The free body diagram shows the forces that act on the object.
What is a free body diagram?We know that force is a vector quantity as such the direction of the force can also be seen to be very important and this is what have given rise to the idea of the free body diagram because it would show all the forces that have acted on the objects.
In effect, what we have been asked to do here is to draw the free body diagram of the system that is under study here. In this diagram all of the forces that is acting on each of the objects must be balanced.
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imagine you are standing in the northern hemisphere. looking directly north, you see a star just above the horizon. a little later you notice that it has shifted position slightly. which way did it move?
Answer:
If one is looking north one would see the sun rise in the East (move counterclockwise) - the star will move in the same direction - counterclockwise towards the zenith
Discuss the ethical considerations in providing immunization.
There are numerous, interconnected ethical problems that arise with delivering immunizations and vaccine mandates.
Many interconnected ethical problems can be present in debates about vaccine mandates. This is true of the human papillomavirus (HPV) vaccine, which prevents the sexually transmitted disease (STD). The initial HPV vaccination was given b approval in 2006. Several state legislatures attempted to impose immunizations requirements after the ACIP recommended three doses of the vaccine for girls between the ages of 11 and 12. Religious objections to the mandate range from worries that an STD vaccine goes against abstinence-based teachings to worries that the vaccine would force a child to have an intervention that isn't in line with her family's values.
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Write a rate equation for the following reaction given the indicated mechanism. Click in the answer box to activate the palette
We know that slowest step is the rate determining step so according to rate law, rate equation for this reaction will be : rate = k [ (CH3)3CBr ]
where, k = rate constant
How to explain the rateBecause the rate of reaction only depends upon the nature of tertiary alkyl haide i.e. (CH3)3CBr ( substrate) and not depends upon the nature of attacking species i.e. weak nucleophile (OH - ). therefore the given reaction indicates the SN1 ( i.e. Unimolecular Nucleophilic Substitution) reaction.
Favourable conditions of SN1 reaction :-
(1) tertiary alkyl halide > secondary alkyl haide > primary alkyl halide
(2) weak nucleophile
(3) good leaving group i.e. I > Br > Cl
(4) Polar protic solvent.
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A 2 kg ball falls to the ground from 3 m. At impact, the velocity of the ball was 7.70 m/s. How much kinetic energy did it have at impact?
Group of answer choices
59.3 J
75.1 J
46.2 J
67.2 J
The kinetic energy the ball has on impact, given that the ball has a mass of 2 Kg and a velocity of 7.70 m/s is 59.3 J (First option)
How do I determine the kinetic energy?Kinetic energy is the energy of moving objects. It is represented as:
KE = ½mv²
Where
KE is the kinetic energy of the objectm is the mass of the objectv is the velocity of the object.Now, we shall determine the kinetic energy of the ball on impact. Details below:
Mass of ball (m) = 2 KgVelocity of ball (v) = 36 m/sKinetic energy of ball (KE) =?KE = ½mv²
KE = ½ × 2 × 7.70²
KE = 1 × 59.3
KE = 59.3 J
Thus, we canconclude that the kinetic energy is 59.3 J (First option)
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a ball is thrown straight up. what are the velocity and acceleration of the ball at the highest point in its path?
When a ball is straight up , then at highest point velocity is zero and acceleration is "acceleration due to gravity" .
When the ball thrown upwards reaches the highest point, the velocity changes from upward to downward, and the acceleration of ball changes from upward to downward.
At this point , the velocity of the ball becomes zero(0) and the acceleration is directed downward, that means that the ball is momentarily at rest position and then begins to fall back down.
The acceleration(g) of the ball which is due to gravity will be constant and will act in downward direction , and this acceleration causes the velocity of ball to increase as it falls back downwards .
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the bandwidth of a signal is question 5 options: 1) the lowest frequency value subtracted from the highest 2) the average of the frequencies 3) the range of frequencies in the signal 4) the maximum amplitude of the signal
The correct option is B. The spectrum of a signal is the range of frequencies in the signal.
A spectrum (plural spectra or spectrums) is a condition that isn't restricted to a specific set of values but can vary, without gaps, across a continuum. The word became first used scientifically in optics to explain the rainbow of colors in visible light after passing via a prism. As clinical information of mild superior, it got here to apply to the whole electromagnetic spectrum. It thereby has become a mapping of a variety of magnitudes (wavelengths) to a range of traits, which are the perceived "shades of the rainbow" and different houses which correspond to wavelengths that lie outdoors of the visible light spectrum.
Spectrum has due to the fact that been implemented via analogy to topics outside optics. therefore, one would possibly communicate approximately the "spectrum of political opinion", the "spectrum of interest" of a drug, or the "autism spectrum". In these uses, values within a spectrum may not be associated with precisely quantifiable numbers or definitions. Such makes use of implying a wide variety of situations or behaviors grouped together and studied under an unmarried identity for ease of discussion. Nonscientific makes use of the time period spectrum is once in a while deceptive.
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Complete Question:
The spectrum of a signal is:
A. the lowest frequency value subtracted from the highest
B. the range of frequencies in the signal
C. all of the frequencies from 0 to the highest frequency used
D. the average of the highest frequency and the lowest
B. A guitar string has a length of 0. 90 m. When you pluck it, it plays a "C" that has a frequency of 256 Hz. How fast is the wave moving back and forth along the string? (Choose one of the equations from the box at the top of the page to solve this problem. )
Equations to use: v= λ ∙ f v=d/t
The wave on the guitar string is moving back and forth with a speed of 460.8 m/s.
What is the frequency of a string calculated from?
The frequency is given by f = 1/T = v/. So f = v/λ. We also noticed that the fundamental frequency, f1, has a string length of /2, making f1 equal to v/2L. The linear density, or mass per unit length, and the string tension F are what determine the wave speed. v = (F/)1/2 = (FL/M)1/2.
The speed of a wave (v) on a guitar string can be calculated using the equation:
v = λ * f
The wavelength of the wave can be calculated using the equation:
λ = 2 * L/n
where L is the length of the guitar string, n is the harmonic number (in this case, n = 1 for the fundamental mode).
Substituting L = 0.9 m and n = 1, we get:
λ = 2 * 0.9 m/1 = 1.8 m
The frequency of the wave is given as f = 256 Hz.
Substituting λ = 1.8 m and f = 256 Hz into the first equation, we get:
v = λ * f = 1.8 m * 256 Hz = 460.8 m/s
Therefore, the wave on the guitar string is moving back and forth with a speed of 460.8 m/s.
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how cold does it have to be for boiling water trick
The boiling water trick, where hot water thrown into cold air instantly vaporizes into a mist, typically requires temperatures at or below freezing (0 degrees Celsius or 32 degrees Fahrenheit).
Exact temperature required for this trick to work depends on a variety of factors, including the temperature and humidity of the surrounding air, the altitude, and the initial temperature of the hot water.
Generally, the colder the air temperature and the hotter the water, the more dramatic the effect will be. However, it's important to note that this trick can be dangerous if not done properly, as hot water can cause serious burns if comes into contact with skin or clothing. It's important to follow proper safety precautions.
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an applied horizontal force of 92.4 n is exerted on a 171 n box. the box is on a horizontal floor and the coefficient of kinetic friction between the box and the floor is 0.386. at what rate will be box accelerate? include a free body diagram.
The box will accelerate at a rate of 1.49 m/s^2.
We first need to calculate the net force acting on it. The net force is the vector sum of all the forces acting on the box, and it determines the acceleration of the box using Newton's Second Law of Motion:
net force = mass x acceleration
[tex]net force = f applied - f_k[/tex]
Since the box is not accelerating vertically, the net force in the vertical direction is zero, which means:
[tex]f_k = μ_k x f_N[/tex]
[tex]net force = f_applied - f_k[/tex]
[tex]= 92.4 N - (0.386) x f_N[/tex]
[tex]= 92.4 N - (0.386) x (171 N)[/tex]
[tex]= 26.0 N[/tex]
[tex]f_N = m x g = 171 N[/tex]
[tex]f_k = μ_k x f_N[/tex]
[tex]= 0.386 * 171 N[/tex]
[tex]= 65.9 N[/tex]
Using Newton's Second Law, we can solve for the acceleration of the box: net force = mass x acceleration
[tex]26.0 N = 17.4 kg x acceleration[/tex]
[tex]acceleration = 1.49 m/s^2[/tex]
The mass of the box is [tex]m = 171 N / 9.81 m/s^2 = 17.4 kg[/tex] (using the acceleration due to gravity g of [tex]9.81 m/s^2[/tex]).
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Over the next two days you will be doing a gas laws lab. Describe what you
changed in each experiment and what you observed. Explain why you think each
experiment works, or describe problems that caused the experiment to fail.
Respond to your classmates and compare your answers to theirs. See if you can
help classmates who are having trouble
In this experiment, I changed the temperature of the gas by immersing the container in hot and cold water. In other experiment, I changed the volume of the gas by placing a lid on the container and then removing it.
I observed that when the container was immersed in hot water, the pressure of the gas increased, and when the container was immersed in cold water, the pressure of the gas decreased. I think this experiment works because of the gas law formula, which states that pressure and temperature are inversely proportional, meaning that as temperature increases, pressure increases, and when temperature decreases, pressure decreases.
I observed that when the lid was placed on the container, the pressure of the gas increased, and when the lid was removed, the pressure of the gas decreased. I think this experiment works because of the gas law formula, which states that pressure and volume are inversely proportional, meaning that as volume decreases, pressure increases, and when volume increases, pressure decreases.
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how does the fujita scale measure tornado intensity?
The Fujita or Fujita-Pearson scale is majorly used to measure the intensity of the tornadoes. It takes into account the degree of destruction which is caused by the tornado in structures built by men.
On the other hand, the intensity of hurricanes is measured using the Saffir-Simpson scale, which classifies them from level 1 (the lowest) to level 5 (the highest) depending on the strength of the winds.
The Fujita Scale (F Scale) also known as the Fujita-Pearson Scale (FPP Scale) measures and classifies the intensity of tornados. The scale bases and its rating on the destruction caused by the tornado. The scale recently was modified in the United States in 2007. It was renamed it as the Enhanced Fujita Scale (EF Scale).
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Which elements should form an ionic bond
A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of the carriage has__ energy. Calculate it.
The required energy the carriage has, when the displacement of the carriage and mass of the carriage with the baby are given is calculated to be 1029 J.
The energy in the above case is nothing but the work done by the carriage.
The work is defined as,
W = F d
where,
F is force
d is displacement
Entering the values in the above equation, we have,
W = F d = m × a × d = 5 × 9.8 × 21 = 1029 J
Thus, the required energy the carriage has is calculated to be 1029 J.
The given question is inappropriate. The question is 'a baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 5kg whats the energy the carriage has?'
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Problem 7
A projectile launched straight up into the air has a velocity of 10 m/s and a mass of 1-kg.
A. What is the KE of the projectile after it is launched?
B. What is the distance it will travel into the air?
A. The KE of the projectile after it is launched is 50J.
B. The projectile will travel 19.62 metres into the air before reaching its maximum height.
Given :
A. The kinetic energy (KE) of the projectile can be calculated as follows:
KE = [tex]1/2 * m * v^2[/tex]
where m is the projectile's mass and v is its speed.
KE = [tex]1/2 * 1 kg * (10 m/s)^2 = 50 J[/tex]
B. The distance travelled by the projectile can be calculated using the equation of motion:
y = [tex]v_0 * t + 1/2 * a * t^2[/tex]
where an is the gravitational acceleration (9.8 m/s2), y is height, v 0 is initial velocity, t is time, and v 0 is initial velocity
We can set v 0 = 10 m/s and a = -9.8 m/s2 because the projectile was fired vertically up into the air at a velocity of 10 m/s.
By setting y = 0 (the point at which the projectile reaches its highest point and stops), calculating the time t, and then re-inserting the result into the equation for y, the following can be done:
[tex]0 = 10 m/s * t - 4.9 * t^2\\t = 10 m/s / 4.9 m/s^2 = 2.04 s\\y = 10 m/s * 2.04 s - 4.9 * (2.04 s)^2 = 19.62 m[/tex]
So, the projectile will travel a distance of 19.62 m into the air before reaching its maximum height.
What is a projectile's kinetic energy when it is at its highest point?
Half of the projectile's initial kinetic energy remains at its highest point.
What is the formula for kinetic energy?
Kinetic energy (K.E.) is directly inversely correlated with an object's mass and the square of its velocity: K.E. = / m v2.The kinetic energy is measured in kilograms-meters squared per second squared, where the mass is measured in kilogrammes and the velocity is measured in metres per second.
At what point of projectile motion kinetic energy is minimum?
A projectile's highest point has the least amount of kinetic energy. As a result, the horizontal distance is equal to 0 and the range R.
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when setting up a lab scope to measure a waveform that ranges from 0 to 15 volts; if there are eight vertical divisions, what must the voltage level be set at to display the entire waveform?
When the waveform ranges from 0 to 15 volts on a lab scope with eight vertical divisions, each division corresponds to 15/8 = 1.875 volts. In order to precisely measure the waveform.
An illustration of a signal's fluctuation over time or space is called a waveform. Visualizing electrical, acoustic, and other sorts of signals is frequently done in physics, engineering, and electronics. The waveform displays the signal's amplitude, frequency, phase, and other characteristics, giving analysts and troubleshooters vital data. The underlying characteristics of the system that produced a waveform, such as harmonics, noise, distortion, and modulation, can be seen in the shape of the waveform. Different waveforms, including sine, square, sawtooth, and triangle waves, have various mathematical characteristics and serve various functions. For the purpose of designing and testing electronic circuits and systems, waveforms must be precisely measured and interpreted.
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Could someone explain how to solve this?
If a 1,300 kg car is moving at 27 m/s when it hits a truck, resulting in a 21,000 N force that slows the car down to 15 m/s, for how long did the car experience the force?
Answer:
Explanation:
We can use the equation:
$F = ma$
where F is the force, m is the mass, and a is the acceleration.
To find the acceleration, we can use:
$a = \frac{\Delta v}{\Delta t}$
where $\Delta v$ is the change in velocity and $\Delta t$ is the time interval.
Rearranging the first equation, we get:
$t = \frac{m\Delta v}{F}$
Substituting the given values, we get:
$t = \frac{(1300\text{ kg})(15\text{ m/s} - 27\text{ m/s})}{21000\text{ N}} \approx 1.86\text{ s}$
Therefore, the car experienced the force for about 1.86 seconds.
an object moves at a constant velocity of 11 m/s in the southwest direction for an interval of 20 s. what is the magnitude of its instantaneous velocity halfway through this interval?
Calculating the change in velocity involves dividing the deceleration by the amount of time that has passed: pace change = 6.95 x 4 = 27.8 m/s. Due to a zero velocity profile.
What is the velocity speed?
The final velocity, on the other hand, is a vector number that gauges a moving body's speed and direction when it has reached its highest acceleration. How is the final velocity determined? It is easy to determine the final velocity with a few math and little conceptual understanding.
Is the term "velocity" a vector term?
In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate. A moving item can never move at a negative speed. A moving item can have zero velocity. The main determinant of an object's quickness is its speed.
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what is the strength and direction of the electric field inside the membrane just before the stimulus (
The strength and direction of the electric field inside the membrane just before the stimulus is zero.
What is electric field?An electric field is a region of space around a charged particle or object that exerts an electric force on other charged objects within its vicinity. Electric fields are created by differences in electric potential, which is the amount of energy contained within a region of space due to the presence of electric charge. Electric fields are represented by lines of force, which indicate the direction of the force and its magnitude. Electric fields are measured in units of volts per meter (V/m).
This is because in the resting state, the membrane potential is in equilibrium, meaning that the total electric field inside the membrane is equal to zero. This is due to the fact that the concentration of positive and negative ions on both sides of the membrane are equal, so the electric field created by the positive ions is canceled out by the electric field created by the negative ions.
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There is a bell at the top of a tower that is 45 m high. The bell has a mass of 40kg. The bell has__ energy. Calculate it.
The required energy the bell has at the top of a tower, when the height of the bell and mass of the bell are given is calculated to be 17.6 kJ.
The energy in the above case is nothing but the gravitational potential energy.
Gravitational potential energy = m × g × h
where,
m is mass
h is height
g is gravity
Entering the values in the above equation, we have,
P.E = m × g × h = 40 × 9.8 × 45 = 17640 J = 17.6 kJ
Thus, the required energy the bell has at the top of the tower is calculated to be 17.6 kJ.
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a 1000-lb wrecking ball hangs from a 50-ft cable of density 6 lb/ft attached to a crane. calculate the work done if the crane lifts the ball from ground level to 50 ft in the air by drawing in the cable.
Work done if the crane lifts the ball from ground level to 50 ft in the air by drawing in the cable. is 67208.4Joule.
In material science, work is the energy moved to or from an item through the utilization of power along a dislodging. In its least complex structure, for a consistent power lined up with the heading of movement, the work rises to the result of the power strength and the distance voyaged. A power is said to accomplish positive work if when applied it has a part toward the removal of the place of utilization. A power accomplishes negative work on the off chance that it has a part inverse to the heading of the uproot.
So,here potential energy store in a wrecking ball is equal to work done by crane.
We know that potential energy is =mgh
Here m=1000-lb,h=50ft,g=9.8m/sec²
=>W=1000×50×9.8m/sec²
In 1lb=0.45kg and 1ft=0.3048m
Therefore,W=1000×0.45×50×0.3048×9.8=67208.4Joule.
Hence,work done by crane is 67208.4Joule.
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determine the power density from an ideal isotropic antenna measured at a distance of 12 kilometers from the transmitting antenna, at a frequency of 100 mhz, and a transmit power of 10 watts:
Answer:
5.53E-9
Explanation:
The power density from an ideal isotropic antenna measured at a distance of 12 kilometers from the transmitting antenna is 0.55 watts/ft.
Given data in the question:
Distance = 12 km
Frequency = 100 mhz
Transmit power = 10 watts
As per the formula of the power density,
[tex]P_{D}=\frac{Pt Gt}{4\pi R^{2} }\\[/tex]
= (100)(10) / 4(3.14)(12x12)
=1000/1808.64
=0.55 watts/ft
The ideal isotropic antenna is a theoretical antenna. It does not exist in practical life. It is very useful and important in explaining power density along with the unguided EM signal attenuation. In practical sense, we have no ideal isotropic antenna in existence. It is only imaginary concept which radiating in all directions and use as an arbitrary point for antenna gain.
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If a gas exerts 3.54 atmospheres at a temperature of 295 K, what pressure will it exert at
275 K?
Considering the Gay-Lussac's law, the gas exerts at a pressure of 3.3 atmospheres at a temperature of 275 K.
Definition of Gay-Lussac's lawGay-Lussac's law states that the pressure of a gas is directly proportional to its temperature when the volume is constant. This is because as the temperature increases, the gas molecules move faster and therefore the number of collisions against the walls increases, that is, the pressure increases.
Mathematically, Gay-Lussac's law states that the ratio between pressure and temperature always has the same value:
P÷T= k
where:
P is the pressure.T is the temperature.k is a constant.Being 1 an initial state and 2 a final state, it is fulfilled:
P₁÷T₁= P₂÷T₂
Pressure at 275 KIn this case, you know:
P₁= 3.54 atmT₁= 295 KP₂= ?T₂= 275 KReplacing in Gay-Lussac's law:
3.54 atm ÷295 K= P₂ ÷275 K
Solving:
(3.54 atm ÷295 K)× 275 K= P₂
3.3 atm= P₂
The final pressure is 3.3 atm.
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magine you are the observer shown on earth in the northern hemisphere. in seven months from the time shown, which constellation will be highest in the sky at midnight?
As an observer on Earth in the northern hemisphere, the constellation that will be highest in the sky at midnight in seven months will depend on the current season and the time of year.
Assuming that the current time is in February, the highest constellation in the sky at midnight in seven months, which would be September, will be Pisces. It rises in the east and sets in the west and reaches its highest point in the sky at around midnight during September. For example, in June, the highest constellation would be Scorpius, and in December, it would be Orion. This is because the Earth's orbit around the sun and its axial tilt change throughout the year, causing different constellations to be visible at different times.
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What happens more on Earth, physical or chemical changes?
Chemical changes happens more on earth because, every living as well as non living things are under going some chemical changes day to day.
What are chemical changes ?Chemical changes involves the formation or breaking of chemical bonds that leads to a new product. Whereas, physical changes does not involves any change in chemical bonds. Phase change, change in size, shape etc. are physical changes.
For example rusting of iron is the formation of red iron oxide by the reaction of iron with oxygen from air or water. This oxide will spread over the surface of the metal and eventually gets corroded. This is a chemical change where a new product is formed.
The photosynthesis, and all biological process taking place every day in all living things are chemical changes. Similarly, non-living things as well undergoing similar changes by their reactivity towards air, water etc.
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Physical changes happens more on earth.
What are physical and chemical changes?Physical changes are reversible and do not produce a new substance. Chemical changes result in the production of a new substance and cannot be reversed.
Given terms,
Physical and Chemical changes on earth on Earth,
Earth has about 71 percent on the Earth's surface, and the oceans hold about 96.5 percent of all Earth's water.
which undergoes through physical change during whole water cycle,
Hence, On earth physical changes happen more.
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I NEED HELP URGENTLY
a ray of light is incident at 32° to a plane surface.Calculate the angle of deviation of the ray
Answer:
116°
Explanation:
REFER TO THE GIVEN ATTACHMENT
HOPE THIS HELPS!
two identical traveling waves, moveing in the same direction, areout of phase by pi/3 rad. what is the amplitude of the resultant wave in terms of the common amplitude ym of the two combining waves?
The amplitude of the resultant wave is equal to ym√(4.5).
What is resultant wave?Resultant wave is a wave that is created when two or more waves overlap. When two or more waves come together they combine and form a new wave, this is known as the resultant wave. The resultant wave is a combination of the individual waves that compose it and is affected by their frequency, amplitude, and phase. The resultant wave will have a frequency, amplitude, and phase that is different from that of the individual waves. When two waves of the same amplitude and frequency meet, the resultant wave will have an amplitude that is the sum of the individual waves' amplitudes.
The amplitude of the resultant wave is equal to the square root of the sum of the squares of the amplitudes of the two traveling waves. In this case,
the amplitude of the resultant wave is equal to the square root of (ym2 + ym2 + 2ym2 cos(π/3)) = ym√(2 + 2 cos(π/3)).
Since cos(π/3) = 1/2, the amplitude of the resultant wave is equal to ym√(4.5).
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how long does it take light to travel through a 3.8- mm -thick piece of window glass? express your answer in seconds.
Time taken by light to travel through a 3.8 mm thick piece of window glass is [tex]1.9 \times 10^{-11}[/tex] seconds.
Speed is defined as the rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered.
The refractive index of glass is 1.5.
Speed of light in air is [tex]3 \times 10^8[/tex] m/s.
Using snell's law,
[tex]\dfrac{n_1}{n_2} = \dfrac{v_2}{v_1}[/tex]
The speed of light in glass is,
[tex]\dfrac{1}{1.5} \times 3 \times 10^8[/tex]
[tex]2 \times 10^8[/tex] m/s
The formula for time is given as [Time = Distance ÷ Speed].
To travel a distance of 3.8 mm in glass, time taken will be,
Time = Distance/speed
Time = [tex]\dfrac{3.8 \times 10^{-3}}{2\times 10^8}[/tex]
Time = [tex]1.9 \times 10^{-11}[/tex] seconds
Time taken by light is [tex]1.9 \times 10^{-11}[/tex] s.
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which of the following statements about orbitals is false?group of answer choicesthey cannot contain more than two electrons.they contain electrons of the same energy.they are paths around the nucleus in which the electrons orbit.they correlate with the number of protons in the nucleus.
The false statement about orbitals is they contain electrons of the same energy (b)
The options might be like this :
A. they cannot contain more than two electrons
B. they contain electrons of the same energy
C. they are paths around the nucleus in which the electrons orbit
D. they correlate with the number of protons in the nucleus.
Protons and neutrons are located in an atom's nucleus, while electrons float around the atom in energy levels. An orbital is regions of space within an atom where the electrons are most likely to be found.
In atom, the electrons surround the nucleus and arranged in shells. It makes each successive shell being farther from the nucleus. Electron shells consist of one or more subshells, and subshells consist of one or more atomic orbitals. There are four types of subshells: s (sharp), p (principle), d (diffuse) and f (fundamental).
In terms of energy, electrons located in the same subshell have the same energy, while electrons in different sub shells have different energies. The number of energy levels (n) increases, so there is a greater distance between the nucleus and the outermost orbital. Each orbital can hold no more than two electrons. Two electrons in the same orbital must have opposite spins.
With more protons in the nucleus, the attractive force for electrons to the nucleus is stronger. Thus, the orbital energy becomes more negative (less energy). The presence of proton, not only leads to accurate distance but explains the curious probability nature of the electron and the shape of atomic orbitals.
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The statement that is a FALSE fact about orbitals is that "they contain electrons of the same energy." Therefore, the second option is the correct one.
Atom orbitals are regions around the nucleus of an atom where there is a high probability of finding an electron. Each orbital has a specific shape and can hold a certain number of electrons.
The most common types of orbitals are the s, p, d, and f orbitals. Electrons that are on the same orbital have the same energy, but electrons that are on different orbitals have different energies.
Orbitals play an important role in determining the chemical properties of an atom, as the arrangement of electrons in the orbitals determines how an atom will interact with other atoms.
Your question's format is off. The full question should be as follows:
Which of the following statements about orbitals is false?
Group of answer choices:
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what is the primary advantage of multiple focal zones along each scanline of a two-dimensionalimage?
A two-dimensional image's flexibility and control are increased when there are several focal zones, which enhances the clarity and accuracy of the image.
What are focal zones?The focal zones are the areas where light is focused sharply and objects seem distinct.
Improved depth of field and greater picture quality are the main benefits of having several focal zones along each scanline of a two-dimensional image. Different areas of the image can be brought into focus at various distances from the scanner using multiple focal zones. Even when the subject or objects in the image are at various depths, this can produce a sharper, clearer image with less blur.
Additionally, having numerous focal zones gives the photographer more control over the outcome by enabling modifications to the image's sharpness and focus.
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a 7.2 nc point charge and a - 2.7 nc point charge are 3.0 cm apart. what is the electric field strength at the midpoint between the two charges?
The electric field strength at the midpoint between two charges is [tex]10^3[/tex]N/C.
The electric field strength at a point in space is defined as the force per unit charge at that point. The electric field strength due to a point charge can be calculated using Coulomb's law: E = kQ / r^2, where k is the Coulomb constant, Q is the charge of the point charge, and r is the distance from the point charge to the point where the field strength is being calculated.
In this case, the electric field strength at the midpoint between the two charges can be calculated by finding the vector sum of the electric field strengths due to each of the two charges. The midpoint is equidistant from both charges, so the electric field strengths due to each charge will have equal magnitude and point in opposite directions.
Thus, the vector sum of the two electric field strengths will be equal to their difference, or E = kQ / [tex]r^2[/tex], where Q is the net charge (7.2 nC - (-2.7 nC) = 9.9 nC) and r is the distance from each charge to the midpoint (3.0 cm). Plugging in the numbers, the electric field strength is
E = [tex](9 * 10^9 N m^2/C^2) * (9.9 * 10^{-9} C) / (3 * 10^{-2} m)^2 = 10^3 N/C[/tex].
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