If the plane travels at 600 km/h for 2 hours, how far has it traveled?

Answer:

The pressure is [tex]P_2 = 1.84 \ a.t.m[/tex]

Explanation:

From the question we are told that

   The first  volume of  is  [tex]v_1 = 3.5 \ L[/tex]

   The first  pressure is  [tex]P_1 = 2.7 \ a.t.m[/tex]

   The first  temperature is  [tex]T_1 = 350 \ K[/tex]

    The  new temperature is  [tex]T_2 = 620 \ K[/tex]

     The  new volume is  [tex]V_2 = 9.1 \ a.t.m[/tex]

Generally according to the combined gas law we have that

      [tex]\frac{P_1 V_1 }{T_1 } = \frac{P_2 V_2 }{T_2 }[/tex]

=>  [tex]P_2 = \frac{P_1 * V_1 * T_2 }{T_1 * V_2 }[/tex]

=>    [tex]P_2 = \frac{ 2.7 * 3.5 * 620 }{ 350 * 9.1 }[/tex]

=>  [tex]P_2 = 1.84 \ a.t.m[/tex]

Answer:

The pressure on the wall is 9416.25 N/m²

Explanation:

Please see the attachments below

Answer:

[tex] \boxed{\sf Kinetic \ energy \ (KE) = 48 \ J} [/tex]

Given:

Mass (m) = 6 kg

Speed (v) = 4 m/s

To Find:

Kinetic energy (KE)

Explanation:

Formula:

[tex] \boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}[/tex]

Substituting values of m & v in the equation:

[tex] \sf \implies KE = \frac{1}{2} \times 6 \times {4}^{2} [/tex]

[tex] \sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 3 \times 16[/tex]

[tex] \sf \implies KE =3 \times 16[/tex]

[tex] \sf \implies KE = 48 \: J[/tex]

Answer:

(a) the current will flow in opposite direction

(b) the current needed is 33.25 A

Explanation:

(a) At the center of the two parallel wires, the two wires will have the same magnitude of magnetic field. In order to have a non a zero value of magnetic field at the center, the field must be in the same direction and the current will flow in opposite direction according to right hand rule.

(b) How much current is needed

Given;

distance between the two parallel wires, d = 9.5 cm = 0.095 m

magnitude of magnetic field at a point halfway between the wires, [tex]B_c[/tex] = 280 μT (This unit was corrected to obtain feasible current)

The magnetic field at distance R due to an infinite wire is given by;

[tex]B = \frac{\mu_o I}{2\pi R}[/tex]

At the center of the wire, [tex]B_c = 2B[/tex]

[tex]B_c = 2(\frac{\mu_o I}{2\pi R} )\\\\B_c = \frac{\mu_o I}{\pi R}[/tex]

where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

R is the center point between the wires, R = d/2 = 0.095m / 2 = 0.0475 m

I is the current needed

[tex]B_c = \frac{\mu_o I}{\pi R} \\\\I = \frac{B_c \pi R}{\mu_o} \\\\I = \frac{280* 10^{-6}*\pi *0.0475}{4\pi *10^{-7}} \\\\I = 33.25 \ A[/tex]

Answer:

a. [tex]3.04\times 10^{-8}m[/tex]

b. = 40 km/ million years

Explanation:

The computation is shown below;

According to the question, Data provided in the question

Average speed = 4.0 cm / per year

Distance move in 1 second at this speed

Based on the above information

a. For distance move in 1 second is

As we know that

[tex]d_1 = v_g \times t\\\\ = 4\ cm \times \frac{1}{100\times 365.25\times 3,600} \times 1\s\\\\= 3.04\times 10^{-8}m[/tex]

b. For speed per kilometer per million years is

[tex]v_1 = 4\times \frac{10^6}{10^5} \\\\[/tex]

= 40 km/ million years

Answer:

The velocity is  [tex]v_x = 0.356 \ m/s[/tex]

Explanation:

From the question we are told that

   The  mass is  [tex]m = 1.10 \ kg[/tex]

   The  spring constant is  [tex]k = 18 \ N/m[/tex]

   The  speed is [tex]v = 40 \ cm / s = 0.4 m/s[/tex]

    The  position considered is  x =  0.45 A  

Here A is the amplitude which is mathematically represented as

     [tex]A = v * \sqrt{\frac{m}{k} }[/tex]

=>     [tex]A = 0.4 * \sqrt{\frac{1.10}{18 } }[/tex]

=>     [tex]A = 0.0989 \ m[/tex]

So     [tex]x = 0.45 * 0.0989[/tex]

=>     [tex]x = 0.045 \ m[/tex]

Generally the speed at  x  is mathematically represented as

      [tex]v_x = \sqrt{ \frac{k}{m} * [A^2 - x^2 ]}[/tex]

=>    [tex]v_x = \sqrt{ \frac{18}{ 1.10} * [0.0989^2 - 0.045^2 ]}[/tex]

=>    [tex]v_x = 0.356 \ m/s[/tex]

Answer:

a) A = 4.0 m , b)   w = 3.0 rad / s , c)  f = 0.477 Hz , d) T = 20.94 s

Explanation:

The equation that describes the oscillatory motion is

          x = A cos (wt + fi)

In the exercise we are told that the expression is

          x = 4.0 cos (3.0 t + 0.10)

let's answer the different questions

a) the amplitude is

         A = 4.0 m

b) the frequency or angular velocity

         w = 3.0 rad / s

c) angular velocity and frequency are related

          w = 2π f

           f = w / 2π

           f = 3 / 2π

           f = 0.477 Hz

d) the period

frequency and period are related

           T = 1 / f

           T = 1 / 0.477

           T = 20.94 s

e) the phase constant

          Ф = 0.10 rad

f) velocity is defined by

          v = dx / dt

         v = - A w sin (wt + Ф)

speed is maximum when sine is + -1

         v = A w

          v = 4 3

          v = 12 m / s

g) the angular velocity is

          w² = k / m

          k = m w²

          k = 1.2 3²

          k = 10.8 N / m

h) the total energy of the oscillator is

          Em = ½ k A²

           Em = ½ 10.8 4²

          Em = 43.2 J

i) the potential energy is

           Ke = ½ k x²

for t = 0 x = 4 cos (0 + 0.1)

               x = 3.98 m

j) kinetic energy

           K = ½ m v²

for t = 00.1 ²

    v = A w sin 0.10

    v = 4 3 sin 0.10

    v = 1.98 m / s

Answer:

 λ =365.4 nm

Explanation:

Boh's atomic model of the Hydrogen atom the energy of each level is

        Eₙ = - 13.606 / n²

where the synergy is in electonvotes and the value of E₀ = 13.606 eV is the energy of the base state of hydrogen.

An atomic transition occurs when an electron goes from an excited state and joins everything of lower energy.

                 ED = 13.606 (1 / n₀² - 1 /[tex]n_{f}^{2}[/tex])

we are going to apply this relationship to answer slash.

At the beginning of the studies of atomic transitions, each group did not consider having a different name

name        Initial state

Lymman         1

Balmer           2

the final state is any other state sta the continuum that corresponds to n = inf

Let's look for the highest energy of the Balmer series

              ΔE = 13.606 (1/2² - 1 /∞)

              ΔE = 3.4015 eV

Let's use the Planck relation for the energy

                E = h f = h c /λ

                λ = h c / E

Let's reduce the energy to J

              E = 3.4015 eV (1.6 10⁻¹⁹ J / 1 eV) = 5.4424 10⁻¹⁹

            λ = 6.63 10⁻³⁴  3 10⁸ / 5.4424 10⁻¹⁹

            λ = 3.654 10⁻⁷ m

            λ = 3,654 10⁻⁷ m (10⁹ nm / 1m)

            λ =365.4 nm

this eta radiation in the ultraviolet range

Answer:

0.2871 kg m/s

Explanation:

p = mv

convert 33g into kg (0.033)

mulitply byt 8.7 to get 0.2871

Answer:

The work done to lift the counterweight equals the potential energy acquired

Explanation:

since this is vertically applied force on the counterweight, and the distance the force is displacing the counterweight is in the same direction as the applied force, it equals the gained potential energy

Answer:

Explanation:

Given the simultaneous equation,

3C+4D=5  .............. 1

2C+5D=2 ............... 2

Solving for the value of C and D using substitution method.

From equation 1;

3C = 5-4D

Divide both sides by 3

3C/3 =  (5-4D)/3

C = (5-4D)/3 .... 3

From equation 2:

2C+5D=2

5D = 2-2C

Divide both sides by 5;

5D/5 = 2-2C/5

D = (2-2C)/5 ..... 4

Substitute equation 4 into 3;

C = 5-4{(2-2C)/5}/3

C = [5 - (8-8C/5)]/3

C = [25-(8-8C)/5]/3

C = (17+8C)/15

15C = 17+8C

15C-8C = 17

7C = 17

C = 17/7

Substitute C = 17/7 into equation 4 to get the value of D

D = (2-2(17/7))/5

D = (2-34/7)/5

D = 14-34/35

D = -20/35

D = -4/7

Hence the value of C = 17/7, D = -4/7

Answer:

increase the tension on the hose and shake the end fewer times per second.

Explanation:

This is because Tension of the rope is directly proportional to wavelength and inversely proportional to the frequency ( shakes per second) so increasing tension increases wavelength and vice versa

Wavelength= Tension/ frequency

The most efficient way for her to increase the wavelength is to increase the rate of shaking the rope per second.

Wavelength measures the distance of wave that occur between one crest and another crest.

To increase the wavelength the rope end should be shaked in a number of time per second this will help build up tension in the rope.

Therefore, she should increase the rate of shaking the rope per second.

Learn more on wavelength here,

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Answer:

Therefore, electron will have a longer de Broglie Wavelength.

Explanation:

The de Broglie wavelength is given by the following formula:

λ = h/mv

where.

λ = de Broglie wavelength

h = Plank's Constant

m = mass of the particle.

v = speed of the particle

Since, the speed of both electron and proton is same and Plank's constant is also a constant. Therefore, the de Broglie wavelength depends solely upon the mass of electron and proton, as follows:

λ ∝ 1/m

It shows that wavelength is inversely proportional to the mass of particle.

Since, the mass of electron is less than the mass of proton.

Therefore, electron will have a longer de Broglie Wavelength.

Answer and Explanation: When tossing a ball up in the air, the forces acting on the ball are due to Gravity, which is defined by gravitational acceleration on that location on Earth (approximately 9.8 m/s²) multiplied by mass of the ball; Force of thrown, i.e., the force you threw the ball and air resistance force, which is proportional to the square of the ball's through the air and the ball's cross section area. To facilite calculations, air resistance force is normally ignored.

Answer:

weight and drag

Explanation:

Answer:

The  work function is  [tex]\phi = 2.46 \ eV[/tex]

Explanation:

From the question we are told that

    The light energy is  [tex]E = 3.56 eV[/tex]

     The  stopping voltage is  [tex]V = 1.10 \ V[/tex]

Generally work function is mathematically represented as

      [tex]\phi = E - KE[/tex]

Where KE is the kinetic energy of the ejected electron and it is mathematically represented as

         [tex]KE = V * e[/tex]

Where  e is the charge on the electron

So  

        [tex]KE = 1.10eV[/tex]

Thus  

        [tex]\phi = 3.56eV - 1.10 eV[/tex]

=>      [tex]\phi = 2.46 \ eV[/tex]

Answer:

a) 0.22 m/s

b) 531.67 N

c) 508.81 J

d) 38.72 J

Explanation:

the mass of the astronaut = 121 kg

astronaut's push of speed = 2.9 m/s

mass of the space capsule = 1600 kg

a) according to the conservation of momentum, the summation of the total momentum in a system must be equal to zero.

let us take the direction of the astronaut as positive.

Astronaut's momentum p = mv

where

m is the mass

v is the velocity

momentum p = 121 x 2.9 = 350.9 kg-m/s

The space capsules momentum = mv

==> 1600 x (-v) = -1600v    this is because the space capsule moves in the opposite direction to the astronaut.

according to conservation of momentum

350.9 + (-1600v) = 0

350.9 = 1600v

v = 350.9/1600 = 0.22 m/s

b) magnitude of the force F is the rate of change of momentum.

The astronaut and the space capsule both change momentum from 0 to 350.9 kg-m/s. In 0.66 seconds, the force will be

F = [tex]\frac{m(v - u)}{t}[/tex]

where

u is their initial velocity = 0 m/s

where v = 2.9

t = 0.66

substituting, we have

F = [tex]\frac{121(2.9 - 0)}{0.66}[/tex] = 350.9/0.66 = 531.67 N  this same force is experienced by the space capsule

c) Kinetic energy of the astronaut = [tex]\frac{1}{2} mv^{2}[/tex]

m is the mass = 121 kg

v is the velocity = 2.9 m/s

KE = [tex]\frac{1}{2}*121*2.9^{2}[/tex] = 508.81 J

d) Kinetic energy of the space capsule = [tex]\frac{1}{2} mv^{2}[/tex]

KE = [tex]\frac{1}{2}* 1600* 0.22^{2}[/tex] = 38.72 J

Answer:

The height of the object is 50 feet

Explanation:

Given that:

The path of an object projected at a 45 degree angle with initial velocity of 80 feet per second is given by the  function  [tex]h (x) =\dfrac{-32}{(80)^2}x^2+x[/tex]

where;

x  is the horizontal distance traveled and  h(x) is the height in feet.

The objective is to use the TRACE feature of your calculator to determine the height of the object when it has traveled 100 feet away horizontally.

Before then;

If the function [tex]h (x) =\dfrac{-32}{(80)^2}x^2+x[/tex]

and x = 100

then :

[tex]h (x) =\dfrac{-32}{(80)^2}(100)^2+100[/tex]

[tex]h (x) =\dfrac{-32}{6400} \times 10000+100[/tex]

[tex]h (x) =- 0.005 \times 10000+100[/tex]

[tex]h (x) =- 50+100[/tex]

h(x) = 50 feet

Using the TRACE CALCULATOR,

In your Trace calculator;

input Y = X - 32 X^2/(80)        this  because in the calculator Y denotes h(x)

Now over to the WINDOW

set the window as follows:

Xmin = 0

Xmax = 200

Xsc1 =1

Ymin = 0

Ymax = 50

Ysc = 1

Xres = 1

After that, click on the graph key and an output will display as seen in the image below.

Therefore, the show the value of Y which we earlier said it denotes the h(x) = 50 feet

This question is incomplete, the complete question is;

When an auditorium has a solid wall, sound waves will tend to perfectly reflect off the wall (i.e. with a 180o phase change). If listening to music, as from an orchestra, the incoming and reflected waves will interfere with each other. For a listener sitting 0.5 m from the wall, what is the lowest frequency which gets suppressed by this interference? Use vsound=330 m/s.

Answer: f = 165 Hz

the lowest frequency which gets suppressed by this interference is 165 Hz

Explanation:

For a reflected wave (out of phase), the path difference between the incoming and reflected wave should be equal to the half integral multiple of wavelength.

r₂ - r₁ = ( m + 1/2) λ/2

r₂ is the distance from the source to observer via reflection

r₁ is distance from source to observer

here r₂ would travel an additional distance of 0.5 m due to reflection that straight approaching wave.

Therefor to have minimum/lowest possible frequency, we say m = 0

we substitute

0.5 = ( 0 + 1/2 ) λ/2

λ = 2m

The frequency would be

f = Vsound / λ

f = 330 / 2

f = 165 Hz

Therefore the lowest frequency which gets suppressed by this interference is 165 Hz

Explanation:

The total displacement is 3 miles

What is displacement?

Simply put it is the sum total of the changes in position of an object from it initial position to it final position, It is a vector quantity and has a direction and magnitude.

In our example the displacement the total points of movement can be annotated as

From A to B to C

From A to B= 1 mile

From B to C= 1 miles

Displacement is 1 + 2= 3 miles

Answer:

C) three

Explanation:

Let gram of gold required be m . Let temperature change in both be Δ t .

heat absorbed = mass x specific heat x change in temperature

for copper

heat absorbed = 1 x .385 x Δt

for gold

heat absorbed = m x .129 x Δt

So

m x .129 x Δt = 1 x .385 x Δt

m = 2.98

= 3 g approximately .

Answer:

In this process, the pressure increases by a factor of 2.

Explanation:

For an isothermal process, the temperature remains constant throughout the process.

Also, PV = constant

It means that there is an inverse relationship between pressure and volume of the gas.

If the volume is decreased by a factor of 2, the pressure increases by a factor of 2. Hence, the correct option is (c).

Answer:A is the correct answer

Explanation:

Answer:

D

Explanation:

pressure change have nothing to do with the spontaneity.

Entropy change , enthalpy change , temperature have roles in deciding spontaneity.

Calculate the acceleration ,a .

s = ut + 1/2 at²

According to the second equation of motion, we have

s = ut + 1/2 at²

★Substituting the values in the above formula,we get:

⇒ 16 = 8 × 4 + 1/2 × a × 4

⇒ 16 = 32 + 2a

⇒ 2a = 16 - 32

⇒ 2a = -16

⇒ a = -16/2

⇒ a = -8 m/s²

Hence,the acceleration is -8 m/s² .

Answer:

   k = -3.1450 10⁻⁴  s⁻¹

Explanation:

In this exercise we are given the equation that describes the cooling process

        dT / dt = k (T -)

Let's solve is this equation,

        dT / (T-T_ {e}) = k dt

change of variable for integration

       T -T_{e} = T ’

       dT = dT '

       ∫ dT ’/ T’ = k  ∫ dt

we integrate

        ln T ’= k t

we change to the initial variables

        ln (T - T_{e}) = k t

Let's evaluate from the lower limit T = T for t = 0 to the upper limit T = T₀ for time t

       ln (T₀ -T_{e}) - ln (T -T_{e}) = k (t-0)

we simplify

       ln (T₀ -T_{e} / T -T_{e}) = k t

       k = ln (T₀ -T_{e})  / (T-Te) / t

In the exercise they indicate that the temperature T = 205 F, the ambient temperature is T_{e} = 70F, the temperature to which T₀ = 200 F falls in a time t = 2 min = 120 s

Let's calculate

           k = ln [(200- 70) / (205 -70)] / 120

           k = -0.0377403 / 120

           k = -3.1450 10⁻⁴  s⁻¹

Answer:B

Explanation: I just did it on a p e x

273 K gives the object's temperature in the SI unit therefore the correct answer is option B

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation. Any additional quantity of that type can be stated as a multiple of the measurement unit.

The International System of Units, sometimes known as the SI system of units, is the most frequently used and acknowledged system of units in use nowadays. There are three additional units and 7 SI basic units in this system of SI units.

The three supplemental SI units are radian, steradian, and becquerel, whereas the base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole. These base units can be used to create all other SI units.

Thus,273 K gives the object's temperature in the SI unit therefore the correct answer is option B

Learn more about the unit of measurement from here

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Answer:

633nm

Explanation:

Given the following :

Number of lines per centimeter(N) = 7000

Angle θ = 62.4°

Order (n) = 2

If grating element = d

Wavelength (λ) = (d* SinΘ) / 2

If number of lines = 7000 per cm

Converting to metre :

100 cm = 1m

7000 lines per 1 cm

Number of lines per m:

7000 lines * 100 = 700,000 lines per meter

Recall :

d = reciprocal of N

d = 1 / 700,000

d = 0.00000142857

Substituting into (λ) = (d* SinΘ) / 2

λ = (0.00000142857 * Sin 62.4°) / 2

λ = 0.00000126600 / 2

λ = 0.000000633002

λ = 0.000000633

λ = 633 × 10^-9 m = 633nm

Answer:

The speed of the car just before braking is 23.66 m/s.

Explanation:

Given;

mark of the skid, d = 80 m

deceleration of the car, a = 3.5 m/s²

To determine the speed of the car just before braking, we apply the following kinematic equation;

[tex]v^2 = u^2 + 2ad\\\\v^2 = 0 + 2(3.5)(80)\\\\v^2 = 560\\\\v= \sqrt{560}\\\\v = 23.66 \ m/s[/tex]

Therefore, the speed of the car just before braking is 23.66 m/s.

Answer:

Energy will be reduced by 0.3

Explanation:

Given that E = 1/2 QV

So if V is increased by 6

=> V = E/ 3Q

So the energy will be divided by a factor 1/3 of be reduced by 0.3

Answer:

Therefore, the brick appears to have an additional force pushing it upward.

Explanation:

When a brick is submerged in the water, it has two forces acting upon it. One force is the gravitational force or the weight of the brick, that acts downward. The weight force also acts on the brick when it is not in water. But, in water an additional force acts on the brick. This additional force is named as Buoyant Force. This force is equal to the weight of the water displaced by the brick. And this Buoyant Force acts on the brick in the upward direction. The formula for this force is given as follows:

Buoyant Force = (Density of Water)(Volume of Water Displaced)(g)

Therefore, the brick appears to have an additional force pushing it upward.