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Answer: Lithium, an alkali metal with three electrons, is also an exception to the octet rule. Lithium tends to lose one electron to take on the electron configuration of the nearest noble gas, helium, leaving it with two valence electrons. There are two ways in which atoms can satisfy the octet rules.

Explanation: Hope this helped! :)

Answer:

22.4 L at standard temperature and pressure.

Answer

b

Explanation:

Answer:

a

Explanation:

Answer:

CH4 + O2 = CO2 + H2O.

Answer:

CH4 + O2 = CO2 + H2O.

Explanation:

The elements of period 2 that satisfy the descriptions are;

a) Neon

b) carbon

c) sodium

c) sodium

We know that the periodic table is an arrangement of the elements in the order of their reactivity. We know that the elements that we have are arranged into groups and periods.

The elements that are in the same group do have similar chemical properties while the elements that are in the same period do have the same number of shells. The properties of the elements in a periods tends to change across the period.

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Answer:

Zinc mercury transition metal

Silicon boron metalloid

Oxygen nitrogen non metal

Sodium alkali metal

Explanation:

Answer:

see above

Explanation:

check for cfe's

Answer:

239.7mL

Explanation:

Using the general gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas constant (0.0821 Latm/molK)

T = temperature (K)

The balanced chemical equation in this question is as follows:

CaC2(s) + 2H2O(l) --> Ca(OH)2(aq) + C2H2(g)

From the equation, 1 mole of CaC2 produces 1 mole of ethylene gas, C2H2.

Using mole = mass/molar mass

Molar mass of CaC2 = 40 + 12(2)

= 40 + 24

= 64g/mol

mole = 0.5487/64

mole = 0.00857mol of CaC2

Hence, 0.00857mol of CaC2 produced 0.00857mol of C2H2

Based on the information provided, n = 0.00857mol, T = 43°C = 43 + 273 = 316K, p = 0.926 atm

PV = nRT

V = nRT/P

V = 0.00857 × 0.0821 × 316/0.926

V = 0.222/0.926

V = 0.2397L

In mL, volume = 0.2397 × 1000

= 239.7mL

Molarity= no. of moles of solute/ volume of solution(in L)

Molarity = 6.2 moles/ 2.5 L = 62/25 mol/L

= 2.48 mol/L

Answer: The answer is D,

Answer:

A. The specific heat keeps the ocean temperatures more even.

Explanation:

I just took a test on a p e x  and it was correct! :)

Answer:

Ignore all friction

Answer:

The electron has an acceleration of 838800 [tex]\frac{m}{min^{2} }[/tex]

Explanation:

An electron has an acceleration of 2.33*10² [tex]\frac{m}{sec^{2} }[/tex]

To be able to express in units [tex]\frac{m}{min^{2} }[/tex], you must carry out the conversion taking into account that 1 [tex]\frac{m}{sec^{2} }[/tex]= 3600 [tex]\frac{m}{min^{2} }[/tex]. Then you can apply the following rule of three: if 1 [tex]\frac{m}{sec^{2} }[/tex] equals 3600 [tex]\frac{m}{min^{2} }[/tex], 2.33 * 10² [tex]\frac{m}{sec^{2} }[/tex] equals how much [tex]\frac{m}{min^{2} }[/tex]?

[tex]\frac{m}{min^{2} }=\frac{2.33*10^{2} \frac{m}{sec^{2} }*3600\frac{m}{min^{2} }}{1\frac{m}{sec^{2} }}[/tex]

[tex]\frac{m}{min^{2} }=838800[/tex]

The electron has an acceleration of 838800 [tex]\frac{m}{min^{2} }[/tex]

Answer:

[tex]C_2H_4O_2[/tex]

Explanation:

¡Hola!

En este caso, dado que conocemos la composición porcentual del compuesto, es posible primero obtener la formula empírica al asumir que dichos porcentajes son gramos, que se vuelven moles con las masas atómicas de carbono, hidrógeno y oxígeno respectivamente:

[tex]n_C=40gC*\frac{1molC}{12.01 gC}=3.33molC \\\\n_H=6.7gH*\frac{1molH}{1.01gC}=6.6molH\\\\n_O=53.3gO*\frac{1molO}{16.00gO}=3.33molO[/tex]

De este modo, ahora obtenemos las relaciones molares entre ellos, con el fin de obtener los subíndices en la fórmula empírica:

[tex]C:\frac{3.33}{3.33}=1\\\\ H:\frac{6.6}{3.33}=2\\\\O:\frac{3.33}{3.33}=1[/tex]

Por consiguiente, la fórmula empírica es:

[tex]CH_2O[/tex]

Finalmente, dado que la masa molar del compuesto es 6.0/0.10=60g/mol (dada la masa y las moles), es posible notar que como la masa molar de la fórmula empírica es 30; esta es dos veces la molecular, por lo que esta ultima resulta:

[tex]C_2H_4O_2[/tex]

¡Saludos!

Answer:

25,104

Explanation:

100.0 x 4.184 x 60.0 = 25,104

Energy required to heat up 100 grams of water(4.184J/g°C) from 0.000C to 60.00C is 25,104.

The science of thermodynamics examines the connections between heat, work, temperature, and energy. The rules of thermodynamics explain how energy moves inside a system and whether or not the system is capable of performing beneficial work on its surroundings. The heat needed to increase one gram of a substance's temperature by one degree Celsius is known as specific heat capacity.

Here,

The specific heat capacity of water is 4.184 J/g° C

This is the heat required to increase the temperature by 1°C.

same way, 4.186J is heat required to raise the temp of 1 gram of water.

Derived equation is: q = mcΔT

Where,

q is heat required

c is specific heat capacity of the substance

m is mass of the substance and

ΔT is the change in temperature

Given,

m = 100g

ΔT = 60.00C - 0.00C

ΔT = 60°C

c = 4.184 J/g°C

now, substitute the values:

q = mcΔT

q = 100 × 60 × 4.184

∵ q = 25,104

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answer is below!! hope this helped

A 6.0-V battery does 1200 J of work transferring charge, then 100C charge is transferred.

One or more electrochemical cells with external connections for powering electrical equipment make up an electric battery, which is a source of electric power.

A battery's positive terminal serves as the cathode and its negative terminal serves as the anode when it is delivering electricity.

Electricity is accepted, stored, and released on demand by batteries and similar devices. Like many other common energy sources, batteries store energy through chemistry in the form of chemical potential.

For instance, until they are burned, logs store energy in their chemical bonds for later conversion to heat.

V = 12 V

W = 1200 J

q = ?

V = W / q

12 = 1200 / q

q = 100 C

Thus, A 6.0-V battery does 1200 J of work transferring charge, then 100C charge is transferred.

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An

196 becase we all rice

Explanation:

Explanation:

The answer to the question is (3) K2SO4

Answer:

A ( I think? )

Explanation:

your welcome

Answer:

[tex]0.30molNH_3[/tex]

Explanation:

Hello there!

In this case, since the reaction for the formation of ammonia is:

[tex]3H_2+N_2\rightarrow 2NH_3[/tex]

We can evidence the 1:2 mole ratio of nitrogen gas to ammonia; therefore, the appropriate stoichiometric setup for the calculation of the moles of the latter turns out to be:

[tex]0.15molN_2*\frac{2molNH_3}{1molN_2}[/tex]

And the result is:

[tex]0.30molNH_3[/tex]

Best regards!

Answer:

1144 g of FeS

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Fe + S —> FeS

From the balanced equation above,

1 mole of Fe reacted to produce 1 mole of FeS.

Therefore, 13 moles of Fe will also react to produce 13 moles of FeS.

Finally, we shall determine mass of 13 moles of FeS. This can be obtained as follow:

Mole of FeS = 13 moles

Molar mass of FeS = 56 + 32

= 88 g/mol

Mass of FeS =?

Mass = mole × molar mass

Mass of FeS = 13 × 88

Mass of FeS = 1144 g

Therefore, 1144 g of FeS were obtained from the reaction.

Answer:

V=f*(wavelength)

V= (800)(20m)

16000m/s

Explanation:

Answer:

They must be selected for a narrow pH range.

Explanation:

Indicators are compounds that change to a specific colour in a solution within a specific pH range.

The chemical indicators does not give the exact value of pH. They only provide the range of pH. They must be selected for a narrow pH range. The correct option is C.

The acid base indicators or neutralization indicators are substances which are employed for the visual detection of the end point on the basis of their ability to change colour during the pH change that occurs in vicinity of the end point.

The chemical indicators are usually weak organic acids or bases which change colour in characteristic pH ranges. The particular range or interval of pH in which an acid-base indicator changes its colour is known as the colour-change interval.

Methyl orange is a weak base which changes its colour in the pH range 3.1-4.4 being red below pH 3.1 and yellow above pH 4.4.

Thus the correct option is C.

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Answer:

One is the classic example of friction. When two surfaces rub together, they generate thermal energy, or heat. This is a transformation of the mechanical kinetic energy of the objects into the thermal non-mechanical energy (which is small-scale kinetic energy).

Mechanical energy can be used to overcome friction or lost in form of heat in machine parts. Friction and heat are two non-mechanical energy.

Based on the principle of conservation of energy, energy can neither be created nor destroyed but can be transformed from one form to another.

The two ways mechanical energy can be transformed include the following;

Mechanical energy can be used to overcome friction or lost in form of heat in machine parts, in this process, the mechanical energy (kinetic energy) would be converted into other forms of energy such as heat.

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