I need help with this math

Answer:

[tex]4^{\left(x-1\right)}=1[/tex]

[tex]\Rightarrow\left(x-1\right)\ln \left(4\right)=\ln \left(1\right)[/tex]

[tex]\hookrightarrow x=1[/tex]

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OAmalOHopeO

❅❅❅❅❅❅❅❅❅❅

Answer:

C. 468 mm²

Step-by-step explanation:

Surface area of the composite solid = 2(LW + LH + WH)

Length (L) = 12 mm

Width (W) = 6 mm

Height (H) = 2 + 7 = 9 mm

Plug in the values into the formula

Surface area = 2(12*6 + 12*9 + 6*9)

Surface area = 2(72 + 108 + 54)

Surface area = 2(234)

= 468 mm²

Hey there!

[tex]\large\textsf{FACTORS OF 160: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, \& 160}[/tex]

[tex]\large\textsf{FACTORS OF 198: 1, 2, 3, 6, 9, 11, 18, 22, 33, 66, 99, \& 198}[/tex]

[tex]\large\text{Go through the factors to see if there’s any like terms and if you find any,} \\\large\text{look for the greatest one the numbers share together.}[/tex]

[tex]\large\text{Like terms: \boxed{\textsf{\bf 1 \& 2}}}[/tex]

[tex]\large\checkmark\boxed{\large\text{GCF: \bf 2 }}\large\checkmark[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \huge the GCF \underline{G}reatest \underline{C}ommon \underline{F}actor is \bf 2}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

The probability of randomly selecting one employee who earned less than or equal to $45,000=0.00621

Step-by-step explanation:

We are given that

Mean,[tex]\mu=50000[/tex]

Standard deviation,[tex]\sigma=2000[/tex]

We have to find the probability of randomly selecting one employee who earned less than or equal to $45,000.

[tex]P(x\leq 45000)=P(\frac{x-\mu}{\sigma}\leq \frac{45000-50000}{2000})[/tex]

[tex]P(x\leq 45000)=P(Z\leq-\frac{5000}{2000})[/tex]

[tex]P(x\leq 45000)=P(Z\leq -2.5)[/tex]

[tex]P(x\leq 45000)=0.00621[/tex]

Hence,  the probability of randomly selecting one employee who earned less than or equal to $45,000=0.00621

Answer:

[tex]EA = \frac{21 \times 15}{7} = 45 \\ { \tt{ \frac{21}{7} = \frac{x}{45} }} \\ x = 135[/tex]

Answer:

[tex]\displaystyle f(x)=\frac{3}{2}x^3-\frac{27}{2}x^2+36x-21[/tex]

Where:

[tex]\displaystyle a=\frac{3}{2}, \, b=-\frac{27}{2}, \, c=36, \text{and } d=-21[/tex]

Step-by-step explanation:

We are given a cubic function:

[tex]f(x)=ax^3+bx^2+cx+d[/tex]

And we want to find a, b, c and d such that the  function has a relative maximum at (2, 9); a relative mininum at (4, 3); and an inflection point at (3, 6).

Since the function has a relative maximum at (2, 9), this means that:

[tex]f(2)=9=a(2)^3+b(2)^2+c(2)+d[/tex]

Simplify:

[tex]8a+4b+2c+d=9[/tex]

Likewise, since it has a relative minimum at (4, 3):

[tex]f(4)=3=a(4)^3+b(4)^2+c(4)+d[/tex]

Simplify:

[tex]64a+16b+4c+d=3[/tex]

We can subtract the first equation from the second. So:

[tex](64a+16b+4c+d)-(8a+4b+2c+d)=(3)-(9)[/tex]

Simplify:

[tex]56a+12b+2c=-6[/tex]

Divide both sides by two. Hence:

[tex]28a+6b+c=-3[/tex]

Relative minima occurs only at the critical points of a function. That is, it occurs whenever the first derivative equals zero.

Find the first derivative. We can treat a, b, c and d as constant. Hence:

[tex]f'(x)=3ax^2+2bx+c[/tex]

Since it has a minima at (2, 9), it means that:

[tex]f'(2)=3a(2)^2+2b(2)+c=0[/tex]

Thus:

[tex]12a+4b+c=0[/tex]

(We will only need one of the two points to complete the problem.)

Inflection points occurs whenever the second derivative of a function equals zero. Find the second derivative:

[tex]f''(x)=6ax+2b[/tex]

Since there is a inflection point at (3, 6):

[tex]18a+2b=0\Rightarrow 9a+b=0[/tex]

Solve for b:

[tex]b=-9a[/tex]

Substitute this into the above equation:

[tex]12a+4(-9a)+c=0[/tex]

Solve for c:

[tex]c=24a[/tex]

Substitute b and c into the previously acquired equation:

[tex]28a+6(-9a)+(24a)=-3[/tex]

Solve for a:

[tex]\displaystyle -2a=-3\Rightarrow a=\frac{3}{2}[/tex]

Solve for b and c:

[tex]\displaystyle b=-9\left(\frac{3}{2}\right)=-\frac{27}{2}\text{ and } c=24\left(\frac{3}{2}\right)=36[/tex]

Using either the very first or second equation, solve for d:

[tex]\displaystyle 8\left(\frac{3}{2}\right)+4\left(-\frac{27}{2}\right)+2(36)+d=9[/tex]

Hence:

[tex]d=-21[/tex]

Hence, our function is:

[tex]\displaystyle f(x)=\frac{3}{2}x^3-\frac{27}{2}x^2+36x-21[/tex]

Answer:

n = 4 is 10

hope it helps and have a good day

Answer:

y = 9

Step-by-step explanation:

Answer:

there is no file attached

Step-by-step explanation:

Answer:

x²+6x-4 is answer maybe

Answer:

tgis moght help

Step-by-step explanation:

https://opentextbc.ca/introbusinessstatopenstax/chapter/full-hypothesis-test-examples/

Answer:

x=2pi/3 +2pi n, 4pi/3 +2pi n for all integar of n.

Step-by-step explanation:

Answer:

D. allows a person to borrow more money at a lower interest rate

Answer:

x = 16

Step-by-step explanation:

The product of the lengths theorem is a property that can be sued to describe the relationships of the sides between the tangents and secants in a circle. One of these products states the following;

The distance between the point of tangency and its intersection point with the exterior secant squared is equal to the product of the exterior secant times the interior secant.

This essentially means the following equation can be formed;

[tex](AB)^2=(DC)(CB)[/tex]

Substitute,

[tex]12^2=x*9[/tex]

Simplify,

[tex]144=9x[/tex]

Inverse operations,

[tex]\frac{144}{9}=x\\\\16=x[/tex]

Answer:

[tex]\boxed{\sf x=7}[/tex]

Step-by-step explanation:

By Targent-secant theorem...

[tex]\sf 9(x + 9) = {12}^{2} [/tex]

Use the distributive property to multiply 9 by x+9.

[tex]\sf 9x+81= {12}^{2} [/tex]

Now, let calculate 12 to the power of 2 and get 144.

[tex]\sf 9x+81=144[/tex]

Subtract 81 from both sides.

[tex]\sf 9x=63[/tex]

Divide both sides by 9.

[tex] \sf \cfrac{ 9x}{9} = \cfrac{63}{9} [/tex]

[tex]\sf x=7[/tex]

Answer:

Kevin is correct.

Step-by-step explanation:

3 girls + 5 boys = 8 students.

Answer:

he is incorrect since in a ratio you don't add them together instead what this ratio means is for every 3 girls there is 5 boys

Hope This Help!!!

Answer:

Average of 65 boxes each day

Step-by-step explanation:

1950÷30=65

Answer:

The answer is true

Step-by-step explanation:

Answer:

Assuming you want better payment each week, any number of hours above 33.333 or 33 hours and 20 minutes per week

Step-by-step explanation:

There are several ways we could do this.  We could say we want to have Tim Hortons be the better employer on the first week, or after so many weeks by adjusting the hours.  I am going to assume we are saying we want it to be a better employer on the first week, so the profit will be the amount made every week plus the money made per hour times the number of hours.

Let's say number of hours is H

So Tim Hortons winds up as 200 + 5H for one week and  Mcdonalds will be 300 + 2H.

If you set the two expressions equal to each other you will find where they intersect, which means at that number of hours they will give the same amount of money while any amount before one of the companies will give more and after that many hours the other will.  Let's go ahead and solve.

200 + 5H = 300 + 2H

3H = 100

H = 100/3

So H is about 33.333.  let's check.

200 + 5(33.333) = 366.665 which rounds to 366.67 dollars

300 + 2(33.333) = 366.666 which also rounds to 366.67 dollars

So at 33.333 hours both give 366.67 dollars.  Let's look at a value below it, say 32.

200 + 5(32) = 360

300 + 2(32) = 364

So you can see here Tim Hortons  pays less.  Now we will try 34 as a value above 33.333

200 + 5(32) = 370

300 + 2(32) = 368

Here Mcdonalds pays less.  This was to show that values below 33.333 make Tim Hortonspay less and values above 33.333 make Mcdonalds pay less.  In other words any value above 33.333 hours will have Tim Hortons be the better employer.  And this is per week

I want to repeat, you can expand this to be multiple weeks and see which of the two becomes better in that epriod of time.  This was, I think, the simplest way to answer though.  

So the conditions where Tim Horton pays more isif you work more than 33.333 hours per week.  This will make them pay more every single week.  

Answer:

7% probability that the next 2 cards are hearts.

Step-by-step explanation:

Cards are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

10 cards, which means that [tex]N = 10[/tex]

3 are hearts, which means that [tex]k = 3[/tex]

Probability that the next 2 cards are hearts:

This is P(X = 2) when n = 2. So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 2) = h(2,10,2,3) = \frac{C_{3,2}*C_{7,0}}{C_{10,2}} = 0.0667[/tex]

0.0667*100% = 6.67%

Rounded to the nearest whole number, 7% probability that the next 2 cards are hearts.

B is the answer for this question hope it helps

Answer:

Ok so these triangle are the same with equivalent angles

so we can add up the angles 80+26=106

now we subtract from 180

180-106=74

so the measure of angle b is 74

Hope This Helps!!!

Answer:

3.15 seconds is the answer.

Explanation

when the ball touches the ground, h =0

hence,

0=255-21t-16t²

16t²+21t-225=0

here a=16 ,b=21, c= -225

[tex]t= \frac{ - b± \sqrt{ {b }^{2} - 4ac} }{2a} \\ \\ t= \frac{ - 21± \sqrt{ {21}^{2} - 4 \times 16 \times - 225} }{2 \times 16} \\ = \frac{ - 21 ± \sqrt{441 - ( - 14400)} }{32} \\ = \frac{ - 21± \sqrt{14841} }{32} \\ = \frac{ - 21±121.82}{32} \\ \\ t = \frac{ - 21 + 121.82}{32} \: or \: \: t = \frac{ - 21 - 121.82}{32} \\ t = 3.15 \: \: or \: \: t = - 4.46[/tex]

time cannot be negative, hence t = -4.46 can be avoided

The ball takes 3.15 seconds to hit the ground.

9514 1404 393

Answer:

  10 minutes

Step-by-step explanation:

The current legal tender conversion rate is 50 kobo = 0.50 naira. Then the airtime balance is ...

  (300 NGN)/(0.50 NGN/s) × (1 min)/(60 s) = 300/(0.50×60) min = 10 min

9514 1404 393

Answer:

Step-by-step explanation:

Each x-intercept at x=a corresponds to a polynomial factor of (x -a).

__

The top graph has x-intercepts of -3, 0, +2, so the factors of this cubic are ...

  y = (x +3)(x -0)(x -2)

  y = x(x +3)(x -2) . . . . . . . matches upper right tile

__

The bottom graph has x-intercepts of -2, -1, 1, 2, so the factors of this quartic are ...

  y = (x +2)(x +1)(x -1)(x -2) = (x² -4)(x² -1)

  y = x⁴ -5x² +4 . . . . . . . matches lower left tile

Answer:

options aren't given but the correct answer will be [tex]\frac{27x^6y^9}{z^9}[/tex]

Step-by-step explanation:

The simplified form of (3x²y³/z³)³ is 27x⁶y⁹/z⁹.

To simplify the expression (3x²y³/z³)³, we apply the rules of exponents. When we raise a power to another power, we multiply the exponents.

First, let's apply the exponent of 3 to each term inside the parentheses:

(3x²y³/z³)³ = 3³ × (x²)³ × (y³)³ / (z³)³

Simplifying further:

= 27 × x⁶ × y⁹ / z⁹

Therefore, the simplified form of (3x²y³/z³)³ is 27x⁶y⁹/z⁹.

This means that each term inside the parentheses is raised to the power of 3, resulting in the expression 27x⁶y⁹/z⁹.

The final expression represents the cube of the original expression, where each term is cubed individually. The exponents are multiplied by 3 to reflect this operation.

In summary, the simplified form is 27x⁶y⁹/z⁹.

To learn more about the exponents;

brainly.com/question/30066987

#SPJ6

Answer:

1 /2

Step-by-step explanation:

Given :

Bag 1 : Red (R) ; Blue (B) ; White (W)

Bag 2 : Red (R) ; Pink (P) ; Yellow (Y) ; Green (G)

Total number of possible outcomes :

3C1 * 4C1 = 3 * 4 = 12 outcomes

Sample space (S) ;

_______ R ______ B _______ W

R_____ RR _____ RB ______ RW

P_____ PR _____ PB ______ PW

Y _____YR_____ YB ______ YW

G _____GR ____ GB ______ GW

To win price of baked goods ; Atleast one red ball must be drawn :

Probability of winning ; P(winning) = required outcome / Total possible outcomes

Required outcome = {RR, RB, RW, PR, YR, GR} = 6

Total possible outcomes = S = 12

P(winning) = 6/12 = 1/2

Answer:

(0.3049 ; 0.3751)

Step-by-step explanation:

The confidence interval for proportion can be obtained using the relation :

Phat ± Zcritical * [√phat(1-phat) / n]

phat = x / n

Sample size, n = 700

x = 238

phat = 238/700 = 0.34

Zcritical at 95% = 1.96

C.I = 0.34 ± 1.96 * [√0.34(1-0.34) / 700]

C.I = 0.34 ± 1.96 * 0.0179045

C. I = 0.34 ± 0.0350928

Lower boundary = 0.34 - 0.0350928 = 0.3049

Upper boundary = 0.34 + 0.0350928 = 0.37509

(0.3049 ; 0.3751)

Answer:

24/25

Step-by-step explanation:

The sin value is the y coordinate of the exact value point.

24/25 is the y coordinate so 24/25 is the answer.

Answer:

24/25 is the correct answer

Answer:

Range:

UCL = 4.73

LCL = 18.08

MEAN :

UCL = 27.115

LCL = 31.219

Step-by-step explanation:

Given the data:

The mean and range of each sample :

Sample __ Thread wear __ xbar __ R

1 ___31 __ 42 ___ 28 ____ 33.67 _14

2___ 26 _ 18 ____35____ 26.33 _17

3___25 __30 ___ 34____29.67 _ 9

4 __ 17 __ 25 ___ 21 _____ 21 ___ 8

5 __ 38 _ 29 ___ 35 _____ 34 __ 9

6 __ 41 __42 ___36 _____39.67_ 6

7 __ 21 __ 17 ___29 _____22.33 _12

8 __ 32 __26___28 ____ 28.67 _ 6

9 __ 41 __ 34 __ 33 ______ 36 __8

10__29___17___30 _____25.33_ 13

11 __26 __ 31 __ 40 _____32.33_ 14

12__23 __ 19 __ 45 _____12.33 __6

13 __17 __ 24 __ 32_____24.33__15

14 __43__ 35___17_____ 31.67 _ 26

15__18 ___25__ 29_____ 24 ___ 11

16__30___42___31 ____34.33__ 12

17__28___36 __ 32____ 32 ____8

18__40 __ 29 __ 31 ____33.33 __ 11

19__18 ___29__ 28____ 25 ____11

20_ 22 __ 34 __ 26 ___ 27.33 __12

Size per sample, sample size, n = 3

Number of samples, k = 20

We calculate the sample mean and range average :

Sample mean, x-- = Σxbar/n = 29.167

Range average, Rbar = ΣR/n = 11.4

The mean control limit :

x-- ± A2Rbar

From the x chart ;

A2 for n = 20 is A2 = 0.180

29.167 ± 0.180(11.40)

LCL = 29.167 - 0.180(11.40) = 27.115

UCL = 29.167 + 0.180(11.40) = 31.219

The Range control limit :

Rbar(1 ± 3(d3/d2))

From the R-chart :

d2 at n = 20 ; d2 = 3.735

d3 at n = 20 ; d3 = 0.729

LCL = 11.40(1 - 3(0.729/3.735)) = 4.725

UCL = 11.40(1 + 3(0.729/3.735)) = 18.075