If the battery costs $75 and has a life of 300 charge-discharge cycles, what is the cost of the energy in dollars per kilowatt hour

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]Region\ A = 81218576[/tex]

Required

The acres owned by the government

The question is incomplete as the proportion (p) owned by the government is not given.

However, the formula to use is as follows:

[tex]Govt = p * Region\ A[/tex]

Assume the proportion is 28%, the equation becomes

[tex]Govt = 28\% * 81218576[/tex]

[tex]Govt = 22741201.28[/tex]

The acres owned by the government will be 22741201.28

Step-by-step explanation:

the graph should look something like this

Answer:

21 + x < 28

Step-by-step explanation:

27 is in fact greater than 28 if you where to input 6 into the x spot, this is the only one that's a true expression.

Step-by-step explanation:

given the geometric sequence 2, -4, 8, -16, ...

a1 = 2

r = -4/2 = -2

find : a9 and a15

solutions:

an = a1. r^(n-1)

=> a9 = 2. (-2)^(9-1)

= 2. (-2)^8

= 2. 2^8

= 2^9

= 512.

=> a15 = 2. (-2)^(15-1)

= 2. (-2)^14

= 2. 2^14

= 2^15

= 32,768

Step-by-step explanation:

Hey there!

The given geometric sequence is: 2, -4, 8, -16.

The;

a1 = 2

Common ratio (r) = T2/T1

= -4/2

= -2

Now;

Use general formula of geometric sequence;

[tex]tn = {a1.r}^{n - 1} [/tex]

Where, "a1" is first term, "n" is no.of terms and "r" is common ratio.

Then;

[tex]t9 = 2 \times { (- 2)}^{9 - 1} [/tex]

or, t9 = 2*256

Therefore, t9 = 512.

Again;

[tex]t15 = 2. { (- 2)}^{15 - 1} [/tex]

or, t15= 2*16384

Therefore, t15 = 32768.

Hope it helps!

Answer:

EXPLAINED ON THE ATTACHED

The percentage rate of change of the given functions is given by the

derivative of their natural logarithm.

Responses:

[tex]f(t) = 1.18^t[/tex]

[tex]g(t) = 2^{-2 \cdot t}[/tex]

[tex]h(t) = 1.19^{\frac{t}{10} }[/tex]

[tex]k(t) = 0.13^t[/tex]

The percentage rate of change can be presented as follows;

[tex]Percentage \ rate \ of \ change = \mathbf{100 \times \dfrac{d}{dt} ln \left(f(t)\right)}[/tex]

[tex]f(t) = \mathbf{ 1.18^t} \ gives;[/tex]

[tex]g(t) = \mathbf{2^{-2 \cdot t} }\ gives;[/tex]

[tex]100 \times \dfrac{d}{dt} \left( ln \left(2^{-2 \cdot t}\right) \right) = \mathbf{ 100 \times -2 \times ln(2)} \approx \underline{ -138.6 \%}[/tex] , exponential decay

[tex]h(t) = \mathbf{1.19^{\frac{t}{10} } }\ gives;[/tex]

[tex]100 \times \dfrac{d}{dt} \left( ln \left(1.19^{\frac{t}{10} }\right) \right) = \mathbf{ 100 \times \dfrac{10 \cdot ln(1.19)}{100}} \approx 1.7 \%[/tex], exponential growth

[tex]k(t) = \mathbf{ 0.13^t} \ gives;[/tex]

[tex]100 \times \dfrac{d}{dt} \left( ln \left(0.13^t }\right) \right) = \mathbf{100 \times ln(0.13)}\approx -204 \%[/tex], exponential decay

Learn more about exponential functions here:

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Answer:

(a)

[tex]3 \sqrt{5} [/tex]

(b)

[tex] \frac{6}{ \sqrt{5} } [/tex]

Step-by-step explanation:

A(-3,0)

B(0,6)

[tex]d = \sqrt{{( - 3 - 0)}^{2} + {(0 - 6)}^{2} } = \sqrt{9 + 36} = 3 \sqrt{5} [/tex]

[tex]d = \frac{ax0 + by0 + c}{ \sqrt{ {a}^{2} + {b}^{2} } } [/tex]

2x-y+6=0

a=2, b=-1, c=6

x0=0, y0=0

[tex]d = \frac{6}{ \sqrt{4 + 1} } = \frac{6}{ \sqrt{5} } [/tex]

Answer:

A. Energy (weight)

Step-by-step explanation:

Mark me as brainiest

Answer: the answer is D. I took the test & got it right

Step-by-step explanation:

The expression is equivalent to 3/2 will be;

⇒ 3y/(2y - 6) + 9/(6 - 2y)

Option D is true.

What is an expression?

Expression in math is defined as the collection of the numbers, variables and functions by using signs like addition, subtraction, multiplication, and division.

Given that;

Equivalent expression is 3/2.

Now,

Let the expression is;

⇒ 3y/(2y - 6) + 9/(6 - 2y)

Solve the expression as;

⇒ 3y/(2y - 6) - 9/(2y - 6)

⇒ (3y - 9) / (2y - 6)

⇒ 3 (y - 3) / 2 (y - 3)

⇒ 3/2

So, The expression is equivalent to 3/2 will be;

⇒ 3y/(2y - 6) + 9/(6 - 2y)

Option D is true.

Learn more about the fraction visit:

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Answer:

26.31

Step-by-step explanation:

Use distance formula

d = [tex]\sqrt{(x_{2}-x_{1)^{2} + (y_{2}-y_ ^{1)^2} } }[/tex]

substitute in points and solve

d =  [tex]\sqrt{(7-3)^2 + (23-(-3))^{2} }[/tex]

d = [tex]\sqrt{4^{2}+26^{2} }[/tex]

d = [tex]\sqrt{16 + 676}[/tex]

d = [tex]\sqrt{692}[/tex]

d = 26.30589288

d = 26.31 rounded

Answer:

-0.80

1.66

0.26

2.56

-0.50

Step-by-step explanation:

The values are the probability values either to the right or left of a given z - value ;

The Z - values could be obtained using the standard normal distribution table or a calculator :

Using the Z probability calculator ;

Area to the left of z is 0.2119

1.)

P(z < z) = 0.2119

z = - 0.8

2.)

Area between - z and z = 0.9030

Area to the left of z = 0.9030 plus

Area to the right of z = (1 - 0.9030) / 2 = 0.097/2 = 0.0485

(0.9030 + 0.0485) = 0.9515

P(z < z) = 0.9515

z = 1.66

3.)

Area between - z and z = 0.2052

Area to the left of z = 0.2052 plus

Area to the right of z = (1 - 0.2052) / 2 = 0.7948/2 = 0.3974

(0.2052 + 0.3974) = 0.6026

P(z < z) = 0.6026

z = 0.26

D.)

The area to the left of z is .9948

P(Z < z) = 0.9948

z = 2.562

E.)

The area to the right of z is .6915.

P(Z < z) = 1 - 0.6915

P(Z < z) = 0.3085

z = - 0.5

Answer:

850/28=30 miles a gallon

Step-by-step explanation:

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Answer:

[tex]q=8.5[/tex]

Step-by-step explanation:

The ratio of the side lengths (AB) and (BC) is given. One is also given an expression for the side lengths of each of these sides. Set up a proportion to describe this scenario, then solve using cross products;

[tex]\frac{AB}{BC}=\frac{3}{4}[/tex]

Substitute,

[tex]\frac{60}{10q+15}=\frac{3}{4}[/tex]

Cross products,

[tex]\frac{60}{10q+15}=\frac{3}{4}[/tex]

[tex](60)(4)=(10q+15)(3)\\\\240=30q+45[/tex]

Inverse operations,

[tex]240=30q+45\\\\195=30q\\\\8.5=q[/tex]

Answer:

r = 30°

Step-by-step explanation:

According to the Exterior Angle Sum Theorem, the exterior angle, which is 90°, is equal to the 2 interior angles, which are 60° and r°. We know that the angle next to the exterior angle is 90°, and since all angle sums add up to 180°, r = 30°.

[tex]11. \: we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{7 + 11 + 13 + 6 + 8 + x}{6} = 8 \\ = > \frac{45 + x}{6} = 8 \\ = > 45 + x = 8 \: \times 6 \\ = > 45 + x = 48 \\ = > x = 48 - 45 \\ = > x = 2 \\ \\ 12. we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{2 + 5 + 1.3 + 2.2 + x}{5} = 1.8 \\ = > \frac{10.5 + x}{5} = 1.8 \\ = > 10.5 + x = 5 \times 1.8 \\ = > 10.5 + x = 9 \\ = > x = 9 - 10.5 \\ = > x = - 1.5 \\ [/tex][/tex]

This is the answer.

Hope it helps!!

Hi there!

[tex]\large\boxed{77m^2}}[/tex]

We can divide the figure into 3 rectangles.

Area of top rectangle:

5 × 5 = 25m²

Long rectangle:

14 × 3 = 42m²

Bottom rectangle:

2 × 5 = 10m²

Add up the areas:

10 + 42 + 25 = 77m²

Answer:

Sales tax: 402.80 Final cost: 5,702.80

Step-by-step explanation:

Sales price x sales tax rate = sales tax

5300 x .076 (7.6%) = 402.80

Sales price + tax = final cost

5300 + 402.80 = 5702.80

Answer:

P is maximum at I = 2

Step-by-step explanation:

Here is the complete question

The rate (in mg carbon/m³/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function P = 100I/(I² + I + 4) where I is the light intensity (measured in thousands of foot candles). For what light intensity P is a maximum?

To find the value of I at which P is maximum, we differentiate P with respect to I and equate it to zero.

So, dP/dI =  d[100I/(I² + I + 4)]/dI

= [(I² + I + 4)d(100I)/dI - 100Id(I² + I + 4)/dI]/(I² + I + 4)²

= [(I² + I + 4)100 - 100I(2I + 1)]/(I² + I + 4)²

= [100I² + 100I + 400 - 200I² - 100I]/(I² + I + 4)²

= [-100I² + 400]/(I² + I + 4)²

=  -100[I² - 4]/(I² + I + 4)²

Since dP/dI = 0,  -100[I² - 4]/(I² + I + 4)² = 0 ⇒ I² - 4 = 0 ⇒ I² = 4 ⇒ I = ±√4

I = ±2

Since I cannot be negative, we ignore the minus sign

To determine if this is a maximum point, we differentiate dP/dI. So,

d(dP/dI)/dI = d²P/dI² = d[-100[I² - 4]/(I² + I + 4)²]/dI

= [(I² + I + 4)²d(-100[I² - 4])/dI - (-100[I² - 4])d(I² + I + 4)²/dt]/[(I² + I + 4)²]²

= [(I² + I + 4)²(-200I) + 100[I² - 4]) × (2I + 1) × 2(I² + I + 4)]/(I² + I + 4)⁴

= [-200I(I² + I + 4)² + 200[I² - 4])(2I + 1)(I² + I + 4)]/(I² + I + 4)⁴

= [-200(I² + I + 4)[I(I² + I + 4) - [I² - 4])(2I + 1)]]/(I² + I + 4)⁴

= [-200(I² + I + 4)[I³ + I² + 4I - I² + 4])(2I + 1)]]/(I² + I + 4)⁴

= [-200(I² + I + 4)[I³ + 4I + 8])(2I + 1)]]/(I² + I + 4)⁴

Substituting I = 2 into d²P/dI², we have

= [-200(2² + 2 + 4)[2³ + 4(2) + 8])(2(2) + 1)]]/(2² + 2 + 4)⁴

= [-200(4 + 2 + 4)[8 + 8 + 8])(4 + 1)]]/(4 + 2 + 4)⁴

= [-200(10)[24](5)]]/(10)⁴

= -240000/10⁴

= -24

Since d²P/dI² = -24 < 0 at I = 2,  this shows that it I = 2 is a maximum point.

So, P is maximum at I = 2

Answer:

Step-by-step explanation:

[tex]C =2\pi r[/tex] and since we have to state the answer to 2 decimal places, that means that we are using the number value for π. In specific, π = 3.1415 is good enough. The other thing we note is that the formula for circumference could also be written in terms of its diameter as opposed to its radius:

C = πd. Let's use that one since we are given the diameter of the tire, not the radius.

C = (3.1415)(.65) so

C = 2.04 m

The circumference of the wheel  is C = 2.04 m.

Given ,

          d = 0.65 m

          π = 3.14

Let's use that one since we are given the diameter of the tire, not the radius.

Use this formula ,     C = πd

                         C = (3.1415)(.65)

                       so, C = 2.04 m

Therefore, the circumference of the wheel  is C = 2.04 m.

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Answer:

h(x) = 3^(x + 1)

Step-by-step explanation:

The exponential function is;

g(x) = 3^(x)

Now, in transformation of exponential functions of say f(x) = b^(x), when the new function g(x) is created by stretching by a factor of say c along the y-axis, we have;

g(x) = c•b^(x)

In this question, we are told it is stretched by a factor of 3 along the y-axis.

Thus, new function h is;

h(x) = 3 × 3^(x)

Using law of indices, we have;

h(x) = 3^(x + 1)

Answer:

x = 90

Step-by-step explanation:

If lines A and B were parallel , then

∠ 1 and ∠ 4 are corresponding angles and congruent, so

3x - 160 = x + 20 ( subtract x from both sides )

2x - 160 = 20 ( add 160 to both sides )

2x = 180 ( divide both sides by 2 )

x = 90

Answer:

(-1,2)

Step-by-step explanation:

hope you find this useful!

https://ncalculators.com/geometry/mid-points-calculator.htm

Answer:

I believe that it is the first one.

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

The greatest number of plates Jill can split the 20 cookies and 12 brownies into can be determined by calculating the highest common factor and 20 and 12

Factors of 12 = 1, 2, 3, 4, 6, 12

Factors of 20 = 1, 2,4, 5, 10, 20

Answer:

zero

Step-by-step explanation:

5x+10 = 5x-8

5x-5x = -8-10

0 = -18

so zero

Answer:

If you go to a website that has a red (or orange) triangle with an exclamation mark next to the link, it's an untrusted site. The things you list (your phone is being attacked and then said something with 26..) are likely to be scam ads (probably viruses). Therefore,  I do not recommend you to click the ads or enter that site again.

9514 1404 393

Answer:

  3.31227766..., irrational

Step-by-step explanation:

  3/20 +√10 = 0.15 + 3.16227766017...

The root of 10 is irrational, so adding that to a rational number will give an irrational sum.

The sum is about 3.31227766017..., an irrational number.

Answer:

A

Step-by-step explanation:

Answer:

a. 0.9599 = 95.99% probability of a random diabetic person having a glucose level less than 120 mg/100 ml.

b. 0.9371 = 93.71% of people have a glucose level between 90 and 120 mg/100 ml.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 106 mg/100 ml and standard deviation 8 mg/100 ml

This means that [tex]\mu = 106, \sigma = 8[/tex]

a. Calculate the probability of a random diabetic person having a glucose level less than 120 mg/100 ml.

This is the p-value of Z when X = 120. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{120 - 106}{8}[/tex]

[tex]Z = 1.75[/tex]

[tex]Z = 1.75[/tex] has a p-value of 0.9599

0.9599 = 95.99% probability of a random diabetic person having a glucose level less than 120 mg/100 ml.

b. What percentage of persons have a glucose level between 90 and 120 mg/100 ml?

The proportion is the p-value of Z when X = 120 subtracted by the p-value of Z when X = 90. So

X = 120

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{120 - 106}{8}[/tex]

[tex]Z = 1.75[/tex]

[tex]Z = 1.75[/tex] has a p-value of 0.9599

X = 90

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{120 - 106}{8}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a p-value of 0.0228

0.9599 - 0.0228 = 0.9371

0.9371 = 93.71% of people have a glucose level between 90 and 120 mg/100 ml.

Answer:

Step-by-step explanation:

[tex]\frac{2}{3} * 5 = \frac{2}{3}\frac{3}{2} x \\[/tex]

x = 10/3