identify the two functional groups in the following compound

Answer:

Loss of protons and electrons in plutonium 240 decay is not an example of an everyday reaction

Answer:

since 1 mole = 6.022×10^23

hence in 2.32 moles no. of atoms= 6.022×10^23 × 2.32

=

13.97104 ×10^23

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Answer:

X is moving into the cell by active transport

Explanation:

According to Oxford dictionary;active transport refers to ''the movement of ions or molecules across a cell membrane into a region of higher concentration, assisted by enzymes and requiring energy''.

Since the concentration of X is higher inside the cell than it is outside the cell, energy must be required in order to move substance X across the cell membrane against existing concentration gradient. This process is called active transport.

Answer:

0.01228s⁻¹ = rate constant

Half-life = 56.4s

Explanation:

The first order reaction follows the equation:

ln[A] = -kt + ln[A]₀

Where [A] is amount of reactant after time t = 45.0%, k is rate constante and [A]₀ initial amount of reactant = 100%

ln[45%] = -k*65s + ln[100%]

-0.7985 = -k*65s

0.01228s⁻¹ = rate constant

Half-life is:

Half-life = ln2 / k

Answer:

See explanation

Explanation:

One of the important trends in the periodic table is electronegativity. Electro negativity decreases down the group and increases across the period. This trend has important consequences on the observed properties of the compounds of elements in a particular group in the periodic table.

As we move down in group 6A, the electro negativity of the elements elements the group decrease and as such, the magnitude of intermolecular hydrogen bonding between the molecules also decrease accordingly. Hydrogen bonds occur between

molecules of a substance when hydrogen is covalently bonded to an electronegative element. Hydrogen bonding is responsible for the high melting and boiling points of small molecules such as water which contain the highly electronegative oxygen atom.

So, as we move down the group there is lesser intermolecular hydrogen bonding between the hydride molecules of group 6A elements resulting in the observed trend in melting and boiling points of the hydrides.

The weaker hydrogen bonds that occurbetween molecules of group 6A hydrides lead to a steady decrease in melting and boiling points of the hydrides of group 6A elements as we move down the group.

Answer:

A. How the concentration of the reactants affects the rate of a reaction

Explanation:

Let's consider a generic reaction.

A + B ⇒ Products

The generic rate law is:

rate  = k × [A]ᵃ × [B]ᵇ

where,

As we can see, the rate law shows how the concentration of the reactants affects the rate of a reaction.

Answer:Answer: BeCl2 And CO2 Both Molecules Have The Same - OOOOOOO Molecular Geometry (molecular Shape) Number Of Covalent Bonds To The Central Atom Total Number Of Each Type Of Bond (single, Double, Triple) Number Of Electron Pairs Around The Central Atom Electron Region Geometry (3-D Arrangement Of Electron Pair Regions

Explanation:

Answer:

.This is because gravity pulls down harder on the heavier one, which increases its friction with the floor

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Answer:

The mechanical properties of urea formaldehyde resins may be improved by incorporating therein polyvinyl alcohol. The polyvinyl alcohol may be incorporated during pre-mixing, mid mixing, and/or post mixing of the resin components. Resins prepared using polyvinyl alcohol are particularly desirable in articles requiring improved mechanical strength and water resistance, as compared to similar resins prepared without the polyvinyl alcohol such as shingles.

Answer:

a it rarely reach with other elements

Explanation:

A=Butan-2-one

B=Pentan-3-one

Answer:

.

Explanation:

Answer:

6, double

Explanation:

Hex- is a prefix for number 6.

Ene- is a suffix for a double bond.

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1.01 x 10^-3 moles

n = 0.20 mol

N

N = n × 6.02 × 10²³ atoms/mol

N = 0.2 mol × 6.02 × 10²³ atoms/mol

N = 1.20 × 10²³ atoms

Therefore, there are 1.20 × 10²³ gold atoms in 0.2 mol of a gold sample.

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Answer:

941 g

Explanation:

Step 1: Write the balanced equation

Zn + 2 HCl ⇒ ZnCl₂ + H₂

Step 2: Calculate the moles corresponding to 14.5 g of H₂

The molar mass of H₂ is 1.01 g/mol.

14.5 g × 1 mol/1.01 g = 14.4 mol

Step 3: Calculate the number of moles of Zn required to form 14.4 moles of H₂

The molar ratio of Zn to H₂ is 1:1. The moles of Zn required are 1/1 × 14.4 mol = 14.4 mol.

Step 4: Calculate the mass corresponding to 14.4 moles of Zn

The molar mass of Zn is 65.38 g/mol.

14.4 mol × 65.38 g/mol = 941 g

Answer:

Characteristics of oxygen are as follows:

Answer:

In an ionic bond, the elctrons are transferred. For example, NaCl has an ionic bond because Na loses an electron and the Cl atom gains the electron. However in a covalent bond, the electrons are shared equally. Covalent bonds usually occur between two nonmetals.

Explanation:

Answer:

See explanation

Explanation:

9) If an extra electron is added to the neon atom, then the electronic configuration becomes; 1s2 2s2 2p6 3s1

This last electron has quantum numbers;

n=3, l=0, m=0 and s = +1/2

This is so because the 2s level is already filled so the extra electron must go into the 3s level. The orbital quantum number and the magnetic quantum number for the s orbital is zero.

10) Electron affinity is the energy released when one mole of gaseous atoms accept one mole of gaseous electrons to form one mole of gaseous ions having a negative charge.

In the second period, fluorine has the greatest electron affinity since electron affinity increases across the period. The noble gas, neon has an electron affinity of 0KJ/mol.

11) Ionization energy decreases down the group but increases across the period due to increase in the size of the nuclear charge and decrease in the distance between the nucleus and the outermost electron. Hence, the process; Br+(g) ---->Br2+(g) + e- has the greatest ionization energy. Recall that the second ionization is always higher than the first ionization energy.

12)The order of decreasing metallic character here is K> As> P. Even though As and P belong to the same group, we must note that metallic character increases down the group hence the order written above.

Answer:

LIBs have had a huge impact on our society. They enabled modern portable electronics such as laptops and mobile phones. And they are now enabling clean and low-carbon transport, be it via electric cars or even flying taxis, and grid-scale storage of renewable energy

Explanation:

Answer:

Molarity: 6.2x10⁻³M NaCl

Molality: 6.2x10⁻³m NaCl

Mole Fraction: 1.1x10⁻⁴

Mass% NaCl: 0.036% (m/m NaCl)

Explanation:

Molarity -Moles NaCl / L-

Moles NaCl -Molar mass: 58.44g/mol-

0.018g * (1mol/58.44g) = 0.000308 moles NaCl

Liters water:

50mL * (1L/1000mL) = 0.050L

M = 0.000308 moles NaCl / 0.050L

Molality -Moles NaCl / kg water-

Moles NaCl = 0.000308 moles NaCl

kg water = 50mL * (1g/mL) * (1kg/1000g) = 0.050kg

m = 0.000308 moles NaCl / 0.050kg

Mole Fraction -Moles NaCl / Moles water+ Moles NaCl-

Moles water = 50g * (1mol/18.01g) = 2.776 moles

Moles fraction = 0.000308 moles NaCl / 0.000308 moles NaCl + 2.776moles water

Mass Percent -Mass NaCl / Mass NaCl+Mass Water * 100

0.018g / 50g+0.018g * 100

Answer:

184.8 g

Explanation:

Step 1: Write the balanced thermochemical equation

C₈H₁₈(l) + 25/2 O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(g)   ΔH°rxn = -5074.1 kJ

Step 2: Calculate the moles of octane required to produce 8210 kJ of heat

According to the thermochemical equation, 5074.1 kJ of heat are released per mole of octane consumed.

-8210 kJ × 1 mol C₈H₁₈/(-5074.1 kJ) = 1.618 mol

Step 3: Calculate the mass corresponding to 1.618 moles of octane

The molar mass of C₈H₁₈ is 114.23 g/mol.

1.618 mol × 114.23 g/mol = 184.8 g

1mol produces=5074.1KJ heat .

Moles produce 8210 KJ heat :-

Molar mass of Octane :-

Mass of Octane=

Answer:

See explanation

Explanation:

TLC is a chromatographic method in which the solute is spotted on a plate and the plate is placed in an air tight chamber containing a solvent. The solvent is maintained below the level of the spot. The capillary movement of the solvent through the plate achieves the required separation.

If two spots have Rf values of 0.25 and 0.26 respectively and then the plate was removed from the developing chamber, subsequently, the residual solvent was allowed to evaporate from the plate, and then the plate was returned to the developing chamber.

It will be observed after the second development is complete that the new Rf values will be 0.50 and 0.52 respectively. It will just be as though the second chromatogram picked up from where the first chromatogram stopped.

Answer:

11) the difference in heat energies between products and reactants

12) enthalpy change

Explanation:

The heat of reaction is defined as that energy released or absorbed as chemical substances participate in a chemical reaction. It is a term used to denote the change in energy as reactants change into products.

Another name of heat of reaction is enthalpy of reaction. It is a state function since it depends on the initial and final states of the system.

Answer:

Explanation:

[H+] = 0.1x0.03x2 + 0.2x0.03 = 0.012 mol

[OH-] = 0.001x0.05x2 = 0.0001 mol

=> [H+] dư = 0.012 - 0.0001 =0.0119 mol

pH = -log[H+] = 1.92

Answer:

A. HCl is the limiting reactant.

B. Theoretical yield of Cl₂ is 20.9 g.

C. Actual yield of Cl₂ = 15.2 g.

Explanation:

The balanced equation for the reaction is given below:

4HCl + MnO₂ –> MnCl₂ + 2H₂O + Cl₂

Next, we shall determine the masses of HCl and MnO₂ that reacted and the mass of Cl₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of HCl = 1 + 35.5

= 36.5 g/mol

Mass of HCl from the balanced equation = 4 × 36.5 = 146 g

Molar mass of MnO₂ = 55 + (2×16)

= 55 + 32

= 87 g/mol

Mass of MnO₂ from the balanced equation = 1 × 87 = 87 g

Molar mass of Cl₂ = 2 × 35.5

= 71 g/mol

Mass of Cl₂ from the balanced equation = 1 × 71 = 71 g

SUMMARY:

From the balanced equation above,

146 g of HCl reacted with 87 g of MnO₂ to produce 71 g of Cl₂.

A. Determination of the limiting reactant.

From the balanced equation above,

146 g of HCl reacted with 87 g of MnO₂.

Therefore, 42.9 g of HCl will react with = (42.9 × 87)/146 = 25.6 g of MnO₂.

From the calculation made above, we can see clearly that only 25.6 g out of 43.1 g of MnO₂ given was needed to react completely with 42.9 g of HCl.

Therefore, HCl is the limiting reactant.

B. Determination of theoretical yield of Cl₂.

Here, the limiting reactant will be used.

From the balanced equation above,

146 g of HCl reacted to produce 71 g of Cl₂.

Therefore, 42.9 g of HCl will react to produce = (42.9 × 71)/146 = 20.9 g of Cl₂.

Thus, the theoretical yield of Cl₂ is 20.9 g.

C. Determination of the actual yield of Cl₂.

Theoretical yield of Cl₂ = 20.9 g

Percentage yield of Cl₂ = 72.9%

Actual yield of Cl₂ =?

Percentage yield = Actual yield / Theoretical yield × 100

72.9% = Actual yield / 20.9

Cross multiply

Actual yield = 72.9% × 20.9

Actual yield = 72.9/100 × 20.9

Actual yield = 0.729 × 20.9

Actual yield of Cl₂ = 15.2 g

Fabric A is likely to be a material that has a moderate tendency to gain electrons when in contact with other materials and is lower in the electrostatic series than ebonite but higher than wood.

The electrostatic series is a list of materials ranked in order of their tendency to gain or lose electrons when in contact with another material.

Materials higher in the series tend to lose electrons more readily and become positively charged, while materials lower in the series tend to gain electrons more readily and become negatively charged.

Ebonite is a synthetic polymer that is known to become negatively charged when rubbed, and it is typically placed near the top of the electrostatic series.

Wood, on the other hand, is a poor conductor of electricity and does not readily become charged when rubbed. Based on these facts, we can infer that Fabric A is lower in the electrostatic series than ebonite, but higher than wood.

To learn more about an electrostatic series, follow the link:

https://brainly.com/question/31065393

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Answer:

NH4Cl is the solute, and the solution is unsaturated.

Explanation:

To create a saturated solution of ammonium chloride at 70°C, we need to dissolve 62 g of ammonium chloride in 100 g of water.

The question tells us that 45 grams of NH4Cl was dissolved in 100 grams of H20 at 70°C. This creates an unsaturated solution since the amount of solute present is less than the amount of solute that the NH4Cl solution can normally hold at 70°C.

Hence, NH4Cl is the solute, and the solution is unsaturated.

Answer:

Benzene <  Cyclohexane < CH4

Explanation:

The location of a peak in an NMR spectrum is determined by chemical shift. In 1H NMR, a proton that is strongly shielded, It implies a proton that has a high electron density, is exposed to a low magnetic field, which causes the chemical shift to diminish, resulting in a signal towards the right direction of the spectrum.

However, a de-shielded proton with its electron density reduced is exposed to a high magnetic field, which causes and resulted in a chemical shift and causes it to shift to the left of the spectrum.

Electronegativity is one of the factors that influence the electron density because it decreases the proton's electron density attached to it as well as the ones attached to nearby atoms due to the inductive effect. The impact of an electronegative atom diminishes fast as the distance between them grows.

We can utilize the impact of electronegativity to calculate how much chemical shift will take place in each molecule in this question.

The chemical shift for benzene is = 7.26 ppm

Chemical shift for cyclohexane is = 1.44 ppm

Chemical shift for methane = 0.23 ppm

Thus, in decreasing order, the chemical shift with the lowest shift from left to right is:

Benzene <  Cyclohexane < CH4