If 23.2 g of a given gas occupies a volume of 93.2 L at a particular temperature and pressure, what
mass of the gas occupies a volume of 10.4 L under the same conditions?

Answers

Answer 1

Answer:

2.59g

Explanation:

Using Avagadro's law equation as follows:

V1/n1 = V2/n2

Where;

V1 = initial volume (litres)

V2 = final volume (litres)

n1 = first amount of gas in grams

n2 = second amount of gas in grams

According to the information provided in this question, v1 = 93.2L, v2 = 10.4L, n1 = 23.2 g, n2 = ?

Using V1/n1 = V2/n2

93.2/23.2 = 10.4/n2

Cross multiply

93.2 × n2 = 23.2 × 10.4

93.2n2 = 241.28

n2 = 241.28/93.2

n2 = 2.588

n2 = 2.59g

Answer 2

The mass of the gas is 2.59g that occupies a volume of 10.4 L under the same conditions.

Avogadro's law equation:

V₁/n₁ = V₂/n₂

Where

V₁ = initial volume (litres)

V₂ = final volume (litres)

n₁ = first amount of gas in grams

n₂ = second amount of gas in grams

Given:

V₁ = 93.2L,

V₂ = 10.4L,

n₁ = 23.2 g,

To find:

n₂ = ?

On substituting the values:

93.2/23.2 = 10.4/n₂

93.2 * n₂ = 23.2 * 10.4

93.2* n₂ = 241.28

n₂ = 241.28/93.2

n₂ = 2.588

n₂ = 2.59g

Thus, the mass of the gas is 2.59g.

Find more information about Avogadro law here:

brainly.com/question/3491421


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Answers

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Answers

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Answers

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Answers

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Answers

Answer:

Effusion  is the process of a gas being poured out through a hole diametrically smaller than the structural exit of the container.

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Explanation:

The gas with a lower molar mass will have a lower density and diffuses at a slower rate. Thus gas A has a lower density than gas B and diffuses slower than gas B.

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Learn more about the density of gas here: https://brainly.in/questions/16376906

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