If the resistance in the coil is 2.0 , what is the magnitude of the induced current in the coil while the field is changing

Answer:

The atmosphere would become warmer

Explanation:

methane absorbs the suns heat, therefore warming the atmosphere. if all the methane from the premafrost melted, would would have a huge large scale global warming, the giant increase of temperature could have devistating effects on all life on our planet.

Answer:

Explanation:

Step one:

given data

let the mass of the rider be m,=110kg

let the velocity be v=?

let the mass of the car be M,=110kg

let velocity of the car V=6m/s

Step two:

the momentum of an object is given by the expression

P=mv

Step two:

since the two the bicycle rider must have the same momentum as the car,

then we need to equate their momentum

mv=MV

110*v=1400*6

110v=8400

divide both sides by 110 to find v

v=8400/110

v=76.36m/s

The rider is expected to have a speed of 76.36m/s

Answer:

Vf = 3.67 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} ^{2} =v_{i} ^{2} -(2*a*x)[/tex]

where:

Vf = final velocity [m/s]

Vi = initial velocity = 4.3 [m/s]

a = acceleration or desacceleration = 0.5 [m/s²]

x = distance = 5 [m]

Note: The negative sign in the above equation means that the velocity of the ball is decreasing (desacceleration).

Now replacing:

Vf² = (4.3)² - (2*0.5*5)

Vf² = 18.49 - 5

Vf² = 13.49

using the square root, we have.

Vf = 3.67 [m/s]

Answer:

Explanation:

range of projectile = u² sin2θ / g

u = 30 m /s

θ = 40°

range = 30² x sin 80 / 9.8

= 90.44 m

b )

maximum altitude H = u² sin²θ / 2 x g

= 30² sin²40 / 9.8

= 37.94 m .

Answer:

[tex]L^2(\dfrac{8m}{3}+m_r)[/tex]

Explanation:

m = Mass of each rod

L = Length of rod = Radius of ring

[tex]m_r[/tex] = Mass of ring

Moment of inertia of a spoke

[tex]\dfrac{mL^2}{3}[/tex]

For 8 spokes

[tex]8\dfrac{mL^2}{3}[/tex]

Moment of inertia of ring

[tex]m_rL^2[/tex]

Total moment of inertia

[tex]8\dfrac{mL^2}{3}+m_rL^2\\\Rightarrow L^2(\dfrac{8m}{3}+m_r)[/tex]

The moment of inertia of the wheel through an axis through the center and perpendicular to the plane of the ring is [tex]L^2(\dfrac{8m}{3}+m_r)[/tex].

Explanation:

a fluorine atom has nine protons and electrons so it is electrically neutral

Answer:

no bloody idea

Explanation:

???

Answer:

1000 cm³

Explanation:

The product of powers property is a rule that helps in simplifying the difficulties that comes with multiplying powers of numbers. It states that when multiplying two powers having the same base, we take one of the base, and then just add the exponents.

This is illustrated in the example.

S¹ * S². The product of powers asks us to pick one of the bases, S, and then add up the powers, thus

S¹ * S² = S^(¹+²)

S¹ * S² = S³

Now, using this in our question, volume of the cube is S³. Since we aren't given a length, I'm going to assume a length.

L = 10 cm. We all know that all sides are equal in a cube,

So, S = 10 cm.

S³ = volume of the cube

V = 10³

V = 1000 cm³

Now, to test the property of products, we say

S = 10, even though it doesn't show any visible exponent, we know that it's raised to the power of 1, and thus

S = 10¹

V = S * S * S

V = 10¹ * 10¹ * 10¹

V = 10^(¹+¹+¹)

V = 10³

V = 1000 cm³

Justified.......

Please vote me brainliest if it helped you. Thanks

Answer:

United States

Explanation:

Angle of projection of the dart = 60°

initial velocity of the dart = 14.1 m/s

Using basic trigonometry, we can see that:

Vertical component of the Dart = 14.1*Sin 60° = 12.2 m/s

Horizontal component of the Dart = 14.1*Cos 60° = 7.05 m/s

Explaining the concept:

Once the dart is in mid-air, there will be no force that will reduce its horizontal velocity

So, the dart will be moving at a constant horizontal velocity of 7.05 m/s

but the force of gravity will be applied on the dart while mid-air and will pull it downwards with an acceleration of 9.8 m/s²

Hence, the time the dart will be aloft is the same as the time taken by the dart to reach the ground if we threw it vertically upwards at a velocity of 12.2 m/s

Solving for the time taken for the dart to reach the ground:

initial velocity = 12.2 m/s          

velocity at max height = 0 m/s      

acceleration = -9.8 m/s

time taken to reach max height:

v = u + at            using the first equation of motion

replacing the variables

0  = 12.2 + (-9.8)t

t = -12.2 / -9.8

t = 1.24 seconds

Time taken to reach the ground:

time taken to reach the ground = 2 * time taken to reach max height

(Since the dart will take the same time to come back down)

Time taken to reach the ground = 2 * 1.24

Time taken to reach the ground = 2.48 seconds

Therefore, the dart will hit the ground and stop 2.48 seconds after throwing

Explaining the concept:

From newton's second equation of motion

s = ut + 1/2 at²

Since we need the max vertical height, we need the vertical component of the values,

so this equation can be rewritten for vertical height as :

s(vertical) = u(vertical)* t + 1/2 * a(vertical) * t²

from the last section, we know that the dart reaches its maximum height at  t = 1.24 seconds

replacing the values in this equation:

s(vertical) = (12.2 * 1.24) + 1/2 * (-9.8) * (1.24)²

s(vertical) = 15.128 + (-7.5)

s(vertical) = 7.63 m

Therefore, the maximum height of the dart is 7.63 m

Explaining the concept:

The range of the dart is the horizontal distance covered by the dart

from the second section, we know that the dart travels horizontally with a constant velocity of 7.05 m/s

from the third section, we know that the total time taken by the dart to hit the ground is 2.48 seconds

Since the horizontal velocity of the dart is constant, we can say that it moved horizontally for 2.48 seconds at a constant velocity of 7.05 m/s

Solving for the range:

s = ut + 1/2 at²            From the second equation of motion

this equation can be rewritten for horizontal distance as:

s(horizontal) = u(horizontal)* t + 1/2 (a)(t)²

The dart is moving at a constant velocity, that means that its acceleration is 0

s(horizontal) = u(horizontal)* t + 1/2 (0)(t)²

s(horizontal) = u(horizontal)* t

replacing the variables

s(horizontal) = 7.05 * 2.48   [here, 2.48 is the time taken by the dart to reach the ground and stop]

s(horizontal) = 17.484 m

The horizontal distance covered by the dart is 17.484 m

Therefore, the range of the dart is 17.484 m

Answer:

time =  2.49 s

max height = 7.61 m

range = 17.57 m

See below for exact values.

Explanation:

Since we are given the angle at which the object is tossed, this object is in projectile motion.

We are given the initial velocity of the dart, and we can use the angle to solve for its horizontal and vertical components.

Horizontal component:

Vertical component:

In order to find the time that the dart stays in the air, we can use the constant acceleration equation that does not include displacement. This equation is:

Since we solve for time using the vertical motion of the projectile, we will use this equation in terms of the y-direction.

We don't know what the final velocity of the dart when it reaches the ground is, but we do know that its final velocity when it reaches its maximum height is 0 m/s.

Therefore, we can solve for half of the full time that it takes the object to reach the ground, and double this value at the end.

Let's set the downwards direction to be negative and the upwards direction to be positive.

Using our knowledge and previous calculations, we know that:

The acceleration of gravity is in the y-direction and facing downwards, so that's why it is -9.8 m/s².

Substitute these values into the constant acceleration equation.

Subtract 14.1 * sin(60) from both sides of the equation.

Divide both sides of the equation by -9.8 to solve for t.

Now, this is only the time for half of the object's trajectory. Double it to find the total time the dart is aloft:

The dart is in the air for a total of 2.49 seconds.

We can find the maximum height of the dart by using another constant acceleration equation.

Since we don't have the final velocity of the object, we can use this equation:

Subtract [tex]x_i[/tex] from both sides to get the change in position, or delta x.

In order to find the maximum height, we need to use this equation in terms of the y-direction.

Remember that time is the same regardless of the x- or y- direction.

Now, we can solve for the displacement in the y-direction by plugging in the values that we know.

Note that we are using half of the time t, since this is where the maximum height occurs.

Plug these known values into the constant acceleration equation:

The maximum height of the dart is 7.61 meters.

Finding the range of the object in projectile motion involves the same constant acceleration equation, but this time we are solving for the displacement in the horizontal direction (x-direction). Therefore:

We know the horizontal component of the initial velocity vector, which is what we will be using.

The acceleration, of an object in projectile motion, in the x-direction is always 0 m/s².

We will use the full time of the object since we want to find the entire horizontal distance that the object covers. We have:

Plug these values into the constant acceleration equation.

The range of the dart is 17.57 meters.

Answer:

c. √2T

Explanation:

The period of a simple pendulum is given by;

[tex]T = 2\pi \sqrt{\frac{L}{g} } \\\\\frac{T}{2\pi} = \sqrt{\frac{L}{g}} \\\\\frac{T^2}{4\pi^2} = \frac{L}{g}\\\\\frac{g}{4\pi^2} = \frac{L}{T^2}\\\\ \frac{L_1}{T_1^2}= \frac{L_2}{T_2^2}\\\\T_2^2 = \frac{L_2T_1^2}{L_1}\\\\L_2 = 2L_1\\\\ T_2^2 = \frac{2L_1T_1^2}{L_1}\\\\ T_2^2 =2T_1^2\\\\T_2 = \sqrt{2T_1^2}\\\\T_2 = T_1\sqrt{2}[/tex]

Thus, the the new period will be √2T

Answer:

85.14 m

__________________________________________________________

(y) denotes "in the vertical direction"

(x) denotes "in the horizontal direction"

We are given:

Initial Horizontal velocity of the Ball (u(x)) = 19.8 m/s

Initial height of the ball (s(y)) = 92 m

Initial Vertical velocity of the Ball (u(y)) =  0 m/s

Time taken to reach the ground:

taking downwards direction as positive

Since the horizontal velocity is not opposed by any force, it will be the same until the ball reaches the ground

The vertical velocity will be increasing at a rate of (10 m/s)/s until the ball hits the ground

ay = 10 m/s²

So, while calculating the time. we can just ignore the horizontal velocity

Solving for the time taken:

s(y) = u(y)t + 1/2a(y)t²                                   [second equation of motion]

92 = (0)(t) + 1/2(10)(t)²                               [replacing the variables]

92 = 5t²

t² = 92/5                                            [dividing both sides by 5]

t = √18.4                                            [taking the square root of both sides]

t = 4.3 seconds

So, it took the ball 4.3 seconds to reach the ground

Horizontal Distance travelled by the ball:

We know that the ball will reach the ground in 4.3 seconds

Since the horizontal velocity will not change, the ball will move with a constant velocity of 19.8 m/s in the horizontal direction

Horizontal distance travelled:

s(x) = u(x)t + 1/2a(x)t²                    [second equation of motion]

s(x) = (19.8)(4.3) + 1/2(0)(t)²          [replacing the variables]

s(x) = 85.14 m

Hence, the ball travels 85.14 m horizontally

Answer:

Linear velocity is speed in a straight line (measured in m/s) whileangular velocity is the change in angle over time (measured in rad/s, which can be converted into degrees as well).

Explanation:

hope this helps :)

We are given:

Initial velocity (u) = 32 m/s

Acceleration (a) = 3 m/s²

Displacement (s) = 40 m

Final Velocity (v) = v m/s

Solving for the Final Velocity:

from the third equation of motion:

v² - u² = 2as

replacing the variables

v² - (32)² = 2(3)(40)

v² = 240 + 1024

v² = 1264

v = √1264

v = 35.5 m/s

Therefore, the velocity of the bike after travelling 40 m is 35.5 m/s

The  bike's velocity after covering 40 m distance is 35.55 m/s.

Explanation:

Given:

The initial velocity of the bike = 32 m/s

The rate of acceleration of the bike = 3 ms^2

Distance covered by the bike  = 40 m

To find:

The final velocity of the bike.

Solution:

The initial velocity of the bike = u = 32 m/s

The rate of acceleration of the bike = a = 3 ms^2

Distance covered by the bike = s = 40 m

The final velocity of the bike = v

Using the third equation of motion, which is written as :

[tex]v^2-u^2=2as\\v^2-(32m/s)^2=2\times 3m/s^2\times 40m\\v^2-1024 m^2/s^2=240 m^2/s^2\\v^2=240 m^2/s^2+1024 m^2/s^2\\v^2=1264 m^2/s^2\\v=35.55 m/s[/tex]

The  bike's velocity after covering 40 m distance is 35.55 m/s.

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Answer: By electromagnetic waves that transfer heat and light energy

Explanation: electromagnetic waves travels through space it cant be radio waves use electromagnetic waves so they can travel through spac too but with the help of  electromagnetic waves.

please give brainliest, tell if right or wrong

Thanks have a good day :)!

Light and heat energy from sun reach earth by electromagnetic waves that transfer heat and light energy.

The electromagnetic radiation consists of waves made up of electromagnetic field which are capable of propogating through space and carry the radiant electromagnetic energy.

The radiation are composed of electromagnetic waves which are synchronized oscillations of electric and magnetic fields . They are created due to change which is periodic in electric as well as magnetic fields.

In vacuum ,all the electromagnetic waves travel at the same speed that is with the speed of air.The position of an electromagnetic wave in an electromagnetic spectrum is characterized by it's frequency or wavelength.They are emitted by electrically charged particles which undergo acceleration and subsequently interact with other charged particles.

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Gravitational potential energy is the energy stored in an object as the result of its vertical position or height. It can be calculated as its weight times the height. This is:

[tex]\boxed{U_g=W\cdot h=mgh}[/tex]

Where:

Solving for the h:

[tex]h=\dfrac{U_g}{mg} = \dfrac{35944\;J}{310\;kg\cdot 9.8\;m/s^2} = 11.8\;m[/tex]

Answer:

 F = mg /μ

Explanation:

For this exercise we define a coordinate system with the horizontal x axis and the vertical y axis, let's write the equilibrium equations for each axis

X axis

         F -N = 0

          F = N

Y axisy

         fr - W = 0

         fr = W                (2)

the force and touch have the expression

           fr = μ N

we substitute

          fr = μ F

we substitute in 2

         μ F = m g

          F = mg /μ

Answer:

[tex]s = 414.7 m\\[/tex]

Explanation:

The relationship between the linear distance covered by an object and its angular displacement is given by the following formula:

s = rθ

where,

s = distance traveled on road = ?

r  radius of tires = diameter/2 = 2.2 m/2 = 1.1 m

θ = angular displacement = (60 rev)(2π rad/1 rev) = 377 rad

Therefore,

[tex]s = (1.1 m)(377 rad)\\s = 414.7 m[/tex]

Answer: an element is a substance that cannot be broken down. it can’t be chemically decomposed into a different substance. elements are made up of just one atom

Explanation:

Answer:

1620000J

Explanation:

Given parameters:

Resistance  = 24ohm

Current  = 5A

Time  = 45min

Unknown:

Work done = ?

Solution:

Electrical work done is given as the product of power with time;

  Electrical work done  = power x time

     Power  = I²R

 Electrical work done  = I²R x time

Convert the given time to seconds;

          1min  = 60s

          45 min  = 45 x 60  = 2700s

Now,

  Work done  = 5² x 24 x 2700 = 1620000J

Answer:

By a factor of 2

Explanation:

The angular displacement would change by a factor of 2.

The angular acceleration is represented by the formula

α = Δw / Δt, where

α = angular acceleration

Δw = change in velocity.

Δt = change in time taken

The angular displacement is given by the relation

s = rθ

s = arc length

r = distance

θ = angular displacement

We all know that velocity is the ratio of displacement and time, thus,

v = s/t

Angular acceleration on the other hand says that

α = w/t, substitute w for v, we have

α = s/t ÷ t

α = s/t * 1/t

α = s/t²

We see here that multiplying the acceleration by 2 will only be balanced by increasing the displacement by the same number, 2 in this case

Answer:

What is the magnitude of the centripetal acceleration of a car following a curve of radius 500 m at a speed of 25.0 m/s (about 90 km/h)? Compare the acceleration with that due to gravity for this fairly gentle curve taken at highway speed. See Figure 2a.

Strategy

Because v and r are given, the first expression in

a

c

=

v

2

r

;

a

c

=

r

ω

2

a

c

=

v

2

r

;

a

c

=

r

ω

2

is the most convenient to use.

Solution

Entering the given values of v = 25.0 m/s and r=500 m into the first expression for ac gives

a

c

=

v

2

r

=

(

25.0

m/s

)

2

500

m

=

1.25

m/s

2

a

c

=

v

2

r

=

(

25.0

m/s

)

2

500

m

=

1.25

m/s

2

.

Discussion

To compare this with the acceleration due to gravity (g = 9.80 m/s2), we take the ratio of

a

c

g

=

(

1.25

m/s

2

)

(

9.80

m/s

2

)

=

0.128

a

c

g

=

(

1.25

m/s

2

)

(

9.80

m/s

2

)

=

0.128

. Thus, ac=0.128 g and is noticeable especially if you were not wearing a seat belt.

Explanation:

Answer:

44 m

Explanation:

Given that,

Horizontal velocity of the ball, u = 40 m/s

It is 6 m above the level field.

We need to find the distance covered by the ball when move horizontally before striking the ground. Let it is d.

Firstly, we will find time taken for the ball to hit the ground. Using second equation of motion as follows :

[tex]s=ut+\dfrac{1}{2}at^2[/tex]

Put u = 0 and a = g

[tex]s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 6}{9.8}} \\\\t=1.1\ s[/tex]

No finding the horizontal distance as follows :

d = ut

d = 40 m/s × 1.1 s

d = 44 m

So, the ball will move 44 m horizontally before striking the ground.

Answer:

Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny, dense, positively-charged nucleus. Based on these results, Rutherford proposed the nuclear model of the atom.

In the early 1900s, scientists thought that an atom consisted of a positive substance with negative charges scattered throughout the substance, but Rutherford explains that the positive charge is present at the center while the negative charges are present around it in the form of clouds.

There are various models that tried to explain the atomic model, and one  of that  Rutherford model is one in which he explains the model using the gold foil, which he then bombarded with the alpha particles. some of the particles that came back, while some passed through it by making some angles, and from this he concluded that the positive charge remains in the center while the negative is displaced.

Hence, in the early 1900s, scientists thought that an atom consisted of a positive substance with negative charges scattered throughout the substance, but Rutherford explains that the positive charge is present at the center while the negative charges are present around it in the form of clouds.

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Answer:

Atoms of elements in the same group of the periodic table share the same ELECTRONS

Explanation:

May I have brainliest please? :)

Answer:

Accurate

Explanation:

Accuracy deals with the nearness of the measured values to the true value.

Precision is the ability to reproduce a certain result in a repeated fashion.

The reading is not precise because, the same weight is not reproduced. Different values of weight was reported from each of the measurement process.

Answer: .36 m

Explanation:

The distance that the force is exerted over is equal to 0.3625 meter.

Given the following data:

To calculate the distance that the force is exerted over, we would apply the law of conservation of energy.

According to the law of conservation of energy, the work done by an external force equals the change in kinetic energy for the motion of the tennis ball hit by the racket.

Mathematically, this is given by this expression:

[tex]Work\;done = \Delta K.E = Fd[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]29 = 80 \times d\\\\d=\frac{29}{80}[/tex]

Distance, d = 0.3625 meter.

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Answer:

39975kgm/s due east

Explanation:

Given parameters:

Mass of the blimp  = 533kg

Velocity  = +75m/s due east

Unknown:

Momentum of the body  = ?

Solution:

The momentum of a body is the amount of motion it posses.

 Momentum is the product of mass and velocity;

  Momentum = mass x velocity

  Insert the parameters and solve;

    Momentum  = 533 x 75  = 39975kgm/s

The momentum of the body is 39975kgm/s due east

The momentum of a 533 kg blimp moving east at +75 m/s is 39,975kgm/s.

Momentum of a body can be calculated by multiplying the mass of the substance by its velocity. That is;

Momentum (p) = mass (m) × velocity (v)

According to this question, a 533 kg blimp is said to be moving east at +75 m/s. The momentum is calculated thus:

Momentum = 533 × 75

Momentum = 39,975kgm/s.

Therefore, momentum of a 533 kg blimp moving east at +75 m/s is 39,975kgm/s

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