If one DNA strand reads CCGTAATGCAT, what will be the sequence of the complementary
strand?
Si una hebra de ADN lee CCGTAATGCAT, ¿cuál será la secuencia de la hebra
complementaria?
Write your answer here:
Escriba su respuesta aquí:
a) CCGTAATGCAT
b) GGCATTACGTA
c) CCGATTAGCTA
d) GGCTAATCGAT

Answer:water expands as it goes from liquid to solid.

Explanation:

The temperature is warm , water works it’s way to to cracks in rock

Answer:

Lithium oxide, Li₂O.  

Explanation:

Hello!  

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

[tex]M_2O+H_2\rightarrow 2M+H_2O[/tex]  

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

[tex]5.00gM_2O*\frac{1molM_2O}{(2*X+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{XgM}{1molM}=2.32gM[/tex]  

Thus, we perform the operations in order to obtain:

[tex]\frac{10X}{(2X+16)}=2.32[/tex]  

So we solve for x as shown below:

[tex]10X=2.32(2X+16)\\\\10X=4.64X+37.12\\\\X=\frac{37.12}{10-4.64}\\\\X= 6.93g/mol[/tex]  

Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.  

Best regards!

Mass of Nitrogen= 42 grams

Given

one mole of Sodium azide

Required

mass of Nitrogen

Solution

Reaction

The decomposition of one mol of sodium azide :

2 N a N 3 ( s ) → 2Na ( s ) + 3 N2 ( g )

From the equation, the mol ratio of N a N 3 ( s ) :  N2 ( g ) = 2 : 3, so mol N2 :

= 3/2 x mol N a N 3

= 3/2 x 1

= 1.5 moles

Mass of Nitrogen

= mol x molar mass

= 1.5 x 28 g/mol

= 42 grams

Answer:

0.200 m K3PO3

Explanation:

Let us remember that the freezing point depression is obtained from the formula;

ΔTf = Kf m i

Where;

Kf = freezing point constant

m = molality

i = Van't Hoff factor

The  Van't Hoff factor has to do with the number of particles in solution. Let us consider the  Van't Hoff factor for each specie.

0.200 m HOCH2CH2OH - 1

0.200 m Ba(NO3)2 - 3

0.200 m K3PO3 - 4

0.200 m Ca(CIO4)2 - 3

Hence, 0.200 m K3PO3 has the greatest van't Hoff factor and consequently the greatest freezing point depression.

Answer:

Polarity.

Explanation:

The most important intermolecular force to allow a solvent to dissolve in water is polarity. This is because water is a polar substance and there is a chemical law that states that there is only solubility between substances of equal polarity. Thus, water is only able to dissolve a polar substance, just like it. In this case, we can say that the equal polarity between the two solvents is the most important for one to be able to dissolve the other.

Answer:

[tex]T_F=47.3\°C[/tex]

Explanation:

Hello!

In this case, since we have hot and cold water, we infer that as hot water cools down, cool water heats up based on the first law of thermodynamics; thus, we can write:

[tex]Q_{hot}+Q_{cold}=0[/tex]

In such a way, we can write the expression in terms of mass, specific heat and temperature change:

[tex]m_{hot}C_{hot}(T_F-T_{hot})+m_{cold}C_{cold}(T_F-T_{cold})=0[/tex]

However, since they both have the same specific heat and the same mL are in g due to the 1.00-g/mL density, we obtain:

[tex]m_{hot}(T_F-T_{hot})+m_{cold}(T_F-T_{cold})=0\\\\T_F=\frac{m_{hot}T_{hot}+m_{cold}T_{cold}}{m_{hot}+m_{cold}}[/tex]

Now, we plug in to obtain:

[tex]T_F=\frac{140.0g*95.00\°C+300g*25.00\°C}{140.0g+300g}\\\\T_F=47.3\°C[/tex]

Best regards!

Answer:

the scientific definition of work

Explanation:

In physics, work is defined as the use of force to move an object. For work to be done, the force must be applied in the same direction that the object moves.

I hope it helps! ^^

☁️☁️☁️☁️☁️☁️☁️

Answer:

4

Explanation:

In a rate law, The reaction order is basically the superscript (power) of the concentration of the reaction. It defines the extent to which the rate of the reaction depends on the concentration of the reaction.

In this rate law, the order of the reactants are;

[BrO3] = 1

[Br] = 1

[ht] = 2

The overall reaction order is the sum total of the individual orders. We have;

1 +1 + 2 = 4

Answer:

1216 mmHg = Partial pressure N₂

Explanation:

In a mixture of n gases, the partial pressure of each compound follows the equation:

Total pressure = Partial pressure n₁ + Partial pressure n₂ + Partial pressure n₃ + Partial pressure n₄ + Partial pressure n₅ + ... + Partial pressure nₙ

In a mixture of O₂, He and N₂, the total pressure = 3040mmHg is defined as:

3040 mmHg = Partial pressure O₂ + Partial pressure He + Partial pressure N₂

Replacing:

3040 mmHg = 304 mmHg + 1520 mmHg + Partial pressure N₂

3040 mmHg = 1824 mmHg + Partial pressure N₂

1216 mmHg = Partial pressure N₂

Answer:

13. t = 1183 min and 0.50 M.

14. [tex]t_{1/2}=2.67x10^{-8}hr[/tex]

Explanation:

Hello!

13. In this case, according to the units, we infer this is a second-order reaction which has the following integrated rate law:

[tex]\frac{1}{[A]} =\frac{1}{[A]_0} +kt[/tex]

Which can be solved for the time as shown below:

[tex]t=\frac{ \frac{1}{[A]}-\frac{1}{[A]_0}}{k}[/tex]

Thus, we plug in the given concentrations and rate constant to obtain:

[tex]t=\frac{ \frac{1}{0.250M}-\frac{1}{0.850M}}{0.002387M^{-1}min^{-1}}\\\\t= 1183min[/tex]

For the second part, we proceed by using the same rate constant and the new initial concentration as follows:

[tex]\frac{1}{[A]} =\frac{1}{[A]_0} +kt\\\\\frac{1}{[A]} =\frac{1}{0.750M} +0.680M^{-1}min^{-1}*0.996min\\\\\frac{1}{[A]} =1.99,M[/tex]

[tex][A]=0.50M[/tex]

14. In this case, according to the units of the rate constant, we infer this is a zeroth-order reaction, therefore we compute the half-life has shown below:

[tex]t_{1/2}=\frac{[A]_0}{2k}[/tex]

Thus, we plug in to obtain:

[tex]t_{1/2}=\frac{2.696x10^{-6}M}{2*50.5M*hr^{-1}}[/tex]

[tex]t_{1/2}=2.67x10^{-8}hr[/tex]

Best regards!

Answer:

it bubbles up and has a chemical reaction also releases co2

Explanation:

Hope it helps <3

Answer:

5.56g/ml or 5560kg/m^3

Explanation:

Denisty=mass/volume.

therefore Density= 24.84/4.47.using theSI  unit for density is kg/m^3.

Answer:

All of the above. The CV system transports blood and plasma the do all 4.

Answer:

false

Explanation:

Distance in space is measured using the speed of light.

Answer:

Distance in space is measured using the speed of light.

Explanation:

I took the test

Answer:

glucose and oxygen gas

Explanation:

Answer:

Explanation:

Phenolphthalein is a protonated indicator and methyl orange is a basic indicator having hydroxyl ionisable part .

Phenolphthalein can be represented by the following formula

HPh  which ionizes in water as follows

       HPh        + H₂O      ⇄    H₃O⁺      +        Ph⁻

( colourless  )                    ( pink  )

In acidic solution it is in the form of protonated Hph form which is colourless

In basic medium , it ionises to give H₃O⁺ and unprotonated  Ph⁻ whose colour is pink .

Answer:

131 mg

Explanation:

Percent yield = 89%

Actual yield = 117 mg

Percent yield is given by

[tex]\text{Percent yield}=\dfrac{\text{Actual yield}}{\text{Theoretical yield}}\times 100\\\Rightarrow 89=\dfrac{117}{\text{Theoretical yield}}\times 100\\\Rightarrow \text{Theoretical yield}=\dfrac{117}{89}\times 100\\\Rightarrow \text{Theoretical yield}=131.46\approx 131\ \text{mg}[/tex]

The theoretical yield, for this reaction is 131 mg.

Answer:

Explanation:

Feel free to bang me- your teacher

Answer:

depends lol

Explanation:

Answer:

The atoms are ranked in decreasing order as follows:

Fluorine ---4

Carbon ----3

Boron ------2

Beryllium --1

Explanation:

Effective nuclear charge (Zeff) is defined as the difference between the actual nuclear charge (the atomic number, Z) and the shielding constant (S).

It is calculated by finding the atomic number and electronic configuration, attributing a shielding value to each electron, adding all the shielding values and using the formula:

                 Z eff = Z - S

Effective nuclear charges:

An atom of carbon: 3.25

An atom of fluorine: 5.20

An atom of beryllium: 1.95

An atom of boron: 2.60

The molality of a solution : m = 2 mol/kg

Given

6 moles of NaOH

3 kg water

Required

The molality

Solution

Molality shows the number of moles dissolved in every 1000 grams of solvent( 1 kg solvent)

m = n. (1000 / p)

m = Molality

n = number of moles of solute

p = Solvent mass (gram)

Input the value :

m = 6 moles : 3 kg

m = 2 mol/kg

Answer:

2914 J

Explanation:

Step 1: Given data

Step 2: Calculate the temperature change

ΔT = 27.09 °C - 15.71 °C = 11.38 °C

Step 3: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.3850 J/g.°C × 665.0 g × 11.38 °C

Q = 2914 J

Answer:

Nuclear reactors do not produce direct carbon dioxide emissions. Unlike fossil fuel-fired power plants, nuclear reactors do not produce air pollution or carbon dioxide during operation. However, processes for mining and refining uranium ore and the production of reactor fuel all require a large amount of energy. Nuclear plants create more jobs than other forms of energy. 7  They create 0.5 jobs for every megawatt hour of electricity produced. This is in comparison to 0.19 jobs in coal, 0.05 jobs in gas-fired plants, and 0.05 in wind power. As a result, new gas-fired power plants were built from 1992 to 2005. an Advantages of nuclear energy  Low-cost energy. Although building nuclear power plants has a high initial cost, it's relatively cheap to produce energy from them and they have low operating cost.

Explanation:

This is a straightforward dilution calculation that can be done using the equation

[tex]M_1V_1=M_2V_2[/tex]

where M₁ and M₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and V₁ and V₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (M₁) and the initial (V₁) and final (V₂) volumes, and we want to find the final concentration (M₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for M₂:

[tex]M_2=\frac{M_1V_1}{V_2}.[/tex]

Substituting in our values, we get

[tex]\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].[/tex]

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.