If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.




1. x = ?

2. m∠MKL = ?

3. m∠DEF = ?​

Answer:

Hey there!

[tex]8x^3+2x^2-20x-5[/tex]

[tex](8x^3+2x^2)+(-20x-5)[/tex]

[tex]2x^2(4x+1)+(-5)(4x+1)[/tex]

[tex](2x^2-5)(4x+1)[/tex]

Let me know if this helps :)

The solution of the expression are,

⇒ (4x + 1) (2x² - 5)

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The expression is,

⇒ 8x³ + 2x² - 20x - 5

Now, We can simplify as;

⇒ 8x³ + 2x² - 20x - 5

⇒ (8x³ + 2x² )  + (- 20x - 5)

⇒ 2x² (4x + 1) - 5 (4x + 1)

⇒ (4x + 1) (2x² - 5)

Thus, The solution of the expression are,

⇒ (4x + 1) (2x² - 5)

Learn more about the mathematical expression visit:

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Hi there! :)

Answer:

[tex]\huge\boxed{x = -4, -2}[/tex]

x² + 6x + 8 = 0

Factor the equation by finding two numbers that sum up to 6 and multiply into 8:

4 + 2 = 6

4 ×2 = 8

Rewrite in factored form:

(x + 4) (x + 2) = 0

Find the roots using the Zero-Product Property:

x + 4 = 0

x = - 4

x + 2 = 0

x = -2.

Therefore, the roots of this equation are at x = -4 and -2.

Answer:

To know which is better to pay.

Step-by-step explanation:

Good Luck

Answer:

18 values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

[tex]$x^2 - mx + n$[/tex]

such that:

Roots are positive prime integers and

[tex]$m < 20$[/tex]

To find:

How many possible values of [tex]n[/tex] are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

[tex]Ax^{2} +Bx+C[/tex]

and the roots are: [tex]\alpha[/tex] and [tex]\beta[/tex]

Then sum of roots, [tex]\alpha+\beta = -\frac{B}{A}[/tex]

Product of roots, [tex]\alpha \beta = \frac{C}{A}[/tex]

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots,  [tex]\alpha+\beta = -\frac{-m}{1} = m[/tex]

Product of roots, [tex]\alpha \beta = \frac{n}{1} = n[/tex]

We are given that [tex]m<20[/tex]  

[tex]\alpha[/tex] and [tex]\beta[/tex] are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of [tex]n (= \alpha \times \beta)[/tex] are:

[tex]1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\[/tex]

[tex]11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77[/tex]

So,as shown above 18 values for n are possible.

Answer:

5 buses

Step-by-step explanation:

Total number of 6th graders going for the field trip = 184

Step 1

Divide the total number of students by 4

184/4 = 46

We have 46 groups of six graders.

Step 2

There needs to be one chaperone for every four students.

We have 46 groups of six graders

This means there is need for 1 chaperone per group

Hence, we have 46 chaperones

Step 3

Find total number of people going for the field trip

184 students + 46 chaperones

= 230 people

Step 4

If a bus can hold 50 people, how many buses will they need for the trip?

50 people = 1 bus

230 people = ??y

50 × y = 230

y = 230/50

y = 4.6 buses

Hence, 4.6 buses would be needed but since we can't have 0.6(part) of a bus figuratively, as buses come in whole numbers, we approximate to the nearest whole number

= 4.6 ≈ 5

Therefore, they would be needing 5 buses for the trip.

5 buses

Step-by-step explanation:

i got 10 out of 10

49,400-20,000=29400

29400/24=1225 average miles per month

Answer:

36[tex]\sqrt{3}[/tex] + 72

Step-by-step explanation:

The length of the rectangle = diameter of 2 circles = 4 × 3 = 12 mm

The width of the rectangle = 2 radii + distance d between radii ( lower to upper )

Using the right triangle formed by joining the 3 centres with legs 3 and d and hypotenuse 6

Using Pythagoras' identity, then

d² + 3² = 6²

d² + 9 = 36 ( subtract 9 from both sides )

d² = 27 ( take the square root of both sides )

d = [tex]\sqrt{27}[/tex] = 3[tex]\sqrt{3}[/tex]

Thus width of rectangle = 3 + 3[tex]\sqrt{3}[/tex] + 3 = 6 + 3[tex]\sqrt{3}[/tex]

Hence

area = length × width

        = 12 × (6 + 3[tex]\sqrt{3}[/tex] ) = 36[tex]\sqrt{3}[/tex] + 72 mm ²

36 [tex]\sqrt{3}[/tex]+ 72

The length of the rectangle = diameter of 2 circles = 4 × 3 = 12 mm

The width of the rectangle = 2 radii + distance d between radii ( lower to upper )

Using the right triangle formed by joining the 3 centres with legs 3 and d and hypotenuse 6

Using Pythagoras' identity, then

d² + 3² = 6²

d² + 9 = 36 ( subtract 9 from both sides )

d² = 27 ( take the square root of both sides )

d =  = 3

Thus width of rectangle = 3 + 3 + 3 = 6 + 3

Hence

area = length × width

       = 12 × (6 + 3 ) = 36 + 72 mm ²

Answer:

∠ PQR = 143°

Step-by-step explanation:

∠ PQR and ∠ SQR are adjacent angles and are supplementary, thus

∠ PQR = 180° - 37° = 143°

Answer:

Step-by-step explanation:

Hello friend!!!!!

Third option is the correct answer.

Hope this helps

plz mark as brainliest!!!!!!!

Step-by-step explanation:

Hey, there!!

Option 3 is the correct answer.

here,

when we cube the sum of 5 and 3 times y^2 it looks like,

=[tex] {(5 + 3 {y}^{2}) }^{3} [/tex]

now, when we divide it by cube of the product of 4 and y we get,

=[tex] \frac{ {(5 + 3 {y}^{2}) }^{3} }{ {4y}^{3} } [/tex]

so, answer is option 3.

Hope it helps..

The inequality expression is :

16 + 8B ≥ 50

Least amount that could be spent = $4500

The total number of rooms required should be atleast 50

Already booked = 16

Number of rooms per block = 8

If the number of blocks = B

Summing together :

Then we have :

16 + 8B ≥ 50

The leat additional amount to be spent:

(50 - 16) / 8

34/8 = 4.25

Least number of blocks, B = 5

Least amount = $900 * 5 = $4500

Learn more : https://brainly.com/question/15974141

Inequalities are used to represent unequal expressions.

Given that:

[tex]Room = 50[/tex] at least

[tex]Reserved = 16[/tex]

[tex]Rate = 8[/tex] per block

A. The inequality

Let the number of blocks be B.

"At least" means, greater than or equal to. So, we have:

[tex]Rate \times B + Reserved \ge 50[/tex]

Substitute known values

[tex]8 \times B + 16 \ge 50[/tex]

[tex]8B + 16 \ge 50[/tex]

So, the inequality that describes the scenario is:

[tex](b).\ 8B + 16 \ge 50[/tex]

B. The least amount

Solve for B in: [tex]8B + 16 \ge 50[/tex]

[tex]8B \ge 50 - 16[/tex]

[tex]8B \ge 34[/tex]

Divide both sides by 8

[tex]B \ge 4.25[/tex]

The number of blocks cannot be a decimal. So, we round 4.25 to the smallest integer greater than 4.25

This gives:

[tex]B \ge 5[/tex]

The least number of block is 5.

Given that:

[tex]Cost = \$900[/tex] per block

The least amount is calculated as follows:

[tex]Least = B \times Cost[/tex]

So, we have:

[tex]Least = 5 \times \$900[/tex]

[tex]Least = \$4500[/tex]

Hence, the least additional money is: $4500

Read more about inequalities at:

https://brainly.com/question/17675534

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Hi my lil bunny!

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Answer : [tex]\boxed{(2x + 5 ) (2x - 5)}[/tex]

[tex]4x^2-25[/tex]

Rewrite [tex]4x^2[/tex] as [tex](2^x)^2[/tex].

[tex](2x)^2 - 5^2[/tex]

Rewrite [tex](2x)^2[/tex] as [tex]5^2[/tex].

[tex](2x)^2 - 5^2[/tex]

Since both terms are perfect squares, factor using the difference of squares formula, [tex]a^2 - b^2 = ( a + b ) ( a - b )[/tex] where [tex]a = 2x[/tex] and [tex]b = 5[/tex].

[tex](2x + 5 ) (2x - 5)[/tex]

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Have a great day/night!

❀*May*❀

Answer:

y = 9

Step-by-step explanation:

6.4x + 2.8y = 44.4

6.4(3) + 2.8y = 44.4

19.2 + 2.8y = 44.4

2.8y = 25.2

y = 9

hi

40 students

30 read chemistry

20 read physics

so logical deduction is that 10 read chemistry and physics.  

So only 20 read only chemistry and only 10 read only physics.  

So read only chemistry is  20/40 = 1/2

Answer as a fraction =  1/2

Answer in decimal form = 0.5

Answer in percent form = 50%

All three represent the same idea, but in a different form.

=======================================================

Work Shown:

30 read chem, 20 read physics

30+20 = 50 read either one, but this is over 40, so 50-40 = 10 students must read both

From that,

30-10 = 20 read chem only

20-10 = 10 read physics only

This makes the venn diagram you see below

Divide the number of people who read chemistry only (20) over the total number of people (40). This gives 20/40 = 2/4 = 1/2

Then you would use your calculator to find 1/2 = 0.5 = 50%

Answer:

-32

Step-by-step explanation:

Negative plus negative = Negative

Just add those 2 together,

(-)18 + (-) 14

Which is -32

(-) 32 = -32

Answer:

This is a third-degree trinomial.

Step-by-step explanation:

To find the degree of a polynomial, simply look at the term with the highest power.  In the case of this polynomial, the term with the highest power is 2x^3 which is a third power.  Hence, this is a 3rd degree trinomial.

Cheers.

Answer:

X= 7

Step-by-step explanation:

Answer:

12,500 euro = 61,250 cedis

Step-by-step explanation:

1 euro = 4.9 cedis

12500 euro = 4.9 * 12500 cedis

12,500 euro = 61,250 cedis

Answer:

15/28

Step-by-step explanation:

If the line goes downhill as you read from left to right, then the slope is negative.

The slope is positive when you go uphill, reading from left to right.

A slope of 0 means the line is completely horizontal or level

If the line is completely vertical, then the slope is undefined.

==========================================

Explanation:

The two smaller circles have a height of h, so one circle has a height of h/2 = 0.5h

The radius of each smaller circle is (0.5h)/2 = 0.25h

Draw an xy axis. Place the bottom left corner of the rectangle at the origin (0,0)

The center of the lower smaller circle is at location (0.25h, 0.25h). Call this point A.

Let B be the center of the larger circle. It has coordinates (x,y). We don't know x, but we know that y = 0.5h since the center must be at the halfway point in terms of the height of this rectangle. So the larger circle has a radius of 0.5h

Draw a line segment connecting A and B. The length of this segment, call it d, is d = 0.5h + 0.25h = 0.75h. Note how I added the two radius values mentioned earlier.

-------------

Summarizing everything so far, we have

A = (0.25h, 0.25h)

B = (x, 0.5h)

d = 0.75h

The distance formula is then used

d = distance from A to B

d = length of segment AB

d = sqrt( (x1-x2)^2 + (y1-y2)^2 )

0.75h = sqrt( (0.25h - x)^2 + (0.25h - 0.5h)^2 )

(0.75h)^2 = (0.25h - x)^2 + (-0.25h)^2

0.5625h^2 = 0.0625h^2 - 0.5hx + x^2 + 0.0625h^2

x^2 - 0.5hx + 0.4375h^2 = 0

From here you use the quadratic formula to get x = 0.9571067811865h approximately (the other solution is ignored as it's negative). See the attached image below if you're curious what the quadratic formula steps would look like.

This x value is the x coordinate of point B, which is the center of the larger circle. This spans the horizontal distance from the left edge of the rectangle to the center of the larger circle. The remaining horizontal distance is h/2 as it is the radius of the larger circle.

Therefore,

w = 0.9571067811865h + 0.5h

w = 1.4571067811865h

-------------

We have turned w into a roughly equivalent expression that has an h in it, allowing us to find the ratio of h to w

h/w = h/(1.4571067811865h) = 1/1.4571067811865 = 0.68629150101527

When rounding to two decimal places, we get roughly 0.69

Answer:

EF = 58 units

Step-by-step explanation:

Given:

DF = 9x - 39

DE = 47

EF = 3x + 10

Find:

EF

Computation:

DF = DE + EF

9x - 39 = 47 + 3x + 10

9x - 3x = 47 + 39 + 10

6x = 96

x = 16

EF = 3x + 10

EF = 3(16) + 10

EF = 58 units

Answer:

To make a true equation, check your math to make sure that the values on each side of the equals sign are the same. Ensure that the numerical values on both sides of the "=" sign are the same to make a true equation. For example, 9 = 9 is a true equation. 5 + 4 = 9 is a true equation.You will be able to determine if an equation has one solution (which is when one variable equals one number), or if it has no solution (the two sides of the equation are not equal to each other) or infinite solutions (the two sides of the equation are identical).

Answer: 23

Step-by-step explanation: he had 12 and 24 which makes 36

then he had 13 which means he gave 23 because adding them together gives the original amount

Answer:

the domain is {0, 1, 2, 3, 4... to positive infinity}

The range is {-1, -3, 0, -4 and so on}

this is not a function

Step-by-step explanation:

domain is a set of all x values, so just write the x values based on the graph

range is a set of all y values, so just write y values based on the graph

not function because it doesnt satisfy with the vertical line test.

i hop it help u

Answer:

ONE IS DA ANSWR 1

Step-by-step explanation:

so 5/12 +5/6 simpify 5/6 you get 5/12 + 10/12 = 15/12 and 15/12 is 1 and 3/12 1/3

Answer:

x > 7/3   or x < -11/3

Step-by-step explanation:

|3x + 2| > 9

There are two solutions, one positive and one negative, remembering to flip the inequality when taking the negative solutions

3x+2 > 9         or         3x+2 < -9

Subtract 2

3x+2-2 >9-2   or      3x+2-2 < -9-2

3x >7                           3x>-11

Divide by 3

3x/3 > 7/3                    3x/3 < -11/3

x > 7/3   or x < -11/3

Answer:

2+2+2=6

4+52-32+2=26

finally add 26+6=32

angle FHG = 42 degrees

angle GHI = 100 degrees

=========================================================

Explanation:

FHI is the largest angle. It is split into two pieces FHG and GHI which have measures of (3x+6) and (9x-8) degrees respectively.

Put another way, those two smaller angles (FHG and GHI) combine to form the larger angle (FHI)

This is the angle addition postulate.

------------------

(angle FHG) + (angle GHI) = angle FHI

(3x+6) + (9x-8) = 142

3x+6+9x-8 = 142

(3x+9x) + (6-8) = 142

12x - 2 = 142

12x-2+2 = 142+2 ... adding 2 to both sides

12x = 144

12x/12 = 144/12 .... dividing both sides by 12

x = 12

------------------

Use that x value to find the angles we're after

angle FHG = 3x+6 = 3*12+6 = 36+6 = 42

angle GHI = 9x-8 = 9*12-8 = 108-8 = 100

Note how

(angle FHG) + (angle GHI) = 42 + 100 = 142

which is the measure of angle FHI. This confirms the answers.

Merhaba ;))

Answer:

4.952

#Başarılar

Answer:

Step-by-step explanation:

[tex]\begin{matrix}\space\space&2&3&8&9&\textbf{1}\\ -&1&8&9&3&\textbf{9}\end{matrix}\\\mathrm{The\:bottom\:number\:is\:larger\:than\:the\:upper\:number.\:\:\\Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}\\\mathrm{Borrow\:}1\mathrm{\:from\:}9\mathrm{.\:\:The\:remainder\:is\:}8\\\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{8}&10\\ \space\space&2&3&8&\textbf{\linethrough{9}}&1\\ -&1&8&9&\textbf{3}&9\end{matrix}[/tex]

[tex]\begin{matrix}\space\space&\space\space&\space\space&\space\space&8&\textbf{11}\\ \space\space&2&3&8&\linethrough{9}&\textbf{\linethrough{1}}\\ -&1&8&9&3&\textbf{9}\end{matrix}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{8}&11\\ \space\space&2&3&8&\textbf{\linethrough{9}}&\linethrough{1}\\ -&1&8&9&\textbf{3}&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{5}&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&8&11\\ \space\space&2&\textbf{3}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&\textbf{1}&10&\space\space&8&11\\ \space\space&\textbf{\linethrough{2}}&3&8&\linethrough{9}&\linethrough{1}\\ -&\textbf{1}&8&9&3&9\end{matrix}}{\begin{matrix}\space\space&\textbf{\space\space}&\space\space&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&\textbf{13}&\space\space&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{3}}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&\textbf{12}&10&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{13}}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&12&\textbf{18}&8&11\\ \space\space&\linethrough{2}&\linethrough{13}&\textbf{\linethrough{8}}&\linethrough{9}&\linethrough{1}\\ -&1&8&\textbf{9}&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{\space\space}&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&12&\textbf{18}&8&11\\ \space\space&\linethrough{2}&\linethrough{13}&\textbf{\linethrough{8}}&\linethrough{9}&\linethrough{1}\\ -&1&8&\textbf{9}&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{9}&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&\textbf{12}&18&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{13}}&\linethrough{8}&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{4}&9&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&\textbf{1}&12&18&8&11\\ \space\space&\textbf{\linethrough{2}}&\linethrough{13}&\linethrough{8}&\linethrough{9}&\linethrough{1}\\ -&\textbf{1}&8&9&3&9\end{matrix}}{\begin{matrix}\space\space&\textbf{0}&4&9&5&2\end{matrix}}\\\\=4952[/tex]