displacement vectors is zero degrees, and cos(0) = 1.
So, the work done by the worker is:
Work = Force x Distance x cos(theta)
Work = 235 N x 3.3 m x cos(0)
Work = 773.5 J
Therefore, the work done by the worker on the crate is 773.5 J.
Good luck !
Steel ball 1 is released from rest at the same time steel ball 2 is given a horizontal kick. The dots represent the locations of the two balls at t=0,1,2,3 and 4 s. The balls continue to fall after t=4 s. Evaluate each of the following statements.
Considering the motion of the two balls:
The magnitude of the vertical component of the velocity of ball 1 at point A is equal to the magnitude of the vertical component of the velocity of ball 2 at point C.The speed of ball 1 at point E is equal to the speed of ball 2 at point B.The magnitude of the horizontal component of the velocity of ball 2 at point G is greater than the magnitude of the horizontal component of the velocity of ball 2 at point B.The magnitude of the horizontal component of the velocity of ball 1 at point A is less than the magnitude of the horizontal component of the velocity of ball 2 at point C.The magnitude of the vertical component of the velocity of ball 1 at point H is less than the magnitude of the vertical component of the velocity of ball 2 at point B.What are horizontal and vertical velocities?The projectile's displacement horizontally as a result of velocity is shown by the horizontal velocity component (vx).
The projectile's displacement vertically as a result of velocity is shown by the vertical velocity component (vy).
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Jasmine is investigating the effect force has on the motion of an object. She predicts if she puts a strong force on pushing a bowling ball, it will travel a farther distance than when a weak force is applied. Is her prediction correct? (Please answer quickly, it's due in 5 hours)
No, a weak or a strong force applied to the ball is unable to affect the motion of the ball.
No, the force applied to the bowling ball should be a strong force.
Yes, the force applied to the bowling ball affects the motion of the ball.
Yes, the ball will travel a longer distance when a weak force is applied.
a dockworker applies a constant horizontal force of 79.0 n to a block of ice on a smooth horizontal floor. the frictional force is negligible. the block starts from rest and moves a distance 11.0 m in a time of 5.30 s
According to the statement, the mass of the ice block is38.1 kg.
The mass of the block of ice can be calculated using the equation F=ma, where F is the applied force, m is the mass of the block, and a is the acceleration.
Assuming the force is constant, the acceleration can be calculated by dividing the distance moved (11.0 m) by the time taken (5.30 s) to get an acceleration of 2.08 m/s². Then the mass of the block can be calculated by dividing the force by the acceleration, giving a mass of 38.1 kg.
A constant horizontal force is a force that is applied in a straight line parallel to the ground and does not change in magnitude or direction. This type of force is typically applied to an object that is already in motion, such as a rolling ball or a sliding box, and keeps it moving in a straight line.
Complete questions:
A dockworker applies a constant horizontal force of 79.0 n to a block of ice on a smooth horizontal floor. the frictional force is negligible. the block starts from rest and moves a distance 11.0 m in a time of 5.30 s. What is the mass of the block of ice?
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A point charge is placed in an electric field which varies with location. No force is exerted on this charge: at locations where the electric field is zero at locations where the electric field strength is 1/(1.6 times 10^-19) N/C if the charge is moving along an electric field line if the charge is moving perpendicular to an electric field line if the electric field is produced by an equal amount of positive and negative
A point charge placed in an electric field does experience a force due to the interaction of the electric field with the charge. At locations where the electric field is zero, the force on the point charge would be zero as well, as it would not experience any interaction with the field.
If the electric field strength is 1/(1.6 times 10^-19) N/C, the force on the point charge would be equal to the product of the electric field strength and the magnitude of the charge.
The direction of the force would depend on the sign of the charge - if it is positive, it would experience a force in the direction of the electric field, and if it is negative, it would experience a force in the opposite direction.
If the charge is moving along an electric field line, it would experience a force in the direction of the field.If the charge is moving perpendicular to an electric field line, it would experience no net force in the direction perpendicular to the field. However, it would still experience a force in the direction of the field due to the interaction of the field with the charge.If the electric field is produced by an equal amount of positive and negative charges, the net force on a point charge would be zero, as the field would cancel out. However, the charge would still experience a force due to the interaction of the electric field with the charge.Here you can learn more about the electric field
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A amusement park ride consists of a large vertical wheel of radies R
An amusement park ride consists of a large vertical wheel of radius R and a horizontal axis through its center that revolves counterclockwise.
What is an amusement ride?Amusement rides, often known as carnival rides, are machines or installations that move people for entertainment and fun.
Many people mistakenly believe that rides are scarier or more dangerous than they actually are. This can be the result of the design, acrophobia, or knowledge of accidents involving similar rides. Some people enjoy the adrenaline rush that comes with riding amusement attractions since it adds to the experience.
amusement rides such as ferris wheels, Enterprise, and Skydiver are examples of vertical rides that typically move their guests in a vertical plane and around a fixed point.
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A team of engineers is developing a new waterslide for a theme park. The riders of the slide will climb several flights of steps to reach the top of the slide and will sit in a round inner tube as they slide down. The engineers are testing a computer simulation to measure the kinetic energy that the riders will have on the slide. The kinetic energy will be based on the potential, or stored. energy and will depend on mass and speed. The engineers want to develop a way to transfer the most kinetic energy to the riders to make their trip down the slide as fast as possible.
Which of these solutions would increase the kinetic energy in the model slide?
a. adding twists and turns to the slide b.
decreasing the volume of water pushing the riders
C. increasing the friction between the tube and the slide
d. increasing the number of flights of steps that the rider will climb
Please don’t give me a explanation and just give me the answer :)
The kinetic energy is increased by the number of flights of steps that the rider will climb. The correct option is D.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the stated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.
Given that the engineers are testing the waterslide for the theme park.
As we can know that kinetic and potential energy are two energies which are converted from one to another. The potential energy is increased by increasing the height of the slide from the ground level.
If the potential energy is higher than the kinetic energy of the slider will also increase during the downward journey.
So by increasing the number of flights of steps that the rider will climb there will be more kinetic energy in the slide. The correct option is D.
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where the i and f subscripts indicate quantities evaluated in the initial and final states, respectively. in the initial state, the electron is at rest at a point midway between the two plates. we choose this location as the reference point for the electric potential energy, so that (peel) is ?
We choose the point midway between the two plates as the reference point for the electric potential energy to quantify energy stored.
The electric potential energy (PE) is a measure of the energy stored in an electric field. It is defined as the work done by an external agent to move a charged particle from one point in the electric field to another.
In the case of an electron at rest at a point midway between two plates, we can choose this location as the reference point for the electric potential energy. This means that the electric potential energy at this point is zero, and all other points in the electric field can be defined relative to this reference point.
The i and f subscripts indicate quantities evaluated in the initial and final states, respectively. So, (PE)_i indicates the electric potential energy of the electron in the initial state, when it is at rest at the reference point, and (PE)_f indicates the electric potential energy of the electron in the final state, after it has been moved by an external agent.
The electric potential energy can be calculated using the formula PE = qV, where q is the charge of the electron and V is the electric potential difference between the initial and final states. In this case, the electric potential difference between the two plates can be calculated using the equation V = Ed, where E is the electric field strength and d is the distance between the plates.
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Work done by the gravitational force on a body of mass m moving on a smooth horizontal surface through a distance s is: (Given acceleration due to gravity =g):A) mgsB) -mgsC) 0D) 2mgs
The work done by gravity will be 0 since the gravitational force is perpendicular to the distance travelled by the body.
What is gravitational force?
Any two bodies will be attracted to one another by the force of gravity. There is an attraction between every thing in the cosmos, but most of the time it is too faint to be noticed due to the extreme distance between the objects. Furthermore, although the influence of gravity is weaker as objects are moved away, its range is infinite.
The gravitational force is a central force that always acts along the line connecting the centers of the two masses and only depends on the distance between the test mass and the source mass.
Only when displacement is in the direction of the force is work accomplished.
When a force is perpendicular to a displacement, no work is done.
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A telecommunications tower is supported by three cables affixed to its top and ground. We can find the vertical force induced in the tower by the cables by a) considering the product to pairs of vectors and projecting a resultant force from the tower. b) Cartesian vector analysis to the coplanar forces, finding the resultant and direction cosine, and then resolving the resultant into its parallel and perpendicular components.c) applying Newton's second law of motion and the Pythagorean Theorem to the analysis. d) force resolution, the determination of force components to find the resultant vertical force on the tower. e) all of the above
The vertical force induced in the tower by the cables by:
e) all of the above. All of the methods listed (a, b, c, and d) can be used to find the vertical force induced in the tower by the cables, and each method provides a different approach to finding the solution. The choice of method will depend on the complexity of the problem and the level of mathematical sophistication required for the solution.
Vertical force inducedThe various methods listed (a, b, c, and d) all involve mathematical and physical principles that can be used to find the vertical force induced in the tower by the cables.
a) Product to pairs of vectors and projecting a resultant force from the tower: This method involves using vector dot products or cross products to find the projection of one vector onto another, which can then be used to find the magnitude and direction of the vertical force.
b) Cartesian vector analysis to the coplanar forces: This method involves finding the components of each cable force in a two-dimensional coordinate system, adding the components to find the resultant force, and then finding the direction cosine to determine the direction of the resultant force.
c) Applying Newton's second law of motion and the Pythagorean Theorem: This method involves using Newton's second law of motion (F = ma) to find the net force acting on the tower and then using the Pythagorean Theorem to find the magnitude and direction of the vertical force.
d) Force resolution: This method involves breaking down the cables' forces into their individual components, finding the net force in each direction, and then using vector addition to find the magnitude and direction of the vertical force.
Each method has its own advantages and disadvantages, and the choice of method will depend on the complexity of the problem, the level of mathematical sophistication required for the solution, and the desired level of accuracy.
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Cell phone conversations are transmitted by high-frequency radio waves. Suppose the signal has wavelength 36.5cm while traveling through air.
What is the frequency as the signal travels through 3 mm thick window glass into your room?
in MHz please
What is the wavelength as the signal travels through 3 mm thick window glass into your room?
in cm please
show work please I really need to understand this stuff
I will rate good
The frequency of a signal traveling through a window with a thickness of 3 mm is 12270 MHz and the wavelength is 24.33 cm.
What is wavelength?The distance between two successive peaks or troughs of a wave is referred to as its wavelength.
How do you determine it?The formula f = c /λ, where f is the frequency, c is the speed of light, and λ is the wavelength, relates a wave's frequency to both its wavelength and speed.
When a signal enters glass, its speed slows and its wavelength lengthens because glass has a slower rate of light propagation than air. We require knowledge about the glass's refractive index in order to compute the new wavelength and frequency. The new speed of light in the glass would be c/1.5 assuming that the refractive index of the glass is 1.5.
The new wavelength in the glass is given by= λ' = λ * (c / c') = λ * (c / (c / 1.5)) = λ / 1.5
The formula for the new frequency in the glass is: f' = c / λ' = c / (λ / 1.5) = 1.5 * f
As a result, the frequency of a signal traveling through a window with a thickness of 3 mm would be 1.5 * (8.18 x 109 Hz) = 12.27 x 109 Hz = 12.27 GHz *1000 = 12270 MHz.
The wavelength of the signal would be (λ/1.5) = (36.5 cm) / 1.5 = 24.33 cm as it passes through the 3 mm thick window glass into your room.
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A cubic box of side a, oriented as shown, contains an unknown charge. The vertically directed electric field has a uniform magnitude E at the top surface and 4 E at the bottom surface. How much charge Q is inside the box?
The charge Q is inside the box for a cubic box of side a, oriented as shown, and contains an unknown charge is [tex]Q = \frac{4Ea^2}{k}[/tex].
To calculate the charge inside the cubic box, we may apply the electric field equation in terms of charge and distance:
[tex]E = \frac{kQ}{r^2}[/tex]
where r is the distance from the place of interest to the charge and k is Coulomb's constant.
The equation may be stated as follows since the electric field at the top surface is E:
[tex]E = \frac{kQ}{a^2}[/tex]
Because the electric field at the bottom surface is 4 E, the equation may be written as:
[tex]4E = \frac{kQ}{(a/2)^2}[/tex]
When we divide the second equation by the first, we get:
[tex]\frac{4E}{E} = \frac{\frac{kQ}{(a/2)^2}}{\frac{kQ}{a^2}}[/tex]
[tex]4 = \frac{(a/2)^2}{a^2}[/tex]
Solving for Q, we have:
[tex]Q = \frac{4Ea^2}{k}[/tex]
The uniform electric field at the top surface may thus be multiplied by the area of one box face, divided by Coulomb's constant, to get the amount of charge within the cubic box.
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The question is -
A cubic box of side a, oriented as shown, contains an unknown charge. The vertically directed electric field has a uniform magnitude of E at the top surface and 2E at the bottom surface. How much charge Q is inside the box?
A car traveling eastwards gains 1 m/s eastwards every second. The car is _____. Choose all that are correct.
traveling with constant velocity
changing its speed
changing its velocity
slowing down
accelerating
traveling with constant speed
speeding up
A car traveling eastwards gains 1 m/s eastwards every second. The car is E: accelerating and C: changing its velocity.
A car traveling eastwards that gains 1 m/s of velocity every second is considered to be accelerating. This is because acceleration is defined as the rate of change of velocity. In this case, the velocity of the car is changing in the eastward direction, indicating that it is accelerating eastwards. It is also important to note that acceleration can be either positive or negative, depending on the direction of the velocity change.
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True/Falsethe moisture content of the air in different locations of the country must be taken into account when selecting air conditioning equipment.
The statement "the moisture content of the air in different locations of the country must be taken into account when selecting air conditioning equipment" is true because moisture affects the performance.
The selection of the conditioning equipment must take into account the differences in humidity between the two locations (different sections of the country). The conventional copper tube-aluminum fin coil transfers heat more slowly than the all-aluminum coil.
The general rule of thumb is that for every 20°F increase in temperature, saturated air's ability to store twice as much moisture increases. The moisture retention capacity of air at 50°F is 0.0077 lb H2O/lb dry air, which is a little over twice as much as that of air at 30°F, which is 0.0035 lb H2O/lb dry air.
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Now we replace the resistor in the circuit of problem 1 with a diode-connected PMOS device asshown.A. What W/L ratio is needed for M6 in order to set IREF = 25 mA?B. If M6 is implemented as a diode-connected nFET instead of pFET, what W/L ratio would berequired?C. Which implementation, pFET or nFET would take up the most area?
The circuit of an electric bell consists of an electromagnet, a switch, and a source of power. When the switch is activated, the electromagnet is energized, creating a magnetic field. This magnetic field attracts a metal hammer, which strikes a bell and produces a ringing sound. When the switch is released, the circuit is broken, de-energizing the electromagnet and allowing the hammer to return to its original position. This process repeats each time the switch is activated.
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water displacement is a good method to find the volume of an object that is more dense than water but does not work for objects which float
The volume of an item may be determined simply yet accurately by measuring the displacement of water.
It works by putting the object in a water-filled container and then calculating how much water the object has moved out of the container. The volume of the item may be calculated using the difference in water level before and after it is submerged.
Unfortunately, this approach does not work with floating objects. This is due to the fact that the item does not move the same volume of water as it does while immersed.
Water will be moved by the item, although considerably less water will be moved than by the submerged object.
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A tourist purchases a car in England and ships it home to the United States. The car stickers advertised that the car's fuel consumption was the rate of 40 miles per gallon on the open road.
The tourist does not realize that the U.K. gallon differs from the U.S. gallon:
1 U.K. gallon =4.546 090 0 litres
1 U.S. gallon =3.785 411.8 litres
For a trip of 750 miles (in the United states), how many gallons of fuel does the mistaken tourist believe she needs ?
The actual amount of fuel needed for the 750 mile trip is 22.54 U.S. gallons.
What is fuel ?Fuel is a material that is burned or used to produce energy. It can come in many forms, including gasoline, diesel, propane, wood, coal, natural gas, and oil. Fuel can be used to power engines to move vehicles, generate electricity, and heat homes and buildings. It is a necessity of modern life, as it is required to power many of the machines, appliances, and systems that make our lives easier. Without fuel, transportation, communication, and many other essential services would be impossible. Fuel is often divided into two categories, renewable and non-renewable.
The tourist mistakenly believes that she needs 18.75 gallons of fuel for a trip of 750 miles. This is calculated as follows:
750 miles/40 miles per gallon = 18.75 gallons
However, since the tourist is using a U.K. gallon, which is larger than a U.S. gallon, the actual amount of fuel needed is less. To do the conversion, we need to convert the 18.75 gallons to litres and then back to U.S. gallons:
18.75 U.K. gallons x 4.546090 litres/U.K. gallon = 85.22 litres
85.22 litres/3.785411.8 litres/U.S. gallon = 22.54 U.S. gallons
Therefore, the actual amount of fuel needed for the 750 mile trip is 22.54 U.S. gallons.
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The vertical component of a force id 75N and the force itself is 140N. Calculate the horizontal component
Answer:
Below
Explanation:
The components form a RIGHT triangle with legs = Horizontal comp and Vertical comp and hypotenuse = the force...
SO you can use the Pythagorean theorem
Hypotenuse ^2 = leg1^2 + leg2^2
140^2 = 75^2 + Horizontal^2
Horizontal^2 = 140^2 = 75^2 = 13975
Horizontal = 118.2 N
Calculate the wavelength and the energy in joules associated with an NMR signal at 250 MHz. The wavelength of the signal is 1.2m and the energy is 1.67 x 10-25J?
The wavelength of an NMR signal at 250 MHz is 1.2m and its energy is 1.67 x 10⁻²⁵ J.
Nuclear Magnetic Resonance (NMR) spectroscopy is a widely used technique in physics and chemistry for determining the chemical and physical properties of substances. The frequency of an NMR signal is related to the magnetic field strength and the magnetic properties of the nuclei being studied.
The wavelength of an NMR signal can be calculated using the equation:
λ = c/v
where c is the speed of light (3 x 10⁸ m/s) and v is the frequency of the signal (250 MHz).
λ = c / v
λ = 3 x 10⁸ m/s / (250 x 10⁶ Hz)
λ = 1.2 m
The energy of an NMR signal can be calculated using the equation:
E = hv
where h is Planck's constant (6.63 x 10⁻³⁴ J s) and v is the frequency of the signal.
E = h × v
E = 6.63 x 10⁻³⁴ J s × (250 x 10⁶ Hz)
E = 1.67 x 10⁻²⁵ J
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What is the kinetic energy of a 22 kg dog that is running at a speed of 8.2 m/s (about 18 mi/h)?
E=1/2 mv^2
E=1/2 22x(8,2)^2
E=739,64
A spring with spring constant of 20 N/m is stretched 0.16 m from its equilibrium position. How much work must be done to stretch it an additional 0.063 m? Answer in units of J.
Answer: 0.497 J
Explanation:
Spring energy
Spring energy is stored in a compressible or stretchable object like a spring or rubber band.
The work done on a spring in changing its original length is converted to its elastic potential energy or spring energy.
Given -
The spring constant is k = 20N/m,
The initial stretch is x1 = 0.16m,
The additional stretch is x2 = 0.063m,
W = 0.5k (x1 + x2)^2 - 0.5k x1^2
W = 0.5 (20 N/m) (0.16m + 0.063m)^2
W = 0.497 J
The figure below shows three positions of the pedal on a bicycle, which has a crank 0.20 m long the cyclist exerts the same vertically downward push of 25 Newton with his foot. Calculate the turning effect in: A, B and C
The turning effect is 5 N/m.
What is the torque?We have to note that the torque is the product of the force and the distance that it has turned. The torque can be used to describe the kind of force that can be able to provide a turning effect.
In this case for the question that we have here we know that;
Force = 25 Newton
Distance = 0.20 m
Torque = 0.20 m * 25 Newton
= 5 N/m
This is the force that would cause the pedal to be turned so that we can have the movement of the bicycle as shown above.
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A 5.2 "kilo" bag of sugar is on a counter. How much work is required to put the bag on a shelf a distance of 0.37 m above the counter?
Answer: approximately 18.854 Joules of work is required to put the bag of sugar on the shelf. where Force is the weight of the bag of sugar and Distance is the vertical distance lifted.
Explanation: