identify whether 1352 is perfect square number if not then find the smallest number by which is given number should be multiplied not make them perfect square number .
please help me !!!!!​

Answer:

[-3, 7].

Step-by-step explanation:

do i need to explain all that?

Answer:

The inequality can be rewritten as x-7 ≤ 50, which we can solve by adding 7 to both sides to get x ≤ 57.

Step-by-step explanation:

It seems like there are multiple questions combined in this one prompt. I will break them down and provide solutions for each one.

Solution for O x≤-3 or 2 Ox<-3 or 2 O-3≤x≤2 or x > 7:

To find the solution for this inequality, we need to solve each part separately and then combine the solutions using the union (OR) operation.

a) x ≤ -3: This part is already solved for x. The solution is x ≤ -3.

b) 2x < -3: We divide both sides by 2 to isolate x and get x < -3/2.

c) 2 ≤ x ≤ -3: This is not possible as there is no number that is both greater than or equal to 2 and less than or equal to -3.

d) x > 7: This part is already solved for x. The solution is x > 7.

The solution to the entire inequality is the union of these solutions: x ≤ -3 OR x < -3/2 OR x > 7.

Solution for x²+x-6 < 0

To solve this quadratic inequality, we can factor it as (x-2)(x+3) < 0 and use the sign chart method.

We create a sign chart for the expression (x-2)(x+3) and test the sign of the expression in each interval

  -3         2

  ---|-------|---

    -         +

(x-2) - 0 + +

(x+3) - - - 0 +

-------------

- + - 0 +

The sign chart tells us that the expression is negative when x is between -3 and 2. Therefore, the solution to the inequality is -3 < x < 2.

Solution for x-7 ≤ 50₂

It seems like the expression "50₂" is intended to represent the number 50 in base 2 (binary). To convert this number to base 10 (decimal), we can write 50₂ as

50₂ = 12^5 + 12^4 + 02^3 + 02^2 + 12^1 + 02^0 = 32 + 16 + 2 = 50

Therefore, the inequality can be rewritten as x-7 ≤ 50, which we can solve by adding 7 to both sides to get x ≤ 57.

Answer:

m<1 = 63° (Exterior alternating Angles)

m<2 = 62°

m<3 = 118°

Step-by-step explanation:

[tex]{ \tt{m \angle 2 + 63 \degree + 55 \degree = 180 \degree}} \\ { \sf{(exterior \: corresponding \: angles)}} \\ { \tt{m \angle 2 = 180 - (63 + 55)}} \\ { \tt{ \underline{ \: m \angle 2 = 62 \degree \: }}}[/tex]

[tex]{ \tt{m \angle 3 = m \angle 1 + 55 \degree}} \\ { \tt{m \angle 3 = 63 + 55}} \\ { \tt{ \underline{ \: m \angle 3 = 118 \degree \: }}}[/tex]

Answer:

Step-by-step explanation:

your given is not cleared repost it then post

Answer:

g(x)

=6x−4

=3x

2

−2x−10

Escribe (g∘f)(x) como una expresión en términos de x.

Step-by-step explanation:

Primero necesitamos conocer la función f(x). Luego podemos sustituir f(x) en g(x) para obtener (g∘f)(x).

Como la función f(x) no se proporcionó en la pregunta, asumiré que f(x) es:

f(x) = x^2 - 2x + 1

Entonces, podemos sustituir f(x) en g(x) de la siguiente manera:

g(f(x)) = 6f(x) - 4

= 6(x^2 - 2x + 1) - 4 (sustituyendo f(x))

= 6x^2 - 12x + 2

Por lo tanto, (g∘f)(x) = 6x^2 - 12x + 2.

The car must drive at a constant speed of approximately 112.89 km/hr to cover the same distance in 2 hours 35 minutes.

The formula for time is: time = distance / speed

where "distance" is the distance traveled by an object, and "speed" is the rate at which the object is moving.This formula can be used to calculate the time taken by an object to travel a certain distance at a constant speed, or to calculate the speed or distance if the other two variables are known.

The formula for speed is: speed = distance / time

where "distance" is the distance traveled by an object and "time" is the duration of travel.

This formula can be used to calculate the speed of an object if the distance it has traveled and the time it took to travel that distance are known. It can also be used to calculate the distance traveled by an object if its speed and the time it traveled at that speed are known.

In the given question,

Let's first calculate the distance traveled in 2 hours 45 minutes (2.75 hours) at an average speed of 106 km/hr.

distance = speed × time

distance = 106 × 2.75

distance = 291.5 km

Now, we need to find at which constant speed the car must drive to cover the same distance in 2 hours 35 minutes (2.5833 hours). Let's call this speed "x".

distance = speed × time

291.5 = x × 2.5833

x = 291.5 / 2.5833

x ≈ 112.89 km/hr

Therefore, the car must drive at a constant speed of approximately 112.89 km/hr to cover the same distance in 2 hours 35 minutes.

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Answer:

Percentage of the circle that lies outside the triangle = 15%

Step-by-step explanation:

Given,

The area of the intersection of circle and triangle is 45% of the area of the union.

The area of the triangle outside of the circle is 40% of the area of their union.

Required to find,

The percentage of the circle lies outside the triangle

Let us take 'C'  as the area of the circle and 'T' as the area of the triangle.

The union of the area of the circle and triangle = C∪T

Let CUT be  A

and the percentage of the circle that lies outside the triangle be 'x'

The intersection of the area of the circle and triangle = C∩T

Area of the triangle outside the circle = T - C

Area of the circle outside the triangle = C - T

Given,

C∩T = 45% of CUT = 45% of A

T - C = 40% of CUT = 40% of A

We know that,

The union of the area of the circle and triangle = Area of The intersection of the area of the circle and triangle + Area of the triangle outside the circle + Area of the circle outside the triangle

(CUT) = (C∩T) + (T - C) + (C - T)

[tex]A = 45\%A + 40\%A + x\%A[/tex]

[tex]A = (85+x)\% A[/tex]

[tex]85 +x = 100[/tex]

∴ [tex]x = 15[/tex]

Percentage of the circle that lies outside the triangle = 15%

The volume of the solid obtained by rotating the region bounded by the curves y = x and y = √x about the line x = 6 is (128π/15) - (13π/3), or approximately 3.013 cubic units.

To find the volume of the solid obtained by rotating the region bounded by the curves y = x and y = √x about the line x = 6, we can use the method of cylindrical shells.

First, we need to determine the limits of integration. Since the curves intersect at (0,0) and (1,1), we can integrate with respect to y from 0 to 1.

The radius of each cylindrical shell is the distance from the line x = 6 to the curve y = x or y = √x. We can express this distance as r = 6 - x or r = 6 - y^2, depending on which curve we are using.

The height of each cylindrical shell is the difference between the two curves at the given y-value. This is given by h = y - √x for y = x, and h = y^2 - x for y = √x.

Therefore, the volume of the solid is:

V = ∫(2πrh) dy from 0 to 1

Substituting r and h, we get:

V = ∫(2π(6 - x)(y - √x)) dy from 0 to 1 (for y = x)

V = ∫(2π(6 - y^2)(y^2 - x)) dy from 0 to 1 (for y = √x)

Evaluating these integrals using u-substitution and simplifying, we get:

V = (128π/15) - (13π/3)

Therefore, the volume of the solid is (128π/15) - (13π/3), or approximately 3.013 cubic units

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_____The given question is incomplete, the complete question is given below:

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified in y = x, y = sqrt(x) ; about x = 6

Answer:

4 + - 6 = -2

Hope this helps!

Step-by-step explanation:

The arrow closest to the line shows going forward 4 or + 4

The second arrow shows going back 6 or -6

+ 4 - 6 = -6 + 4 = -2

Answer:

look at the explanation

Step-by-step explanation:

okay so here if AC is equals to DC and BC is equals to CE then AB is equals to DE as well hence, angle A would be equals to angle D.

The second reason that prove that angle A is a angle D is that angle A and angle D are alternate angles

I am also in ninth grade so do recheck yourself

Answer:

Devan's age = 2 years.

Deepa's age = 6 years.

Step-by-step explanation:

Present age:      

 Let the present age of Devan = x

             Present age of Deepa = 3x

After 2 years:

                     Age of Devan = x + 2

                     Age of Deepa = 3x + 2

     Deepa's age = 2* Devan's age

          3x + 2        = 2 *(x + 2)

                3x + 2  = 2x + 2*2    {Use distributive property}

               3x + 2   = 2x + 4

  Subtract '2' from both sides,

                           3x = 2x + 4 - 2

                           3x = 2x + 2

Subtract '2x' from both sides,

                   3x  - 2x = 2

                             x = 2

Devan's age = 2 years.

Deepa's age = 3*2

                      = 6 years  

The correct order of the steps to test the general hypothesis is given as B, A, E, C, D, F.

A hypothesis is basically a uncertain fact that is backed by some logical and solid information. While using the hypothesis, it s important that we use the correct method to verify the credibility of the hypothesis in the system.

So, as per the given option, the correct sequence should be, B, A, E, C, D, F.

We first set up the null hypothesis and the alternative hypothesis, and then we choose the degree of significance. The next phases in hypothesis testing are choosing the test statistics and creating the decision-making rule.

When we get to a conclusion based on the hypothesis after carefully calculating and computing the hypothesis' performance, the procedure is said to be finished.

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Complete question - place the following steps in order. what is the correct order for the general procedure for hypothesis testing?

A. Select the level of significance

B. setup null and alternative hypothesis

C. Establish the decision rule

D. performance computation

E. select the test statistics

F. Draw conclusions

The length of the side of the hexagon is 12 cm and option d is the correct answer.

A regular polygon is a closed shape made up of straight line segments with sides and angles that are all of the same length. For instance, a regular hexagon is a polygon having six equal-length sides and six equal-sized angles. Regular polygons have a variety of intriguing characteristics. For instance, their diagonals (lines connecting non-adjacent vertices) all intersect at a single point, and their centre of symmetry is located at the centre of the polygon's circumscribed circle (the circle that passes through all of the polygon's vertices).

Given that, regular hexagon is inscribed into a circle.

The radius of a circle enclosing a regular hexagon is the same as the length of the hexagon's sides.

Hence, the length of the side of the hexagon is 12 cm and option d is the correct answer.

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In linear equatiοn, the bοοkcase shοuld be apprοximately 12.2 inches in οrder tο give Bria's sοap carving cοllectiοn a 300-square-inch area.

An algebraic equatiοn with simply a cοnstant and a first-οrder (linear) term, such as y=mx+b, where m is the slοpe and b is the y-intercept, is knοwn as a linear equatiοn.

Sοmetimes, the afοrementiοned is referred tο as a "linear equatiοn οf twο variables," where x and y are the variables. Equatiοns with variables οf pοwer 1 are referred tο as linear equatiοns. One example with οnly οne variable is where ax+b = 0, where a and b are real values and x is the variable.

the bοοkcase's tοp is rectangular, with length "L" and width "b". Because the area οf a rectangle is the prοduct οf its length and width, we get:

L * b = 300

Tο find "b," we can rearrange the equatiοn as fοllοws:

b = 300 / L

L ≈ 2b

When we plug this intο the equatiοn abοve, we get:

b = 300 / (2b) (2b)

Tο simplify, we have:

b² = 150

When we take the square rοοt οf bοth sides, we get:

b ≈ 12.2

We have, rοunded tο the nearest tenth οf an inch:

b ≈ 12.2 inches

the width οf the tοp οf the bοοkcase shοuld be apprοximately 12.2 inches in οrder tο give Bria's sοap carving cοllectiοn a 300-square-inch area.

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Answer:

E.  x² + (y - 3)² = 16

Step-by-step explanation:

The equation of a circle in the standard (x, y) coordinate plane with center (h, k) and radius r is given by:

[tex]\boxed{(x - h)^2 + (y - k)^2 = r^2}[/tex]

To find the equation of the circle with a radius of 4 units and the same center as the circle determined by x² + y² - 6y + 4 = 0, we need to first write the equation of the second circle in the standard form.

We can complete the square for y to rewrite this equation in standard form. To do this move the constant to the right side of the equation:

[tex]\implies x^2 + y^2 - 6y + 4 = 0[/tex]

[tex]\implies x^2 + y^2 - 6y = -4[/tex]

Add the square of half the coefficient of the term in y to both sides of the equation:

[tex]\implies x^2 + y^2 - 6y +\left(\dfrac{-6}{2}\right)^2= -4+\left(\dfrac{-6}{2}\right)^2[/tex]

[tex]\implies x^2 + y^2 - 6y +9= -4+9[/tex]

[tex]\implies x^2 + y^2 - 6y +9=5[/tex]

Factor the perfect square trinomial in y:

[tex]\implies x^2+(y-3)^2=5[/tex]

[tex]\implies (x-0)^2 + (y-3)^2=5[/tex]

So the center of this circle is (0, 3) and its radius is √5 units.

Since the new circle has the same center, its center is also (0, 3).

We know its radius is 4 units, so we can write the equation of the new circle as:

[tex]\implies (x - 0)^2 + (y - 3)^2 = 4^2[/tex]

[tex]\implies x^2 + (y - 3)^2 = 16[/tex]

Therefore, the equation of the circle in the standard (x, y) coordinate plane with a radius of 4 units and the same center as the circle determined by x² + y² - 6y + 4 = 0 is x² + (y - 3)² = 16.

To find:-

Answer:-

The given equation of the circle is ,

[tex]\implies x^2+y^2-6y + 4 = 0 \\[/tex]

Firstly complete the square for y in LHS of the equation as ,

[tex]\implies x^2 + y^2 -2(3)y + 4 = 0 \\[/tex]

Add and subtract 3² ,

[tex]\implies x^2 +\{ y^2 - 2(3)(y) + 3^2 \} -3^2 + 4 = 0 \\[/tex]

The term inside the curly brackets is in the form of a²-2ab+b² , which is the whole square of "a-b" . So we may rewrite it as ,

[tex]\implies x^2 + (y-3)^2 -9 + 4 = 0 \\[/tex]

[tex]\implies x^2 + (y-3)^2 - 5 = 0 \\[/tex]

[tex]\implies x^2 + (y-3)^2 = 5\\[/tex]

can be further rewritten as,

[tex]\implies (x-0)^2 + (y-3)^2 = \sqrt5^2\\[/tex]

now recall the standard equation of circle which is ,

[tex]\implies (x-h)^2 + (y-k)^2 = r^2 \\[/tex]

where,

So on comparing to the standard form, we have;

[tex]\implies \rm{Centre} = (0,3)\\[/tex]

Now we are given that the radius of second circle is 4units . On substituting the respective values, again in the standard equation of circle, we get;

[tex]\implies (x-h)^2 + (y-k)^2 = r^2 \\[/tex]

[tex]\implies (x-0)^2 + (y-3)^2 = 4^2 \\[/tex]

[tex]\implies \underline{\underline{\red{ x^2 + (y-3)^2 = 16}}}\\[/tex]

and we are done!

The area of the composite figure is 159.9 cm²

From the question, we are to determine the area of the given composite figure

In the given diagram, the area of the composite figure = Area of triangle + Area of rectangle

First, we will calculate the area of the triangle

Area of triangle = 1/2 × base × height

Thus,

Area of the triangle = 1/2 × 16.4 × 5.5

Area of the triangle = 45.1 cm²

Calculating the area of the rectangle

Area of rectangle = Length × Width

Thus,  

Area of the rectangle = 16.4 × 7

Area of the rectangle = 114.8 cm²

Therefore,

The area of the composite figure = 45.1 cm² + 114.8 cm²

The area of the composite figure = 159.9 cm²

Hence, the area is 159.9 cm²

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The analysis of the relationship in the question and the graph of the relationship indicates that the cost of the delivery truck between 1 mile and 2 miles is a constant, therefore;

The graph of a dataset displays the relationship,  between the variables in the dataset. It is a visual representation of the connection between the variables.

The fixed base price of the delivery truck for (the first) 2 miles = $6

The additional amount the delivery truck charges after 2 miles = $2 per mile

The additional amount charged by the delivery truck after 6 miles = $4 per mile

The part of the question obtained from a similar question posted on the website, includes;

The cost of the delivery truck, between 1 mile and 2 miles based on the graph is an horizontal line.

The horizontal line of a graph, indicates that the relationship between the input and output is a constant, such that the output of the relationship, within the interval of the horizontal line is a constant. The correct option is therefore;

b). The cost of the delivery truck between 1 mile and 2 miles is constant

The possible question options includes;

a) More information is required to determine the cost of the delivery truck between 1 mile and 2 miles

b) The cost of the delivery truck between 1 mile and 2 miles, is constant

c) The cost of the delivery truck is decreasing between 1 mile and 2 miles

d) The cost of the delivery truck is increasing between 1 mile and 2 miles

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Answer:

0.600 or 600, 0.500 or 500, select option 2

Step-by-step explanation:

Answer:

Step-by-step explanation:

We can use the distributive property and FOIL method to multiply these two complex numbers:

(-4 + i)(2 - 3i) = -4(2) + (-4)(-3i) + (i)(2) + (i)(-3i)

Simplifying each term, we get:

(-4 + i)(2 - 3i) = -8 + 12i + 2i - 3i^2

Since i^2 = -1, we can replace it with -1:

(-4 + i)(2 - 3i) = -8 + 12i + 2i - 3(-1)

Simplifying further, we get:

(-4 + i)(2 - 3i) = -5 + 14i

Therefore, the product of (-4 + i) and (2 - 3i) is -5 + 14i.

Answer:

8(3/4y - 2) + 6(-1/2x + 4) + 1 can be simplified as:

6(-1/2x) = -3x

8(3/4y) = 6y

8(-2) = -16

6(4) = 24

1 remains as 1.

So the expression becomes:

6y - 3x - 16 + 24 + 1

which simplifies to:

6y - 3x + 9

Therefore, the expressions that are equivalent to 8(3/4y - 2) + 6(-1/2x + 4) + 1 are:

6y - 3x + 9

Answer:

87

Step-by-step explanation:

87

Conditions for constructing a confidence interval for the population mean are met in first scenario. Conditions are generally met for population mean sales price, but potential outliers and non-normality need to be checked.

Yes, the conditions are met for constructing a confidence interval for the population mean in first scenario. The sample is randomly selected and independent, and we can also assume that the sample size is sufficiently large due to the Central Limit Theorem.

The sample comes from a normal population, or use a t-distribution if the sample size is small and the population standard deviation is unknown.

Yes, the conditions are generally met for constructing a confidence interval for the population mean sales price. We can assume that the sample is randomly selected and independent, and we can also assume that the sample size is sufficiently large due to the Central Limit Theorem.

However, we may want to check for these issues and consider using a non-parametric method, such as a confidence interval based on the median or the bootstrap, if there are concerns.

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In response to the stated question, we may state that Therefore, the trigonometry exact values of sin(u), cos(u), sin(2u), and cos(2u) are 4/5, 3/5, 24/25, and -7/25, respectively. The exact value of sin(t/2) is 2√5 / 5.

The study of the connection between triangle side lengths and angles is known as trigonometry. The concept first originated in the Hellenistic era, during the third century BC, due to the application of geometry in astronomical investigations. The subject of mathematics known as exact techniques deals with certain trigonometric functions and their possible applications in calculations. There are six commonly used trigonometric functions in trigonometry. Sine, cosine, tangent, cotangent, secant, and cosecant are their separate names and acronyms (csc). The study of triangle characteristics, particularly those of right triangles, is known as trigonometry. As a result, geometry is the study of the properties of all geometric forms.

Using the given triangle, we can find the values of sin(u), cos(u), and tan(u) as follows:

sin(u) = opposite / hypotenuse = 4 / 5

cos(u) = adjacent / hypotenuse = 3 / 5

tan(u) = opposite / adjacent = 4 / 3

To find the values of sin(2u) and cos(2u), we can use the double angle formulas:

[tex]sin(2u) = 2 sin(u) cos(u)\\cos(2u) = cos^2(u) - sin^2(u)\\sin(2u) = 2 (4/5) (3/5) = 24/25\\cos(2u) = (3/5)^2 - (4/5)^2 = -7/25[/tex]

sin(t/2) = ± [tex]\sqrt((1 - cos(t)) / 2)[/tex]

We need to determine the sign of the square root based on the quadrant in which t/2 lies. Since 7t/2 is in the second quadrant (between pi and 3pi/2), t/2 is in the second quadrant as well (between pi/2 and pi). In the second quadrant, sine is positive and cosine is negative. Therefore, we take the positive square root:

[tex]sin(t/2) = \sqrt((1 - cos(t)) / 2)\\= \sqrt((1 - (-3/5)) / 2)\\= \sqrt(8/10)\\= \sqrt(4/5)\\[/tex]

= 2/√5

= 2√5 / 5

Therefore, the exact values of sin(u), cos(u), sin(2u), and cos(2u) are 4/5, 3/5, 24/25, and -7/25, respectively. The exact value of sin(t/2) is 2√5 / 5.

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The probability that at least 3 minutes will elapse before the next telephone order is 0.797.

The probability that less than 15 minutes will elapse between orders is 0.677.

The probability that between 15 and 30 minutes will elapse between orders is 0.2275

To solve the following problem, we need to use the Poisson distribution, which is a probability distribution that describes the number of events that occur in a fixed interval of time or space, given the average rate of occurrence of those events.

The Poisson distribution has the following formula:

               [tex]P(X = k) = (\lambda\times ex^{-\lambda}) / k![/tex]    

Where:

P(X = k) is the probability that there are exactly k events in the interval

λ is the average rate of occurrence of events in the interval

e is the mathematical constant e (approximately 2.71828)

k! is the factorial of k (i.e., k * (k-1) * (k-2) * ... * 2 * 1)

Here we have

Between 11 pm and midnight on Thursday night Mystery pizza gets an average of 4.2 telephone orders per hour

A. The probability that at least 3 minutes will elapse before the next telephone order, using the complement rule:

=> P(at least 3 minutes) = 1 - P(less than 3 minutes)

Assume that the time between telephone orders follows an exponential distribution with a mean of 1/4.2 = 0.2381 hours (or 14.28 minutes).

Therefore, the Poisson distribution is λ = 1/0.2381 = 4.2/1.0 = 4.2.

Using the exponential distribution, we can find the probability of less than 3 minutes elapsing between orders as follows:

P(less than 3 minutes) = [tex]1 - e ^{(-\lambda \times t) }[/tex]

Where t = 3/60 = 0.05 hours

P(less than 3 minutes) = [tex]1 - e^{(-4.2\times 0.05) } = 0.203[/tex]

Therefore,

P(at least 3 minutes) = 1 - 0.203 = 0.797

The probability that at least 3 minutes will elapse before the next telephone order is 0.797.

B. To find the probability that less than 15 minutes will elapse between orders, we can use the same exponential distribution as before and set t = 15/60 = 0.25 hours:

P(less than 15 minutes) = [tex]1 - e ^{(-\lambda \times t) }[/tex]

P(less than 15 minutes) = [tex]1 - e^{(-4.2 \times 0.25)} = 0.677[/tex]

Hence, The probability that less than 15 minutes will elapse between orders is 0.677.

C. To find the probability that between 15 and 30 minutes will elapse between orders, we can subtract the probabilities found in less than 15 minutes and less than 30 minutes.

P(15 to 30 minutes) = P(less than 15 minutes) - P(less than 30 minutes) -

P(15 to 30 minutes) = [tex]e^{ (-\lambda0.5)} - e^{ (-\lambda 0.25)}[/tex]  

= 0.3499 - 0.1224  = 0.2275

Therefore,

The probability that at least 3 minutes will elapse before the next telephone order is 0.797.

The probability that less than 15 minutes will elapse between orders is 0.677.

The probability that between 15 and 30 minutes will elapse between orders is 0.2275

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Answer:

(15+x)÷4 = 80-x

by criss cross we'll get:

15+x = 4(80-x)

15+x = 320-4x

x+4x=320-15

5x = 305

x = 61

The least common multiple (LCM) of 6 and 7 is 42. To find the LCM, we must first list out all the multiples of 6 and 7.

Number is a mathematical object used to count, measure, and label. It is also commonly used to represent a certain quantity. Numbers are a fundamental part of mathematics, and they can be used in a variety of ways. From basic arithmetic operations to complex equations, numbers are essential in the field of mathematics. Numbers can be used to represent any quantity, such as distance, size, time, or money. Numbers can also be used to represent abstract concepts, such as emotions or thoughts.

Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72

Multiples of 7: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84

The LCM is the smallest number that is a multiple of both numbers. In this case, the LCM of 6 and 7 is 42. This can be seen because both 6 and 7 have 42 as a multiple and no other number is smaller.

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The least common multiple (LCM) of 6 and 7 is 42. To find the LCM, we must first list out all the multiples of 6 and 7.

Number is a mathematical object used to count, measure, and label. It is also commonly used to represent a certain quantity. Numbers are a fundamental part of mathematics, and they can be used in a variety of ways. From basic arithmetic operations to complex equations, numbers are essential in the field of mathematics. Numbers can be used to represent any quantity, such as distance, size, time, or money. Numbers can also be used to represent abstract concepts, such as emotions or thoughts.

Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72

Multiples of 7: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84

The LCM is the smallest number that is a multiple of both numbers. In this case, the LCM of 6 and 7 is 42. This can be seen because both 6 and 7 have 42 as a multiple and no other number is smaller.

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Complete questions as follows-

How to find LCM of 6 and 7.

The parameter an in the Lotka-Volterra predator-prey model denotes the capture efficiency (alpha).

The lotka-Volterra predator-prey model is what.

The Lotka-Volterra model makes the assumption that a predator's rate of prey consumption is inversely related to its abundance.

The parameter an in the Lotka-Volterra predator-prey model denotes the capture efficiency (alpha).

In conclusion, the lotka-volterra predator-prey model aids in estimating the rate at which prey is consumed.

We possess that

The predator population is x.

y is the number of prey.

The dy/dt equation contains the coefficient c. Hence, this coefficient is correlated with the prey population. The presence of a minus sign indicates a decline in the population of prey. It multiplies x as well, indicating a connection to the predator population.

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36.92 lbs. of the $3.45 tea and 43.08 lbs. of the $2.15 tea are needed.

Let x and y be the amount of tea that sells fo 3.45 and 2.15 a pound respectively:

x+y=80....................eq 1

3.45x+2.15y=2.75(80)......eq 2

:

rewrite eq 1 to x=80-y and plug that value into eq 2

:

3.45(80-y) +2.15y=2.75(80)

:

276-3.45y+2.15y=220

:

-1.3y=56

:

y=43.07 pounds of $2.15 tea

:

28x=80-43.07=36.93 pounds of $3.45 tea

Let a= the pounds of the more expensive tea needed

Let b= the pounds of the less expensive tea needed

(1) a+%2B+b+=+80

(2) 345a+%2B+215b+=+80%2A275 (in cents)

--------------------------

In words, (2) says.

(lbs of 'a' tea x price/lb) + (lbs of 'b' tea x price/lb) =

(lbs of mixture x price/lb of mixture)

-------

Multiply both sides of (1) by 215 and then.

subtract from (2)

345a+%2B+215b+=+80%2A275

-215a+-+215b+=+-80%2A215

130a+=+80%2A60

130a+=+4800

a+=+36.92

and, from (1)

(1) a+%2B+b+=+80

36.92+%2B+b+=+80

b+=+80+-+36.92

b+=+43.08

36.92 lbs. of the $3.45 tea and 43.08 lbs. of the $2.15 tea are needed.

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The mixture contains 34 pounds of black tea and 46 pounds of Earl Gray tea.

What is an algebraic expression?

An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations.

Let's denote the amount of black tea in pounds by "x" and the amount of Earl Gray tea in pounds by "y".

Since the total amount of mixture is 80 lb, we have:

x + y = 80 ----(1)

We also know that the mixture sells for $2.75 a pound, so the total revenue from selling 80 lb of mixture is:

80 x $2.75 = $220

On the other hand, the cost of the mixture is the sum of the costs of the black tea and the Earl Gray tea, which is:

3.45x + 2.15y

Since the company wants to make a profit, the revenue must be greater than the cost, so we have:

3.45x + 2.15y < $220

We can simplify this inequality by dividing both sides by 0.1:

34.5x + 21.5y < 2200 ----(2)

Now we have two equations with two unknowns (equations (1) and (2)), which we can solve using substitution or elimination.

Substitution method:

From equation (1), we have:

y = 80 - x

Substituting this into equation (2), we get:

34.5x + 21.5(80 - x) < 2200

Simplifying and solving for x, we get:

x < 34.5

Rounding x to the nearest pound, we get x = 34.

Substituting this value into y = 80 - x, we get y = 46.

Therefore, the mixture contains 34 pounds of black tea and 46 pounds of Earl Gray tea.

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Answer:

Step-by-step explanation:

a) One possible function that satisfies the conditions is:

f(x) = (x^2 - 25) / (x - 5)

This function is undefined when x = 5, but it is defined for all other real numbers.

b) One possible function that satisfies the conditions is:

g(x) = 1 / (x - 1)

This function is undefined when x = 1, but it is defined for all other positive numbers greater than 1.

c) One possible function that satisfies the conditions is:

h(x) = ln(x - 1)

This function is undefined when x = 1, but it is defined for all other positive numbers greater than 1. The range of this function is all real numbers.

Answer:

To calculate the moles of hydrogen gas produced, we need to use the ideal gas law equation:

PV = nRT

where P is the total pressure, V is the volume of the gas, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature to Kelvin by adding 273.15:

T = 26.0 + 273.15 = 299.15 K

Next, we need to calculate the pressure of the hydrogen gas by subtracting the vapor pressure of water from the barometric pressure:

P(H2) = P(total) - P(vapor) = 745 - 25.5 = 719.5 mmHg

Now we can plug in the values into the ideal gas law equation and solve for n:

n = PV/RT

n = (719.5 mmHg)(94.00 mL)/(62.3637 L mmHg/K mol)(299.15 K)

n = 0.00384 mol

Therefore, the moles of hydrogen gas produced by the reaction is 0.00384 mol.