If the ocular lens magnifies a specimen 10x, and the objective lens used magnifies the specimen 35x. What is the total magnification being used to observe the specimen?

Answers

Answer 1

Answer:

350x^2

Explanation:

I'm assuming you're saying you're using them together, like stacking them on top of each other, so if that's the case then this is a simple multiplication problem, which can be written as 10x(35x). Solve it and you get 350x^2.


Related Questions

Guys please help me I am dead confused

Answers

Answer:

A

Explanation

The diagram in A. contain a variable resistor which can be use to vary the pd from the 6v battery

An object with a mass 4.0 kg has a momentum of 64 kgm/s . How fast is the object traveling ?

Answers

Answer:

The object will travel at the speed of 16 m/s.

Explanation:

Given

Mass m = 4.0 kg Momentum p = 64 kgm/s

To determine

How fast is the object traveling?

Important Tip:

The product of the mass and velocity of an object —  momentum.

Using the formula

[tex]p = mv[/tex]

where

m = massv = velcityp = momentum

Thus, in order to determine the speed of the object, all we need to do is to substitute p = 64 and m = 4 in the formula

[tex]p = mv[/tex]

[tex]64\:=\:4\times v[/tex]

switch the equation

[tex]\:4\times \:v\:=64[/tex]

divide both sides by 4

[tex]\frac{4v}{4}=\frac{64}{4}[/tex]

simplify

[tex]v=16[/tex] m/s

Therefore, the object will travel at the speed of 16 m/s.

Is it resistant to mud fire ​

Answers

Dirt that you can not burn typically does no longer have any materials that are flammable at decrease temperatures. Mostly due to the fact it is full of water and non-burnable minerals. But a lot of what's in grime can certainly burn if it is dried. Dirt is made of many unique things.

yes

Explanation:

since they are extremely dense they lack the ability to trap air due to its structure

A horse has a momentum of 25 kg*m/s and a velocity of 2.5 m/s. What is the horse mass?

Answers

Answer:  10 kg

==================================================

Work Shown:

We have these variables

p = momentum = 25 kg*m/sm = mass = unknownv = velocity = 2.5 meters per second

Solving for the mass gets us...

p = m*v

25 = m*2.5

25/2.5 = m

10 = m

m = 10

The mass of the horse is 10 kg.

6th grade science pls help

Answers

Answer:

D

Explanation:

I hope you get a good grade!

An object moving in the air at a constant speed is considered to be in a balanced state. Explain Why

Answers

Answer:

and there is no friction

Explanation:

An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force. An object in motion with a velocity of 2 m/s, East will (in the absence of an unbalanced force) remain in motion with a velocity of 2 m/s, East. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force. Objects resist changes in their velocity.

An outfielder throws a baseball to home plate with a velocity of 27 m/s at 35o. It is caught by the first baseman. How long was it in the air

Answers

Answer:

Explanation:

Initial velocity of the ball = 27 m /s .

Its vertical component = 27 sin 35 = 15.48 m /s

Considering vertical displacement to the top point ,

initial velocity u = 15.48 m /s

acceleration due to gravity g = 9.8 ,

velocity at the top v = 0

v = u - gt  

0 = 15.48 - 9.8 t

t = 15.48 / 9.8 = 1.579 s

So time of ascent = 1.579 s

Similarly , time of descent = 1.579

Total time of flight = 2 x 1.579

= 3.16 s

An island reports that in the year 2000 there were 240 babies born. That same year, 100 individuals died.
What is the growth rate for this island?(Show your work and indicate if it is positive or negative.)

Answers

Answer:

+ 140

Explanation:

You can show the natural growth rate by subtracting the death rate from the birth rate during one year and converting this into a percentage.

Here it would be:

240 - 100 = + 140

// if you want to convert it to percentage, you need to know the size of the population

it would be

140 / (population size) * 100 %

What is a Sport car transformation

Answers

Answer:

when a car transforms...

Explanation:

Explanation:

Vivimos en un puente en lo que el diseño de coches se refiere, consecuencia de la gran disrupción de la automación que ocurriría en los próximos años.

What is the only part in our body we do not stretch?

Answers

Answer:

The quadriceps consists of four muscles: the skinny rectus femoris and the three huge “vasti” — vastus lateralis/intermedius/medialis. The vasti are only elongated by knee flexion, which is limited to about 120˚ when the calf hits the hamstrings. The vasti cannot be stretched strongly.

Answer:Masseter and temporalis

Why it’s unstretchable: The jaw can only open so far.

Why it’s a dang shame: Jaw tension is epidemic, and trigger points in these muscles cause a wide array of strange face and head pains, including toothaches, headaches, and earaches.

A 100-newton object is lifted 100 meters in 100 seconds. What is the
power generated in this situation?

Answers

Power equation: Work / time

Work = F * distance
W = 100N * 100

10000 / 100 = 100

The power generated is 100 watts.

In a bar magnet the magnetic force seems to come from each end. The ends of a bar magnet are
called the___
What one word completes the sentence?

Answers

Answer: poles

North Pole and South Pole? I hope this help

If Jay pushes on a box with a force of 20 N to the right and Bradley pushes on a box with a force of 15 N to the left, what is the net force on the box?

Answers

Answer:

Net force = 5N

Explanation:

Jay = 20N to the right

Bradley = 15N to the left

To find the net force;

Since the forces are being applied to the box in opposite direction i.e acting in opposite direction, we would subtract them.

Net force = 20 - 15

Net force = 5N

Therefore, the net force on the box is 5 Newton.

the unit of acceleration is derived unit why​

Answers

Answer:

Mass is a base unit, acceleration is a derived unit calculated as a function of length and time which are both base units. Any unit definition that is a function of more basic units is considered a derived unit.

A concrete dam holds back a large reservoir of water
potential or kinetic energy

Answers

Answer:

The water in a reservoir behind a hydropower dam is another example of potential energy. The stored energy in the reservoir is converted into kinetic energy as the water flows down a large pipe called a penstock and spins a turbine.

Explanation:

Hope this helps :))

A concrete dam holds back a large reservoir of water potential energy, the stored potential energy is converted into the kinetic energy which is converted into mechanical energy and then further converted into electrical energy.

What is hydropower?

A dam or other construction that alters the natural flow of a river or other body of water is used to generate hydropower, often known as hydroelectric power.

In order to generate energy, hydropower uses the perpetual, never-ending water cycle, which uses water as a fuel and leaves no waste products behind. Although there are many different kinds of hydropower plants, they are always propelled by the kinetic energy of water moving downstream.

Thus, a concrete dam holds back a large reservoir of water potential energy.

To learn more about hydropower here, refer to the link given below ;

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#SPJ2

15. Which of the following is the correct electron configuration for neon (10Ne)?
A. 1s 2s22p
C. 184 2s2 3s2 2p?
B. 1s 2s2 3s2 2p4
D. 152 282 3s2p5​

Answers

Answer:

1s2,2s2,2p6 or (He) 2s2 2p6

1. How much electrical energy is needed to bring two charges Q1= 5.5 x 10-7C and Q2= 1.7 x 10-6 C from infinity to where they are 1 meter apart.

Answers

Answer:

The electrical energy needed is 8.415*10⁻³ N

Explanation:

Energy is the ability of a body to make changes or work.

By separating or joining two electric charges a distance (for example, a radius r) within their electric fields, you are taking away or giving the electric charges energetic potentials, relative to each other. By releasing these charges, they will attract or repel each other, releasing that acquired electrical energy.

In other words, electric potential energy is linked to the particular configuration of a conglomerate of point charges in a defined system.

That is, it calculates the capacity of an electrical system to carry out a task based exclusively on its position or configuration. So, it is a kind of energy stored in the system, or the amount of energy that it is capable of delivering.

Thus, a charge will exert a force on any other charge and the potential energy is the result of the set of charges.

The electric potential energy that has a point charge q in the presence of another point charge Q that are separated by a certain distance r is:

[tex]Ep=K*\frac{Q1*Q2}{r^{2} }[/tex]

where:

Ep is the electric potential energy. It is measured in Newton (N). Q1 and Q2 are the values ​​of the two point charges. They are measured in Coulombs (C). r is the value of the distance that separates them. It is measured in meters (m). K is the constant of Coulomb's law. For vacuum its value is approximately 9*10⁹ N*m²/C²

In this case:

Q1=5.5*10⁻⁷ CQ2=1.7*10⁻⁶ Cr=1 m

Replacing:

[tex]Ep=9*10^{9}\frac{N*m^{2} }{C^{2} } *\frac{5.5*10^{-7}C *1.7*10^{-6}C }{(1m)^{2} }[/tex]

Solving:

Ep= 8.415*10⁻³ N

The electrical energy needed is 8.415*10⁻³ N

The electrical energy is needed to bring two charges Q1 and Q2 from infinity to where they are 1 meter apart is 8.415 x 10⁻³ N.

What is the electric potential?

An electric potential can be defined as the amount of work or energy needed to move a charge from one point to another against the electrical field.

We know that in order to know electrical energy is needed to bring two charges Q1= 5.5 x 10⁻⁷C and Q2= 1.7 x 10⁻⁶ C from infinity to where they are 1 meter apart, we need to calculate electric potential energy between the two charged particles,

[tex]E_P = k\dfrac{Q_1Q_2}{d^2}[/tex]

Substitute the values,

[tex]E_P = 9 \times 10^9 \dfrac{5.5 \times 10^{-7} \times 1.7 \times 10^{-6}}{1^2}\\\\E_P = 8.415 \times 10^{-3}\rm\ N[/tex]

Hence, the electrical energy is needed to bring two charges Q1 and Q2 from infinity to where they are 1 meter apart is 8.415 x 10⁻³ N.

Learn more about Electrical Potential:

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How many straight edges does a cube have

Answers

12 is correct

Explanation: it's a cube

Answer:

12

Explanation:

Theoretically, what would be the mass of an object accelerated
to 100% the speed of light?

Answers

I know most of the answers will say infinity, but still this needs deeper look about its physical meaning and does it consider a practical logic?

Infinity usually used for something we could not measure, however the reality may be different!

The denominator of the equation would become 0 and the mass would become infinite if the mass's velocity ever surpassed the speed of light.

Speed of light and mass:

The amount of energy needed to accelerate an infinite mass would be infinite as well. The fact that light travels at the speed of c indicates that it has no rest mass.

When a mass particle approaches the speed of light, its energy grows and becomes infinite at that speed, which is why it can never be accelerated to that speed.

Experiments have confirmed this, and it has been demonstrated that nothing goes faster than the speed of light.

Find out more information about 'Speed of light'.

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Two charged spheres 10 cm apart attract each other with a force of 3.0 x 10^-6 N. What electrostatic force will result if both charges are doubled and the distance remains the same?

Answers

Answer:

The electrostatic force that will result if both charges are doubled and the distance remains the same is 6.0 * 10⁻⁶ N

Explanation:

Coulomb's law of  electricity states that the magnitude of the force of attraction or repulsion between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance of of separation between them.

In formula; F = KQ₁Q₂/d²

Using the formula for electrostatic force of attraction above to determine the force of between the two charged spheres

Let the charges be Q₁ and Q₂; distance of separation be d, K is a constant

Initially, F₁ = KQ₁Q₂/d² ---- (1)

F₁ = 3.0 * 10⁻⁶ N

when the charges are doubled, Q₁ = 2Q₁; Q₂ = 2Q₂; K and d remains constant

F₂ = 2KQ₁Q₂/d² ----(2)

Dividing equation (2) by (1) to find the ratio of their forces

F₂/F₁ = (2KQ₁Q₂/d²) / KQ₁Q₂/d²

F₂/F₁ = 2

Thus, F₂ is twice F₁.

Since F₁ = 3.0 * 10⁻⁶ N; F₂ = 2 * 3.0 * 10⁻⁶ N

F₂ = 6.0 * 10⁻⁶ N

Therefore, the electrostatic force that will result if both charges are doubled and the distance remains the same is 6.0 * 10⁻⁶ N

Electrostatic force is a force imposed by one charge on another as a result of the field.Electrostatic force will  be 12.0 x 10⁻⁶ N if both charges are doubled and the distance remains the same.

What is the electrostatic force?

It is a force imposed by one charge on another as a result of the field.

The electrostatic force produced by one line charge on another line charge separated by distance d is determined by the charge potency of each charge as well as the separation distance between them.

Hence the electrostatic force is given by  

[tex]\rm F=\frac{Kq_1q_2}{d^2}[/tex]

The given data in the question ,

d is the distance between the charge

F₁ is the electric force for case 1= 3.0 x 10⁻⁶ N

F₂ is the  electric force for case 2= ?

Conditions for case 2;

(q₁=2q₁),(q₂=2q₂),d₂=d₁

For case 1,

[tex]\rm F_1=\frac{Kq_1q_2}{d_1^2}[/tex]

For case 2,

[tex]\rm F_2=\frac{K(2q_1)(2q_2)}{d_1^2}[/tex]

[tex]\rm F_2=4\times\frac{Kq_1q_2}{d_1^2}\\\\\rm F_2=4F_1[/tex]

[tex]\rm F_2=4\times\frac{Kq_1q_2}{d_1^2}\\\\\rm F_2=4\times3.0\times 10^{-6}\\\\\rm F_2=12.0\times10^{-6}[/tex]

Hence electrostatic force will be 12.0 x 10⁻⁶ N.  if both charges are doubled and the distance remains the same.

To learn more about the electrostatic force refer to the link;

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pls help i’ll give brainliest if you give a correct answer!!

Answers

Answer:

C. The distance traveled by an object at a certain velocity.

Explanation:

YW!

Answer:

third option is the most accurate

The acceleration of an object is ____________________ related to the net force exerted upon it and _____________________ related to the mass of the object.

Answers

The acceleration of an object is directly related to the net force exerted upon it and inversely related to the mass of the object.


A ray diagram shows an object placed between 2F and F of a convex lens.

The image produced is
smaller than the object.

upright.

larger than the object.

virtual

Answers

Answer:

larger than object

Explanation:

the image formed will be on the opposite side of lens and magnified

Answer:

C

Explanation:

The center of gravity of the body is at________ position in state of unstable equilibrium. ​

Answers

Answer:

Highest.

Explanation:

This is because, in a state of unstable equilibrium, the center of gravity is at highest which as a result of when the body topples at it's base, there is a shift in the centre of gravity, and the centre of gravity shift position by moving towards the lower position and it does not return to it's former position again.

how was youll day still in school by the way.

Answers

My day is alright! I just finished school for the day.. and I’m excited for the weekend! How was your day?

Light described as what two things?

Answers

Answer:modeled as an electromagnetic wave. In this model, a changing electric field creates a changing magnetic field.

Explanation:

balance the equation
P + 02 → P205 ​

Answers

Answer:

4P + 502 → 2P205

Explanation:

Hence the above equation is balanced.

Explanation:

[tex] \underline{ \underline{ \large{ \text{Given \: chemical \: equation}}}} : [/tex]

[tex] \tt{P \: + O _{2} \: \: \: \: ➞ \: \: P_{2} \: O_{5}}[/tex]

Here , Multiply P2O5 by 2 and O2 by 5 to equalize oxygen :

[tex] \tt{P+ 5O_{2} \: \: ➞\: \: 2P_{2} \:O_{5}}[/tex]

Now , To equalize P atoms , Multiply P by 4

[tex] \boxed{ \large{\tt{ 4P + 5O _{2} \: ➞ \: \: \: \: 2P_{2} \: O_{5}}}}[/tex]

Here , On the left side we have 4P and On the right side ,we have 4P. Again , On the left side , we have 10 O and On the right side , we have 10 O. And yippie , we got the balanced chemical equation !!!

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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Determine the amount of work you would need to do in order to stop a 1100kg car with 1400J of kinetic energy.

Answers

Answer:

 W = -1400 J

Explanation:

Let's use the relationship between work and kinetic energy

           W = ΔK

             

kinetic energy is

            K = ½ m v²

therefore in this case

             K₀ = 1400 J

         

Thus

            W = 0 -1400

            W = -1400 J

The negative sign indicates that the work is done against the energy, that is, in the opposite direction to the movement

A 1-kg book is at rest on a desk. Determine the force the desk exerts on the book

Answers

Answer:

[tex]\displaystyle F_n = 9.8 \ N[/tex]

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Physics

Forces

SI Unit: Newtons N

Free Body Diagrams

Gravitational Force: [tex]\displaystyle F_g = mg[/tex]

m is mass (in kg)g is Earth's gravity (9.8 m/s²)

Normal Force: [tex]\displaystyle F_n[/tex]

Newton's Law of Motions

Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motionNewton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)Newton's 3rd Law of Motion: For every action, there is an equal and opposite reactionExplanation:

Step 1: Define

1 kg book at rest

Step 2: FBD

See Attachment

Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.

Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).

Step 4: Find Normal Force

Define Forces [Newton's Law of Motions]:                                                 [tex]\displaystyle \sum F = 0[/tex][Newton's Law of Motions] Substitute in forces:                                         [tex]\displaystyle F_g - F_n = 0[/tex][Newton's Law of Motions] [Addition Property of Equality] Isolate [tex]\displaystyle F_n[/tex]:     [tex]\displaystyle F_g = F_n[/tex][Newton's Law of Motions] Substitute in [tex]\displaystyle F_g[/tex]:                                               [tex]\displaystyle mg = F_n[/tex][Newton's Law of Motions] Rewrite:                                                             [tex]\displaystyle F_n = mg[/tex][Newton's Law of Motions] Substitute in variables:                                   [tex]\displaystyle F_n = (1 \ kg)(9.8 \ \frac{m}{s^2})[/tex][Newton's Law of Motions] Multiply:                                                             [tex]\displaystyle F_n = 9.8 \ N[/tex]

A hockey puck, with an initial velocity of 65 km/h [W], ricochets off the boards. After 0.76 s in contact with the boards, its final velocity is 47 km/h [E]. Determine the acceleration of the puck.

Answers

Answer:

 a = 40.937 m / s²

Explanation:

For this exercise let's use the relationship between momentum and momentum variation

          I  = Δp

          F t = m v_f - mv₀

          F = m (v_f -v₀) / t

let's reduce the magnitudes to the SI system

          v_f = 47 km / h (1000m / 1 km) (1h / 3600 s) = 13.056 m / s

          v₀ = - 65 km / h = -18.056 m / s

the negative sign is bearing the speed is west

let's calculate

          F = m (13.056 + 18.056) / 0.76

          F = m 40.937

now we can use Newton's second law

          F = m a

          m 40.937 = m a

          a = 40.937 m / s²

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