if a+b=30 and a^2+b^2=740 find the value of ab​

Answers

Answer 1

Step-by-step explanation:

HERE,

a+b=30

a^2+b^2=740

we know that,

[tex]\tt{(a+b)^2=a^2+b^2+2ab }[/tex]

according to the question,

[tex]\tt{ (30)^2=740+2ab }[/tex]

[tex]\tt{900=740+2ab }[/tex]

[tex]\tt{ 2ab=900-740 }[/tex]

[tex]\tt{ ab=\dfrac{160}{2} }[/tex]

[tex]\tt{ab=80 }[/tex]

#quality answer

Answer 2

the value of ab is 80

Answer:

Solution given:

(a+b)=30....(1)

a²+b²=740......(2)

squaring equation 1:

we have;

formula:

(a+b)²=++2ab

use this formula:

(a+b)²=30²

a²+b²+2ab=30²

Substituting value of +=740

740+2ab=30²

take constant term on one side.

2ab=30²-740

subtract :30²-740

2ab=160

divide both side by 2

2ab/2=160/2

we get:

ab=80

the value of ab is 80


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Answers

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Answers

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Step-by-step explanation:

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Answers

Given:

In 16 coins some coins are dimes and some are nickels.

The combined value of her nickels and dimes is 1.35.

To find:

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Solution:

We have,

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