Answer:
141 mphExplanation:
aver. velocity = distance over time
= 500 miles
3 hours + (33 min. x 1 hr. )
60 min.
= 500 miles
3.55 hours
= 140.845 ≈ 141 miles / hour
Imagine holding two identical bricks under water. Brick A is just beneath the surface of the water, while brick B is at a greater depth. What is the force needed to hold brick B in place? (Assume the density of water doesn't change with height.) a) the same as b) larger c) smaller than the force required to hold brick A in place.
Answer:
I think it's c
Explanation:
The brick's mass, helps to hold it under the water but brick A is being held up. If you dropped the brick, it would sink to the bottom. You need a stronger force to hold it up.
Hope this helps you! x
Buoyancy force is needed to hold brick B in place.
What is force?
A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Upthrust, often known as buoyancy, is an upward force applied by a fluid against the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth. The brick's mass, helps to hold it under the water but brick A is being held up. If you dropped the brick, it would sink to the bottom. You need a stronger force to hold it up.
Buoyancy force is needed to hold brick B in place.
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A student puts a besker of warm water next to a besker of cold water so that they fough which two statements are true? DA Thermal energy will move from the warm water to the cold water Thermal energy will move from the air to the cold water. Thermal energy utill move from the air to the warm water Thermal energy till move from the cold water to the warm water
Explanation:
so sorry
don't know but please mark me as brainliest please
Which dwarf planet has a moon nearly as large as itself?
Answer:
The answer is the Pluto.
what are fundamental quantities
Answer: length, luminous intensity,mass, time, temperature, electric current, amount of a substance.
Explanation:
A particle with charge q and mass m moving with speed v in the x direction enters a magnetic field of strength B pointing in the y direction. The magnitude of the acceleration of the particle as it travels one semicircle is
Answer:
The acceleration of the particle as it travels one semicircle is
[tex]a= \frac{\pi R}{t^2}[/tex]
Explanation:'
Kindly see attached a sketch of a semi-circle
Step one:
given data
velocity =v
let the time taken be t
The path PQM is the distance covered
so distance [tex]d= \pi R[/tex]
we know that time= distance/velocity
t= πR/v
step two:
velocity =distance/time
[tex]velocity=\frac{\pi R}{t}[/tex]
also, we know that acceleration is velocity/time
[tex]a= \frac{\pi R}{\frac{t}{t} }[/tex]
[tex]a= \frac{\pi R}{t}*\frac{1}{t}[/tex]
[tex]a= \frac{\pi R}{t^2}[/tex]
People have been able to make materials such as fiber optics cables A. using nails and screws. B. using glue and scissors. C. using rocks and stones. D. using science and technology.
Answer:
D
Explanation:
A student drops a 2.4-kg ball. It’s speed right before hitting the ground is 5 m/s. If 15 J of energy was transferred to the environment as the ball fell, what was the total initial energy of the ball?
21 J
30 J
45 J
6 J
The answer is 45J
Don’t know how to explain sorry
Someone help me please.
Answer:
ionic
ionic
covalent
covalent (i think)
Explanation:
ionic= donate electrons (gain/lose)... (results in ions that have +/- charge, are no longer neutral)
covalent= share electrons
The density for gold is 19.3 g/cm3. What would be the mass of a 45 cm3 piece of gold?
Answer:
868.5 g
Explanation:
Mass= Density x Volume
Mass= 19.3 x 45
=868.5
Answer:
675.5g
Explanation:
The formula for density is: D = m/V.
To solve this problem, we need to rearrange this formula to solve for mass:
m = D x V.
Next, we plug the given values in for density, D, and volume, V:
m = 19.3 g/cm3 x 35 cm3
So, m = 675.5 g
A 65-turn coil has a diameter of 14 cm. Find the magnitude of the emf induced in the coil (in V) if it is placed in a spatially uniform magnetic field of magnitude 0.65 T so that the face of the coil makes the following angles with the magnetic field, and the magnetic field is reduced to zero uniformly in 0.2 s.
Answer:
The value is [tex]\epsilon = 3.24 \ V[/tex]
Explanation:
From the question we are told that
The number of turns is n = 65
The diameter is [tex]d = 14 \ cm = 0.14 \ m[/tex]
The magnetic field is [tex]B_1 = 0.65 \ T[/tex]
The time taken for the magnetic field to be reduced to [tex]B_2 = 0 \ T[/tex] is [tex]\Delta t = 0.2 s[/tex]
Generally the magnitude of the induced emf is mathematically represented as
[tex]\epsilon = N * \frac{B_1 - B_2}{\Delta t } * A[/tex]
Here A is the area of the coil which is mathematically represented as
[tex]A = \pi * \frac{d^2}{4}[/tex]
=> [tex]A = 3.142 * \frac{0.14^2}{4}[/tex]
=> [tex]A = 0.0154 \ m^2[/tex]
So
[tex]\epsilon = 65 * \frac{0.65 - 0 }{0.2 } * 0.01534[/tex]
=> [tex]\epsilon = 3.24 \ V[/tex]
does water not have anomalous expansion?
Explanation:
The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense. ... The density becomes less and less as it freezes because molecules of water normally form open crystal structures when in solid form.
A copper block rests 17.4 cm from the center of a steel turntable. The coefficient of static friction between block and surface is 0.465. The turntable starts from rest and rotates with a constant angular acceleration of 0.406 rad/s 2 . The acceleration of gravity is 9.8 m/s 2 . After what interval will the block start to slip on the turntable
Answer:
12.61 s
Explanation:
Given that
Distance from the center if the turntable, r = 17.4 cm = 0.174 m
Coefficient of static friction, μ = 0.465
Angular acceleration, α = 0.406 rad/s²
Acceleration due to gravity, g = 9.8 m/s²
We know that
F_max = μmg
Also, we know that
F = mω²r
Now, for slip to occur, both forces must be equal to one another, and thus
mω²r = μmg
ω²r = μg
ω² = μg/r
ω² = (0.465 * 9.8)/0.174
ω² = 4.557 / 0.174
ω² = 26.19
ω = √26.19
ω = 5.12 rad/s
t = ω/α
t = 5.12/0.406
t = 12.61 s.
Thus, after 12 seconds, the block will start to slip on the turntable
I need help with this science work
Please tell us the question and we will try to answer.
What are the two main regions of the body?
cranial and spinal
axial and appendicular
trunk and limbs
muscular and skeletal
Answer: Your correct answer would be the second option; axial and appendicular. The axial region makes up the axis of the human body, this includes your head, neck, etc. The appendicular region makes up the parts of the human body that connects to the axial region, for example limbs and appendages.
Light of wavelength 400 nm falls on a metal surface having a work function 1.70 eV. What is the maximum kinetic energy of the photoelectrons emitted from the metal?
a. 4.52 eV
b. 3.11 ev
c. 141 eV
d. 2.82 eV
e. 1.70 eV
Answer:
Ke = 1.41 eV
Explanation:
We know that
h = 6.626 x 10⁻²⁴
c = 3 x 10⁸
λ = 4 x 10⁻⁹ x 1.6 x 10⁻¹⁹
Computation:
Ke = [hc / λ] - w
Ke = [(6.626 x 10⁻²⁴)(3 x 10⁸) / (4 x 10⁻⁹ x 1.6 x 10⁻¹⁹)] - 1.70
Ke = 1.41 eV
At the focal point of a converging lens, the object cannot be seen. O A. True B. False
Answer: True
Explanation: Guessed on A p E x and it was correct
Answer:
True
Explanation:
a p e x
If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how much power was used?
Answer: 207 W
Explanation: I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:
where
m = 47 kg is the mass of the object
g = 9.8 m/s^2 is the acceleration of gravity
is the change in height
Substituting,
Now we can calculate the power used, which is given by
Hope this helps I'm sorry if i'm wrong but I tried :(
If the light ray moves from inside the glass toward the glass–air interface at an angle of 30.0° to the normal, determine the angle of refraction.
Answer:
This question is incomplete
Explanation:
This question is incomplete, however, the relationship to between the angle of incidence and angle of refraction is best explained by snell's law with the equation below
ni sinθi = nr sinθr
where ni is the refractive index of the incident medium (assuming it's plate glass then 1.52)
nr is the refractive index of the refractive medium (1.33)
θi is the angle of incidence (30°)
θr is the angle of refraction (X)
If we substitute the values, we have
1.52 × sin 30 = 1.33 × sin X
1.52 × 0.5 = 1.33 × sin X
0.75 = 1.33 × sin X
sin X = 0.75/1.33
sin X = 0.571
X = sin⁻¹ 0.571
X = 34.82°
Thus, the angle of refraction will be 34.82°
Two men, Joel and Jerry, push against a wall. Jerry stops after 10 min, while Joel is able 1) to push for 5.0 min longer. Compare the work they do. A) Both men do positive work, but Joel does 25% more work than Jerry. B) Both men do positive work, but Joel does 75% more work than Jerry. C) Both men do positive work, but Jerry does 50% more work than Joel. D) Both men do positive work, but Joel does 50% more work than Jerry E) Neither of them does any work.
Answer:
the correct answer is E
Explanation:
Work is defined by the expression
W = F. d
Where the bold indicates vectors, we can make the dot product explicit
W = F d cos θ
We can see that this definition of work the two men apply a force, but the wall does not move, so if there is no displacement the work is zero.
When checking the correct answer is E
When a satellite is in orbit around the Earth, the force of the gravity on the satellite is...
Answer:
Is always towards the center of the Earth
Explanation:
Gravity pushes against all objects, trying to crush it. What pushes against gravity in: a main sequence star, a white dwarf, a neutron star, and a black hole?
Answer:
heat pressure, neutron degeneracy, electron degeneracy,nothing.
Explanation:
In main sequence star, gravity's inward pull is greatly balanced by the heat pressure. In the white dwarf, gravity is mainly balanced by the electron degeneracy pressure that arises from the fact that the electrons are fermions and they obey the Pauli's exclusion principle. So there is no two electrons that have the same the four quantum numbers.
While in neutron star, the neutron degeneracy pressure obeys the Pauli's exclusion principle that gives rise to the degeneracy pressure and noting pushes against the gravity in the black hole. Therefore the correct option is the heat pressure, neutron degeneracy, electron degeneracy and nothing.
While Barb was playing soccer, she was kicked in the anterior thigh by an opposing teammate. Due to this injury, what muscle function may she find difficult to perform?
Answer:
knee extension is the muscle function that will be difficult to perform.
Explanation:
Barb was kicked in the anterior thigh. Now, the thigh muscles performs a combined operation of moving the knee and leg and they reside in the following compartments.
- Anterior compartment which is composed of knee joint extension and thigh flexion.
- Lateral Compartment which is composed of the tensor fasciae latae, which is a tiny muscle that abducts and centrally will make the thigh to rotate.
-Medial compartment which involves thigh addiction which is rotating of the thigh around the hips.
- Posterior compartment which involves knee joint flexion and high extension.
Thus, from the different compartments listed above, we can see that the muscles that extend the knee and flex the thigh all lie in the anterior compartment of the upper leg.
Thus, we can conclude that knee extension is the muscle function that will be difficult to perform.
Only 35 % of the intensity of a polarized light wave passes through a polarizing filter. What is the angle between the electric field and the axis of the filter
Answer:
The angle between the electric field and the axis of the filter is 54⁰
Explanation:
Apply the equation for intensity of light through a polarizer.
[tex]I = I_oCos^2 \theta[/tex]
where;
I is the intensity of the transmitted light
I₀ is the intensity of the incident light
θ is the incident angle
If only 35 % of the intensity of a polarized light wave passes through a polarizing filter, then the ratio of the intensity of the transmitted light to that of the intensity of the incident light is given by;
[tex]\frac{I}{I_o} = Cos^2 \theta\\\\\frac{35}{100} = Cos^2 \theta\\\\Cos^2 \theta = 0.35\\\\Cos\theta = \sqrt{0.35} \\\\Cos\theta = 0.5916\\\\\theta = Cos^{-1}(0.5916)\\\\\theta = 54 ^0[/tex]
Therefore, the angle between the electric field and the axis of the filter is 54⁰
The angle between the electric field and the axis of the filter for the polarized light wave which passes through a polarizing filter is 54°.
What is electric field?The electric field is the field, which is surrounded by the electric charged. The electric field is the electric force per unit charge.
From the Malus's law, the intensity of the polarized beam can be calculated with the following formula.
[tex]I=I_o\cos^2\theta[/tex]
Here, (I₀) is the intensity of the polarized beam incident on the observer θ is the angle of incident.
It is given that only 35 % of the intensity of a polarized light wave passes through a polarizing filter.
The angle between the electric field and the axis of the filter can be found out using the above formula as,
[tex]35\%=(100\%)\cos^2\theta\\\theta=\cos^{-1}\sqrt{\left(\dfrac{35}{100}\right)}\\\theta=54^o[/tex]
Hence, the angle between the electric field and the axis of the filter for the polarized light wave which passes through a polarizing filter is 54°.
Learn more about electric field here;
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An object has density rho.
a. Suppose each of the object's three dimensions is increased by a factor of 2 without changing the material of which the object is made. Will the density change? If so, by what factor? Explain.
b. Suppose each of the object's three dimensions is increased by a factor of 2 without changing the object's mass. Will the density change? If so, by what factor? Explain.
Answer:
a. the density will not change
b. D' = 0.125 D
So, the density will change by a factor of 0.125
Explanation:
a.
Density is the material property and the value of density is constant for all solid materials. So, when the dimensions of the a solid are increased, while the material is same, then the material must be added to the object for increasing its dimensions. So, with the increase in the volume, the mass of the object also increases. And as a result the density of the object remains constant.
Since, here the material remains the same.
Therefore, the density will not change
b.
Density = mass/Volume
D = m/V ------------ equation (1)
Now,
V = LWH ----------- equation (2)
Now, if each dimension increases by a factor of 2, the volume becomes:
V' = (2L)(2W)(2H)
V' = 8 LWH
using equation (2)
V' = 8 V
So, for constant mass, density becomes:
D' = m/V'
D' = m/8V
using equation (1)
D' = D/8
D' = 0.125 D
So, the density will change by a factor of 0.125
(a) The density of the object will be reduced by one-eighth times on increasing the dimension by a factor of two and keeping the material constant.
(b) With constant mass and increasing the dimensions by a factor of 2, the density will reduce by the factor of 1/8.
What is density of object?The degree measure of the compactness of an object is known as the density of an object. Mathematically, it is expressed as the ratio of the mass of the object to its volume.
(a)
Let us consider an object of dimension 'a'. As per the above definition, the density of an object is,
[tex]\rho = \dfrac{m}{V}[/tex]
Here,
m is the mass of the object.
V is the volume of the object. And its value is, [tex]V = a^{3}[/tex].
So the density becomes,
[tex]\rho = \dfrac{m}{a^{3}}[/tex] ..............................................................(1)
Now, if the dimensions of the object is increased by a factor of 2. Then, new density becomes,
[tex]\rho' =\dfrac{m}{(2a) \times (2a) \times (2a)}\\\\\\ \rho' =\dfrac{m}{8a^{3}}\\\\[/tex]
Substitute the value of equation (1) in the above expression as,
[tex]\rho' =\dfrac{1}{8} \times \dfrac{m}{a^{3}}\\\\\rho' =\dfrac{1}{8} \times \rho[/tex]
Thus, we can conclude that the density of the object will be reduced by one-eighth times on increasing the dimension by a factor of two and keeping the material constant.
(b)
The density of the material is equal to the ratio of the mass of the object (m) and the volume of the object (V). So, if the mass remains unchanged and the dimensions increased by the factor of 2, then the result will remain same as the above part.
Thus, we can conclude that with constant mass and increasing the dimensions by a factor of 2, the density will reduce by the factor of 1/8.
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A ferry crossed the Potomac River four times in one day. The ferry traveled the same distance for each trip, but it took different amounts of time. The time for each trip is shown in the table below. Time for Ferry to Cross on Different Trips Trip Number Time Trip 1 10 minutes Trip 2 11 minutes Trip 3 9 minutes Trip 4 12 minutes On which trip did the ferry travel the fastest? A. Trip 3 B. Trip 2 C. Trip 4 D. Trip 1
Explanation:
trip 3 ( 9 minutes)
If the ferry is moving at a faster speed, it will travel the same distance in a shorter time. The ferry crossed the river the fastest on Trip 3 because it took the shortest amount of time on that trip.
What's the temperature 414K in degrees Celsius?
Answer:
212 I think
Explanation:
I looked it up
A 1000 kg car and a 2000 kg car are lifted the same distance in a
mechanic's shop. Neglecting friction, raising the more massive car
requires
Answer:
Twice as much work
Explanation:
A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If the spider has a mass of 1.27 g, what is the tension in the web
Answer:
Tension = 0.012 N
Explanation:
If the black widow spider is hanging vertically motionless from the ceiling above. Then, the weight of the spider must be balancing the tension in the spider web. Therefore,
Tension = Weight
Tension = mg
where,
m = mass of spider = 1.27 g = 0.00127 kg
g = acceleration due to gravity = 9.8 m/s²
Therefore,
Tension = (0.00127 kg)(9.8 m/s²)
Tension = 0.012 N
Under what conditions the reaction rate of an enzymolysis that follows Michaelis-Menten kinetics is a quarter of its maximum value?
a. [S]=KM
b. [S]=KM/3
c. [S]=2KM
d. [S]=KM+3
e. [S]= (KM)^1/3
Solution :
Michaelis-Menten kinetics in the field of biochemistry is considered as one of the well known models for enzyme kinetics. The model represents an equation that describes the enzymatic reactions's rate by relating the reaction rate to the substrate's concentration. The equation is named after the two famous scientists, Leonor Michaelis and Maud Menten.
The formula is :
[tex]$v=\frac{V_{max}[S]}{K_M + [S]}$[/tex]
where v = velocity of reaction
[tex]$V_{max}$[/tex] = maximum rate achieved
[tex]$K_M$[/tex] = Michaelis constant
[S] = concentration of the substrate, S
According to the question, by putting the velocity of reaction, v as [tex]$\frac{V_{max}}{4}$[/tex], we get the above equation as
[tex]$[S]= \frac{K_M}{3}$[/tex]
Therefore the answer is [tex]$[S]= \frac{K_M}{3}$[/tex]
please help im failing!!!