Answer:
The reaction force is the water pushing the swimmer in the rightward direction.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Both igneous and sedimentary rock can become metamorphic rock if enough ________________ are applied.
what's the difference between a lunar eclipse and a solar eclipse?
Answer:
passes
Explanation:
Traditionally, eclipses are divided into two major types: solar and lunar. Solar eclipses occur when the Moon passes between Earth and the Sun, leaving a moving region of shadow on Earth's surface. Lunar eclipses occur when Earth passes between the Sun and the Moon, casting a shadow on the Moon.
how to calculate velocity with acceleration and time
Answer:
Multiply the acceleration by time to obtain the velocity change:
Example:
Velocity change = 6.95 * 4 = 27.8 m/s . Since the initial velocity was zero, the final velocity is equal to the change of speed. You can convert units to km/h by multiplying the result by 3.6: 27.8 * 3.6 ≈ 100 km/h
what is the potential energy of a 2kg plant that is on a windowsill 1.3 m high?
what is the kinetic energy of a 7.26 kg bowling ball that is rolling at a speed of 2 m/s
an apple as 6 J of energy. the apple sits on a counter 3 m high. what is the mass of the apple/
Answer:
25.48
Explanation:
PLEASE HELP LIKE AN ACUALL ANSWER NOT SPAM NO ONE IS GUNNA CLICK THE LINK
Answer:
C. 9.8
Explanation:
Which source of evidence did Wegener use to support his theory of continental drift?
fossils found on Earth
magnetic fields of Earth
satellite mapping of the tropical islands
glaciers found near the poles
Answer:
fossils found on Earth
Explanation:
i just did the test 100%
Answer:
Fossils on Earth
Explanation:
Fossils can show that the continents were all together by putting them together on a map you can see the fit. and when you look where fossils were, they would be right next to each other.
find u + (3v - w)
u =-4i-8j
v= -11i -3j
w=5i+7j
Answer:
gunrun
Explanation:
The following data were collected during a short race between two friends. Velocity (m/s) 0 0.5 1 1.5 2 2 4 6 2 0 Time (s) 0 2 4 6 8 10 12 14 16 18 a) Describe the different sections of the graph. b) Determine the acceleration over the first eight seconds. c) Determine the maximum acceleration. d) Using the graph calculate the displacement: i) over the first eight seconds ii) the total race. e) Find the maximum velocity reached by the runner.
The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.
v = v₀ + a t
y = v₀ t + ½ a t²
where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.
In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:
Positive slope the body is accelerating and the speed is increasing. Negative slope the body is stopping, the speed decreases.
Let's answer the different questions about the system.
a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.
b) The acceleration is the first 8 s
v = v₀ + a t
[tex]a = \frac{v-v_o}{\Delta t}[/tex]
[tex]a = \frac{2-0}{8-0}[/tex]
a = 0.25 m / s²
c) The maximum acceleration is when the slope is maximum.
[tex]a = \frac{6-2}{ 14-10}[/tex]
a = 1 m / s²
Therefore the acceleration is maximum in the section between 10 and 14 s
d) The total displacement is the sum of the displacements of each section.
[tex]d_{total } = d_1 +d_2 + d_3 +d_4[/tex]
We look for every displacement.
d₁ = v₀ + ½ a₁ Δt²
d₁ = 0 + ½ 0.25 8²
d₁ = 8 m
In the second section the velocity is constant
d₂ = v₂ Δt₂
d₂ = 2 (10-8)
d₂ = 4 m
The third section.
d₃ = v₀ + ½ a t²
d₃ = 2 + ½ 1 (14-10) ²
d₃ = 10 m
The distance of the fourth section.
we look for acceleration
a₄ = [tex]\frac{v-v_o}{\Delta t}[/tex]
a₄ = [tex]\frac{0-6}{18-14}[/tex]
a₄ = -1.5 m / s²
d₄ = 6 + ½ (-1.5) (1814) ²
d₄ = -6 m
The total displacement is;
[tex]d_{total}[/tex] = 8 + 4 + 10 -6
[tex]d_{total}[/tex] = 16 m
e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to
v = 6 m / s
In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
Learn more about kinematics here: brainly.com/question/24783036
The engine of a 2400 kg car applies a force of 740 N to make the car accelerate. Calculate the
acceleration of the car.
Answer:
0.31 m/s²Explanation:
The acceleration of an object given only it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass in kg
From the question
m = 2400 kg
f = 740 N
We have
[tex]a = \frac{740}{2400} = \frac{74}{240} \\ = 0.308333...[/tex]
We have the final answer as
0.31 m/s²Hope this helps you
A cannonball explodes in mid-air, fragmenting into several pieces. How does the total
momentum of the pieces after the explosion compare to the total momentum of the
cannonball just before the explosion?
I. They are the same
II. The momentum of the fragments is less than the momentum of the cannonball
III. The momentum of the fragments is more than the momentum of the cannonball
Hi there!
I. They are the same.
Due to the Conservation of Momentum, an explosion as such means that the TOTAL momentum of the system (all of the pieces) is conserved.
1. Sandra buys a $4 000 television and pays $2 000 deposit. The rest is payable in 8 equal monthly payments. If the flat rate of interest charged is 7% p.a. what is the total amount paid for the item?
Answer:
$2140
Explanation:$2000 missing plus 7 percent of 2000 is 140 so 2000+140=2140. Each month she would pay $268 approx.
A cat that has a mass of 6 kg climbs to the top of a tree that is 20 m high. How much potential energy does the cat have at the top of the tree?
Have a great day!
Answer:
1176.798 J
Explanation:
[] Use the following equation:
U = mgh
m - mass
g - gravitational field
h - height
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
For a uniformly accelerated motion the graph of displacement versus time would be
Explanation:
hope this may help you
have a nice day
Select the correct answer
1. Instruments that produce sound are called sources of light.
2. Music has no ability to heal the mental stress.
3. A medium is necessary for sound travel.
4. We hear sounds of frequencies below 20 Hz. O First answer O Second answer O Third answer O Forth answer
Answer:
C or 3
Explanation:
A: no they are called sources of sound. A is incorrect.
B: It does. Many people attest to this. But this is not a property of physics.
C: A media is required is the correct answer.
D: Dogs might. In general we don't.
I would pick C
Calcula el valor de la velocidad de las ondas sonoras en el agua sabiendo que su
densidad es 1.10 3 kg/m 3 y su módulo de comprensibilidad vale 2,16x10 9 N/m 2 ¿Cuál
es la longitud de onda de las ondas sonoras en el agua si su frecuencia es de 1000hz?
1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua ([tex]v[/tex]), en metros por segundo:
[tex]v = \sqrt{\frac{K}{\rho} }[/tex] (1)
Donde:
[tex]K[/tex] - Módulo de compresibilidad, en newtons por metro cuadrado.[tex]\rho[/tex] - Densidad del agua, en kilogramos por metro cúbico.Si sabemos que [tex]\rho = 1\times 10^{3}\,\frac{kg}{m^{3}}[/tex] y [tex]K = 2,16\times 10^{9}\,\frac{N}{m^{2}}[/tex], entonces la velocidad de las ondas sonoras es:
[tex]v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }[/tex]
[tex]v\approx 1469,694\,\frac{m}{s}[/tex]
La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.
2) Luego, determinamos la longitud de onda ([tex]\lambda[/tex]), en metros, mediante la siguiente fórmula:
[tex]\lambda = \frac{v}{f}[/tex] (2)
Donde [tex]f[/tex] es la frecuencia de las ondas sonoras, en hertz.
Si sabemos que [tex]v\approx 1469,694\,\frac{m}{s}[/tex] y [tex]f = 1000\,hz[/tex], entonces la longitud de onda de las ondas sonoras es:
[tex]\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}[/tex]
[tex]\lambda = 1,470\,m[/tex]
La longitud de onda de las ondas sonoras es 1,470 metros.
Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: https://brainly.com/question/1070238
Can someone help me with this physics question? I don't know which answer is correct.
3. Distance is a quantity that is always a vector.
B.
What is the radius of a circular space station that spins with a linear speed of 90.0 m/s I’m order for its walls to supply a centripetal acceleration equal to the acceleration provided by gravity on the surface of the earth?
Answer:
a = v^2 / R centripetal acceleration
R = v^2 / a a at the surface of earth is 9.8 m/s^2
R = (90 m/s)^2 / 9.8 m/s^2 = 827 m
Define "one solar day".
Answer:
the interval between transits of the apparent or mean sun across the meridian at any place.
A passenger of mass 90kg is involved in a minor car crash. The car approaches a solid barrier at 32m/s. It crashes into the barrer and stops in 0.2s. Determine the impulse that must be applied to the car to bring it to rest
Answer:
I hope this helps:)
Explanation:
good luck:)
given the formula p=mv what are the units of p
Answer:
They are kg * m/s.
The unit of the momentum p would be kg × m/s..
What is momentum?Momentum is defined as the ability or tendency of an object to continue moving.
Also momentum is the product of mass and velocity. It can be shown as follows;
p = m × v
where,
p = momentum
m = mass
v = velocity
Thus, we can conclude that the formula p = mv show the relationship between momentum, mass, and velocity.
Now the unit of the momentum p would be;
p = m × v
p = kg × m/s
Hence, the unit of the momentum p would be kg × m/s.
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Draw the following vector: 350 N, 30° south of east [1 cm = 50 N]
The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
The given parameters:
Magnitude of the vector = 350 NPosition of the vector = 30⁰ South eastThe vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.
The length of the arrow represents the magnitude of the vector which is 350 N. The direction of the arrow indicated by the arrow head represents the position of the vector.The position of the vector is 30 degrees South of East.Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
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The position as a function of time for two objects moving along a straight line is shown in the graph,
Which statement is true about the distances the two object have traveled at time ty?
Object 1 has traveled a greater distance.
B
Object 2 has traveled a greater distance.
Both objects have traveled the same distance
D
The total distance traveled by each object cannot be compared using the graph.
The distance traveled by object 1 is greater than the distance traveled by object 2.
The shortest distance between two points is a straight line. More distance is covered when the path of motion is curved.
The distance traveled by each object at different time is compared as follows;
[tex]at \ t_ A , \ \ \ d_1>d_2 \ \ \ (d_2 = 0)\\\\at \ t_B, \ \ d_1 > d_2 \\\\at \ t_C, \ \ \ d_2 > d_1 \\\\at \ t_D \ \ \ d_1 = d_2\\\\at \ t_f \ \ \ d_2 > d_1 \ \ \ (d_1 = 0)[/tex]
The major distinguishing distance traveled by each occurs at [tex]t_B[/tex] and [tex]t_C[/tex].
[tex]d_{(t_B)} > d_{(t_C)} \\\\d_1 > d_2[/tex]
Thus, we can conclude that the distance traveled by object 1 is greater than the distance traveled by object 2.
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A car has a kinetic energy of 4.33x10^5 J when traveling a speed of 25 m/s. What is the mass ?
two forces act concurrently on an object on a horizontal frictionless surface. their resultatn force has the largest magnitude when the angle between the forces is
Answer:
54
Explanation:4
4
4
Answer:
30d
Explanation:
30d
Help it’s multiple choice 11 through 15 please!
1. • Here, force of gravity on the block = 20 N.
• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]
• The coefficient
[tex] u_{k} = 0.4[/tex]
• Force of friction =
[tex]u_{k} \times \: normal \: \: \: force \\ = 0.4 \times 20N \\ = 8N[/tex]
• Hence, the force of sliding friction between the block and the ground is 8 N.
• So, it is option c. 8 N
2. The answer is option d. continue in the same direction with no change in speed.
We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.
3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.
Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.
So, 1 N = 1 Kg × 1 m/s^2.
4. It is d. not zero.
Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.
5. Force = 2 N
Acceleration of the object A = 2 m/s^2.
Acceleration of the object B = 1 m/s^2.
Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg
And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg
So, the mass of object B is greater than that of object A.
Hence, the answer is option c. Object B has more mass.
Hope you could get an idea from here.
Doubt clarification - use comment section.
A point charge of 5. 0 Ă— 10â€""7 C moves to the right at 2. 6 Ă— 105 m/s in a magnetic field that is directed into the screen and has a field strength of 1. 8 Ă— 10â€""2 T. What is the magnitude of the magnetic force acting on the charge? 0 N 2. 3 Ă— 10â€""3 N 23 N 2. 3 Ă— 1011 N.
The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.
Given to us,
the charge [tex]q[/tex] = [tex]5\times 10^{-7}[/tex] C,
the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex] m/sec,
the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,
angle between the direction of v and B [tex]\theta[/tex] = 0,
Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by
[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]
Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N
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A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
Answer:
0.184 m/s
Explanation:
Momentum is conserved. If the velocity of the 0.24 kg mass is positive, then ...
m1v1+m2v2 = m3v3
(0.24 kg)(0.60 m/s) +(0.26 kg)(-0.20 m/s) = (0.24 +0.26 kg)(v)
v = (0.144 -0.052 kg·m/s)/(0.50 kg) = 0.184 m/s
The speed of the combined masses is 0.184 m/s.
_____
Additional comment
The positive sign indicates the combined masses are moving in the direction of the original 0.24 kg mass.
what does and does not impact magnetic force?
Answer:
Image result for what does and does not impact magnetic force?
The magnitude of the magnetic force between them depends on how much charge is in how much motion in each of the two objects and how far apart they are. The direction of the force depends on the relative directions of motion of the charge in each case
Explanation:
The factors that affect magnetic force are magnitude of the charge, speed, magnetic field and inclination of the field.
Magnetic forceThe magnetic force on a charged particle moving in a magnetic field is determined using the following formula;
F = qvBsin(θ)
where;
q is the magnitude of the chargev is the speed of the chargeB is the magnetic fieldθ is the angle between the field and the speed of the chargeThus, the factors that affect magnetic force are magnitude of the charge, speed, magnetic field and inclination of the field.
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Which of the following rivers flows north in eastern Florida?
St. James
St. Johns
Mississippi
Hudson
St. John’s
_________
o0o0o0o0o0
A massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface. The mass hangs over a
frictionless pulley. When the mass is released, the cartaccelerates to the right
2.45 m/s2
4.90 m/s
9.80 m/s?
19.6 m/s
Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]
Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.
Let M = 1kg and m = 3 kg
Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.
When the mass is released, the cart accelerates to the right can be calculated from Newton' second law of motion. That is,
M( g + a) = m(g - a)
1(9.8 + a) = 3( 9.8 - a)
9.8 +a = 29.4 - 3a
collect the like terms
4a = 19.6
a = 19.6/4
a = 4.9 m/[tex]s^{2}[/tex]
Therefore, the cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]
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