I need to know what the answer is

I Need To Know What The Answer Is

Answers

Answer 1

Answer:

F = M a       fundamental Newton's equation

F = 3 kg * 3 m/s^2 = 9 kg m / s^2 = 9 Newtons


Related Questions

The most massive piece of equipment ever carried by a plane was a 1.24 × 105 kg generator built in Germany in 1993. How far above the ground was the generator when the potential energy associated with it was 9.17 × 108 J?

Answers

The answer is 758 m
I will write anything so I can sent the answer sjjjdjdjdidididd

The generator was  754.6 meter far above the ground  when the potential energy associated with it was  9.17 × 10⁸ J.

What is potential energy?

Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.

The gravitational potential energy of an item, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field are examples of common types of potential energy.

Mass of the equipment : M = 1.24 × 10⁵ kg.

The potential energy associated with it was: E = 9.17 × 10⁸ J.

Acceleration due to gravity: g = 9.8 m/s².

Hence, The height of the equipment =  9.17 × 10⁸ J ÷ ( 1.24 × 10⁵ kg×9.8 m/s²)

= 754.6 meter.

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Which chemical equation represents a synthesis reaction

Answers

Answer:

C

Explanation:

i think its C, not too sure

which equation can be used to solve for acceleration?

Answers

Answer:

the answer is the first one.

Explanation:

one way to find out is if you look at the other equations they are mixed matched. For an example a=d/t should be s= d/t.

Answer:

a

Explanation:

i did it

when jogging outside you accidentally bump into a curb. Your feet stop but your body continues to move forward and you end up on the ground. Which law of motion is being described in the scenario?

a) law of universal gravitation
b) Newton’s first law of motion
c) Law of conservation of energy
d) newton’s second law of motion

Answers

the answer is d

hope it helps

6). How does adding thermal energy affect a gas?

Answers

Answer:

When heat is added to a substance, the molecules and atoms vibrate faster. As atoms vibrate faster, the space between atoms increases. The motion and spacing of the particles determines the state of matter of the substance. ... Solids, liquids and gases all expand when heat is added.

what are differences between an entrepreneur and an employee

Answers

Employees execute tasks while entrepreneurs plan. An employee can take work day by day, whereas an entrepreneur has to consider how well the tasks are being performed relative to the long-term plan for the business.

An 9.20 kg ball, hanging from the ceiling by a light wire 130 cm long, is struck in an elastic collision by a 2.80 kg ball moving horizontally at 3.50 m/s just before the collision. Find the tension in the wire just after collision.

Answers

The tension in the wire is caused by the elastic collision between the balls and the magnitude of this tension is determined as 18.81 N.

Speed of the balls after the collision

The speed of the balls after the collision is determined by applying the principle of conservation of linear momentum as shown below.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

9.2(0) + 2.8(3.5) = 9.2v₁ + 2.8(v₂)

9.8 = 9.2v₁ + 2.8v₂   -----(1)

One - directional linear velocity

u₁ + v₁ = u₂ + v₂

0 + v₁ = 3.5 + v₂

v₂ = v₁ - 3.5  ---(2)

Substitute (2) into (1)

9.8 = 9.2v₁ + 2.8(v₁ - 3.5)

9.8 = 9.2v₁ + 2.8v₁ - 9.8

19.6 = 12v₁

v₁ = 19.6/12

v₁ = 1.63 m/s

Tension on the wire

v = √T/μ

v² = T/μ

T = v²μ

where;

μ is mass per unit length of the wire = 9.2/1.3 = 7.08 kg/m

T = (1.63²) x 7.08

T = 18.81 N

Thus, the tension in the wire just after collision is 18.81 N.

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Freebie/Answered: As part of an experiment, a student wraps a wire in an electric circuit around an iron core, producing a magnetic field. Which phrase best describes the resulting apparatus?

Answers

Answer:

An electromagnet

Explanation:

The rest of the answers

adding more cells

As currents increases, the magnetic fuel strengths increases.

They both have north and south magnetic poles.

A current will be induced in the coil of wire.

Answer:

Number three is The current increases as the magnet's movement remains the same

Explanation:

If you apply a force of 200N to an object with a mass of 50kg, what will the acceleration be?​

Answers

Answer:

Acceleration = 4 m/s

Explanation:

Acceleration = force divided by mass

So;

a = 200 ÷ 50 = 4

Question 10 of 13
The majority of your documentation is done in Process Interventions
True
False

Answers

This answer is true but in other contexts it can be false

A force of 10 n acts on a mass of 5 kg producing an acceleration of 1.5 m/s2 what is the magnitude of the force of friction acting on the mass

Answers

The friction is 2.5N. The Net force is 10 N - 2.5 N .= 7.5 N.
acceleration = 7.5 / 5 = 1.5 m/s^2

Given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton

Given the data in the question;

Force acting on the object; [tex]F = 10N[/tex]Mass of the object; [tex]m = 5kg[/tex]Acceleration of the object; [tex]a = 1.5 m/s^2[/tex]Force of friction acting on the mass; [tex]F_k = \ ?[/tex]

To determine the magnitude of the force of friction acting on the mass,

From Newton's laws of motion

[tex]F = m\ *\ a[/tex]

Where F is the force applied, m is the mass of the object and a is the acceleration of the object.

Now, we know that Kinetic Friction is always opposite of the direction of motion.

So, in the question, the force applied overcomes the friction to produce an acceleration of [tex]1.5 m/s^2[/tex]

Hence

[tex]F = F_k + ma[/tex]

Where [tex]F_k[/tex] is the kinetic friction

Now, we substitute our given values into the equation

[tex]10N = F_k +\ ( 5kg\ *\ 1.5m/s^2)\\\\10N = F_k +\ 7.5kg.m/s^2[/tex]

We know that, A newton is defined as [tex]1 kg.m/s^2[/tex]

Hence;

[tex]10N = F_k\ *\ 7.5N\\\\F_k = 10N \ -\ 7.5N\\\\F_k = 2.5N[/tex]

Therefore, given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton.

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If 10 waves come in every 8 seconds with a wavelength of 2 meters, what is the frequency?

Answers

Answer:

Explanation:

frequency = 10/8 = 1.125 Hz

How is the gravitational force related to the distance between two objects?
S
It is directly proportional to the square of the distance.
It is inversely proportional to the square of the distance.
it is directly proportional to the distance.
it is inversely proportional to the distance.

Answers

gravitational force is inversely proportional to the square of the separation distance between the two interacting objects

Gravitational force is inversly proportional to the square of the distance. Option B is correct.

What is gravitational force?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

[tex]\rm F=G\frac{mM}{R^2}[/tex]

Gravitational force is inversly proportional to the square of the distance.

Hence option B is correct.

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a cue ball strikes an 8 ball of equal mass, which is initailly at rest. the cue ball stops and the 8 ball moves forward with a velocity equal to the intial velocity of cue ball. is the collsiion elastic

Answers

The collision is elastic:

In all elastic collisions of that type (unidirectional) the velocity of approach equals the velocity of separation - the collision is elastic even for different masses

e = relative velocity after / relative velocity before

e = 1 for elastic collisions

An object is pushed at an angle of 42˚ by a force of 135 N through a distance of 829 cm. Find the work done by the object.

Answers

The work done by the object is 831.69 J.

What is work?

Work can be defined as the product of mass and distance.

To calculate the work done by the object, we use the formula below

Formula:

W = Fdcos∅............ Equation 1

Where:

W = Work done by the objectF = Force on the object∅ = Angle.

From the question,

Given:

F = 135 Nd = 829 cm = 8.29 m∅ = 42°

Substitute these values into equation 1

W = 135×8.29×cos42°W = 831.69 J.

Hence, The work done by the object is 831.69 J.

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An astronaut is floating in space. There is no rope connecting him to the ship. They have some tools and a
fire extinguisher.
Which action could propel the astronaut back to the ship? (Select two answers)
He could spray the fire extinguisher in the opposite direction of the ship
He could throw a tool in the opposite direction of the ship
He could throw a tool toward the ship
He could point the extinguisher towards the ship and spray it.

Answers

He could spray the fire extinguisher in the opposite direction of the ship. This is definitely the answer because its all about momentum

Answer:

It's A it is correct trust me and no I didn't copy the other person I just read the answers.

Hope this helps:)

Explanation:

a
Gold-198 has a half-life of approximately 3 days. If a 100g sample of gold-198 decays for
9 days, approximately how much gold-198 remains in the sample?
o 13 g
o 25 g
o 33 g
o 50g

Answers

Answer:

13 g

Explanation:

Gold-198 has a half-life of approximately 3 days. If a 100 g sample of gold-198 decays for 9 days, approximately how much gold-198 remains in the sample?

13 g

A spacecraft passes you at 0.255 the speed of light. By what factor does the relativistic energy increase if its speed doubled and if you subtract out the constant rest energy

Answers

The factor increase in the relativistic energy  is 0.129.

Relativistic kinetic energy of the spacecraft

The relativistic kinetic energy of the spacecraft is determined as follows;

[tex]K = (\frac{1}{\sqrt{1- \frac{v^2}{c^2} } } )mc^2[/tex]

where;

v is the speed of the spacecraftc is the speed of light

At 0.255 speed of light, the relativistic kinetic energy is calculated as follows;

[tex]K = (\frac{1}{\sqrt{1- \frac{(0.255c)^2}{c^2} } } )mc^2\\\\K = (\frac{1}{\sqrt{1- \frac{0.065c^2}{c^2} } } )mc^2\\\\K = 1.034mc^2[/tex]

When the speed doubles, v = 2(0.255c)

[tex]K = (\frac{1}{\sqrt{1- \frac{(2 \times 0.255c)^2}{c^2} } } )mc^2\\\\K = (\frac{1}{\sqrt{1- \frac{0.261c^2}{c^2} } } )mc^2\\\\K = 1.163mc^2[/tex]

Increase in energy

ΔK = 1.163mc² - 1.034mc²

ΔK = 0.129mc²

Thus, the factor increase in the relativistic energy  is 0.129.

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A satellite orbiting Earth at a velocity of 3700 m/s collides with a piece of
space debris traveling at 6000 m/s. If the objects have the same mass and
the space debris has a velocity after collision of 3700 m/s, what is the
velocity of the satellite after the collision?
A. 3000 m/s
B. 6000 m/s
c. 5000 m/s
D. 4000 m/s

Answers

Answer: B

Explanation:

You can use the conservation of momentum, under the assumption that no mass was lost when the collision occurred. The initial momentum of the system must equal the final momentum of the system. Our system is the region including, and only including, the satellite and the space debris. Classical momentum is defined as the product of mass and velocity:

[tex]p_i=p_f[/tex]

[tex]m_1v_1_i+m_2v_2_i=m_1v_1_f+m_2v_2_f[/tex]

Due to mass 1 equaling mass 2, we can factor these quantities out:

[tex]m(v_1_i+v_2_i)=m(v_1_f+v_2_f)[/tex]

Cancel the mass term on both sides to get:

[tex]v_1_i+v_2_i=v_1_f+v_2_f[/tex]

We have the initial and final velocities for everything besides the final velocity of the satellite. Plug everything in:

[tex]3700m/s+6000m/s=v_1_f+3700m/s[/tex]

[tex]v_1_f=6000m/s[/tex]

Which of the following exerts the most pressure while resting on a floor?
a. a 25 N cube with 1.5 m sides
b. a 15 N cylinder resting vertically with a base radius of 1.0 m
c. a 25 N cube with 2.0 m sides
d. a 25 N cylinder resting vertically with a base radius of 1.0 m

Answers

The pressure of the cube that exerts the most pressure while resting on a floor is mathematically given as

P=16.6pascal, Option D is correct

Which of the following exerts the most pressure while resting on a floor?

Generally, the equation for the Pressure   is mathematically given as

P=force/Area

Therefore, In considering the one with the most pressure we look at the one with the most force/Area

In conclusion, the one with the most Force/Area is a 25 N cube with 1.5 m sides

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A Carnot engine absorbs heat at a temperature of 127 °C and exhaust heat at a temperature of 77 °C. Its efficiency is

A. 13%
B. 39 %
C.61%
D. 88 %
E. 90 %​

Answers

The answer to this is A.13%

Hope this helped

The efficiency of a carnot engine with absorb temperature and exhaust temperature is 13%. The correct option is A.

What is Efficiency?

The efficiency is defined as the work done by the engine divided by the heat supplied.

So, efficiency η = 1 - T₁/T₂

Where T₁ is the lower temperature and T₂ is the higher temperature.

A Carnot engine absorbs heat at a temperature of 127 °C and exhaust heat at a temperature of 77 °C

Substitute the value into the expression , we get

η = 1 -(77+273)  / (127+273) x 100 %

η = 12.5 %

or

η = 13 %

Thus, the efficiency of the carnot engine is 13%.

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An astronaut weighs 104 newtons on the moon, where the strength of gravity is 1.6N/kg. What is her mass?

Answers

her mass is 65 kilograms
the answer is her mass is 64 Kg

Reuptake means that:

Answers

Answer:

it means absorption by a presynaptic nerve ending of a neurotransmitter that it has secreted.

Explanation: I hoped that helped please leave a 5 rate and thanks. Have a great day .

HELP QUICK
What is the correct definition of the word clan?
a.
a cluster of multistory structures made out of adobe
b.
a large family, or group of families, related through common ancestory
c.
a portable dome or arch shaped home made out of wooden sticks and covered in animal skin, mud, or grass
d.
religious leader who was believed to have the power to heal as well as predict and control future events

Answers

Answer:

The answer is B.

Explanation:

A Clan is usually just one family, but can be multiple families that are related. They were usually very close knit. Sometimes a clan is also a group of people with a common interest.

According to Newton’s first law of motion, what will an object in motion do when no external force acts on it?
come to a stop
move at the same velocity
speed up
change direction

Answers

Answer:

move at the same velocity

Explanation:

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Answer:

move at the same velocity

Explanation:

what is the acceleration of a 10 kg mass pushed by a 5 newton force?

Answers

Answer:

0.5 m/s²

Explanation:

F=ma
F is force
m is mass
a is acceleration

F=ma
5 =  10 x a
a = 5/10
a = 0.5 m/s²

An archerfish, peering from just below the water surface, sees a grasshopper standing on a tree branch that's just above the water. The archerfish spits a drop of water at the grasshopper and knocks it into the water. The grasshopper's initial position is 0.45 m above the water surface and 0.25 m horizontally away from the fish's mouth. The launch angle of the drop is 630 with respect to the water surface.
A. Find an expression for how fast the drop is moving when it leaves the fish's mouth. (Your expression should only contain symbols of physical quantities. No numbers are needed here. )
B. Find the numerical value for how fast the drop is moving when it leaves the fish's mouth. (Plug the values of physical quantities into your expression from part A (do not forget units!) Evaluate your answer that you found in part B by using it to find the value of a physical quantity given in the problem statement. (This is called evaluating for consistency.) For instance, suppose you knew the initial speed of the water (i.e., your answer in part B), the launch angle ( 63º) and the grasshopper's initial horizontal position (0.25 m). Using this information, find the initial vertical position of the grasshopper. Is this value consistent with the value given in the problem statement?

Answers

Answer:

Explanation:

Let the required velocity be V   at angle θ with the horizontal . Let time taken in the whole process be t

horizontal component = v cosθ

It will cover .25 m at this velocity

vertical component = v sinθ

It will cover .45 m with this initial velocity and with deceleration g .

v cosθ t = .25

.45 =v sinθ t - 1/2 g t²

putting the values of t from above

.45 = .25 tanθ - g .25² / 2 v² cos²θ

B ) putting the values of θ

.45 = .25 tan63 - 9.8 x .25² / 2 v² cos² 63

.45 = .49 - 1.53 / v²

1.53 / v² = .04

v² = 38.25

v = 6.18 m /s

time taken to cover distance of .25 m

t = .25 / 6.18 cos63 = .089 s

during this period , vertical displacement

= 6.18 sin 63 x .089  - 1/2 x 9.8 x .089²

= .4895 - .04  = .45 m which is consistence with given height .

A train that travels 100.0 kilometers in 4.0 hours is traveling at what speed?

Answers

Answer:

25 kilometers an hour.

Explanation: Since there is 100 kilometers, you dived it by four hours and you get the kilometers per hour.

Answer:

25 kmph

Explanation:

100 divided by 4 is 25

hope it helps

A supply capsule w/ crew approaches a spy satellite at a relative speed of 0.250 m/s so as to dock. The astronauts will then repair said spy satellite. The supply capsule has a mass of 4000 kg, and the spy satellite has a mass of 7500kg. a. Calculate the final velocity (after docking) by using the frame of reference in which the Spy satellite appears to be originally at rest. b. What is the loss of kinetic energy in this inelastic collision

Answers

The final velocity and the loss of kinetic energy is mathematically given as

vf = 0.087 m/sL-K.E= 81.5 J

What are the final velocity and the loss of kinetic energy?

Question Parameters:

Generally, the equation for the conservation of momentum   is mathematically given as

m1v1 = m2v2

(7500 + 4000) * vf = 4000 * 0.250

vf = 0.087 m/s

b)

Generally, the equation for the loss of kinetic energy  is mathematically given as

loss in kinetic energy = initial kinetic energy - final kinetic energy

Therefore

L-K.E= 0.50 * 4000 * 0.25^2 - 0.50 * (4000 + 7500) * 0.087^2

L-K.E= 81.5 J

In conclusion, the final velocity and the loss of kinetic energy

vf = 0.087 m/s

L-K.E= 81.5 J

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If a system absorbs 155.0 kJ of heat from its surroundings and the system does 45.0 kJ of work on its surroundings, what is the change in the internal energy of the system, in kJ

Answers

The change in the internal energy of the system is 110 kJ.

What is internal energy?

Internal energy is defined as the energy associated with the random, disorder motions of molecules.

calculate the change in internal energy, we apply the formula below.

Formula:

ΔU = Q-W.................... Equation 1

Where:

ΔU = Change in internal energyQ = Heat absorbed from the surroundingsW = work done by the system

From the question,

Given:

Q = 115 kJW = 45. 0 kJ

Substitute these values into equation 1

ΔU = 155-45ΔU = 110 kJ

Hence, The change in the internal energy of the system is 110 kJ.

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Answer:

110.0kJ

Explanation:

The following solution may contain one or more values that are different from the problem provided to you, however, the steps to solve the problem are the same.

.The internal energy (E) of a system can change as heat (q) flows into or out of the system, or work (w) is done on or by the system. The following equation represents the relationship.

ΔE=q+w

In this question, heat is absorbed by the system, so it has a positive sign. Work is done by the system, so it has a negative sign.

ΔE=(155.0 kJ)+(−45.0 kJ)=110.0 kJ

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