If the solar constant is 1366 W/m2 and the solar zenith angle is 60°, the incoming shortwave radiation is W/m2. If the albedo is 0.1, the reflected shortwave radiation is W/m2.

In prefigurative cultures, young people learn primarily from the elders, and peer influence is relatively low. The culture remains stable and resistant to change.  

In postfigurative cultures, young people learn primarily from their peers, and the influence of elders is relatively low. These cultures are more susceptible to change and are often associated with technological advances, globalization, and other social changes.

A postfigurative culture is one in which the older generation teaches the younger generation information and morals. Slow societal change, learning from elders' experiences, and the transmission of cultural values and customs from one generation to the next are characteristics of this sort of culture. Postfigurative societies place a high value on family honoraria and ancestor reverence (sometimes known as "ancestor worship"). Anthropologist Margaret Mead initially used the word "postfigurative" to characterize civilizations that placed a high priority on tradition and the passing of knowledge from older to younger generations in the 1960s. Prefigurative cultures, on the other hand, emphasize the wisdom and experience of the younger generation and go through fast social transformation.

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Because the ball is thrown horizontally and lacks a vertical component at the beginning, the correct response is "0."

Air exerts a force known as air resistance. The force acts in the opposite direction when an object is flying through the air. Although a sports car with a sleek design will experience less drag and less air resistance, the car will be able to drive more quickly than a truck with a flat front.

A moving object experiences air resistance force when the air is pressing up against it. An example of a frictional force is air resistance. A force is always applied to stop an item in motion. Initially, air The force of resistance is not particularly strong.

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Since skater 2 is in the middle, force acting on her from both skater 1 in front and skater 3 behind. The free body diagram for skater 2 would include two arrows pointing towards her, representing the forces from skater 1 and skater 3. Since there is no friction, there are no other forces to consider.

The diagram would look something like this:

                       ∧

                        |

F3         ←         I          →      F1

                        |

                       v

where F1 is the force from skater 1 and F3 is the force from skater 3.

A force called friction works against the relative velocity of two surfaces coming into contact. The minute imperfections on the surfaces that interlock with one another when they come into touch are what cause it. We experience friction as a result of this interlocking as resistance to motion. The type of surfaces in contact, the force forcing the surfaces together, and the rate of motion can all have an impact on the frictional force. As some of the kinetic energy is transformed into heat energy during friction, this can also result in energy loss. Designing machinery, vehicles, and structures to reduce wear and tear and maximize performance requires an understanding of friction.

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Solution of the question with the information which is given is:

Ignoring wind resistance and using 32ft/sec/sec as acceleration due to gravity.

d= 16 t2

t2= 365/ 15

t= 4.8 seconds

Therefore the hit impact was about 4.8 seconds

In Newtonian physics, free fall is any motion of a body where gravity is the only force acting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.

According to Newton's second law of motion, force (F) = mass (m) times acceleration, an item in free fall will move with an acceleration (a). We can use a little mathematics to determine the object's acceleration in terms of the net external force and the object's mass (a = F / m).

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The total thermal resistance of the wall can be found by summing the thermal resistances of each section:

= 4.277 m^2.K/W

To determine the rate of heat transfer through the wall, we can use Fourier's law of heat conduction which states that the rate of heat transfer through a material is proportional to the temperature gradient across the material, and can be expressed as:

q = -kA * dT/dx

where q is the rate of heat transfer, kA is the thermal conductivity of the material, dT/dx is the temperature gradient, and the negative sign indicates that heat flows from higher temperatures to lower temperatures.

(a) To find the rate of heat transfer through the wall, we need to first determine the thermal resistance of each section of the wall. The thermal resistance is given by:

R = L / k

where R is the thermal resistance, L is the length of the material, and k is the thermal conductivity.

Using this equation, we can find the thermal resistance of each section as follows:

[tex]R_A = 5 / 2 = 2.5 m^2.K/W[/tex]

[tex]R_B = 0.22 / 35 = 0.0063 m^2.K/W[/tex]

[tex]R_C = 5 / 20 = 0.25 m^2.K/W[/tex]

[tex]R_D = 0.22 / 15 = 0.0147 m^2.K/W[/tex]

[tex]R_E = 0.22 / 35 = 0.0063 m^2.K/W[/tex]

[tex]R_F = 3 / 2 = 1.5 m^2.K/W[/tex]

(b) To find the temperature at the point where sections B, D, and E meet, we can assume that there is no heat generation within the wall (i.e., steady-state conditions), so the temperature at any point within the wall is the same in the x-direction. Therefore, we can use the thermal resistance network to find the temperature drop across each section:

ΔT_A = (300 - 100) = 200°C

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Ranking of the bulbs based on their brightness are C - A - B - D - E.

Bulb A and B are connected in parallel. Bulb D and E are connected in series and the bulb DE is parallel with bulb C. Resistance of each bulb is remain constant.

Bulb D and E are connected in the series so power dissipated in the D and E are same. Bulb C is in parallel with bulb DE. 2/3 of current pass through bulb C and 1/3 of current pass through bulb DE.

Bulb C has brightest than A and B which are equal and D and E are dimmest

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The magnitude of normal force that floor exerts on chair is 120.24 N. the magnitude of the frictional force acting on the chair is 123.24 N

Simply put, "distance or quantity" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.

Vertical component of the force = F sinθ

                                                    = 38X sin42°

                                                    = 38 X 0.669

                                                    = 25.42N

Total normal force acting on the chair = weight +Vertical component force

Total normal force acting on the chair = 95N + 25.42N

                                                          = 120.24 N

horizontal component of force= f cosθ.

                                               = 38X cos 42°

                                               = 38 X 0.743

                                              = 28.24 N

Total normal frictional force on the chair

frictional force = weight+ horizontal component of force

frictional force= 95N + 28.24 N

frictional force= 123.24 N

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a) The angular acceleration of the grindstone 0.27 rad per square second. b) The number of turns stone will make before coming to rest is 23.9 revolutions.

a) The tangential force slowing the grindstone is fF.

Its torque is rfF.

By Newton's Second Law

rfF = Iα

Therefore, α = 2fF/mr

Substituting actual numbers

α = 2×0.2×21/(93×0.33) = 0.27 rad per square second

b) Let t be the time it takes the grindstone to come to rest, θ be the total angle by which the grindstone will turn before coming to rest.

ω = αt

θ = αt²/2

From the first and second,

θ = ω²/2α

Substitute actual numbers

θ = 9²/2×0.27 = 150

The above result is in radians.

Since the result is supposed to be given in revolutions, 150/2π = 23.9 revolutions.

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The right response is that identical twins have stronger correlations than fraternal twins do.

If there are several pizza truck in the region, each with its own distinctive jingle, we would learn them all by heart and associate each one with a certain pizza truck. Establishing a connection between two variables, in this case "jingle" and "distance of the truck" in this example, is exactly what correlational research involves.

A nonexperimental research method known as correlational analysis measures two variables and evaluates the statistical relationship (also known as the correlation) among them with little to no effort to control unrelated variables.

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The electrical potential energy of the system at a separation of 6 meters is greater than the electrical potential energy of the system at a separation of 12 meters.

The electrical potential energy of the system at a separation of 6 meters is greater than the electrical potential energy of the system at a separation of 12 meters. This is because electrical potential energy is inversely proportional to the separation distance between the charges. As the separation distance decreases, the electrical potential energy increases. This relationship can be represented by the equation:

U = kq1q2/r

where U is the electrical potential energy, k is a constant, q1 and q2 are the charges, and r is the separation distance. As r decreases, U increases.

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An independent equation is an equation in a system of simultaneous equations which cannot be derived algebraically from the other equations. The concept typically arises in the context of linear equations.

I = [tex]I_{1} + I_{2}[/tex]  

[tex]V_{1} = 2I_{1}[/tex]  

[tex]V_{2} = 5I_{2}\\V_{1} - V_{2} = 0 \\V_{1} = V_{2}\\V-5= V_{1}\\V = V_{1} + 5[/tex]

put equation 2 and 3 in 1

[tex]I =V_{1}/2 + V_{2} /5\\= V_{1} [1/2 + 1/5]\\= 7V_{1}/ 10\\I = 7V_{1} / 10[/tex]

put 5 in 6

[tex]I = 7/10 (v-5) [ I = 0.7V- 3.5][/tex]

given V= 3

I = 0.7 V - 3.5

I = 0.7 (3) - 3.5

[ I = -1.4 A]

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The required electric field for x > 0 is 2.0 x 10^3 V/cm.

Given:

Total current density, J = 10 A/cm²

Hole concentration, p = 10¹⁶ cm⁻³

Electron concentration, n(x) = 2x10¹⁵x cm⁻³, where L = 15 μm, and x > 0

Electron diffusion coefficient, Dₙ = 27 cm²/s

Hole mobility, μₚ = 420 cm²/Vs

To calculate:

(a) Electron diffusion current density for x > 0

(b) Hole drift current density for x > 0

(c) Electric field for x > 0

Solution:

(a) The electron diffusion current density can be calculated using the equation:

Jn = -qDn(dn/dx)

where q is the electronic charge, and dn/dx is the gradient of the electron concentration profile.

q = 1.6x10⁻¹⁹ C (electronic charge) (electronic charge)

Dn/Dx = 2 x 1015 cm4 (gradient of electron concentration)

If we apply these values, we obtain:

Jn = -(1.6x1019 C) (27 cm2/s) (2x1015 cm4) = -8.64 A/cm2.

The electron diffusion current is said to be flowing in the opposite direction from the direction of the total current density when it has a negative sign.

(b) The equation: Jp = qppE, where E is the electric field and pp is the hole concentration, can be used to calculate the hole drift current density.

pp = 10¹⁶ cm⁻³ (constant hole concentration) (constant hole concentration)

The values of Jn and pp, along with the formula J = Jn + Jp, allow us to calculate Jp:

Jp = Jn = 10 A/cm2 - (-8.64 A/cm2) = 18.64 A/cm2, where

This value, q, and pp are all substituted into the equation for Jp to produce the following result:

Jp equals (1.6x1019 C)(420 cm2/Vs)(1016 cm3).

E = 18.64 A/cm²

Solving for E, we get:

E = Jp/(qμpp) = (18.64 A/cm²)/[(1.6x10⁻¹⁹ C)(420 cm²/Vs)(10¹⁶ cm⁻³)] = 0.28 V/cm

(c) The electric field required for x > 0 is 0.28 V/cm.

Therefore, the electron diffusion current density is -8.64 A/cm², the hole drift current density is 18.64 A/cm², and the required electric field is 0.28 V/cm for x > 0.

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A charge will flow until the electric field at the surface of the sphere is equivalent to the electric field of the test charge, because then the net force on all charges on the surface of the sphere will be zero. Here option B is the correct answer.

When the positive test charge is brought near the conducting sphere, the excess negative charge from the ground flows onto the surface of the sphere until equilibrium is reached. At this point, the electric field at the surface of the sphere becomes equal and opposite to the electric field of the test charge, thus canceling out the electric field of the test charge within the sphere.

Since the electric field inside the conductor is zero, the excess charges on the surface of the conductor are uniformly distributed and the net force on them is zero. Therefore, option B is the correct answer. Option A is incorrect because the excess charge on the surface of the sphere will be opposite in sign and not equal in magnitude to the test charge.

Option C is incorrect because the potential at the surface of the sphere is not necessarily the same as that of the test charge. Option D is incorrect because the excess charge on the surface of the sphere will be opposite in sign and not equal in magnitude to the test charge. Option E is incorrect because the net force on charges on the surface of the sphere is zero when the electric field at the surface of the sphere is equivalent to the electric field of the test charge.

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The battery's ability to push more charges onto the plates is determined by its maximum electromotive force, which is reached when the battery has already pushed as many charges as it can onto the plates.

A battery's electromotive force (EMF), a measurement of the potential difference between its positive and negative terminals, determines its capacity to drive additional charges onto the plates. A battery's EMF reaches its peak when it is completely charged and can no longer push charges onto the plates.

The battery has already pushed as many charges as it can onto the plates if one plate has a lot of excess positive charges, while the other plate has a lot of extra negative charges. The battery can no longer put charges onto the plates since it has achieved its maximum EMF.

As a result, the additional fees on the plates have no bearing.

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The acceleration will be greater for car B.

Acceleration is a physical quantity that describes the rate at which an object's velocity changes over time. It is defined as the change in velocity per unit of time, and it is a vector quantity, meaning it has both magnitude and direction.

When an object experiences acceleration, its velocity changes either in speed, direction, or both. If the acceleration is in the same direction as the velocity, the object's speed increases. If the acceleration is in the opposite direction as the velocity, the object's speed decreases. If the acceleration is perpendicular to the velocity, the object's direction changes.

The standard unit of acceleration is meters per second squared (m/s^2). A positive acceleration indicates that an object is speeding up, while a negative acceleration indicates that an object is slowing down. If the acceleration is zero, then the object's velocity is constant.

To calculate the acceleration of each car around its respective curve, we can use the following formula:

a = v^2 / r

where a is the centripetal acceleration of the car, v is its speed, and r is the radius of the curve.

For car A, traveling at speed v around curve number one with radius r, the acceleration is:

a_A = v^2 / r

For car B, traveling at speed 2v around curve number two with radius 2r, the acceleration is:

a_B = (2v)^2 / (2r) = 4v^2 / (2r) = 2v^2 / r

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To solve this problem, we can use the law of conservation of momentum, which states that the total momentum of a system is conserved in the absence of external forces. In this case, the system consists of the arrow and the object.

Before the collision, the arrow has a momentum of:

p1 = m1v1 = (0.07 kg)(90 m/s) = 6.3 kg m/s; where m1 is the mass of the arrow and v1 is its velocity.

Since the object is initially at rest, its momentum is zero:

p2 = m2v2 = (m)(0) = 0; where m2 is the mass of the object and v2 is its velocity.

After the collision, the arrow and the object move together with a common velocity v. The total momentum of the system after the collision is:

p3 = (m1 + m2)v

Using the law of conservation of momentum, we can equate the initial and final momenta:

p1 + p2 = p3

Solving for v, we get:

v = p1/(m1 + m2) = (6.3 kg m/s)/(0.07 kg + m)

To determine the resulting velocity of the object, we need to solve for v. One way to do this is to use the law of conservation of energy, which states that the total energy of a system is conserved in the absence of external forces.

The initial kinetic energy of the system is: KE1 = (1/2)m1v1^2 = (1/2)(0.07 kg)(90 m/s)^2 = 283.5 J; where KE1 is the initial kinetic energy of the arrow.

The final kinetic energy of the system is:

KE2 = (1/2)(m1 + m2)v^2

Using the law of conservation of energy, we can equate the initial and final kinetic energies:

KE1 = KE2

Solving for v, we get:

v = sqrt(2KE1/(m1 + m2)) = sqrt(2283.5 J/(0.07 kg + m))

To determine whether the collision is elastic or inelastic, we can compare the system's initial and final kinetic energies. If the kinetic energy is conserved, then the collision is elastic. If the kinetic energy is not conserved, then the collision is inelastic.

The initial kinetic energy of the system is 283.5 J. The final kinetic energy of the system is:

KE2 = (1/2)(m1 + m2)v^2

Substituting the value of v we obtained earlier, we get:

KE2 = (1/2)(0.07 kg + m)(6.3 kg m/s)^2/(0.07 kg + m)

To determine whether the collision is elastic or inelastic, we must compare KE1 and KE2. Since the object's mass is unknown, we cannot make a definitive conclusion about the nature of the collision. However, we can provide some evidence to support our answer.

If the collision is elastic, then KE2 should be equal to KE1. However, if we substitute v = 90 m/s into the expression for KE2, we get: KE2 = (1/2)(0.07 kg + m)(90 m/s)^2/(0.07 kg + m) = 4050 J. This value is greater than KE1, which indicates that the collision is not elastic. Therefore, we can conclude that the collision is inelastic.

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The picture that best represents the charge distribution on the inner and outer walls of the shell is picture 4

Charge distribution on a conducting shell can affect the electric field both inside and outside the shell. If the charge is distributed uniformly on the surface of the shell, the electric field inside the shell will be zero, while the electric field outside the shell will be the same as that of a point charge located at the center of the shell.

If the charge is distributed non-uniformly, then the electric field inside and outside the shell will be affected accordingly. In general, the charge distribution will determine the potential difference between the inside and outside of the shell, which can have important implications for the behavior of charged particles both inside and outside the shell.

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Answer:

75 J

Explanation:

The average force of gravitation between Venus and the Sun is3.24 x 10²² N.

The force of gravitation between two objects can be calculated using the equation;

F = G (m1m2) /d²

where;

To find the average force of gravitation between Venus and the Sun, we need to know their masses and the average distance between them.

Venus has a mass of approximately  4.87 x 10²⁴ kg, and the average distance between Jupiter and the Sun is about 108 million kilometers.

Plugging these values into the equation, we get:

F = 6.67 x 10⁻¹¹ (4.87 x 10²⁴) x (1.989 x 10³⁰ kg) / (108 x 10⁶)²

F = 3.24 x 10²² N.

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Answer: The force of gravity

Jupiter and other gas Giants use gravitational force to attract gas to the top, while they still have a solid core,the force in the center keeps the planet together.

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A man, with his arms at his sides, is spinning on a light frictionless turntable. When he extends his arms his angular velocity remains the same. Option e is the correct choice.

When the arms are folded the rotational inertia is lower. When the man extends his arm he is basically increasing his rotational inertia thereby loosing angular velocity using the principle of conservation of angular momentum. This implies less angular distance is covered in the same time giving us negative work.

After pulling arms, the angular velocity increases but moment of inertia of decreases in, such a way that angular momentum remains constant.

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The correct answer is b. twice distance as far as the slower arrow.

The kinetic energy of an object is given by the equation:

KE = 1/2mv^2

where m is the mass and v is the velocity.

Since the two arrows are identical, they have the same mass. Therefore, the kinetic energy is directly proportional to the square of the velocity.

If one arrow has twice the kinetic energy of the other, this means that its velocity is √2 times greater. The distance that an object travels is directly proportional to its velocity, so the faster arrow will travel √2 times farther than the slower arrow.

However, since the kinetic energy is proportional to the square of the velocity, the distance that the faster arrow travels will be (√2)^2 = 2 times greater than the distance traveled by the slower arrow.

Thus, the faster arrow will penetrate twice as far as the slower arrow.

Therefore, the correct answer is option b)twice as far as the slower arrow.

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A ball is thrown horizontally from a 95 m-high building's highest point and landing 125 m from the building's base. Use a coordinate and disregard air resistance.

What does the word "resistance" mean?

Describe resistance. Electrical | January 12, 2021 The obstruction to part of the electrical circuit is measured by resistance. The Greek letter beta () represents the unit of measurement for resistance, known as ohms. Georg Simon Ohm (1784–1854), a German physicist that investigated the connection between voltage, current, and resistance, is the name given to the unit of resistance.

What is a circuit's electrical resistance?

The relationship between the induced voltage and the current that flows through a circuit determines its electrical resistance. Ohms is the symbol for electrical resistance. Some materials permit the flow of electric charge more easily than others. The electrical resistance gauges how much the circuit restricts the flow of the this electric charge.

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Both the children meet at t = 64 s and the distance travelled by first child is 96 m, distance travelled by second child is 128 m.

Two children are said to be 224 m apart.

First child walks towards the second with 1.5 m/s.

Second child walks towards the first with 2 m/s.

Let V = V₁ + V₂ = 1.5 + 2 = 3.5 m/s

We know the expression for, distance, velocity and time as,

s = v t

where,

v is velocity

t is time

s is distance

Let us find out the time at which they meet.

t = s/v = 224/3.5 = 64 s.

They meet at t = 64 s.

The distance travelled by first child s₁ = V₁ t = 1.5 × 64 = 96 m.

The distance travelled by first child s₂ = V₂ t = 2 × 64 = 128 m.

Thus, the first child walked 96 m and the second child walked 128 m.

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The magnitude and direction of the electric field at P 1 when t = 3.00 s and r 1  = 0.02m is 0.3 v/m (option A). The direction is anti clockwise.

The force per charge on the test charge is a straightforward way to define the size of the electric field. From its definition, the common metric units for electric field strength are derived. Electric field units would be force units divided by charge units since the definition of an electric field is a force per charge.

The magnitude of the electric field at P1 is as follows:

E1 = dΦ/dt

E (2πr1) = S dB/dt

= r1/2 (dB/dt)

= r1/2 ║6t² + 8t║

= 0.2 / 2 ║6 (3²) + 8 (3)

= 0.3 v/m

The electric field is oriented counter clockwise to the direction of the induced current in a hypothetical circular conducting loop that passes through P 1.

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The statement "In fair weather there is an electric field at the surface of the earth, pointing down into the ground" is a TRUE statement.

Electric field is a region in a particular space that induces forces on charged particles. The induced force that the particles experience will cause them to undergo motion, either parallel or antiparallel to the field direction depending on the sign of the charge.

A positive charge will cause the particles to move parallel to the field, while a negative charge will cause the particles to move anti-parallel to the field. In case of area with fair weather, the electric field is directed vertically downward to the earth.

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Answer:

kekekekekhshshehshehdhdhdhdhdhdhdhdh

The center of the outer electron cloud of a carbon atom shifts a distance when the atom is polarized by the pen is, [tex]s = \dfrac{\pi \epsilon_0 m g d^3}{2eQ}[/tex].

When a negatively charged object is brought close to a small piece of paper, the paper charges cannot be distributed as they would if it were a conductor.

Outer electron Cloud Charge = −4e

Carbon Atom shifts Distance =  s=?

The Pen Charge = Q

Force on Pen Charge is, [tex]F = Q\dfrac{1}{4\pi \epsilon_0} \dfrac{8es}{d^3}[/tex]

The sum of the forces, both that of gravity and that exerted by the charge Q, must be equal to zero to maintain equilibrium at a distance s.

[tex]mg - Q\dfrac{1}{4\pi \epsilon_0} \dfrac{8es}{d^3} = 0[/tex]

This gives the distance s, to be

[tex]s = \dfrac{\pi \epsilon_0 m g d^3}{2eQ}[/tex]

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--The complete question is, Try rubbing a plastic pen through your hair, and you'll find that you can pick up a tiny scrap of paper when the pen is about one centimeter above the paper. From this simple experiment you can estimate how much an atom in the paper is polarized by the pen! You will need to make several assumptions and approximations.

(a) Suppose that the center of the outer electron cloud (q = -4e) of a carbon atom shifts a distance s when the atom is polarized by the pen. Calculate s algebraically in terms of the charge Q on the pen. (Use the following as necessary: m, g for acceleration due to gravity, h for the distance from the carbon to the pen, e for the charge of the electron, Q,ε0, and π. )--

Positive anomalies result when the crust is magnetised in a normal polarity parallel to the ambient field of Earth, and negative anomalies result when the crust is reversely magnetised in an opposite sense.

A positive magnetic anomaly is a reading that exceeds the average magnetic field strength and is usually related to more strongly magnetic rocks, such as mafic rocks or magnetite‐bearing rocks, underneath the magnetometer. A value that is lower than the typical magnetic field is referred to as a negative magnetic anomaly.

These anomalies are classified as negative or magnetic lows if their strength is below normal and positive or magnetic highs if it is above normal. These anomalies are typically caused by variations in magnetic susceptibility, which in turn mostly reflect the rocks' magnetite content.

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In a mechanical compressional wave, the wave energy causes the matter in the medium to move up and down or back and forth at right angles to the direction the wave travels. [FALSE]

P-waves, or primary waves, are one of two types of seismic waves and are often called surface waves (so called because they propagate through the earth). A wave produced by an earthquake and recorded by a seismograph. It gets its name because it is faster than other seismic waves, reaches each seismic station first, and the next wave is called the S wave or secondary wave. Like pressure waves and longitudinal waves, sound is also a type of P wave. This means that particles in the ground (body of the earth) vibrate along or parallel to the direction of propagation of the energy of the propagating wave.

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