If 100 ml of a 0.75 m hno3 is required to exactly neutralize 50 ml of naoh what is the concentration of the base?

Answers

Answer 1

Answer:

1.5M

Explanation:

M1V1=M2V2

(0.75M)(100ml)=(M2)(50 ml)

M2= 1.5 M

*Text me at 561-400-5105 for private tutoring if interested: I can do homework, labs, and other assignments :)


Related Questions

Calculate the pH of 0.65 M H2SO4 (sulfuric acid) solution? (Ka2: 1.1x10-2)

Answers

Answer:

Explanation:

.65 M H₂SO₄

     H₂SO₄ ⇄ 2H⁺ + SO₄⁻²

  C(1-x)             2xC         xC

(2xC)². xC /C( 1- x )  = 1.1 x 10⁻²

4 x³C² =  1.1 x 10⁻²

4 . x³ .65² = 1.1 x 10⁻²

x³ =   .0065 = 6.5 x 10⁻³

x =      1.867 x 10⁻¹

H⁺ ion concentration =

2xC = 2 x 1.867 x 10⁻¹ x .65

=  .2427

pH = - log ( .2427 )

= 0 .615 .    

Which of these is the smallest?
atom
molecule
proton
an ant

Answers

Answer

proton

Explanation:

Why was meteorology such a late developer compared to other branches of science?

Answers

Answer:

Because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface

Explanation:

Hello,

In this case, meteorology is the branch of science studying the atmosphere in its weather processes and forecasting and it had a late development because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface. We cannot forget that even nowadays, it is very difficult to predict upcoming weathers with the 100 % assurance and with many days in advance.

Best regards.

Meteorology is developed lately as compared to other branches of science due to far away from the reach of humans.

Meteorology is a late developer compared to other branches of science because the measuring the climatic conditions in the atmosphere is difficult and even impossible without the presence of advance technologies.

To find out the weather as well as climatic conditions can't be measured due to it is not reachable to the human like other materials present on the earth surface so we can conclude that meteorology is developed lately as compared to other branches of science due to far away from the reach of humans.

Learn more: https://brainly.com/question/16565664

2. A flask and stopper have a mass of 110.525 g. A 50.0-mL sample of gasoline is transferred to the flask, and the flask, stopper, and liquid have a mass of 145.028 g. Find the density of gasoline in g/mL. Show work and report density with the appropriate number of significant figures.

Answers

Answer:

  0.690 g/mL

Explanation:

Density is the ratio of mass to volume:

  gasoline mass = (flask+gas mass) - (flask mass) = 145.028 g -110.525 g

  gasoline mass = 34.503 g

Density = (gas mass)/(gas volume) = (34.503 g)/(50.0 mL)

Density = 0.690 g/mL

_____

The least-precise number in this calculation is the sample volume, which has 3 significant figures. Thus, the answer is good only to 3 significant figures.


50 Points
Atoms contain subatomic particles called protons and neutrons. When these protons and neutrons split, a lot of energy is released.

What kind of energy is this?

nuclear
radiant
thermal
chemical

Answers

Answer:

nuclear

Explanation:

This is because when the protons and neutrons split the energy being released is heat, also known as nuclear fission.

Answer:

The answer is Nuclear

1. _ LiBr2 + __K2CO3 -->___ LiCO3 +_ KBr
Reaction Type:

Answers

Answer:

Double displacement chemical reaction.

Explanation:

Hello,

In this case, for the given reaction we firstly balance it:

[tex]LiBr_2 +K_2CO3 \rightarrow LiCO3 +2KBr[/tex]

Then, since the lithium and potassium cations are being exchanged to each other from bromide and carbonate, we are talking about a double displacement chemical reaction.

Best regards.

Calculate the number of moles of Li3PO4 in 2.2 L of a 0.60 M Li3PO4 solution.

Answers

Answer:

1.32 mole

Explanation:

The following data were obtained from the question:

Volume of solution = 2.2L

Molarity of solution = 0.60M

Mole of Li3PO4 =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:

Molarity = mole /Volume

With the above formula we can easily calculate the number of mole of Li3PO4 as shown below:

Molarity =mole /Volume

0.6 = mole of Li3PO4 /2.2

Cross multiply

Mole of Li3PO4 = 0.6 x 2.2

Mole of Li3PO4 = 1.32 mole

Therefore, 1.32 mole of Li3PO4 is contained in the solution.

A burner on a stove produces?

Answers

Answer:

thermal energy

Explanation:

Answer:

B- Thermal Energy

Explanation:

Thermal energy is produced due to all of the movement of particles inside the material.

How do you draw the following structural formulas: 2,4-dimethylhexane; 4-methyl-2-pentene; 4-chloro-7-methyl-2-nonyne

Answers

Answer:

The answer to your question is given below

Explanation:

1. 2,4-dimethylhexane can be drawn as follow:

a. The parent name: Hexane i.e it contains 6 carbon atom.

b. The substitute group attached: Methyl i.e CH3 and it is at carbon 2 and 4.

c. Draw 6 carbon atom in a straight line and put CH3 at carbon 2 and 4. As shown in attach photo.

2. 4-methyl-2-pentene can be drawn as follow:

a. The parent name: pentene i.e it contains 5 carbon atom and the double bond is at carbon 2.

b. The substitute group attached: Methyl i.e CH3 and it is at carbon 4.

c. Draw 5 carbon atom in a straight line and put a double bond at carbon 2 and CH3 at carbon 4 as shown in attach photo.

3. 4-chloro-7-methyl-2-nonyne can be drawn as follow:

a. The parent name: nonyne i.e it contains 9 carbon atom and the triple bond is at carbon 2.

b. The substitute group attached:

i. Chlorine (Chloro) i.e Cl and it is at carbon 4.

ii. Methyl i.e CH3 and it is at carbon 7.

c. Draw 9 carbon atom in a straight line and put a triple bond at carbon 2, Cl at carbon 4 and CH3 at carbon and 7 as shown in attach photo.

What diseases are spread in warm temperatures?

Answers

Answer:

malaria, st louis encephalitis, lyme disease, influenza, cyptosporidium, cholera.

Malaria and viral diseases such as dengue, yellow fever, and the Zika virus.

The student is now told that the four solids, in no particular order, are magnesium bromide (MgBr2), sugar (C6H12O6), acetic acid (CH3COOH), and potassium bromide (KBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive. To rank items as equivalent, overlap them.

Answers

Answer:

Order is MgBr₂ > KBr > (CH₃COOH) > (C₆H₁₂O₆)

Explanation:

Find the given attachment

How many moles would needed to be dissolved in 1 dm3 to get a 3M solution? How many would be needed if only 0.1 dm3 were used?

Answers

Answer:

I sent u on insta

Explanation:

Found it

can you pls tell me the net ironic equation of H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
please its urgent

Answers

Answer:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

Explanation:

H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)

A careful observation of the equation above, shows that the equation is already balanced.

To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

The Pecos Pueblo developed as a trading center over time. What evidence in the text supports the idea that this took a long time?

Because of its value as trading center, the Pecos Pueblo grew in size."

One of the last places the trail passed through was the Pecos Pueblo.

The site was just right for the trade.

Today, the trail attracts tourist instead of traiders.

Answers

Answer:

hi idk the answer

Explanation:

A tetrahedral site in a close-packed lattice is formed by four spheres at the corners of a regular tetrahedron. This is equivalent to placing the spheres at alternate corners of a cube. In such a close-packed arrangement the spheres are in contact and if the spheres have a radius r, the diagonal of the face of the cube is 2r. The tetrahedral hole is inside the middle of the cube. Find the length of the body diagonal of this cube and then find the radius of the tetrahedral hole.

Answers

Answer:

Now length of body diagonal of this cube = √3×√2×r =2.45r

Explanation:

a) length of body diagonal of this cube = √3×√2×r = 2.45 r

it can solved as following

length of body diagonal = √3a   (where a is edge length of cube)

length of face diagonal = √2a

But length of face diagonal = 2r

Therefore a = 2r /√2  = √2×r

Now length of body diagonal of this cube = √3×√2×r

Two cylinders are made of the same material. Cylinder A is one-fourth (1/4) the length of cylinder B and it has a radius that is four times greater than the radius of cylinder B. What is the ratio of the mass of cylinder A to the mass of cylinder B?

Answers

Answer:

[tex]M_{A}[/tex] : [tex]M_{B}[/tex]  = 4 : 1

Explanation:

Given that:

Volume of a cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h

For cylinder A, [tex]l_{A}[/tex] = [tex]h_{A}[/tex] = [tex]\frac{1}{4} l_{B}[/tex] and [tex]r_{A}[/tex] = 4[tex]r_{B}[/tex].

Volume of cylinder A = [tex]\pi[/tex][tex](4r_{B}) ^{2}[/tex] × [tex]\frac{1}{4} l_{B}[/tex]

                                   = 4[tex]\pi[/tex][tex]r_{B} ^{2}[/tex] [tex]l_{B}[/tex]

Volume of cylinder B =  [tex]\pi[/tex][tex](r_{B}) ^{2}[/tex] [tex]l_{B}[/tex]

                                  =  [tex]\pi[/tex][tex]r_{B} ^{2}[/tex][tex]l_{B}[/tex]

To determine the ratio of their masses, density (ρ) is defined as the ratio of the mass (M) of a substance to its volume (V).

i.e    ρ = [tex]\frac{M}{V}[/tex]

Thus, since the cylinders are made from the same material, they have the same density  (ρ). So that;

density of A = density of B

density of A = [tex]\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }[/tex]

density of B = [tex]\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }[/tex]

⇒            [tex]\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }[/tex]  =  [tex]\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }[/tex]

The ratio of mass of cylinder A to that of B is given as;

                       [tex]\frac{M_{A} }{M_{B} }[/tex]  =  [tex]\frac{4\pi r_{B} ^{2} l_{B} }{\pi r_{B} ^{2} l_{B} }[/tex]

⇒                        [tex]\frac{M_{A} }{M_{B} }[/tex] = [tex]\frac{4}{1}[/tex]

Therefore, [tex]M_{A}[/tex] : [tex]M_{B}[/tex]  = 4 : 1

Answer:

4.

Explanation:

Hello,

In this case, since we are talking about the same material, their densities are the same:

[tex]\rho _A=\rho _B[/tex]

And each density is defined by:

[tex]\rho _A=\frac{m_A}{V_A} \\\\\rho _B=\frac{m_B}{V_B}[/tex]

Thus, we also define the volume of a cylinder:

[tex]V_{cylinder}=\pi r^2h[/tex]

Therefore, we obtain:

[tex]\rho _A=\frac{m_A}{\pi r_A^2h_A}[/tex]

[tex]\rho _B=\frac{m_B}{ \pi r_B^2h_B}[/tex]

Now, the given information regarding the the length and the radius is written mathematically:

[tex]h_A=\frac{1}{4} h_B\\\\r_A=4 r_B[/tex]

So we introduce such additional equations in:

[tex]\frac{m_A}{\pi r_A^2h_A}=\frac{m_B}{\pi r_B^2h_B}\\\\\frac{m_A}{\pi (4r_B)^2(\frac{1}{4}h_B)}=\frac{m_B}{\pi r_B^2h_B}\\\\\frac{m_A}{m_B} =\frac{\pi (4r_B)^2(\frac{1}{4}h_B)}{\pi r_B^2h_B}[/tex]

So we simplify for the radius and lengths:

[tex]\frac{m_A}{m_B} =\frac{\pi (4r_B)^2(\frac{1}{4}h_B)}{\pi r_B^2h_B}\\\\\frac{m_A}{m_B} =16 *\frac{1}{4}\\ \\\frac{m_A}{m_B} =4[/tex]

So the ratio of the mass of cylinder A to the mass of cylinder B is 4.

Best regards.

What is the [H30+] in a solution with (OH) = 1.0 x 10-12 M?

Answers

Answer:

Concentration of hydronium ion, H3O+ is 1x10^-2 M

Explanation:

The following data were obtained from the question:

Concentration of Hydroxide ion, [OH-] = 1.0x10^-12 M

Concentration of hydronium ion, [H3O+] =?

Next, we shall determine the pOH of the solution. This is illustrated below below:

pOH = - Log [OH-]

pOH = - Log 1.0x10^-12

pOH = 12

Next, we shall determine the pH of the solution.

pH + pOH = 14

pOH = 12

pH + 12 = 14

Collect like terms

pH = 14 - 12

pH = 2

Finally, we shall determine the Concentration of hydronium ion, [H3O+] as follow:

pH = - log [H3O+]

pH = 2

2 = - log [H3O+]

- 2 = log [H3O+]

[H3O+] = Antilog (-2)

[H3O+] = 0.01M = 1x10^-2 M

Which of the following elements has the lowest ionization energy?

Na

C

F

He

Rb

Answers

Answer:

Rb

Explanation:

Ionization energy is defined required energy to eliminate or remove an electron from an ion or atom.

From the given elements Rb or Rubidium has the lowest ionization energy as it has lowest shielding effect, so it easy to remove electron from it's shell.

The ionization energy generally decreases from top to bottom in groups due to lower shielding effect and outer electrons are loosely packed so easy to remove and increases from left to right across a period because of valence shell stability.

Rubidium has atomic number 37 and lies below than other given elements and also placed in the left side in the periodic table.

Hence, the correct option is Rb

Use the following terms to fill in the blanks:
a. Molality,
b. Mole Fraction,
c. Molarity, Percent by Mass,
d .Unsaturated, Concentration
1. In chemistry, the most commonly used unit of concentration is_________ .
2. The amount of solute (in any measurement unit) divided by the amount of solvent or solution (in any measurement unit) is defined by the basic term of________________ .
3. Dividing the mass of solute by the total mass of solvent and solute will give you the _____________.
4. A method of describing concentration which shows the comparison of moles of solute to moles_____________.

Answers

Answer:

1. Molality.

2. Concentration.

3. Percent by mass.

4.  Mole fraction.

Explanation:

Molarity is the measurement by which the number of moles is measured by a solute. The solution here is one liter respectively.

Concentration is the product which is emerged when the amount of the solute is divided by the amount o the solvent or solution.

Mole fraction refers to the number of component moles divided by the number of the solution moles.

If electrons are collectively compressed into a very small volume (e.g., within the core of a dying white dwarf star) where quantum mechanical considerations become important in preventing one electron from occupying space near to a second electron (Pauli exclusion principle), what is the result?

Answers

Answer:  A degenerate pressure will generate a large force to repel further  compression.

Explanation: In the production of new stars from the core of old dying white dwarf stars, the inner parts of the star will experience contraction with the release of  heat , as they contract, their atoms will be  squeezed such that their electrons start to overlap, and because of the Pauli's exclusive principle which states that no two electrons can occupy same space, the electrons will begin to repel each other and an opposing pressure called degenerate pressure will create a force so that the electrons  cannot continually be crushed or overlap. With the limit of contraction, the outer parts of the star will expand and be repelled releasing the old stars called nebula  and creating space for the inner new stars to form.

Using the cell voltage measured for the first cell studied, with cell chemistry Zn/Zn^2+ \ Cu^2+/Cu, and the known half life potential for Zn^2/Zn calculate the reduction potential for Cu^2+/Cu and enter value below.

The information received for this problem were the values obtained during an online lab:

Cu xM cell voltage:1.100 V

Range: 0.005 V

Temp: 25 degrees C

Answers

Answer:

The reduction potential of   [tex]Cu^2+/Cu[/tex] is  [tex]E_c^o = 0.34 \ V[/tex]

Explanation:

From the question we are told that

      The potential of the cell is  [tex]M_{cell} = E^o _{cell} = 1.100 \ V[/tex]

       The range is  [tex]R = 0.005 \ V[/tex]

        The temperature is  [tex]T = 25 ^oC[/tex]

Note the reason why Zn is oxized and  Cu is reduced is because Zn is higher than Cu on the electrochemical series

    The reaction at the anode is  

              [tex]Zn ^{2-} _{(aq)} + 2e \to Zn_{(s)} \ \ \ \ \ E^o_a = -0.76 \ V[/tex]    

The [tex]E^o\ is \ the \ standard\ oxidation \ potential\ value\ for\ Zn\ oxidation[/tex]

    The reaction at the anode is  

             [tex]Cu^{2+} _{(aq)} + 2e^{-} \to Cu_{(s)} \ \ \ \ \ \ \ \ E^o_c = c \ V[/tex]  

Now

          [tex]E^o _{cell} = E_c^o - E_a^o[/tex]  

substituting values

           [tex]1.100 = E_c^o -(- 0.76)[/tex]

           [tex]E_c^o = 1.100 - 0.76[/tex]

           [tex]E_c^o = 0.34 \ V[/tex]

Hence the reduction potential of   [tex]Cu^2+/Cu[/tex] is  [tex]E_c^o = 0.34 \ V[/tex]

1-bromo-3-isobutil-4-heptanol

Answers

Answer:

See explanation.

Explanation:

Hello,

In this case, the chemical structure of the given compound, which is an alcohol, based on the suffix "ol", the bromo radical at the first carbon and the isobutyl radical at the 3rd carbon is shown on the attached picture wherein the hydroxyl is drawn at the 4th carbon. Remember that IUPAC rules for nomenclature help us to easily name or draw organic molecules by indicating the radicals and their positions and the main chain at the en of the name.

Best regards.

The diagrammatic structure for the compound 1-Bromo-3-isobutyl-4-heptanol  can be seen in the image below.

When naming an organic compound, we will first consider the longest chain of the carbon atom and attach the substituents in such a way that we will have the lowest number when adding them.

In the compound 1-Bromo-3-isobutyl-4-heptanol, we first draw the seven carbon chain with -OH substituent on the fourth carbon. This was followed by adding the substituent of isobutyl to carbon atom 3 and bromine to carbon atom 1.

Learn more about naming organic compounds here:

https://brainly.com/question/5994723?referrer=searchResults

A certain half-reaction has a standard reduction potential E0red = +0.13V . An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 1.10V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell.

Required:
a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?
b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?

Answers

Answer:

a. 1.23 V

b. No maximum

Explanation:

Required:

a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?

b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

If E°cell must be at least 1.10 V (E°cell > 1.10 V),

E°red, cat - E°red, an > 1.10 V

E°red, cat - 0.13V > 1.10 V

E°red, cat > 1.23 V

The minimum standard reduction potential is 1.23 V while there is no maximum standard reduction potential.

Consider the following information.

A+ KOH → B+ 2 KNO3What is the molecular formula of A, what is the molecular formula for B? You have to balance the A + KOH part of the equation. MM of B = 62.068g/mol

B is 38.67 % C, 9.67% H and 51.56 % O

Answers

Answer:

The molecular formula for A is C2H4(NO3)2

The molecular formula for B is C2H6O2

Explanation:

I linked an image that will show the work.

Kayla wants to be an active listener. What can she do?
A. She can tell people what she knows about their backgrounds.

B. She can ask people about their backgrounds .

C. She can say she already knows everything about different backgrounds.

D.She can write songs about people's backgrounds .

Answers

B. she can ask people about their backgrounds

This requires listening, the rest do not

Answer:

B. She can ask people about their backgrounds .

Explanation:

A, C, and D, aren't good answers.

(A. She can tell people what she knows about their backgrounds.) Telling is far different from listening.

(C. She can say she already knows everything about different backgrounds.) Saying you know everything about a background wouldn't be a good answer.

(D. She can write songs about people's backgrounds.) This could be an answer but I believe that B. is the answer.

Hope this helped :)

How many liters of air are in a room that measures 10.0 ft × 11.0 ft and has an 8.00 ft ceiling? 1 in. = 2.54 cm (exactly); 1 L = 103 cm3

Answers

Answer:

2.42x10^5 L

Explanation:

10.0ft x 11.0 ft x 8.00 ft = 880. ft^3 (1 cubic foot = 28316.8 cubic cm)

880. ft^3 * (28316.8 cubic cm/ 1 cubic foot) = 24,918,784 cm^3

(1L=103 cm^3)

24,918,784 cm^3 (1L/103 cm^3) = 2.42x10^5 L

[tex]2.42*10^5[/tex]  liters of air are in a room.

Unit conversions:  

It helps to show another person the exact amount you have. Assist in solving a mathematical problem, especially in chemistry, where you can follow the units to get to the answer. Show which measurement system the person is using.

1 in. = 2.54 cm

1 L = 10³ cm³

Given: 10.0 ft × 11.0 ft 8.00 ft ceiling

Now, converting into given quantities:

[tex]10.0ft * 11.0 ft * 8.00 ft = 880. ft^3 ( = 28316.8 \text{ cubic cm})\\\\880. ft^3 * (\frac{28316.8 \text{ cubic cm}} {\text{1 cubic foot}} }) = 24,918,784 cm^3\\\\24,918,784 cm^3 (\frac{1L}{10^3 cm^3})= 2.42*10^5 L[/tex]

→  Thus,[tex]2.42*10^5[/tex] liters of air are in a room that measures 10.0 ft × 11.0 ft and has an 8.00 ft ceiling.

Find more information about Unit conversion here: brainly.com/question/13016491

.The Lithosphere is another name used for one of the earth systems. Name this system!

Answers

Answer:

Earth's crust

Explanation:

The lithosphere is the rigid outer part of the earth, consisting of the crust and upper mantle. It is the, rigid, rocky outer layer of the Earth, consisting of the crust and the solid outermost layer of the upper mantle. It extends to a depth of about 60 miles (100 km). It is the outer part of the solid earth composed of rock essentially like that exposed at the surface, consisting of the crust and outermost layer of the mantle.

We can also look at it as the solid part of the earth on which plants grow and animals survive. It contains all the rock formations that bear the various minerals found on earth.

The lithosphere is composed of both the crust and the portion of the upper mantle that behaves as a brittle, rigid solid.

Question 2
In the reaction:
P4+6C12 - 4PC13
How many grams of P4 are required for the complete reaction of 2.40 moles of CIZ?
0 0.1168
12.4g
298 g
1988
49.6 g

Answers

I think the answer should be 12.4g but idk why u don’t have abcd

how many moles are in 15 grams of lithium?

Answers

Answer:

there are approximately 52 moles in 15 grams of lithium.

Base your answers on the graph below, which represents uniform cooling of a sample of a pure substance, starting as a gas. Solid and liquid phases can exist in equilibrium between points

Answers

Answer:

D & E

Explanation:

I think this is dealing with latent heat and D & E would be the range where you will find solid and liquid phases in equilibrium, cuz it starts as gas at from A to B, B to C is gas and liquid equilibrium, C to D is liquid, D to E solid and liquid, and then E to F is solid.

Other Questions
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