If California experienced drought, which system would be responsible for it and WHY?

Answer:

Spaceship Vibes

Explanation:

Song written by NoCap

Answer: Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

Explanation:

Answer:Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

Explanation:

Answer:

Statement B is the only true statement

"Decreasing the mass of an object increases its acceleration while force is  constant."

Explanation:

Recall that Newton's 2nd Law states:

F = m * a

Therefore, if the force (F) is constant, and the mass (m) decreases, the acceleration (a) of the object must increase.

This agrees with the statement labeled as B: "Decreasing the mass of an object increases its acceleration while force is  constant."

The true statement about the law of acceleration is that decreasing the mass of an object increases its acceleration while force is constant.

NEWTON'S LAW:

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Answer:

False, it is a fuse.

Explanation:

In electronics and electrical engineering, a fuse is an electrical safety device that operates to provide overcurrent protection of an electrical circuit. Its essential component is a metal wire or strip that melts when too much current flows through it, thereby stopping or interrupting the current. It is a sacrificial device; once a fuse has operated it is an open circuit, and must be replaced or rewired, depending on its type.

Fuses have been used as essential safety devices from the early days of electrical engineering. Today there are thousands of different fuse designs which have specific current and voltage ratings, breaking capacity and response times, depending on the application. The time and current operating characteristics of fuses are chosen to provide adequate protection without needless interruption. Wiring regulations usually define a maximum fuse current rating for particular circuits. Short circuits, overloading, mismatched loads, or device failure are the prime or some of the reasons for fuse operation.

A fuse is an automatic means of removing power from a faulty system; often abbreviated to ADS (Automatic Disconnection of Supply). Circuit breakers can be used as an alternative to fuses, but have significantly different characteristics.

Source: https://en.wikipedia.org/wiki/Fuse_(electrical)

A fuse is a small glass or plastic tube that contains a piece of wire. That wire is carefully calibrated so that it will only allow a certain level of current to pass through it. Any more, and the wire will melt from the heat, breaking the circuit. This means that if a power surge comes into your home, a circuit will be broken before it causes damage to your appliances.

A circuit breaker achieves the same thing, but by a different method. A circuit breaker also disconnects the circuits in your home if the current gets too large but does it using electromagnets. If the current gets high enough, then the electromagnet will become powerful enough to attract a contact and break the circuit that way.

Both circuit breakers and fuses can be used to help with another situation. If you have an appliance with a metal case and that appliance comes in contact with a live wire, it can cause you to electrocute yourself. But if that metal case is connected to a ground wire (the third pin in some plugs), then the electricity will flow through the ground wire, through the circuit breaker or fuse box, and break the circuit, stopping you from potentially getting electrocuted.

Source: https://study.com/academy/lesson/the-differences-between-fuses-circuit-breakers.html

Explanation:

All of the ways mentioned can be used to determine the mass of the box and pencils contained.

Answer:

I think it's no. 3

Decrease the volume of the horizontal and vertical stabilizer material.

Explanation:

Lemme know if it's correct

Answer:

all of the above

Explanation:

Explanation:

With the change in medium the speed of light wave travel changes. Therefore, the absolute refractive index changes. The speed of light is maximum is vacuum and changes with the change in medium. This is the refractive indices of different medium are different.

The refractive index is the characteristic of the wave that can not change as the wave enters the second medium.

The refractive index of a substance also known as the refraction index or index of refraction is a dimensionless quantity that specifies how quickly light passes through it in optics.

When the refractive index of a substance is increased, the speed of light in the material decreases.

The speed at which light waves travel changes as the medium changes. The absolute refractive index changes.

As a result, the speed of light is greatest in a vacuum and decreases as the medium changes. This is due to the fact that the refractive indices of various media are different.

Hence the refractive index is the characteristic of the wave that can not change as the wave enters the second medium.

To learn more about the refractive index refer to the link;

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Answer:

My youngins heartless, so they ain't playin' no games

We really want 'em dead, he got hit up close range

He fuc__ked up in the head, he wanna see some more brains

On that corner, I couldn't stay up out that do_0pe game

My cousin got indicted dealin' coc__aine

She an Insta>:gram addict, she want more fame

I used to starve, now I'm blowing up like pro__pane

Told my inner self, "I promise you I won't change"

Explanation:

Answer:

A) Energy is tranferred from Joey to the water. The temperature of the water increases.

Explanation:

At first Joey jumps and gains a height above the water level of the pool, this way has an energy potential initial, as Joey falls into the water his speed is increased that is to say its energy potential is transformed into kinetic energy, and at the moment of impact with the water, this energy kinetic is transformed into heat which is transferred to the water. Therefore the temperature increment.

Note: This is one of the reasons why space agencies are studying  spatial asteroids that are directed toward the earth, as these come with great kinetic energy, and great potential energy, if these are of a considerable size can cause catastrophic damage, even if they fall into the ocean, due to the large amount of energy which can cause the instantaneous evaporation of large amounts of water and collateral damage in other areas.

Answer:

[tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]

Explanation:

From the question we  are told that

Voltage decreases at   [tex]\frac{dv}{dt} =-0.03volts/sec[/tex]

Resistance increase at [tex]\frac{dR}{dt}=0.02ohms /sec[/tex]

Resistance at [tex]R=100ohms[/tex]

Current at [tex]I=0.02amps[/tex]

Generally the equation for ohms law is mathematically represented as

       [tex]V=IR[/tex]

Therefore

       [tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

Generally making [tex]\frac{dI}{dt}[/tex] subject of the formula in the above equation mathematically gives

       [tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

      [tex]R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}[/tex]

       [tex]\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})[/tex]

Therefore

       [tex]\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))[/tex]

Generally it is given that the change in current is

       [tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]

Answer: that the object is negatively charged.

Explanation:

We know that the force between objects that have the same type of charge is a repulsive force, while for objects with an opposite charge, the force is attractive.

In this case, we know that we have an attractive force between an object and a positively charged rod.

Then the only conclusion we can take in this situation is that the object is negatively charged.

Answer:

T on edge

Explanation:

Answer:

true

Explanation:

Answer:

Blank 1: 10

Blank 2: 4

Blank 3: 10

Blank 4: 5

Blank 5: 5

Answer:

[tex]\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}[/tex]

Explanation:

From the given information, the LED is operating with a given wavelength of 850 nm or 0.85 μm.

Hence, the material dispersion is [tex]\dfrac {d \tau _{mat}}{d \lambda } \simeq (80 \ ps / (nm.km) \ )[/tex]

Now, using the pulse spread formula:

[tex]\dfrac{\sigma_{mat}}{L} = \dfrac{d \tau _{mat} }{d \lambda} \sigma \lambda[/tex]

[tex]\dfrac{\sigma_{mat}}{L} = (80 \ ps/ ( m.km) \ ) \times (45 \ nm)[/tex]

Thus, the pulse spreading as a result of  material dispersion is:[tex]\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}[/tex]

The pulses spreading will be 3.6 ns/km. The greatest frequency or the number of pulses per second that may be transmitted into a fiber is pulse spreading.

As an optical pulse travels the length of a fiber, it widens. This feature, which is commonly represented in nanoseconds of widening per kilometer, restricts the usable bandwidth of the Fiber.

The greatest frequency, or the number of pulses per second that may be transmitted into a fiber and anticipated to emerge intact at the other end, has a limit.

This is due to a process known as pulse spreading, which restricts the file's "Bandwidth."

The given data in the problem is;

[tex]\lambda[/tex] is the wavelength = 850 nm

The pulse spreading formula is given as;

[tex]\rm \frac{\sigma_{mat}}{L} =\frac{d \tau_{mat}}{d \lambda} \sigma\lambda \\\\ \rm \frac{\sigma_{mat}}{L} = 80 \times 45 \\\\ \frac{\sigma_{mat}}{L} =3.6 \ ns/km[/tex]

Hence the pulses spreading will be 3.6 ns/km

To learn more about the pulse spreading refer to the link;

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Answer:

force; distance; energy.

Explanation:

An impulse can be defined as the net force acting an object for a very short period of time.

Mathematically, impulse is given by the formula;

[tex] Impulse = force * time[/tex]

An impulse is a force acting over some amount of time to cause a change in momentum. On the other hand, work is a force acting over some amount of distance to cause a change in energy.

Mathematically, work done is given by the formula;

[tex] Work done = force * distance [/tex]

Answer:

11,627.91 kg/m^3

Explanation:

The computation of the density of the material is shown below

Given that

Mass , m = 1 kg

Height, H - 47 mm = 0.047 m

Diameter, d = 49 mm = 0.049 m

Now radius, r = D ÷ 2

= 0.049 ÷ 2

= 0.0245

Volume = πr^2h

= 3.14 × (0.0245)^2 × 0.047

= 0.000086m^3

Now the density of the material is

= mass ÷ volume

=  1÷  0.000086m^3

= 11,627.91 kg/m^3

Answer: 11,282.8 kg/m^3

Explanation:

We know:

Density = mass/volume

1 kg = mass

(π)(r^2)(h) = volume

Density = m/(πr^2h)

Plug in your values:

Density = 1kg/(π)(24.5 mm)^2(47 mm)

^we have to cut 49 (the diameter) in half because the equation calls for radius

Remember to multiply the density by 10^9 mm/ 1 m because the answer asks for kg/m^3

Answer:

We need the question

Explanation:

The answer is the first choice.

Answer:

100m/s²

Explanation:

F=ma

50=0.5a

a=50/0.5

a=100

Answer:

15.106 N

Explanation:

From the given information,

The weight of the bucket can be calculated as:

[tex]W_b = m_bg = \\ \\ W_b = (0.730 \ kg) ( 9.80 \ m/s^2) \\ \\ W_b = 7.154 \ N[/tex]

The mass of the water accumulated in the bucket after 3.20s is:

[tex]m_w= (0.20 \ L/s) ( 3.20)s[/tex]

[tex]m _w=0.64 \ kg[/tex]

To determine the weight of the water accumulated in the bucket, we have:

[tex]W_w = m_w g[/tex]

[tex]W_w = ( 0.64 \ kg )(9.80\ m \ /s^2)[/tex]

[tex]W_w = 6.272 \ N[/tex]

For the speed of the water before hitting the bucket; we have:

[tex]v = \sqrt{2gh}[/tex]

[tex]v = \sqrt{2*9.80 \ m/s^2 * 3.60 \ m}[/tex]

v = 8.4 m/s

Now, the force required to stop the water later when it already hit the bucket is:

[tex]F = v ( \dfrac {dm}{dt} )[/tex]

[tex]F = (8.4 \ m/s)( 0.200 \ L/s)[/tex]

F = 1.68 N

Finally, the reading scale is:

[tex]F_{scale[/tex] = 7.154 N + 6.272 N + 1.68 N

= 15.106 N

Answer:

F_scale ≈ 15.12 N

Explanation:

We are given;

Mass flow rate; m' = 0.2 l/s

Time; t = 3.2 s

Mass of bucket; m_b = 0.730 kg

Height; h = 3.6 m

Now, mass of water is;

m_w = 0.2 l/s × 3.2 s

m_w = 0.64 l

From conversion, 1 litre = 1 kg

Thus: m_w = 0.64 kg

Now, let's calculate final velocity from Newton's third equation of motion.

v² = u² + 2gh

Initial velocity is 0. Thus;

v² = 0 + 2(9.8 × 3.6)

v² = 70.56

v = √70.56

v = 8.4 m/s

Now, total mass of water and bucket is;

m_t = m_w + m_b = 0.64 + 0.73

m_t = 1.37 kg

Force on the scale is calculated from;

F_scale = (m_t)g + (m_w)v/t

F_scale = (1.37 × 9.81) + (0.64 × 8.4/3.2)

F_scale ≈ 15.12 N

Answer:

A circle.

Explanation:

When a charged particle moves perpendicularly to a uniform magnetic field, what best describes its trajectory is a circle.

This ultimately implies that, a charged particle moving perpendicularly to a uniform magnetic field would undergo or experience a uniform circular motion and this simply, describes its trajectory.

Additionally, the frequency would be directly proportional to the mass of the charged particle.

Answer: 0

Explanation: because when it return total displacement is 0

Answer:

194.81 revolutions

Explanation:

Given that,

Initial angular velocity, [tex]\omega_i=3700\ rpm[/tex]

Final angular velocity, [tex]\omega_f=1800\ rpm[/tex]

Time, t = 4.25 seconds

We need to find the number of revolutions occur during this time.

3700 rpm = 387.46 rad/s

1800 rpm = 188.49 rad/s

Let [tex]\alpha[/tex] is angular acceleration. Using first equation to find it.

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{188.49 -387.463 }{4.25}\\\\\alpha =-46.81\ rad/s^2[/tex]

Now let us suppose that the number of revolutions are [tex]\theta[/tex].

[tex]\theta=\dfrac{\omega_f^2+\omega_i^2}{2\alpha}\\\\=\dfrac{188.49 ^2-387.463 ^2}{2\times -46.81}\\\\=1224.087\ rad[/tex]

or

[tex]\theta=\dfrac{1224.087}{2\pi}\\\\=194.81\ rev[/tex]

Hence, there are 194.81 revolutions.

Answer:

The total net momentum after the push is 0.

Explanation:

The total net momentum is given by:

[tex] p_{f} = p_{1_{f}} + p_{2_{f}} = m_{1}v_{1} + m_{2}v_{2} [/tex]

Where:

m₁: is the mass of 70 kg

m₂: is the mass of 60 kg

v₁: is the speed of 2.5 m/s

v₂:?

To find the final momentum first we need to find the speed v₂:

[tex]m_{1}v_{1} + m_{2}v_{2} = p_{i}[/tex]  

Where [tex]p_{i}[/tex] is the initial momentum = 0 (they are at rest)          

[tex] v_{2} = -\frac{m_{1}v_{1}}{m_{2}} = -\frac{70 kg*2.5 m/s}{60 kg} = -2.92 m/s [/tex]          

The minus sign is because the second person is moving in the opposite direction to the first person.

Now, the total net momentum is:

[tex] p_{f} = m_{1}v_{1} + m_{2}v_{2} = 70 kg*2.5 m/s + 60 kg*(-2.92 m/s) = 0 [/tex]

The final total momentum (after the push) should be zero because of momentum conservation.

Therefore, the total net momentum after the push is 0.

I hope it helps you!                

Answer:

6g/cm³

Explanation:

Given parameters;

Mass  = 600g

Dimension  = 2cm wide, 2cm tall and 25cm long

Unknown:

Density  = ?

Solution

Density is the mass per unit volume of any substance. To solve this problem:

   Density  = [tex]\frac{mass}{volume}[/tex]  

 Since mass = 600g

Let us find the volume;

    Volume  = length x width x height

   Volume  = 25cm x 2cm x 2cm  = 100cm³  

Therefore;

         Density  = [tex]\frac{600}{100}[/tex]    = 6g/cm³

Answer:

The length of the simple pendulum is 0.248 m.

Explanation:

Given;

period of the simple pendulum, T = 1.00 s

let the length of the simple pendulum = L

The period of oscillation of a simple pendulum is calculated as;

[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2\pi } = \sqrt{\frac{l}{g} }\\\\\frac{T^2}{4\pi ^2 } = \frac{l}{g}\\\\l = \frac{gT^2}{4\pi ^2 } \\\\l = \frac{(9.8)(1)^2}{4\pi ^2 } \\\\l = 0.248 \ m[/tex]

Therefore, the length of the simple pendulum is 0.248 m.

Hope this helps

Answer:

See explanation

Explanation:

Electric field strength;

E = kq/d^2

k= coulombs constant

q= magnitude of charge

d = distance if separation

If

d is constant

q = 2q

Then;

E = 2 kq/d^2

Hence, the electric field strength will double.