If a statistic used to estimate a parameter is said to be unbiased, then which of the following must be true? (A) The statistic is equal to the true value of the parameter it is being used to estimate for every possible sample. (B)The mean of the sampling distribution of the statistic is equal to the true value of the parameter it is being used to estimate. (C) The sampling distribution of the statistic has the same mean and standard deviation as the distribution of the population. (D)The statistic is a proportion. (E) The mean of the sampling distribution of the statistic will change as the sample size is changed.

the volume of the rectangular prism with a width of 10 cm, height of 3 cm, and a depth of 7 cm is 210 cubic cm.

The volume of a rectangular prism is calculated by multiplying its length, width, and height. In this case, the width is 10 cm, the height is 3 cm, and the depth is 7 cm. Therefore, the volume of the rectangular prism can be calculated as follows:

Volume = Length x Width x Height

Since the length of the rectangular prism is not given, we cannot calculate the exact volume. However, we can provide a formula that can be used to calculate the volume of any rectangular prism with the given dimensions.

Formula for the volume of a rectangular prism:

Volume = Width x Height x Depth

Substituting the given values, we get:

Volume = 10 cm x 3 cm x 7 cm

Volume = 210 cubic cm

Therefore, the volume of the rectangular prism with a width of 10 cm, height of 3 cm, and a depth of 7 cm is 210 cubic cm.

It is important to note that the unit of measurement used for the dimensions should be the same for all three dimensions in order to obtain the correct volume. In this case, the unit of measurement used is centimeters (cm), and the volume is expressed in cubic centimeters (cm³).

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In response to the stated question, we may state that As a result, the function student will have to pay off the debt in 24 weeks.

In mathematics, a function is a connection between two sets of numbers in which each member of the first set (known as the domain) corresponds to a single element in the second set (called the range). In other words, a function takes inputs from one set and produces outputs from another. Inputs are commonly represented by the variable x, whereas outputs are represented by the variable y. A function can be described using an equation or a graph. The equation y = 2x + 1 represents a linear function in which each value of x yields a distinct value of y.v

a. Let L(w) be the monetary amount owing after w weeks.

Because the starting amount owing is $360 and the weekly payment is $15, the equation for the amount owed as a function of time is: L(w) = 360 - 15w

b. The inverse function of L(w) reflects the number of weeks required to repay a certain loan amount. In terms of L, we can solve for w:

L = 360 - 15w

L - 360 = -15w

w = (360 - L)/15

As a result, the inverse function is: L(-1)(w) = (360 - w)/15.

c. 0 = 360 - 15w

15w = 360 = 24

As a result, the student will have to pay off the debt in 24 weeks.

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The slopes are,

1) 7/6

2)7/2

3) -1

4) -2

5) 10/9

What is slope?

Calculated using the slope of a line formula, the ratio of "vertical change" to "horizontal change" between two different locations on a line is determined. The difference between the line's y and x coordinate changes is known as the slope of the line.Any two distinct places along the line can be used to determine the slope of any line.

1) The given points , [tex](x_1,y_1) =(0,1)[/tex] and [tex](x_2,y_2) = (6,8)[/tex] then,

=> slope  = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] = [tex]\frac{8-1}{6-0} = \frac{7}{6}[/tex]

2) The given points [tex](x_1,y_1) =(-1,10)[/tex] and [tex](x_2,y_2) = (-5,-4)[/tex] then,

=> Slope = [tex]\frac{-4-10}{-5+1} = \frac{-14}{-4}=\frac{7}{2}[/tex]

3)  The given points [tex](x_1,y_1) =(-10,2)[/tex] and [tex](x_2,y_2) = (-3,-5)[/tex] then,

=> slope = [tex]\frac{-5-2}{-3+10} = \frac{-7}{7}=-1[/tex]

4)  The given points [tex](x_1,y_1) =(-3,-4)[/tex] and [tex](x_2,y_2) = (-1,-8)[/tex] then,

=> slope = [tex]\frac{-8+4}{-1+3} = \frac{-4}{2}=-2[/tex]

5)The given points [tex](x_1,y_1) =(0,1)[/tex] and [tex](x_2,y_2) = (-9,-9)[/tex] then,

=> slope = [tex]\frac{-9-1}{-9+0} = \frac{-10}{-9}=\frac{10}{9}[/tex]

Hence the slopes are,

1) 7/6

2)7/2

3) -1

4) -2

5) 10/9

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Increasing lexicographic order: (0, 0), (0, 1/2), (1/4, 0), (1/4, 1/2)).Thus, the increasing lexicographic order of the critical points of the function f(x,y) = xy(1 - 4x - 2y) are (0, 0), (0, 1/2), (1/4, 0), and (1/4, 1/2).

lexicographic order: (0, 0), (0, 1/2), (1/4, 0), (1/4, 1/2)).Thus, the increasing lexicographic order of the critical points of the function f(x,y) = xy(1 - 4x - 2y) are (0, 0), (0, 1/2), (1/4, 0), and (1/4, 1/2).

Suppose that f(x,y) = xy(1 - 4x - 2y). f(x,y) has 4 critical points.

Let's discuss what are critical points and how we can determine them,A critical point is a point on the graph where the derivative changes its sign.

In other words, the derivative either changes from negative to positive or from positive to negative. A critical point is also known as a stationary point or a turning point

To determine the critical points, we need to find the derivative of the given function and set it equal to zero.The given function is[tex]f(x,y) = xy(1 - 4x - 2y).[/tex]

Let's find the partial derivative of f with respect to [tex]x:f_x(x,y) = y(1 - 4x - 2y) - 4xy = (1-2y)(1-4x)y.[/tex] (1)

Now, find the partial derivative of f with respect to y:f_y(x,y) = x(1 - 4x - 2y) - 2xy = (1-2x)(1-2y)x. (2)

To find the critical points, we need to set both partial derivatives (1) and (2) equal to zero.

(1-2y)(1-4x) = 0 and (1-2x)(1-2y) = 0.

Solving both equations separately, we have the following critical points:(1/4, 1/2), (1/4, 0), (0, 1/2), and (0, 0).

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Answer:

9. 6.32

10. 4.12

Step-by-step explanation:

9. c^2 = 2^2 + 6^2 = 4 + 36 = 40

c = √40 = 6.32

10. c^2 = 1^2 + 4^2 = 17

c = √17 = 4.12

Answer: Yes Sofia will have enough money

=======================================================

Explanation:

Refer to the drawing below. I've split the hexagon into two pieces. The bottom is a rectangle and the top is a trapezoid.

The area of the rectangle is 16*7 = 112 square meters.

The trapezoid has 16 as one of the parallel sides. The other side is x meters. We'll use the perimeter 54 to determine what x must be

sum of the exterior sides = perimeter

6+7+16+7+6+x = 54

42+x = 54

x = 54-42

x = 12

The top most side is 12 meters. This is the missing side of the trapezoid. The hexagon has a height of 12.66 meters, so the trapezoid's height must be 12.66-7 = 5.66 meters. Refer to the blue segment I marked in the drawing below.

area of the trapezoid = 0.5*height*(base1+base2)

area = 0.5*5.66*(16+12)

area = 79.24 square meters

----------------

Recap so far

The total area of the entire hexagon is therefore 112+79.24 = 191.24 square meters.

Let's convert that to square decimeters.

Recall that 1 decimeter = 10 centimeters

Multiply both sides by 10

1 decimeter = 10 centimeters

10*(1 decimeter) = 10*(10 centimeters)

10 decimeters = 100 centimeters

10 decimeters = 1 meter

Then,

[tex]191.24 \text{ sq m}= 191.24 \text{ sq m} * \frac{10 \text{ dm}}{1 \text{ m}} * \frac{10 \text{ dm}}{1 \text{ m}}\\\\= \frac{191.24*10*10}{1*1} \text{ sq dm}\\\\= 19124 \text{ sq dm}\\\\[/tex]

The entire lawn is 19124 square decimeters.

----------------

We have one final block of calculations to determine the total price.

x = number of rolls

1 roll covers 90 square decimeters

x rolls cover 90x square decimeters

90x = 19124

x = 19124/90

x = 212.489 approximately

Round up to the nearest integer to get x = 213. It doesn't matter that 212.489 is closer to 212. We round up to clear the hurdle. It means we'll have leftover grass that isn't used (perhaps it could be handy to have some back up grass just in case mistakes are made, and some patches need to be redone).

In short, Sofia needs 213 rolls.

1 roll costs $4.50

213 rolls will cost 213*4.50 = 958.50 dollars.

This is under the $1000 threshold (with 1000-958.50 = 41.50 dollars to spare).

Sofia will have enough money to pay for all of the grass.

The greater number is [tex]$n^3+8$[/tex]

Let x be the greater number and y be the smaller number. We know that x-y=8.

We are also given that the smaller number is n³.

So we can set up the equation:

x = y + 8

x = n³ + 8

Therefore, the greater number is [tex]$n^3+8$[/tex].

The greater number is given as n³ + 8. If the smaller number we get is represented by the n³,  then by adding 8 to that value gives the greater number. The difference between the two numbers is always going to be 8, regardless of the value of n.

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The proportionate relationship is used to determine that:

Y=0.5 when x = 1.

Y Equals 1.25 when x = 2.5.

Y = Y = 1.75 when x = 3.5.

What does "proportional relationship" mean?

In a proportional connection, the output variable is determined by the input variable multiplied by a proportionality constant, as in the equation: y = kx.

where k is the proportionality constant.

The relationship in this issue is provided by:

y = x/2

Hence, y = 1/2 = 0.5 when x = 1.

Y = 2.5/2 = 1.25 when x = 2.5.

When x = 3.5:

y = 3.5/2 = 1.75

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Dimension of photograph is 35cm and 22cm.

And external dimension of photo frame is 45cm and 30cm

So, the area of the border surrounding the photograph=Area of photo frame−Area of photo.

So, The area of the border surrounding the photograph [tex]=45\times30-35\times22[/tex]

[tex]=1350-770=580cm^2[/tex]

a.

There are 15,504 ways to choose 20 batteries from the given types.

b.

there are 18,564 ways to choose 20 batteries such that at least four of them are 9-volt batteries.

To choose 20 batteries from the given 5 types (aaa, aa, c, d, and 9-volt), we can use the combination formula and is given by:

nCr = n! / (r! * (n-r)!)

5C20 = 5! / (20! * (5-20)!) = 15,504

there are 15,504 ways to choose 20 batteries from the given types.

b. To choose 20 batteries such that at least four of them are 9-volt batteries, we employ the method:

First, we choose four 9-volt batteries out of the total number of 9-volt batteries, which is 1.

we then need to choose the remaining 16 batteries from the remaining 4 types (aaa, aa, c, and d), while making sure that we don't choose any 9-volt batteries.

Applying the combination formula, with n = 4 and r = 16:

4C16 = 4! / (16! * (4-16)!) = 18,564

Therefore, the total number of ways to choose 20 batteries such that at least four of them are 9-volt batteries is:

1 * 18,564 = 18,564

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One Imaginary solution is not possible for a quadratic equation of the form ax² + bx + c = 0.

By replacing the factorization method, the quadratic formula aids in evaluating the quadratic equations' solutions.

A quadratic equation has the general form ax² + bx + c = 0, where a, b, and c are real numbers, sometimes known as "numeric coefficient".

We can forecast the nature of the roots by determining the discriminant's value.

Three potential outcomes, each with a different impact

If b² - 4ac > 0, two separate roots that are real.

If b² - 4ac = 0, two real roots have magnitudes that are equal.

If b² - 4ac 0, there are no real roots and just imaginary ones.

Thus, the quadratic equation ax² + b x + c = 0 cannot have a single imaginary solution.

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Answer:

576 books.

Step-by-step explanation:

134+254+188=576 books in total.

Hopefully this helps!

Answer:

4[tex]\sqrt{2\\}[/tex]

Step-by-step explanation:

This is a 45 45 90 Triangle meaning that x would be 4 squareroot 2

so the formula goes lets say 4= a and the other side is b

a=b and x=a[tex]\sqrt{2[/tex]

Using the Poisson Approximation the probability are:

a)  0.6321

b)  0.3679

c) 0.2642

The Poisson distribution is utilized to compute the likelihood of a particular amount of occurrences happening over a set period. The Poisson approximation will be used to answer the given question, and it is a form of a probability distribution that can be used to approximate the probability of particular events that occur infrequently, and it is suitable for both continuous and discrete variables.

a) The probability of having at least one student with the same birthday as Brad using the Poisson Approximation.

Let the number of other students with the same birthday as Brad be represented by x. Here, x is a discrete variable with a Poisson distribution that follows a Poisson distribution with an average of λ, which is equal to 1:

λ = average number of students having the same birthday as Brad = 1.

Using the Poisson distribution formula, the probability of having at least one student with the same birthday as Brad is given by:

P(X >= 1) = 1 - P(X = 0)

= 1 - e ^ (-λ)P(X = 0)

= (e^(-λ))(λ^0) / 0!

= e^(-λ)

= e^(-1)

= 0.3679

Therefore, the probability of having at least one student with the same birthday as Brad is:

P(X >= 1) = 1 - P(X = 0)

= 1 - 0.3679

= 0.6321

b) The probability of having exactly one student with the same birthday as Brad using Poisson Approximation

P(X = 1) = (e^(-λ))(λ^1) / 1!

= e^(-1)(1) / 1!

= e^(-1)

= 0.3679

Therefore, the probability of having exactly one student with the same birthday as Brad is:

P(X = 1)

= e^(-1)

= 0.3679

c) The probability of having at least two students with the same birthday as Brad using Poisson Approximation

P(X >= 2) = 1 - P(X < 2)

= 1 - [P(X = 0) + P(X = 1)]

= 1 - [e^(-λ)(λ^0) / 0! + e^(-λ)(λ^1) / 1!]

= 1 - [e^(-1) + e^(-1)(1) / 1!]

= 1 - [e^(-1) + e^(-1)]

= 1 - 2e^(-1)

= 0.2642

Exact probability: 1 - (364/365)^180 = 0.4406

Poisson Approximation Probability: 0.6321

The exact probability is 0.4406, which is less than the Poisson approximation probability, which is 0.6321.

This result indicates that the Poisson approximation formula overestimates the likelihood of having at least one student with the same birthday as Brad.

Exact probability: (364/365)^179(1/365) = 0.3775

Poisson Approximation Probability: 0.3679

The exact probability is 0.3775, which is quite similar to the Poisson approximation probability, which is 0.3679.

This result indicates that the Poisson approximation formula provides a reasonably precise estimate of the likelihood of having exactly one student with the same birthday as Brad.

Exact probability: 1 - [1 + 364/365 + ... + (364!/347!)/365^34] = 0.1827

Poisson Approximation Probability: 0.2642

The exact probability is 0.1827, which is less than the Poisson approximation probability, which is 0.2642.

This result indicates that the Poisson approximation formula overestimates the likelihood of having at least two students with the same birthday as Brad.

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The `det(E2) of the given matrix is equal to 366`.

Given a 5 by 5 matrix E= `[11 2 -1 -3 4;10 -1 -2 -1 -2;-1 2 3 2 1;1 1 1 -1 -1;2 -1 -2 1 1]`.

To find `det(E)`, we can use the following steps.

Step 1: Create a 5 by 5 matrix E1 by adding a multiple of the ith row to the jth row, given i = 3 and j = 5.

We need to add -1/3 times the 3rd row to the 5th row. It can be done by the following operation.`E1 = E` (start with the original matrix) `=> E1(5,:) = E(5,:) - E(3,:) / 3` (subtract the 3rd row of E divided by 3 from the 5th row of E)

This results in the matrix `E1 = [11 2 -1 -3 4;10 -1 -2 -1 -2;-1 2 3 2 1;1 1 1 -1 -1;1/3 -7/3 -7/3 7/3 4/3]

`Step 2: Create a 5 by 5 matrix E2 by adding a multiple of the ith row to the jth row, given i = 2 and j = 5.We need to add -20 times the 2nd row to the 5th row.

It can be done by the following operation.`E2 = E1` (start with the matrix from Step 1) `=> E2(5,:) = E1(5,:) - 20 * E1(2,:)` (subtract 20 times the 2nd row of E1 from the 5th row of E1)

This results in the matrix `E2 = [11 2 -1 -3 4;10 -1 -2 -1 -2;-1 2 3 2 1;1 1 1 -1 -1;0 -13 33 -13 44]

`Step 3: Find det(E2) by using the cofactor expansion along the 5th column.`det(E2) = 0 - (-13) * A1 + 33 * A2 - (-13) * A3 + 44 * A4 - 0 * A5`where A1, A2, A3, A4, and A5 are the 2 by 2 determinants of the submatrices obtained by deleting the 5th row and the ith column, for i = 1, 2, 3, 4, and 5. We can use the following notation.

A1 = det([11 -1 -3 4;10 -2 -1 -2;-1 3 2 1;]) = 324A2 = det([11 2 -3 4;10 -1 -1 -2;-1 2 2 1;]) = -54A3 = det([11 2 -1 4;10 -1 -2 -2;-1 2 3 1;]) = -142A4 = det([11 2 -1 -3;10 -1 -2 -1;-1 2 3 2;]) = 50A5 = det([11 2 -1 -3;10 -1 -2 -1;-1 2 3 2;]) = 366.

Therefore `det(E2) = 0 - (-13) * 324 + 33 * (-54) - (-13) * (-142) + 44 * 50 - 0 * 50 = 366`.

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The equation of the required line in slope-intercept form is y = -1/4x + 8.

Here are the steps to find the equation of the line:

Step 1: Find the slope of the given line in slope-intercept form

y = mx + c

-4x + y = 43 ⇒ y = 4x + 43... (1)

Here, the slope (m1) of the given line is 4.

Step 2: Find the slope of the required line as the two lines are perpendicular to each other.

m1 × m2 = -1

[As the given line and the required line are perpendicular to each other]

4 × m2 = -1 ⇒ m2 = -1/4

So, the slope (m2) of the required line is -1/4.

Step 3: Write the equation of the required line in point-slope form.

y - y1 = m(x - x1)

[Using the point-slope formula]

Let (x1, y1) = (-8, 10)m = -1/4

Putting the values in the above formula, we get

y - 10 = -1/4(x - (-8)) ⇒ y - 10 = -1/4(x + 8)... (2)

Step 4: Simplify the above equation to get the required equation of the line in slope-intercept form.

y - 10 = -1/4x - 2 ⇒ y = -1/4x + 8... (3)

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The expected value of cases in which juries got the right decision is 150, and the variance is 375.

1. Since 25% of defendants in the state are innocent, that means that 75% of the defendants are guilty.
2. This means that in the given year, 150 out of the 200 people put on trial will be guilty.
3. Thus, the expected value of cases in which juries got the right decision is 150.
4. The variance of the number of cases in which juries got the right decision is calculated by taking the expected value and subtracting it from the total number of people put on trial, which is 200.
5. The result of the calculation is 375, which is the variance of cases in which juries got the right decision.

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As a result, the triangles and are similar triangles according to the meaning of similarity. Thus, the Angle-Angle Similarity Principle has been demonstrated.

Three straight edges and three angles make up a closed, two-dimensional triangle. By joining three non-collinear lines, it is created. One of the most fundamental geometric shapes, triangles are used in many disciplines, including physics, engineering, and construction. According to their edges and angles, triangles can be classified as equilateral, isosceles, scalene, acute, obtuse, or right triangles.

given

Take into account two triangles Z and T such that ZT ZX and ZUZY. We must demonstrate the similarity of these two shapes.

We are aware that if two triangles are similar, their respective sides and angles will be proportional.

Now, let's prove that the respective sides of these two triangles are proportional. Since ZT ZX, the respective sides of similar triangles result in TZ/ZX = TU/ZY. If we simplify this number, we obtain:

TU/ZX Equals TZ/ZY.

This demonstrates that the ratio between the respective sides of these two triangles.

As a result, the triangles and are similar triangles according to the meaning of similarity. Thus, the Angle-Angle Similarity Principle has been demonstrated.

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The complete question is :- Write a proof of the Angle-Angle Similarity Theorem.

If two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

Given: ZT ZX, ZUZY

Prove: Δτυν - ΔΧΥΖ

Dilate XYZ by the scale factor

Answer:

Exponents are a mathematical notation used to represent repeated multiplication. An exponent, also known as a power, consists of a base number and a small superscript number, which indicates how many times the base number should be multiplied by itself.

For example, in the expression 2^3, the base number is 2 and the exponent (or power) is 3. This means that 2 should be multiplied by itself three times: 2 x 2 x 2 = 8. So, 2^3 is equal to 8.

Exponents can also be negative or fractions. In these cases, the negative exponent indicates division and the fraction exponent indicates taking a root.

For instance, in the expression 2^-3, the negative exponent means that 2 is in the denominator of a fraction: 1/2 x 1/2 x 1/2 = 1/8. So, 2^-3 is equal to 1/8.

In the expression 4^(1/2), the fraction exponent means that we take the square root of 4: 2 x 2 = 4. So, 4^(1/2) is equal to 2.

Exponents have many practical applications in science, engineering, and other fields. They can be used to represent large or small quantities, as well as to simplify complex mathematical expressions.

Step-by-step explanation:

Answer:

The answer is 657 and 365.

Step-by-step explanation:

Let the two numbers be x and y respectively

In first case,

x+y=1022

x=1022-y----------- eqn i

In second case

x-y=292

1022-y-y=292 [From eqn i]

1022-2y=292

1022-292=2y

730=2y

730/2=y

y=365

Substituting the value of y in eqn i

x=1022-y

x=1022-365

x=657

Hence two numbers are 657 and 365.

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Answer: 5 ≥ y-2 is equivalent to y ≤ 7.

Step-by-step explanation: To check if 5 is greater than or equal to y-2, we need to isolate the variable y on one side of the inequality sign.

5 ≥ y - 2

First, we can add 2 to both sides to get rid of the subtraction of 2 on the right side:

5 + 2 ≥ y - 2 + 2

7 ≥ y

Therefore, we can see that y is less than or equal to 7 for this inequality to hold true.

Answer:

g(x) = x² - 4x + 7

the blue bucket holds 5 x 4 = 20 cups of water.

what is a probability?

In mathematics, probability is a measure of the likelihood or chance of an event occurring. It is represented as a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain.

Since 1 quart of water is equivalent to 2 pints of water and 1 pint of water is equivalent to 2 cups of water, then 1 quart of water is equivalent to 4 cups of water (2 pints x 2 cups per pint = 4 cups).

To determine which bucket holds more water, we need to know the amount of water in the other bucket. Without that information, we cannot compare the two buckets.

Assuming that Janelle filled the other bucket with water as well, we would need to know how many cups of water it holds in order to compare the two buckets.

Therefore, the blue bucket holds 5 x 4 = 20 cups of water.

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Answer: 2 solutions

Step-by-step explanation:

To find the angle of a regular polygon, use the formula 180(n-2)/n (where n is the amount of sides.)

Setting them equal, we get (180n-360)/n = 1680.

Multiplying by n on both sides, we get 180n-360 = 1680n.

Solving, we get 1500n = 360.

n = 0.24, which means it is not a shape, as you cannot have a shape with 0.24 sides.

The other way to look at it is to take full revolutions of 360 away from each angle, giving us 240 (the smallest remainder without it going negative). However, all the angles would be concave. If all the angles are concave, then it might connect backwards.

Subtracting 240 from 360 (to get the "exterior" angles, we get 120. Plugging it in to our equation 180(n-2)/n and solving, we get 180n-360 = 120n, and solving gives us 60n = 360, or n=6.

Since the amount of sides came together cleanly, we can classify this polygon as a normal hexagon, which has 6 sides.

The fireworks display occurred due north of the person at point A. This can be determined by calculating the direction and speed of sound. Assuming the speed of sound is approximately 343 meters per second, the fireworks display must have occurred approximately 0.58 seconds away from point A, which is approximately 343 meters due north of point A. This means that the fireworks display occurred somewhere between the two points.


To double-check the calculations, we can look at the two points and the direction in which the sound traveled. Point A is due north of the fireworks display, and point B is due west. This means that the sound traveled both north and west, which is consistent with the calculations.


Therefore, we can conclude that the fireworks display occurred due north of point A.

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It sounds like you want to find how many diagonals a nonagon has.

A nonagon has n = 9 sides.

The number of diagonals would be...

[tex]d = \text{number of diagonals}\\\\d = \frac{n(n-3)}{2}\\\\d = \frac{9(9-3)}{2}\\\\d = \frac{9(6)}{2}\\\\d = \frac{54}{2}\\\\d = 27\\\\[/tex]

A nonagon has 27 different diagonals.

For (a), the value for x is 11, as P(X>x) = 0.5 when the mean is 7 and the standard deviation is 4. This can be found using the standard normal table.

For (b), the value for x is 19, as P(X>x) = 0.95 when the mean is 7 and the standard deviation is 4. This can also be found using the standard normal table.

For (c), the value for x is 9, as P(x< X<9) = 0.2 when the mean is 7 and the standard deviation is 4. This is found by subtracting the z-scores of x and 9 from each other, and then finding the area of the z-score between those two numbers using the standard normal table.

For (d), the value for x is 4, as P(3< X) = 0.2 when the mean is 7 and the standard deviation is 4. This is found by subtracting the z-score of 3 from the mean and then finding the area of the z-score to the left of that number using the standard normal table.

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To work out the mean cost of a present in pounds (£), we need to divide the total cost of the presents (£80.52) by the number of presents (4).

The calculation will look like this:

£80.52 ÷ 4 = £20.13

Therefore, the mean cost of a present in pounds (£) is £20.13.

A higher confidence level is associated with a wider confidence interval.

a. The point estimate of µ = (14 + 20 + 21 + 16 + 18 + 19) / 6 = 108 / 6 = 18.

b. For 80% confidence interval for µ, the confidence coefficient is 1 - α = 0.8, so α = 0.2 / 2 = 0.1. From the z-table, we can find the corresponding value of z to be 1.28. The confidence interval can be calculated as follows:

Upper Bound: µ + z*σ / √n = 18 + (1.28)(2.3) / √6 = 21.35

Lower Bound: µ - z*σ / √n = 18 - (1.28)(2.3) / √6 = 14.65

The 80% confidence interval is (14.65, 21.35). For 98% confidence interval for µ, the confidence coefficient is 1 - α = 0.98, so α = 0.01. From the z-table, we can find the corresponding value of z to be 2.33. The confidence interval can be calculated as follows:

Upper Bound: µ + z*σ / √n = 18 + (2.33)(2.3) / √6 = 23.88

Lower Bound: µ - z*σ / √n = 18 - (2.33)(2.3) / √6 = 12.12

The 98% confidence interval is (12.12, 23.88). The 80% and 98% confidence intervals are different because as we move to higher confidence levels, the z-values become larger, which in turn causes the confidence intervals to become wider. Therefore, a higher confidence level is associated with a wider confidence interval.

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