Answer: 4.4 x 10^-7
Explanation:
0.000066 x 0.0000066 / 0.01
= 4.4 x 10^-7
5.07 x 10^24 atoms of antimony is how many moles?
8.98 mol
7.99 mol
4.82 mol
8.42 mol
Answer:
8.42 moles (3 sig. figs.)
Explanation:
Given 5.07 x 10²⁴ atoms of antimony (Sb) => ? moles Sb
1 mole of any substance contains 6.02 x 10²³ particles ( atoms or molecules)
∴ Think in terms of 'how many 6.02 x 10²³'s are in 5.07 x 10²⁴ atoms Sb?
That is => moles Sb = 5.07 x 10²⁴ atoms Sb / 6.02 x 10²³ atoms Sb/mole Sb
= 8.42192691 moles Sb (calculator answer) ≅ 8.42 moles (3 sig. figs.)
the article is on newsela called the water cycle
Answer:
Explanation:Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?
C3H8(g) + 5 O2(g) ---->3 CO2 (g)+ 4H2O (g)
If the experiment contains 75.0 grams of O2, how many grams of H2O should be produced?
Answer: 33.75g H2O
Explanation:
75g O2 (1 mol O2/32g O2) (4 mol H2O/5 mol O2) (18g H2O/1 mol H2O) = 33.75g H2O
This is a stoichiometric calculation in which 75 is multiplied by 1, 4, and 18 (the top numbers), and then divided by (32 x 5 x 1), which are the bottom numbers.
Stoichiometry is super fun once you get the hang of it!!
How many bromine atoms are present in 39.1 g of CH2Br2
Answer:
Answer:
2.77 × 10²³ Br Atoms
Solution:
Data Given:
Mass of CH₂Br₂ = 39.9 g
M.Mass of CH₂Br₂ = 173.83 g.mol⁻¹
Step 1: Calculate Moles of CH₂Br₂ as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 39.9 g ÷ 173.83 g.mol⁻¹
Moles = 0.23 mol
Step 2: Calculate number of CH₂Br₂ Molecules,
As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of CH₂Br₂ Molecules can be written as,
Moles = Number of CH₂Br₂ Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹
Solving for Number of CH₂Br₂ Molecules,
Number of CH₂Br₂ Molecules = Moles × 6.022 × 10²³ Molecules.mol⁻¹
Putting value of moles,
Number of CH₂Br₂ Molecules = 0.23 mol × 6.022 × 10²³ Atoms.mol⁻¹
Number of CH₂Br₂ Molecules = 1.38 × 10²³ CH₂Br₂ Molecules
Step 3: Calculate Number of Br Atoms:
As,
1 Molecule of CH₂Br₂ contains = 2 Atoms of Br
So,
1.38 × 10²³ Molecules of CH₂Br₂ will contain = X Atoms of Br
Solving for X,
X = (1.38 × 10²³ CH₂Br₂ × 2 Br) ÷ 1 CH₂Br₂
X = 2.77 × 10²³ Br Atoms
Explanation:
How many moles of product are formed? Can someone help me ?
Answer:
It says right under here what to do
Explanation
Determine the moles of product produced by dividing the grams of product by the grams per mole of product. You now have calculated the number of moles of every compound used in this reaction. 41.304 g of NaCl ÷ 58.243 g/mol = 0.70917 moles of NaCl.
How many joules are in 1.81 calories need to know ASAP
Which rank was NOT included in Linnaeus' taxonomy?
Kingdom
Family
Domain
Order
Answer:
Domain
Explanation:
This is because Linnaeus taxonomy is a system of classification which was invented by a swedish Botanist called Carl Linnaeus and it is refered to hierarchy of grouping organisms called taxa. It involve 7 system of classifications and they include Kingdom, Phylum, Class, Order, Family, Genus, and Species.
Who ever has the best answer to this question gets brainliest
Answer:
"Conduction from the sun heating the metal slide" is the answer
Explanation:
A 23.8 mL sample of HCl of unknown concentration is neutralized by 5.45 mL of 0.331 M Ca(OH)2. What is the concentration of the HCl solution?
(The answer is 0.152, but I need an explanation/steps to get that answer)
A sugar solution is 15% pure. How
many grams of sugar are there in 550
grams of the solution?
Answer:
Amount of sugar in solution = 82.5 gram
Explanation:
Given:
Sugar in solution percentage = 15%
Total solution = 550 grams
Find:
Amount of sugar in solution
Computation:
Amount of sugar in solution = Sugar in solution percentage x Total solution
Amount of sugar in solution = 15% X 550
Amount of sugar in solution = 82.5 gram
What is the specific heat of iron, if it requires 1120 J of heat energy to raise the
temperature of 430.0 g of iron from 10.0ºC to 20.4ºC
Answer:
Specific heat is defined as the amount of heat needed to raise the temperature by one degree celsius. Therefore, in 1 kg there are 100 grams so, 10 grams equal 0.01 Kg. Thus, calculate the specific heat value as follows. Thus, we can conclude that specific heat of the given metal is 0.5 .
Explanation:
When air hockey is played, a small plastic puck slides across a table that has holes through which air is forced. What effect does the air have on the game?
Answer:
it reduces the atmospheric pressure
valence number of a metallic element X is 3. What is the formula of its oxide?
Answer:
the formula of its oxide is X2O3.
There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the formula of given metallic oxide is X[tex]_2[/tex]O[tex]_3[/tex].
What is chemical Compound?Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.
An ionic compound is a metal and nonmetal combined compound. Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.
Since valence number of a metallic element X is 3 and valence number of oxide is 2. So, the formula of its oxide is X[tex]_2[/tex]O[tex]_3[/tex].
Therefore, the formula of given metallic oxide is X[tex]_2[/tex]O[tex]_3[/tex].
To learn more about chemical compound, here:
brainly.com/question/26487468
#SPJ2
120 L of C3H8 is how many grams?
Answer:
44.09562 grams
Explanation:
1°C if the pressure is 149.3 kPa? How many moles of hydrogen sulfide H2S are contained in a 327.3 mL bulb at 48.
Answer:
Number of moles of H₂S gas = 0.0183 moles
Note: The question is incomplete. The complete question is given below:
How many moles of hydrogen sulfide H2S are contained in a 327.3 mL bulb at 48.1°C if the pressure is 149.3 kPa?
Explanation:
The following values are given in the question :
Volume of H₂S gas = 327.3 M = 0.3273 L
Temperature of gas = 48.1°C = (273.15 + 48.1) K = 321.25 K
Pressure of gas = 149.3 kPa
1 kPa = 0.00987 atm; 149.3 kPa = 149.3 × 0.00987 atm = 1.474 atm
Molar gas constant, R = 0.0821 liter·atm/mol·K.
number of moles, n = ?
Using PV = nRT
n = PV/RT
n = (0.3273 × 1.474)/(0.0821 × 321.25)
n = 0.0183 moles
Therefore, number of moles of H₂S gas = 0.0183 moles
A chemist has a sample of 1.88 M HCl. What volume of the sample does he require to prepare 200 mL of 0.45 M HCl?
Answer: v = 200 ml · 0.45 M/ 1.88 M
Explanation: when solution is diluted, amount of substance
is same and n= c · V v1 = v2 · c2 / c1
The appropriate answer is "47.87 mL".
Given values are:
Concentration of undiluted HCl, [tex]C_1=1.88 \ M[/tex]Concentration of diluted HCl, [tex]C_2=0.45 \ M[/tex]Volume of diluted HCl, [tex]V_2=200 \ mL[/tex]By using the dilution equation, we get
→ [tex]C_1V_1=C_2V_2[/tex]
or,
→ [tex]V_1=\frac{C_2V_2}{C_1}[/tex]
By substituting the given values, we get
→ [tex]=\frac{0.45\times 200}{1.88}[/tex]
→ [tex]=\frac{90}{1.88}[/tex]
→ [tex]= 47.87 \ mL[/tex]
Thus the above answer is correct.
Learn more about volume here:
https://brainly.com/question/2520099
Jason has a bag that contains
8
88 identically shaped boxes.
6
6start color #6495ed, start text, 6, end text, end color #6495ed of the boxes are
blue
bluestart color #6495ed, start text, b, l, u, e, end text, end color #6495ed, and
2
2start color #28ae7b, start text, 2, end text, end color #28ae7b are
green
greenstart color #28ae7b, start text, g, r, e, e, n, end text, end color #28ae7b.
3
of the blue boxes have a prize
3 of the blue boxes have a prizestart color #6495ed, start text, 3, space, o, f, space, t, h, e, space, b, l, u, e, space, b, o, x, e, s, space, h, a, v, e, space, a, space, p, r, i, z, e, end text, end color #6495ed, and
1
of the green boxes has a prize
1 of the green boxes has a prizestart color #28ae7b, start text, 1, space, o, f, space, t, h, e, space, g, r, e, e, n, space, b, o, x, e, s, space, h, a, s, space, a, space, p, r, i, z, e, end text, end color #28ae7b.
Jason randomly selects a box from the bag. Let
A
AA be the event that he selects a box with a prize and
B
BB be the event that the box is green.
Which of the following statements are true?
Choose all answers that apply:
Choose all answers that apply:
(Choice A)
A
P
(
A
|
B
)
=
P
(
A
)
P(A | B)=P(A)P, left parenthesis, A, start text, space, vertical bar, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, the conditional probability that Jason selects a box with a prize given that he has chosen a green box is equal to the probability that Jason selects a box with a prize.
(Choice B)
B
P
(
B
|
A
)
=
P
(
B
)
P(B | A)=P(B)P, left parenthesis, B, start text, space, vertical bar, space, end text, A, right parenthesis, equals, P, left parenthesis, B, right parenthesis, the conditional probability that Jason selects a green box given that he has chosen a box with a prize is equal to the probability that Jason selects a green box.
(Choice C)
C
Events
A
AA and
B
BB are independent events.
(Choice D)
D
The outcomes of events
A
AA and
B
BB are dependent on each other.
(Choice E)
E
P
(
A
and
B
)
=
P
(
A
)
⋅
P
(
B
)
P(A and B)=P(A)⋅P(B)P, left parenthesis, A, start text, space, a, n, d, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, dot, P, left parenthesis, B, right parenthesis, the probability that Jason selects a box that contains a prize and is green is equal to the probability that Jason selects a box with a prize multiplied by the probability that he selects a green box.
Answer:
A. P(A | B)=P(A)P, left parenthesis, A, start text, space, vertical bar, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, the conditional probability that Jason selects a box with a prize given that he has chosen a green box is equal to the probability that Jason selects a box with a prize.
B. P(B | A)=P(B)P, left parenthesis, B, start text, space, vertical bar, space, end text, A, right parenthesis, equals, P, left parenthesis, B, right parenthesis, the conditional probability that Jason selects a green box given that he has chosen a box with a prize is equal to the probability that Jason selects a green box.
C. Events AAA and BBB are independent events.
E. P(A and B)=P(A)⋅P(B)P, left parenthesis, A, start text, space, a, n, d, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, dot, P, left parenthesis, B, right parenthesis, the probability that Jason selects a box that contains a prize and is green is equal to the probability that Jason selects a box with a prize multiplied by the probability that he selects a green box.
Explanation:I got it right on Kahn
1L = 1000 mL
Molarity (M) = moles of solute / L of solution
Calculate the moles of NaCl required to prepare 250 mL of 1.5 M aqueous solution.
Answer:· 44 g NaCl Explanation: The problem provides you with the molarity and volume of the target
Explanation:
Equal masses of aluminum and copper are heated to 100 degree C and placed in water. Which would cause the water to reach the higher temperature? Explain your answer.
Answer:
copper will reach to higher temperature first.
Explanation:
help please i don’t know
Answer:
Okay, so basically your first question is asking what parts of everything mean so part A is the atomic number and the atomic number, in this case, the atomic number is 8 and atomic numbers are the number of protons so there are 8 protons, Part B. is the symbol which identifies what it is, O=Oxygen, Part C. is the name, oxygen, Part D. is the atomic mass, you usually round it so it would be 16, the number of protons+neutrons is this number so since we know the number of protons is 8, 16-8=8, therefore giving 8 neutrons, The number of electrons is equal to the number of protons.
After:
Now using this lovely knowledge, find Carbon and neon :)
A solution of silver chlorate reacts with a solution of lithium iodide.
provide the net ionic equation if the reaction takes place.
Answer: [tex]Ag^+(aq)+I^-(aq)\rightarrow AgI(s)[/tex]
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.
The given chemical equation is:
[tex]AgClO_3(aq)+LiI(aq)\rightarrow AgI(s)+LiClO_3(aq)[/tex]
The complete ionic equation is:
[tex]Ag^+(aq)+ClO_3^-(aq)+Li^+(aq)+I^-(aq)\rightarrow AgI(s)+Li^+(aq)+ClO_3^-(aq)[/tex]
The ions which are present on both the sides of the equation are lithium and chlorate ions. and hence are not involved in net ionic equation.
Thus the net ionic equation is:
[tex]Ag^+(aq)+I^-(aq)\rightarrow AgI(s)[/tex]
Plssss help ASAP I really need help with this y’all I’m bad at science
What is a similarity between a fish embryo and a human embryo in the late stages of development?
They both have tails
They both have gills.
They both have spines.
They both have arms.
Answer:In the LATER stages of development they would have a spine
Explanation:
some of Earth layers are not solid and are able to flow true or false
Answer:
True?
can I have brainiest pls
≡(▔﹏▔)≡
What is the function of white blood cells?
A) immunity
b) carry nutrients, waste
C) blood clotting
Answer:
A
Explanation:
They help fight infection and other disease
Answer:
immunity is the answer for this question
Male wood ducks mate only with female wood ducks. They produce male and female wood duck offspring that can mate only with other wood ducks. These facts
indicate that wood ducks:
Are inbred.
Do not mutate.
Are a species.
Lack variability
HELP
Answer:
Anyone got the answers
Explanation:
Answer: A
Explanation: just do as I say
What is the pressure of a mixture of oxygen, nitrogen and carbon dioxide gases if the pressures of these gases are as follows: PO2 = 254 mm Hg, PN2 = 0.351 atm, and
PCO2 = 43.9 kPa?
Answer:
his is an example of a first-year chemistry question where you must first convert two of the pressures to the units of the third and add them up, per Dalton’s law of additive pressures. There are three possible answers, one for each of the three pressure units.
1 atm = 760 torr …… torr and mm Hg are the same
1 atm = 101.3 kPa
Dalton’s law:
P(total) = P(O2) + P(N2) + P(CO2)
Explanation:
Gases will assume whatever pressure depending on the equation of state of the mixture (in this case) and the volume htey are contained in. That could be the ideal gas law and simple mixing law, If you are quoting the partial pressures which you call simply “the pressure” of each gas, and that these refer to their values in the present mixture, then yes, we would add them up. The pressures are low enough for the ideal gas law to apply provided the temperature is not extremely low as well .
can someone help me, please?
Estimate the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm. [Note: This is a high-field (low-spin) complex.]
Answer:
The crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm is - 1987.59kJ/mole
Explanation:
Lets calculate -:
Crystal field stabilization energy -
[tex]E=\frac{hc}{\pi }[/tex]
where h = planks constant = [tex]6.626\times10^-^3^4 Js[/tex]
c= velocity of light = [tex]3\times10^8m/second[/tex]
[tex]\pi =wavelength=600nm=600\times10^-^9m[/tex]
[tex]E=\frac{6.626\times10^-^3^4\times3\times10^8}{600\times10^-^9}[/tex]
=[tex]0.033\times10^-^1^6 J/ion[/tex]
= [tex]0.033\times10^-^1^6\times6.023\times10^2^3[/tex]
= [tex]0.198759\times10^7 J/mole[/tex] = [tex]1987.59\times10^3J/mole[/tex]
= [tex]1987.59kJ/mole[/tex]
Thus , the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) is 1987.59kJ/mole
explain fusion phenomenon
Answer:
is is the process of combination of two or more small nuclei to form large nucleus having large amount of energy