If, instead, the mass remained the same as the original problem, but the spring was replaced by one with a spring constant that was four times as large, the period would be:__________

Answers

Answer 1

Answer:

T = [tex]1/2\pi \sqrt (k/m) \\[/tex] so period of mass spring system becomes 2 times w.r.t original problem.

Explanation:

[tex]T =1/2\pi \sqrt(k/m)\\[/tex] so when k = 1 is replaced by 4 it means it becomes

k" = 4k

[tex]T' = 1/2\pi \sqrt(k'/m)\\T' = 1/2\pi \sqrt(4k/m)\\T' = 2(1/2\pi\sqrt(k/m)\\)\\T' = 2T[/tex]


Related Questions

what is simple harmonic motion
give two examples

Answers

Answer:

S.H.M:- If the acceleration of the vibrating body directly varies with the displacement of the body from the mean position and always directed to the mean position, the motion of that body is called simple harmonic motion.

Ex:- (i) The motion of a pendulum is an S.H.M.

(ii) The motion of vibrating mass attached to a spring is an S.H.M.

Ex1- Swing

Swings that we see in the park is an example of simple harmonic motion

Ex2- Hearing

The process of hearing is is impossible without simple harmonic motion. The sound waves that enter our ear causes the eardrum to vibrate back and forth

Bonus Ex- cradle

The back and forth movement of the cradle caused due to a single push and is maintained by the principle of SHM, and hence, caused the baby to sleep.

Hope it helps

Light of wavelength 400 nm falls on a metal surface having a work function 1.70 eV. What is the maximum kinetic energy of the photoelectrons emitted from the metal?

a. 4.52 eV
b. 3.11 ev
c. 141 eV
d. 2.82 eV
e. 1.70 eV

Answers

Answer:

Ke = 1.41 eV

Explanation:

We know that

h = 6.626 x 10⁻²⁴

c = 3 x 10⁸

λ = 4 x 10⁻⁹ x 1.6 x 10⁻¹⁹

Computation:

Ke = [hc / λ] - w

Ke = [(6.626 x 10⁻²⁴)(3 x 10⁸) / (4 x 10⁻⁹ x 1.6 x 10⁻¹⁹)] - 1.70

Ke = 1.41 eV

What is the best description for a transverse wave? *
A.The movement of the atoms around the wave is parallel to the movement of the ENERGY it is transferring.
B.The movement of the atoms around the wave is parallel to the movement of the MATTER it is transferring.
C.The movement of the atoms around the wave is perpendicular to the movement of the energy it is transferring.
D.The movement of the atoms around the wave is perpendicular to the movement of the matter it is transferring.

Answers

Answer:

Option - C

Hope it helps you

Which vocabulary word would describe both a cell membrane and a screen door?

Answers

Answer:

flexible covering

Explanation:

A machinist with normal vision has a near point at 25 cm. This machinist wears +4.25-diopter eyeglasses in order to do very close work. With these eyeglasses, what is the near point of the machinist?

a. 12 cm
b. 10 cm
c. 7 cm
d. 15 cm
e. 17 cm

Answers

Answer: 12cm.

Explanation:

First we need to calculate the focal length which will be:

= 100 / 4.25

= 23.529

The near point of the machinist will be solved using the equation:

1/u + 1/v = 1/f

where,

v = -25

f = 23.529

1/u + 1/v = 1/f

1/u - 1/25 = 1/23.529

1/u = 1/23.529 + 1/25

u = 12.12cm

u = 12cm approximately

Therefore, the near point of the machinist is 12cm

I’m testing if this app works.What is gravity?

Answers

Answer:

Gravity, or gravitation, is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward one another. On Earth, gravity gives weight to physical objects, and the Moon's gravity causes the ocean tides. 

If the hiker starts climbing at an elevation of 350 ft, what will their change in gravitational potential energy be, in joules, once they reach the top

Answers

Answer:

352,088.37888Joules

Explanation:

Complete question;

A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.

A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)

Chane in potential energy is expressed as;

ΔGPH = mgΔH

m is the mass of the hiker

g is the acceleration due to gravity;

ΔH is the change in height

Given

m = 53kg

g = 9.8m/s²

ΔH = 2574-350 = 2224ft

since 1ft = 0.3048m

2224ft = (2224*0.3048)m = 677.8752m

Required

Gravitational potential energy

Substitute the values into the formula;

ΔGPH = mgΔH

ΔGPH = 53(9.8)(677.8752)

ΔGPH = 352,088.37888Joules

Hence the gravitational potential energy is 352,088.37888Joules

The change in gravitational potential energy be, once the hiker reach the top of the mountain is 352088 joules or 352.1 kJ.

What is gravitational potential energy?

Gravitational potential energy is the energy which a body posses because of its position.

The gravitational potential energy of a body is given as,

[tex]U=mgh[/tex]

Here, (m) is the mass of the body, (g) is the gravitational force and (h) is the height of the body.

The mass of the hiker is 53 kg and the height of the climb is 2574 ft.

Now, the hiker starts climbing at an elevation of 350 ft. Thus, the net height of the hiker has to climb is,

[tex]h=2574-350\\h=2224\rm\; ft[/tex]

Convert this into the meter by multiplying 03048 as,

[tex]h=2224\times0.3048\\h=677.8752\rm\; m[/tex]

It is known that the value of g is 9.8 m/s². Plug in all the values as,

[tex]U=53\times9.8\times677.8752\\U=352088J\\U=352.1 \;\rm kJ[/tex]

Thus, the change in gravitational potential energy be, once the hiker reach the top of the mountain is 352088 joules or 352.1 kJ.

Learn more about the gravitational potential energy here;

https://brainly.com/question/15896499

the force of gravity acting on an object is known as

Answers

it’s known as the weight of an object

n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Use the measured length to predict the theoretical pendulum period with a range of error (use the error propagation method you learned in Lab 1). ii. Compute the percentage difference (as defined in Lab 1) between the measured value and the predicted value .

Answers

Answer:

The answer is "[tex](1.265 \pm 0.010) \ s \ and \ 0.709 \%[/tex]"

Explanation:

In point i:

[tex]T_{theo}= 2\pi \sqrt{\frac{l}{g}}[/tex]

        [tex]=2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s[/tex]

If  error in the theoretical time period :

[tex]\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2} \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}[/tex]

           [tex]= 0.010 \ s[/tex]

 [tex]T_{theo} = (1.265 \pm 0.010) \ s[/tex]

In point ii:

[tex]\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100[/tex]

                    [tex]= \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%[/tex]

Calculate the rotational inertia of a meter stick, with mass 0.499 kg, about an axis perpendicular to the stick and located at the 35.2 cm mark. (Treat the stick as a thin rod.)

Answers

Answer:

The rotational inertia of the meter stick is 0.0618 kgm².

Explanation:

Given;

mass of the meter stick, m = 0.499 kg

perpendicular distance to the rotational axis, r = 35.2 cm = 0.352 m

The rotational inertia or moment of inertia for a point mass is given by;

I = mr²

where;

m is the point mass

r is the perpendicular distance

Substitute the givens and solve for moment of inertia.

I = (0.499)(0.352)²

I = 0.0618 kgm²

Therefore, the rotational inertia of the meter stick is 0.0618 kgm².

If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how much power was used?

Answers

Answer: 207 W

Explanation: I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:

where

m = 47 kg is the mass of the object

g = 9.8 m/s^2 is the acceleration of gravity

is the change in height

Substituting,

Now we can calculate the power used, which is given by

Hope this helps I'm sorry if i'm wrong but I tried :(

What form of energy is released into the atmosphere by the earth's surface

Answers

Answer:

Thermal Energy (Heat)

Answer:

Heat

Explanation:

the form that is raised from the atmosphere from earths surface is heat

Calculate the pressure in pascals if a 560N is applied to an area of 1.6m².​

Answers

Answer:

P = 350 [Pa]

Explanation:

The pressure is calculated by knowing the force and area. By means of the following formula can be calculated by means of the following equation.

Units of 1 [Pa] = 1 [N/m²]

P = F/A

where:

P = pressure [Pa]

F = force = 560 [N]

A = area = 1.6 [m²]

P = 560/1.6

P = 350 [Pa]

A copper block rests 17.4 cm from the center of a steel turntable. The coefficient of static friction between block and surface is 0.465. The turntable starts from rest and rotates with a constant angular acceleration of 0.406 rad/s 2 . The acceleration of gravity is 9.8 m/s 2 . After what interval will the block start to slip on the turntable

Answers

Answer:

12.61 s

Explanation:

Given that

Distance from the center if the turntable, r = 17.4 cm = 0.174 m

Coefficient of static friction, μ = 0.465

Angular acceleration, α = 0.406 rad/s²

Acceleration due to gravity, g = 9.8 m/s²

We know that

F_max = μmg

Also, we know that

F = mω²r

Now, for slip to occur, both forces must be equal to one another, and thus

mω²r = μmg

ω²r = μg

ω² = μg/r

ω² = (0.465 * 9.8)/0.174

ω² = 4.557 / 0.174

ω² = 26.19

ω = √26.19

ω = 5.12 rad/s

t = ω/α

t = 5.12/0.406

t = 12.61 s.

Thus, after 12 seconds, the block will start to slip on the turntable

Under what conditions the reaction rate of an enzymolysis that follows Michaelis-Menten kinetics is a quarter of its maximum value?

a. [S]=KM
b. [S]=KM/3
c. [S]=2KM
d. [S]=KM+3
e. [S]= (KM)^1/3

Answers

Solution :

Michaelis-Menten kinetics in the field of biochemistry is considered as one of the well known models for enzyme kinetics. The model represents an equation that describes the enzymatic reactions's rate by relating the reaction rate to the substrate's concentration. The equation is named after the two famous scientists,  Leonor Michaelis and Maud Menten.

The formula is :

[tex]$v=\frac{V_{max}[S]}{K_M + [S]}$[/tex]

where v = velocity of reaction

           [tex]$V_{max}$[/tex] = maximum rate achieved

           [tex]$K_M$[/tex] = Michaelis constant

           [S] = concentration of the substrate, S

According to the question, by putting the velocity of reaction, v as [tex]$\frac{V_{max}}{4}$[/tex], we get the above equation as

[tex]$[S]= \frac{K_M}{3}$[/tex]

Therefore the answer is [tex]$[S]= \frac{K_M}{3}$[/tex]

A metallic spherical shell has a charge density of 1 mC/m2 on its surface. The shell has radius of 7.5 cm. Determine the electric field magnitude (in kV/m) 10 meters away from the center of the shell.

Answers

Answer:

Explanation:

charge on the shell = 4πR²  x charge density

= 4 x 3.14 x 7.5² x 10⁻⁴ x 10⁻³ C

= 706.5 x 10⁻⁷ C  

electric field = k Q / d² , d is distance of point from centre

= 9 x 10⁹ x 706.5 x 10⁻⁷ / 10²

= 6358.5 N /C

= 6.358 kV / m

A group of students conduct an experiment with a block of wood sliding down an incline. They find that the final energy of the block is less than the initial energy of the block. Which statement best describes this situation?

A. The students made an error in deterring the final energy.
B. The students made an error in calculating the initial energy.
C. Some energy was transformed to other forms.
D. Some energy was destroyed or lost.

Answers

The answer is C) energy was lost to heat and sound

I need help ASAP
The water cycle functions because the matter in water changes:

a.forms
b.properties
c.minerals

Answers

Answer:

(a). forms.

Explanation:

Bro even i ain't sure.

Answer:

I think its A? Because in the water cycle it goes from a liquid to a gas?

Explanation:

Artificial gravity is a must for any space station if humans are to live there for any extended length of time. Without artificial gravity, human growth is stunted and biological functions break down.


An effective way to create artificial gravity is through the use of a rotating enclosed cylinder, as shown in the figure. Humans walk on the inside of the outer edge of the cylinder, which has a diameter of =3335 m that is large enough such that its curvature is not readily noticeable to the inhabitants. (The space station in the figure is not drawn to scale.)


Once the space station is rotating at the necessary angular speed to create an artificial gravity of 1 , how many minutes would it take the space station to make one revolution?


I did [tex]2\pi \sqrt{\frac{1667.6}{9.8} } =81.96[/tex] then I converted 81.96 to minutes which was 1.4 but it still got marked wrong. 81.96 was wrong as well. Am I using the wrong equation for it? I'm not sure what to do.

Answers

The period of the enclosed cylinder is approximately 115.866 seconds.

The rotating enclosed cylinder is rotating at constant angular speed ([tex]\omega[/tex]), in radians per second, which means that experiments a constant radial angular acceleration ([tex]\alpha[/tex]), in radians per square second. Then, we derive an expression for the period of the cylinder, this is, the time needed by the cylinder to make one revolution:

[tex]g = \omega^{2}\cdot R[/tex] (1)

Where:

[tex]g[/tex] - Gravitational acceleration, in meters per square second. [tex]R[/tex] - Radius of the enclose cylinder, in meters.

[tex]g = \frac{4\pi^{2}\cdot R}{T^{2}}[/tex]

[tex]T = 2\pi\cdot \sqrt{\frac{R}{g} }[/tex] (2)

Where [tex]T[/tex] is the period, in seconds.

If we know that [tex]R = 3335\,m[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the period of the enclosed cylinder is:

[tex]T = 2\pi\cdot \sqrt{\frac{3335\,m}{9.807\,\frac{m}{s^{2}} } }[/tex]

[tex]T \approx 115.866\,s\,(1.931\,min)[/tex]

The period of the enclosed cylinder is approximately 115.866 seconds.

We kindly invite to check this question on circular motion: https://brainly.com/question/2285236

When a 20.0-ohm resistor is connected across the terminals of a 12.0-V battery, the voltage across the terminals of the battery falls by 0.300 V. What is the internal resistance of this battery?

a. 3.60 Ω
b. 0.51 Ω
c. 0.30 Ω
d. 1.56 Ω
e. 0.98 Ω

Answers

Answer:

B. 0.51 ohms

Explanation:

Our data is as follows:

Resistor R = 20.0ohms

V1 = 12 volts

V2 = 0.300 V

We are to get the internal resistance of this battery

Now,

I = change in voltage/R

Change in voltage = v1-v2

= 12-0.300

= 11.7

Then,

I = 11.7/20

= 0.585Ri

Now

O.300 = 0.585Ri

Ri = 0.300/0.585

= 0.51 ohms

This is therefore the internal resistance of the battery.

Thank you!

If the light ray moves from inside the glass toward the glass–air interface at an angle of 30.0° to the normal, determine the angle of refraction.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete, however, the relationship to between the angle of incidence and angle of refraction is best explained by snell's law with the equation below

ni sinθi = nr sinθr

where ni is the refractive index of the incident medium (assuming it's plate glass then 1.52)

nr is the refractive index of the refractive medium (1.33)

θi is the angle of incidence (30°)

θr is the angle of refraction (X)

If we substitute the values, we have

1.52 × sin 30 = 1.33 × sin X

1.52 × 0.5 = 1.33 × sin X

0.75 = 1.33 × sin X

sin X = 0.75/1.33

sin X = 0.571

X = sin⁻¹ 0.571

X = 34.82°

Thus, the angle of refraction will be 34.82°

frequency of a vibrating string with a period of 4 seconds ​

Answers

Answer: 2 Hz (8 cycles/4 s = 2 cycles/s).

Explanation:

If a coil of slinky makes 3 vibrational cycles in one second, then the frequency is 3 Hz. And if a coil makes 8 vibrational cycles in 4 seconds, then the frequency is 2 Hz (8 cycles/4 s = 2 cycles/s).

find the mass of an object with a density of 1.5 g/cm^3 and had a volume of 8cm^3

Answers

Answer:

12 g

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 1.5 × 8

We have the final answer as

12 g

Hope this helps you

Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.330 mm wide. The diffraction pattern is observed on a screen 2.55 m away. Define the width of a bright fringe as the distance between the minima on either side.

a. What is the width of the central bright fringe?
b. What is the width of the first bright fringe on either side of the central one?

Answers

Answer:

a)   y_total = 19.916 10⁻⁵ m ,   b)    Δθ = 1.91 10-⁻³ rad

Explanation

This is a diffraction exercise that is described by the expression

          a sin θ = m λ

the first minimum occurs for m = 1

         a sin θ = λ

        sin θ = λ / a

        θ = sin⁻¹ (633 10⁻⁹ / 0.330 10⁻³)

        θ = 1.918 10⁻³ rad

let's use trigonometry

        tan θ = y / x

        y = x tan θ

        y = 2.55 tan (3.936 10-3)

        y = 5.75 10⁻- m

this value is from the central maximum to one extreme of the value,

        y_ total = 2 y

        y_total = 2 (5.75e1)

        y_total = 19.916 10⁻⁵ m

b) For the second point and constructive inference we have m = 2

         sin θl = m λ

         θ = sin⁻¹ (lat / a)

         θ = sin⁻¹ (2 633 10-9 / 0.33010-3) = son-1 (3.836 10-3)

         θ = 3.84 10-3 give

The width of this maximum is

          Δθ = 1.3 10-3

          Δθ = 3.84 10⁻³- 1.918 10⁻³

          Δθ = 1.91 10-⁻³ rad

For a 99 kg person standing at the equator, what is the magnitude of the angular momentum about Earth's center due to Earth's rotation?

Answers

Answer:

L = 4.58 x 10⁴ kg.m²/s

Explanation:

The angular momentum is given by the formula:

L = mvr

but, v = rω

Therefore,

L = mr²ω

where,

L = Angular Momentum of the person = ?

m = mass of person = 99 kg

r = radius of earth = 6.37 x 10⁶ m

ω = Angular Speed of Earth's Rotation = θ/t

Since, earth completes 1 rotation in 1 day. Hence,

ω = (2π rad/1 day)(1 day/24 h)(1 h/3600 s)

ω =  7.27 x 10⁻⁵ rad/s

Therefore,

L = (99 kg)(6.37 x 10⁶ m)²(7.27 x 10⁻⁵ rad/s)

L = 4.58 x 10⁴ kg.m²/s

What is a possible equation fir an ionic compound with calcium

Answers

Answer:

CaO, CaMg, or CaF2

Ca2Cl, CaNa, or CaP

CaF, CaMg, or CaNa

CaO, CaF2, or CaCl2

Explanation: i think

What is your worldview? Explain?

Answers

Answer:

My worldview is that the world is a beautiful place. IT has many wonders, and many kind people. There are also very nice places, governments, tech and more.

This is a graph of a car speeding up and then reaching a constant speed of 105 m/s . After it finishes speeding up, how far does the car travel during the last 6 seconds of the graph, from 4 to 10 s?

Answers

Answer:

60 m

Explanation:

Concept Used:

We know that the area under a velocity-time graph represents the Displacement of the body

Displacement in the Last 6 seconds:

To find the Displacement in the last 6 seconds, we will find the area under the graph between x = 4 and x = 10

We can see that the shape formed is a rectangle also shown in the given graph. So, the area of the rectangle is the Displacement of the car in the last 6 seconds

Area of the Rectangle:

From the graph, we know that the rectangle is 10 (m/s) tall and 6 (s) wide

Area of Rectangle=  length*Breadth        

replacing the values

Area = 10 (m/s) * 6 (s)

Area = 60 m

Hence, the car travelled 60 m in the last 6 seconds of the graph

A student puts a besker of warm water next to a besker of cold water so that they fough which two statements are true? DA Thermal energy will move from the warm water to the cold water Thermal energy will move from the air to the cold water. Thermal energy utill move from the air to the warm water Thermal energy till move from the cold water to the warm water ​

Answers

Explanation:

so sorry

don't know but please mark me as brainliest please

1. The resistance of an electric device is 40,000 microhms. Convert that measurement to ohms

2. When an electric soldering iron is used in a 110 V circuit, the current flowing through the iron is
2 A. What is the resistance of the iron?
3. A current of 0.2 A flows through an electric bell having a resistance of 65 ohms. What must be
the applied voltage in the circuit?

Answers

Answer:

(1) 0.04 ohms (2) 55 ohms (3) 13 volt

Explanation:

(1) The resistance of an electric device is 40,000 microhms.

We need to convert it into ohms.

[tex]1\ \mu \Omega =10^{-6}\ \Omega[/tex]

To covert 40,000 microhms to ohms, multiply 40,000 and 10⁻⁶ as follows :

[tex]40000 \ \mu \Omega =40000 \times 10^{-6}\ \Omega\\\\=0.04\ \Omega[/tex]

(2) Voltage used, V = 110 V

Current, I = 2 A

We need to find the resistance of the iron. Using Ohms law to find it as follows :

V = IR, where R is resistance

[tex]R=\dfrac{V}{I}\\\\R=\dfrac{110}{2}\\\\R=55\ \Omega[/tex]

(3) Current, I = 0.2 A

Resistance, R = 65 ohms

We need to find the applied voltage in the circuit. Using Ohms law to find it as follows :

V=IR

V = 0.2 × 65

V = 13 volt

Answer:

1. 0.04 Ohms

2. 55 Ohms

3. 13 Volts

Explanation:

Penn Foster

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