If there are 30 king sized candy bars in a box and the box sells for $70.50 , how much does each candy bar in the box cost? Please help this paper is due tmr and I get my progress report tmr!!!

If There Are 30 King Sized Candy Bars In A Box And The Box Sells For $70.50 , How Much Does Each Candy

Answers

Answer 1

The cost of one candy bar is $2.35.

What is a unit price?

The meaning of unit price is a price quoted in terms of so much per agreed or standard unit of product or service.

Given that, there are 30 king-sized candy bars in a box and the box sells for $70.50, we need to find that how much does each candy bar in the box cost,

Since, the cost of all 30 candies is given collectively, i.e. $70.50,

We will divide the cost of the whole box by the number of candies to find the unit price of the candies,

Unit price = $70.50 / 30

= $2.35

Hence, the cost of one candy bar is $2.35.

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Related Questions

A tower that is 118 feet tall casts a shadow 130 feet long. Find the angle of elevation of the sun to the nearest degree.

Answers

Answer:

42°

Step-by-step explanation:

A right-angled triangle can formed in this scenario (image attached), where:

θ = angle of elevation of the sun

Opposite side = The height of the tower

Adjacent side = Length of the shadow

Trigonometric function will be used to determine the angle of elevation:

tanθ = [tex]\frac{opposite}{adjacent}[/tex]

        [tex]= \frac{118 feet}{130 feet}[/tex]

feet in the numerator and denominator will cancel each other out completely:

θ =[tex]tan^{-1} (\frac{118}{130})[/tex]

 θ = 42.23°

θ = 42° (Rounded to the nearest degree)

In the figure above, ABCD, BEFG, and DHIJ are squares with AB= 2(DH) and DH = 2(BE). If a point is chosen at random inside square ABCD, what is the probability it will be in the shaded region?
(A) 1/2
(B) 5/8
(C) 11/16
(D) 3/4​

Answers

Answer:

[tex]\dfrac{11}{16}\\\\[/tex]
Option C

Step-by-step explanation:

We have the following information:

AB = 2DH

DH = 2BE or BE = DH/2

The area of square ABCD = (2DH)² = 4DH²

The area of square BEFG = BE² = (DH/2)² = DH²/4

The area of square DHFJ = DH²

Area of the unshaded region

= area of square BEFG  + area or square DHFJ

= DH²/4 + DH² = DH²/4 + 4DH²/4 = 5DH²/4

Area of shaded region

= area of square ABCD - area of unshaded region

[tex]= AB^2 - \dfrac{5}{4}DH^2\\\\= 4DH^2 - \dfrac{5}{4} DH^2\\\\= \dfrac{4DH^2 \cdot 4}{4} - \dfrac{5}{4} \cdot DH^2[/tex]

[tex]= \dfrac{16DH^2 - 5DH^2}{4}= \dfrac{11DH^2}{4}[/tex]

[tex]\textrm{Probability of a point falling in the shaded region} =\dfrac{\textrm{Area of shaded region}}{\textrm{Total area of both regions}}\\\\= \dfrac{11DH^2/4}{4DH^2} = \dfrac{11}{16}\\\\[/tex]

The graph below shows the relationship between the number of money spent and the amount of cans bought. For the data in the graph, which of the following equations can be used to calculate c, the amount of cans, bought for m money spent ?


c = 2m


c = 5m


c = 10m


c = 1/10m

Answers

Answer:

C = 10m

Step-by-step explanation:

when c=20, m=2

when c=40, m=4

we can see that c is equals to 10 times the value of m

Therefore c = 10m

The length of a rectangle is 2 ft longer than it’s width if the perimeter of the rectangle is 36ft find it’s area

Answers

Answer:

two of the sides are x and the other two sides are x+2

x+x+x+2+x+2 = 36

4x = 32

x = 8

the sides are 8, 8, 10, 10

area is length x width

8 x 10 = 80

answer: 80ft

Step-by-step explanation:

4. Write a word problem for 3/4 X 1/2! Please help me!!

Answers

A word problem for the given expression is the division of 3/4 cups of juice among two friends equally.

What are Expressions?

Expressions are mathematical statements which consist of two or more terms and terms are connected to each other using mathematical operators like addition, multiplication, subtraction and so on.

Given is an expression [tex]\frac{3}{4}[/tex] × [tex]\frac{1}{2}[/tex].

Suppose that there are 3/4 cups of juice available.

There are two friends who are in need of this.

The total amount of juice has to be divided equally among these two friends.

Amount of cups of juice each friend gets = [tex]\frac{3}{4}[/tex] ÷ 2.

[tex]\frac{3}{4}[/tex] ÷ 2 = [tex]\frac{3}{4}[/tex] × [tex]\frac{1}{2}[/tex] = [tex]\frac{3}{8}[/tex]

So each friend gets 3/8 cups of juice.

Hence the division of a total of 3/4 cups of juice among two friends equally is a word problem for the given expression.

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round 107.06 one decimal place

Answers

Answer: 107.1

Step-by-step explanation:

4 or less down

5 or more up

In this case, we round to 1 decimal place, so we look at the hundredths column.

It is 6, so we round up.

Assuming that the math module has been imported, which of the following expressions evaluates to True?
a. math.hypot (3,4) == math.sqrt (25)
b. math.hypot (2,5) == math.trunc (2.5)
c. math.hypot (2,5) == math.true (2.5)
d. math.cell (2,5) == math.floor (2.5)

Answers

After evaluating these expression it seems to be the option (a) math.hypot(3,4) == math.sqrt(25) evaluate that is True

The math.hypot function calculates the Euclidean distance between two points in a 2D space, which is equivalent to the length of the hypotenuse of a right triangle with sides of length a and b (where a and b are the arguments to math.hypot).

In this case, math.hypot(3, 4) calculates the length of the hypotenuse of a right triangle with sides of length 3 and 4, which is equal to 5.

The expression math.sqrt(25) calculates the square root of 25, which is equal to 5. Since math.hypot(3, 4) and math.sqrt(25) both evaluate to 5, the expression math.hypot(3, 4) == math.sqrt(25) evaluates to True.

The other expressions are not evaluating to True:

b. math.hypot(2,5) != math.trunc(2.5)

c. math.hypot(2,5) != math.true(2.5)

d. math.cell(2,5) does not exist. It is likely a typo for math.ceil which is not equal to math.floor(2.5)

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Consider the cubic function g(x) = −2( + 4)^3 − 5. Please describe how this function has been transformed from the cubic parent function f(x) = x^3

Answers

The cubic function g(x) = -2(x + 4)³ - 5 can be obtained from f(x) = x³ by a translation of 4 units to the right, a vertical scaling by a factor of -2, and a reflection about the x-axis.

What are functions?

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

The cubic parent function f(x) = x³ has been transformed to the function g(x) = −2(x + 4)³ − 5 through a combination of translations, scaling, and reflection.

Translation: The parent function has been shifted 4 units to the right, resulting in x + 4 instead of x in the argument of the function.

Scaling: The parent function has been scaled vertically by a factor of -2, resulting in a coefficient of -2 in front of the argument.

Reflection: The parent function has been reflected on the x-axis, resulting in the negative sign in front of the argument.

Thus, g(x) = -2(x + 4)³ - 5 can be obtained from f(x) = x³ by a translation of 4 units to the right, a vertical scaling by a factor of -2, and a reflection about the x-axis.

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please tell me what i need to do to solve this problem

Answers

The standard form of the equation of the sphere with center (0, -1, 3) and a radius of square root of 5 is given as follows:

x² + (y + 1)² + (z - 3)² = 5.

How to obtain the equation of a sphere?

The two parameters for the equation of a sphere are given as follows:

Center (x*, y*, z*).Radius r.

Then the equation for the sphere is given as follows:

(x - x*)² + (y - y*)² + (z - z*)² = r².

The parameters for this problem are given as follows:

Center (0, -1, 3).Radius: square root of 5.

Hence the equation of the sphere is defined as follows:

x² + (y + 1)² + (z - 3)² = 5.

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Find and simplify each of the following for f(x) = 4x² - 6x + 9.


(A) f(x + h) =
(Do not factor.)

Answers

ANSWER -

To find f(x+h), we need to substitute (x+h) for x in the equation f(x) = 4x² - 6x + 9.

f(x+h) = 4(x+h)² - 6(x+h) + 9

= 4x² + 8xh + 4h² - 6x - 6h + 9

= 4x² - 6x + 9 + 8xh + 4h² - 6h

= f(x) + 8xh + 4h² - 6h

So, f(x+h) = 4x² - 6x + 9 + 8xh + 4h² - 6h.

A child is flying a kite. If the kite is "h" feet above the child's hand level and the wind is blowing it on a horizontal course at "v" feet per second, the child is paying out cord at _____ feet per second when "s" feet of cord are out. Assume that the cord remains straight from hand to kite.

Answers

The child is paying out cord at a rate of s(ds/dt)) /√(s²-h²) feet per second when "s" feet of cord are out.

What is Differential equation?

A differential equation is an equation that contains one or more functions with its derivatives.

The distance between the kite and the child's hand level "d".

By using the Pythagorean theorem, we can write:

d² + h² = s²

Simplifying and solving for d, we get:

d² = s²-h²

d = √(s²-h² )

Let's call the length of the cord "L". Then, we can write:

d² + L² = s²

Differentiating both sides with respect to time (t), we get:

2d (dd/dt) + 2L (dL/dt) = 2s (ds/dt)

We want to find (dL/dt) when L = s and d = √(s²-h² )

(dd/dt) = 0 as the height of the kite above the child's hand level is constant.

(dL/dt) = (s(ds/dt) - d (dd/dt)) / L

Substituting in the values we found for d and L, we get:

(dL/dt) = s(ds/dt)) / √(s²-h² )

Therefore, the child is paying out cord at a rate of s(ds/dt)) /√(s²-h²) feet per second when "s" feet of cord are out.

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Identify the hypothesis and the conclusion for each of the following conditional statements. (a) If n is a prime number, then n2 has three positive factors.
(b) If a is an irrational number and b is an irrational number, then a⋅b is an irrational number.
(c) If p is a prime number, then p=2 or p is an odd number.
(d) If p is a prime number and p≠2 or p is an odd number.
(e) p≠2 or p is a even number, then p is not prime.

Answers

The hypothesis and conclusion are -

(a) Hypothesis : n is a prime number.

Conclusion : n² has three positive factors.

(b) Hypothesis : a and b are irrational numbers.

Conclusion : a · b is an irrational number .

(c) Hypothesis : p is a prime number.

Conclusion : p = 2 or p is an odd number .

(d) Hypothesis : ap is a prime number and p≠2 .

Conclusion : p≠2, p is an odd number .

(e) Hypothesis : p≠2 and p is a even number.

Conclusion : p is not a prime number .

What is irrational number?

A real number that cannot be stated as a ratio of integers is said to be irrational; an example of this is the number √2. Any irrational number, such as p/q, where p and q are integers, q≠0, cannot be expressed as a ratio.

The hypothesis of a conditional statement is the phrase immediately following the word if.

The conclusion of a conditional statement is the phrase immediately following the word then.

(a) If n is a prime number, then n² has three positive factors.

Hypothesis : n is a prime number.

Conclusion : n² has three positive factors.

(b) If a is an irrational number and b is an irrational number, then a⋅b is an irrational number.

Hypothesis : a and b are irrational numbers.

Conclusion : a · b is an irrational number .

(c) If p is a prime number, then p=2 or p is an odd number.

Hypothesis : p is a prime number.

Conclusion : p = 2 or p is an odd number .

(d) If p is a prime number and p≠2 or p is an odd number.

Hypothesis : ap is a prime number and p≠2 .

Conclusion : p≠2, p is an odd number .

(e) p≠2 or p is a even number, then p is not prime.

Hypothesis : p≠2 and p is a even number.

Conclusion : p is not a prime number .

Therefore, the hypothesis and conclusions are made.

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can someone tell me how to do this problem? please

Answers

Hi there, here's your answer:

The general formula of a circle:

[tex](x-h)^{2} +(y-k)^{2}=r^2\\[/tex]

Where the ordered pair (h, k) is the center of the circle.

Given (h, k) = (-6, -2)

We also have that the circle passes through a point (7, 12)

Which means that (7, 12) lies on the circumference of the circle.

Let this be labelled as [tex](x_{1}, y_{1})[/tex]

Since this point lies on the circumference of the circle, it must satisfy the equation when substituted in for (x, y).

Thus, we substitute [tex]x_{1}[/tex] for x and [tex]y_{1}[/tex] for y.

We get the final equation to be:

[tex](7+6)^2 + (12+2)^2 = r^2[/tex]

Or

[tex]169 + 196 = r^2[/tex]

[tex]r^2 = 365[/tex]

Thus, we get the final equation of the circle to be [tex](x+6)^2 + (y+2)^2 = 365[/tex]

Hope it helps!

Find the volume of a frustum of a pyramid with square base of side 22, square top of side 13 and height 20.

Answers

The volume of a frustum of a pyramid with given dimensions is 6260 cubic units.

What is frustum of pyramid?

The top of a conventional pyramid is removed to create the frustum, which is a pyramid. It is known as a truncated pyramid for this reason. The height of a pyramid is represented by the letter h and is the distance from its base to its summit. Similar to it, it has two bases and a slant height indicated by the letter "s" (top and bottom).

We are given frustum of a pyramid with square base of side 22, square top of side 13 and height 20.

We know that volume of frustum of pyramid(V) = h(b^2 + a^2 + ab)/3

We are given b = 22, a = 13 and h = 20

From this, we get

⇒V = h(b^2 + a^2 + ab)/3

⇒V = 20(22^2 + 13^2 + 22*13)/3

⇒V = 20(484 + 169 + 286)/3

⇒V = 20(939)/3

⇒V = 20*313

⇒V = 6260 cubic units

Hence, the volume of a frustum of a pyramid with given dimensions is 6260 cubic units.

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A car can be rented for $80 per week plus $0.25 per mile. How many miles can be driven if you have at most $110 to spend for weekly transportation?

Answers

Answer: Let x be the number of miles driven.

The cost of renting the car and driving x miles is 80 + 0.25x.

We want to find the maximum number of miles that can be driven given a budget of $110, so we set 80 + 0.25x = 110 and solve for x:

80 + 0.25x = 110

0.25x = 110 - 80

0.25x = 30

x = 120

So the maximum number of miles that can be driven is 120.

Step-by-step explanation:

A multimeter and an oscilloscope cost $574. The oscilloscope cost $356 more than the multimeter. Find the cost of the oscilloscope and the multimeter.

Answers

Answer:

oscilloscope: $465multimeter: $109

Step-by-step explanation:

You want the costs of an oscilloscope and a multimeter when the sum of their costs is $574, and the difference of their costs is $356.

Sum and difference

Let o and m represent the costs of the oscilloscope and multimeter, respectively. Then the costs can be described by ...

  o +m = 574

  o -m = 356

Solution

Adding these two equations gives ...

  2o = (574+356) = 930

  o = 465 . . . . . . . . . . . . divide by 2

Subtracting the second equation from the first gives ...

  2m = 574 -356 = 218

  m = 109 . . . . . . . . . . . . divide by 2

The oscilloscope costs $465; the multimeter costs $109.

__

Additional comment

This is the generic solution to a "sum and difference" problem: the higher value is half the sum of the given numbers, and the lower value is half their difference.

2.
A house that costs $200,000 will appreciate in value by 3% each year.
Write a function that models the cost of the house over time. Use x for years and y for
the value of the house, in dollars.
Find the value of the house at the end of ten years.

Answers

Answer: The function that models the cost of the house over time can be written as y = 200,000 * (1 + 0.03)^x, where x is the number of years and y is the value of the house.

To find the value of the house at the end of ten years, we need to plug in x = 10 into the function:

y = 200,000 * (1 + 0.03)^10 = 200,000 * 1.33489 = 266,978.8

So the value of the house at the end of ten years is $266,978.8.

Step-by-step explanation:

marks) There are more than 600 million bacteria in a person's body. Work out and write your answer correct to 1 significant figure the number of bacteria there would be in the people of a town with a population of 200 thousand. (Write answer in scientific notation)​

Answers

Answer: The number of bacteria in the people of a town with a population of 200 thousand would be 200,000 * 600 million = 120 x 10^9 bacteria.

Step-by-step explanation:

Assume that program runs in f (n) microseconds; where f (n) is the function given on the left. Fill in how large an input can be calculated, given cach of the runtimes given along the top. have filled in two values for you: You do not need to fill in every box, but should have at least of every row filled in, and at least half of the rows complete: second minute hour day month year Ign Vnl n lgn 72 1000 2n Show some calculations, O some of your code if you use code: What row is the most sucktastic one? Why? Do you have any non-integer answers?

Answers

The row with the most sucktastic runtime is the one with[tex]2^n[/tex], as it takes exponentially longer to run than the other runtimes.

No, we do not have any non-integer answers.

Second: 72

Minute: 1000

Hour: [tex]2^(17)[/tex]

Day: [tex]2^25[/tex]

Month: [tex]2^30[/tex]

Year: [tex]2^35[/tex]

Second: f(n) = 72 => n = 72

Minute: f(n) = 1000 => n = 1000

[tex]Hour: f(n) = 2^n = > n = 17Day: f(n) = 2^n = > n = 25 Month: f(n) = 2^n = > n = 30Year: f(n) = 2^n = > n = 35[/tex]

Seconds: The runtime for an input of size n is 72 microseconds, so the largest input that can be calculated in a second is 72.

Minutes: The runtime for an input of size n is 1000 microseconds, so the largest input that can be calculated in a minute is 1000.

Hours: The runtime for an input of size n is[tex]2^n[/tex] microseconds, so the largest input that can be calculated in an hour is [tex]2^17.[/tex]

Days: The runtime for an input of size n is [tex]2^n[/tex] microseconds, so the largest input that can be calculated in a day is [tex]2^25[/tex]

Months: The runtime for an input of size n is [tex]2^n[/tex] microseconds, so the largest input that can be calculated in a month is [tex]2^30.[/tex]

Years: The runtime for an input of size n is [tex]2^n[/tex] microseconds, so the largest input that can be calculated in a year is [tex]2^35.[/tex]

The row with the most sucktastic runtime is the one with [tex]2^n[/tex], as it takes exponentially longer to run than the other runtimes. Therefore, the longer the time period, the larger the input size that can be calculated. No, we do not have any non-integer answers as the runtimes of the inputs are in microseconds and the input size is given as an integer.

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Which of the following lists of properties contains only those that are characteristic properties of a substance? Odensity, solubility, melting point O boiling point, mass, density O volume, density, temperature O solubility, mass, volume

Answers

Of the lists of properties you provided, only the list of "identity, solubility, melting point" contains only those that are characteristic properties of a substance.

Identity refers to the name or chemical formula of the substance, which is unique to that substance and can be used to identify it.

Solubility refers to the ability of a substance to dissolve in a solvent, such as water. The solubility of a substance can also be used to identify it, as different substances have different solubility's.

Melting point refers to the temperature at which a solid substance will change into a liquid. Like solubility, the melting point of a substance is also a characteristic property that can be used to identify it.

On the other hand, boiling point, mass, and density are not always characteristic properties of a substance. While they can give us information about a substance, they are not unique to that substance and cannot be used to identify it.

Volume and temperature are not considered characteristic properties of a substance, as they are dependent on external factors, such as the pressure and the amount of the substance being measured.

In conclusion, the list of "identity, solubility, melting point" contains only those properties that are characteristic of a substance and can be used to identify it.

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Suppose that, in 1998, Japan produced 0.528 million pounds of corn. The total world production that year totaled 71 million pounds of corn. What percent of the world's total production of pounds of corn is contributed by Japan? Round your answer to the nearest tenth.

Answers

The percentage of world production of corn contributed by Japan in 1998 can be calculated as follows:

(0.528 million pounds / 71 million pounds) x 100% = 0.00744 x 100% = 0.744%

Rounding to the nearest tenth, the answer is:

0.744% = 0.7%.



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Alice decides to finish her trip by riding a train 700 miles to Washington D.C. The train travels at an average speed of 80mph. What are the domain and range of the function this creates?

Answers

The range of the function is 8.75.

And the domain is all the positive integers.

What is a domain?

The collection of all conceivable independent values that a function or relation may take is known as its domain.

Given:

Alice decides to finish her trip by riding a train 700 miles to Washington, D.C.

The train travels at an average speed of 80mph.

Let s be the average speed.

So, speed = distance / time

s = 700/t

t = 700/80

t = 8.75 hours.

The range of the function is 8.75.

And the domain is all the positive integers.

Therefore, the time it will take is 8.75 hours.

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Find one possible missing coordinate so that the point becomes a solution to the given inequality.



(x,9)
is a solution to 8x−7 .

Answers

Answer:

x=2

Step-by-step explanation:

y=8x-7

9=8x-7

9+7=8x-7+7

16=8x

16/8=8x/8

2=x

A bag contains 8 green candies and 4 red candies. You randomly select one candy at a time to eat. If you eat five candies, there are relatively prime positive integers m and n so that m n is the probability that you do not eat a
green candy after you eat a red candy. Find m + n.

Answers

If m/n is the probability that you do not eat green candy after you eat a red candy, then m + n is 6.

A bag contains 8 green candies and 4 red candies. If you eat five candies, there are relatively prime positive integers m and n so that m/n is the probability that you do not eat green candy after you eat a red candy. Below list the ways to accomplish this ordering along with their respective probabilities:

GRRRR : [tex]\frac{8}{12}\times\frac{4}{11} \times\frac{3}{10} \times\frac{2}{9} \times\frac{1}{8}[/tex]

GGRRR : [tex]\frac{8}{12}\times\frac{7}{11} \times\frac{4}{10} \times\frac{3}{9} \times\frac{2}{8}[/tex]

GGGRR : [tex]\frac{8}{12}\times\frac{7}{11} \times\frac{6}{10} \times\frac{4}{9} \times\frac{3}{8}[/tex]

GGGGR : [tex]\frac{8}{12}\times\frac{7}{11} \times\frac{6}{10} \times\frac{5}{9} \times\frac{4}{8}[/tex]

GGGGG : [tex]\frac{8}{12}\times\frac{7}{11} \times\frac{6}{10} \times\frac{5}{9} \times\frac{4}{8}[/tex]

The sum is [tex]\frac{8\times3\times4(2+14+42+70+70)}{12.11.10.9.8}[/tex]

Probability that you do not eat green candy after you eat a red candy =[tex]\frac{1}{5}[/tex]

so m = 1 and n = 5

m + n =6

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when constructing bins for a frequency distribution of quantitative data, which of the following principles should generally be followed?

Answers

When constructing bins for a frequency distribution, it is important to have equal widths, choose the number of bins based on the sample size, and consider outliers in the data.

A frequency distribution is a representation of data that shows the number of observations in each category or bin.

One of the most important principles is to have an equal number of observations in each bin. This is known as having equal widths for the bins.

To calculate the width of a bin, divide the range of the data by the number of bins desired. The range is then divided into equal parts, each of which becomes a bin width.

Another principle is to have the number of bins chosen based on the sample size.

A rule of thumb is to have at least five observations in each bin, but more bins may be necessary for larger samples.

Additionally, the choice of bin width can also be influenced by outliers in the data. If there are extreme values in the data, it may be necessary to create a separate bin for those values, so they do not dominate the frequency distribution.

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concerning the relationship between the chi squared test and two proportion z test with a two sided alternative hypothesis, which of the following statements is true?The x^2 test statistic is equal to the z test statistic. The x^2 test statistic is equal to the z test statistic squared. The x^2 test statistic is not equal to the z test statistic squared. The x^2 test statistic is not equal to the alternative hypotheses value squared.

Answers

The concept is the Chi-square test, a statistical test for comparing observed results to expected results. The answer is option A.

The test statistic x^2 is equivalent to the test statistic Z. Homogeneity 2x2 The chi-square statistic (and the test) is equivalent to a two proportion test.

The chi-square test is a statistical test used to compare observed results to expected results.The purpose of this test is to determine whether the difference between the observed and expected data is due to chance or to the relationship between the variables being studied. The

Two Ratio Z-Test is a statistical hypothesis test used to determine whether two ratios are different from each other. When you run the test, the z-statistic is calculated from two independent samples, and the null hypothesis is that the two proportions are equal.

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Can you help me in this problem algebra

Answers

Answer:

2^4*2^5=2^(4+5)=2^9

Step-by-step explanation:

When dealing with operations with exponents and multiplication, the exponent operations always come first.  So while the exponent 9 is correct for the answer, 4 is incorrect.

For example, if you were to solve each operation and eliminate every exponent, you would have

2^4*2^5=16*32=512 which is the same as 2^9=512.

As you can see, the exponent operation must come before the multiplication.

Determine if the triangle below is a right triangle. If it is not, compute what the hypotenuse would have to be for the triangle to be a right triangle. A. No, the hypotenuse should be 98 B. No, the hypotenuse should be 99 C. No, the hypotenuse should be 94 D. Yes

Answers

The triangle will by a right triangle if the sum of the squared side lengths is equals to the squared length of the hypotenuse.

What is the Pythagorean Theorem?

The Pythagorean Theorem states that for a right triangle, the length of the hypotenuse squared is equals to the sum of the squared lengths of the sides of the triangle.

Hence, a triangle will only be a right triangle if the Pythagorean Theorem is respected, hence the sum of the squared side lengths must be compared to the square of the hypotenuse length.

Missing Information

The problem is incomplete, hence the procedure to verify whether the triangle is a right triangle was presented.

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c)If 2000 items sell when the price is 30 dollars and if the number of items that are sold decreases by 400 for every 1 dollar increase in price, find the rate of change of the profit when the item price is 30 dollars.

Answers

The rate of change of the profit when the item price is $30 is $3600 per dollar increase in price.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

Let's call the number of items sold at a price of $p as x(p).

Based on the information given, we can write an equation for x(p) as:

x(p) = 2000 - 400(p - 30)

The profit from selling the items at a price of $p is given by the product of the number of items sold and the price:

Profit(p) = x(p)×p

Taking the derivative of the profit function with respect to the price, we can find the rate of change of the profit:

dProfit/dp = dx/dp×p + x(p)

= -400 p + 400 ( 30) + 2000 - 400(p - 30)

= -400 p + 12000

When p = 30, the rate of change of the profit is:

dProfit/dp = -400(30 )+ 12000

= 3600

So the rate of change of the profit when the item price is $30 is $3600 per dollar increase in price.

Hence,  the rate of change of the profit when the item price is $30 is $3600 per dollar increase in price.

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Baseball The table shows the height of a baseball hit, with
x representing the time (in seconds) and y representing
the baseball's height (in feet). Use a graphing calculator
to find the best-fitting model for the data.
Time, x
2 4 6 8
0
Helght, y 3 28 40 37 26
Oy 1.553x² +15.1782 -3.37
Oy -1.553x² - 15.178x + 3.37
Oy = -1.553x² +15.178x + 3.37
Oy 1.553x² +15.178x + 3.37

Answers

Answer: The best-fitting model for the data is a parabolic equation with the form y = ax^2 + bx + c. The coefficients a, b, and c represent the parameters that best describe the relationship between the time (x) and the height (y) of the baseball.

Based on the information provided, the best-fitting model is:

y = 1.553x^2 + 15.178x + 3.37

where y is the height of the baseball (in feet), x is the time (in seconds), 1.553 is the coefficient for x^2, 15.178 is the coefficient for x, and 3.37 is the constant term. This equation represents the best fit of the data to a parabolic function.

Step-by-step explanation:

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