If the sum of first 7 terms of an A.P is 49 and the sum of first 17 terms is 289 find the sum of first 30 term
Answers
Sum of first 7 terms of an AP = 49.
Sum of first 17 terms = 289
Find:the sum of first 30 term
Solution:We know that,
Sum of first n terms of an AP – S(n) = n/2 * [ 2a + (n - 1)d ]
Hence,
→ 7/2 * [ 2a + (7 - 1)d ] = 49
→ 2a + 6d = 49 * 2/7
→ 2( a + 3d ) = 14
→ a + 3d = 14/2
→ a + 3d = 7 -- equation (1)
Similarly,
→ 17/2 * [ 2a + 16d ] = 289
→ 17/2 * 2 * (a + 8d) = 289
→ a + 8d = 289 * 2/17 * 1/2
→ a + 8d = 17 -- equation (2)
Subtract equation (1) from (2).
→ a + 8d - (a + 3d) = 17 - 7
→ a + 8d - a - 3d = 10
→ 5d = 10
→ d = 10/5
→ d = 2
Substitute the value of d in equation (1).
→ a + 3 * 2 = 7
→ a = 7 - 6
→ a = 1
Now,
Sum of first 30 terms = 30/2 * [ 2(1) + (30 - 1)(2) ]
→ S(30) = 15 (2 + 58)
→ S(30) = 15 * 60
→ S(30) = 900
Therefore, the sum of first 30 terms of the given AP is 900.
I hope it will help you.
Regards.
answer refer in pic siso
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B three over five y + 15
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D nine over five y + 15
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Answers
Answer:
The equivalent to three over five (3y + 15) is nine over five y + 9 ⇒ C
Step-by-step explanation:
Let us solve the question
∵ Three over five means [tex]\frac{3}{5}[/tex]
∴ Three over five (3y + 15) = [tex]\frac{3}{5}[/tex] (3y + 15)
→ By using the distributive property, multiply each term inside the
bracket by three over 5
∴ [tex]\frac{3}{5}[/tex] (3y + 15) = [tex]\frac{3}{5}[/tex] (3y) + [tex]\frac{3}{5}[/tex] (15)
→ Multiply three over five by 3y
∵ [tex]\frac{3}{5}[/tex] (3y) = [tex]\frac{3(3)}{5}[/tex] (y) = [tex]\frac{9}{5}[/tex] y
→ Multiply three over five by 15
∵ [tex]\frac{3}{5}[/tex] (15) = [tex]\frac{3(15)}{5}[/tex] = [tex]\frac{45}{5}[/tex] = 9
∴ [tex]\frac{3}{5}[/tex] (3y) + [tex]\frac{3}{5}[/tex] (15) = [tex]\frac{9}{5}[/tex] y + 9
∴ [tex]\frac{3}{5}[/tex] (3y + 15) = [tex]\frac{9}{5}[/tex] y + 9
∴ The equivalent to three over five (3y + 15) is [tex]\frac{9}{5}[/tex] y + 9
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Answers
Answer:
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Step-by-step explanation:
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Therefore:
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Step-by-step explanation:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
6. Los valores posicionales de dígitos son;
Miles [tex]{}[/tex] cientos decenas unidades
4 [tex]{}[/tex] 9 5 6
7. El número de cuadrados que tiene Fernando = 12
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Step-by-step explanation:
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Step-by-step explanation:
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O 1.9, 1.09, 1.009
Answers
The best choice is A)
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Answer:
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Step-by-step explanation: