I need help with Q11 ASAP!!!

Answer:

B. x=75

Step-by-step explanation:

First, write out the equation as you have it:

x/5=15

Then, multiply both sides of the equation by 5/1:

5/1(x/5)=15(5/1)

Your result is:

x=75

Answer:-75 on a pex quiz 1.4.3

Step-by-step explanat

Answer:

a) 1

Step-by-step explanation:

3(x + 1) = -2(x - 1) +6

3x + 3 = -2x  + 2 + 6

3x + 3 = -2x + 8

Subtract 3 from both sides

3x + 3 -3 = -2x + 8 -3

          3x = - 2x + 5

Add 2x to both sides

3x + 2x  = -2x + 5 +2x

        5x =  5

Divide both sides by 5

 5x/5 = 5/5

x = 1

Answer:

[tex]\frac{5}{7}:\quad 0.71428\\\\= 0.71\\\\\frac{0.71}{1}\times \frac{100}{100}\\ \\= 71/100\\\\= 71\%[/tex]

Step-by-step explanation:

The fraction 5/7 is equal to 0.7 or 70%.

To convert 5/7 to a decimal,

divide the numerator (5) by the denominator (7):

So, 5 ÷ 7 = 0.71428571...

Rounded to the nearest tenth, the decimal equivalent of 5/7 is 0.7.

Now, to convert 0.7 to a percent, we multiply it by 100:

0.7 x 100

= 70%

Therefore, when rounded to the nearest tenth, 5/7 is equal to 0.7 or 70%.

Learn more about Percentage here:

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Answer:

The answer is in the pictures

Answer:

Equation :

[tex]\begin{bmatrix}x_1\\ x_2\end{bmatrix}=\begin{bmatrix}\0.5}&-3\\ 0&1\end{bmatrix}}\begin{bmatrix}2\\ -3\end{bmatrix}[/tex]

Step-by-step explanation:

To isolate the following matrix, we will have to divide either by matrix 1, or the co - efficient of the matrix shown below. By doing so we will have to take the inverse of the co - efficient of that same matrix on the other side. In other words,

[tex]\begin{bmatrix}x_1\\ x_2\end{bmatrix}[/tex] - Matrix which we have to isolate,

[tex]\begin{bmatrix}x_1\\ x_2\end{bmatrix}=\begin{bmatrix}2&6\\ \:0&1\end{bmatrix}^{-1}\begin{bmatrix}2\\ -3\end{bmatrix}[/tex] - Equation used to solve the matrix

Now as you can see this equation is not any of the given options. That is as we have to simplify it a bit further,

[tex]\begin{bmatrix}2&6\\ 0&1\end{bmatrix}^{-1} = \frac{1}{\det \begin{bmatrix}2&6\\ 0&1\end{bmatrix}}\begin{bmatrix}1&-6\\ -0&2\end{bmatrix} = \frac{1}{2}\begin{bmatrix}1&-6\\ -0&2\end{bmatrix} = \begin{bmatrix}\frac{1}{2}&-3\\ 0&1\end{bmatrix}[/tex]

We know that 1 / 2 can be replaced with 0.5, giving us the following equation to solve for x1 and x2,

[tex]\begin{bmatrix}x_1\\ x_2\end{bmatrix}=\begin{bmatrix}\0.5}&-3\\ 0&1\end{bmatrix}}\begin{bmatrix}2\\ -3\end{bmatrix}[/tex]

As you can see our solution is option d.

Answer: d

Step-by-step explanation: on edge

Answer:4.5 ft squared

Step-by-step explanation:

3*1.5/2=4.5

explanation:

Answer:

my name is yeff

Step-by-step explanation:

Answer:

1/2048 or 4.8828125*10^(-4)

Step-by-step explanation:

First, figure out the thickness of 1 sheet of paper in number format:

[(8*10)]^(-3)=(80)^(-3) or (1/(80)^(3))=1/512000

Now, multiply 1/512000 by 250 to find the thickness of 250 sheets of paper:

250(1/512000)=1/2048

In scientific notation, this is written as 4.8828125*10^(-4).

Answer:

0

Step-by-step explanation:

Group like terms= 3r-3r-50+50

Add similar elements= -50+50

Answer=0

I hope this helps!

Answer:

130°

Step-by-step explanation:

Angle ABC = 180°-50° [°.° Supplementary angles]

= 130°

Answer:

a = 97, b = - 56

Step-by-step explanation:

Given

[tex]\frac{7-4\sqrt{3} }{7+4\sqrt{3} }[/tex]

To rationalise multiply numerator/ denominator by the conjugate of the denominator.

The conjugate of 7 + 4[tex]\sqrt{3}[/tex] is 7 - 4[tex]\sqrt{3}[/tex]

= [tex]\frac{(7-4\sqrt{3})(7-4\sqrt{3}) }{(7+4\sqrt{3})(7-4\sqrt{3}) }[/tex] ← expand numerator/ denominator using FOIL

= [tex]\frac{49-28\sqrt{3}-28\sqrt{3}-48 }{49-48}[/tex]

= [tex]\frac{97-56\sqrt{3} }{1}[/tex]

= 97 - 56[tex]\sqrt{3}[/tex]

with a = 97 and b = - 56

Answer:

a = 97, b = - 56

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

Answer:

  A.  True

Step-by-step explanation:

The graph passes the horizontal line test, so the inverse relation is a function.

__

The horizontal line test requires any horizontal line intersect the graph in at most one place.

Answer:

[tex]2500 {kgm}^{3} [/tex]

Step-by-step explanation:

Density =

[tex] density = \frac{mass}{volume} [/tex]

Volume =lbh

Volume= 5x2x7.5

= 75cm^3

[tex]density( {gcm}^{3} ) = \frac{187.5}{75} \\ = 2.5 {gcm}^{3} \\ to \: change \: from \: {gcm}^{3} to \: {kgm}^{3} \\ multiply \: by \: 1000 \\ 2.5 \times 1000 \\ = 2500 {kgm}^{3} [/tex]

Answer:

The other guy got it

Step-by-step explanation

Answer:

[tex]\huge \boxed{\mathrm{36\sqrt{3} +72 \ mm^2}}[/tex]

Step-by-step explanation:

The height of the triangle is important to find the area of the rectangle.

We can split the triangle in half, we get a right triangle.

Apply Pythagorean theorem to solve for the height.

3² + b² = 6²

b² = 6² - 3²

b² = 36 - 9

b² = 27

[tex]b= 3\sqrt{3}[/tex]

The length of the rectangle is 3 + 3 + 3 + 3  =  12 mm

The width is 3 + [tex]3\sqrt{3}[/tex] + 3  = [tex]3\sqrt{3}+6[/tex] mm

The area of a rectangle is length × width.

[tex]12(3\sqrt{3}+6)[/tex]

Distribute.

[tex]36\sqrt{3} +72[/tex]

The area of the rectangle is [tex]36\sqrt{3} +72[/tex] mm².

Answer:

Its the second option.

Step-by-step explanation:

The domain and range are just the x (domain) and y (range) values

Answer:

[tex]width=12[/tex]

Step-by-step explanation:

The formula for the area of a rectangle:

[tex]Area=length*width[/tex]

Insert the known values:

[tex]180=15w[/tex]

Solve for w. Isolate the variable by dividing both sides by 15:

[tex]\frac{180}{15}=\frac{15w}{15} \\\\12=w[/tex]

w is equal to 12, so the width of the rectangle is 12 cm.

:Done

Step-by-step explanation:

5x-4=-3-x

5x+x=4+(-3)

6x=1

x=1/6

Answer:

Step-by-step explanation:

[tex] \sf{5x - 4 = - 3 - x}[/tex]

Move constant to R.H.S and change it's sign

Similarly, Move variable to L.H.S and change it's sign

⇒[tex] \sf{5x + x = - 3 + 4}[/tex]

Collect like terms

⇒[tex] \sf{6x = - 3 + 4}[/tex]

Calculate

⇒[tex] \sf{6x = 1}[/tex]

Divide both sides of the equation by 6

⇒[tex] \sf{ \frac{6x}{6} = \frac{1}{6} }[/tex]

Calculate

⇒[tex] \sf{x = 0.16}[/tex]

Hope I helped!

Best regards!!

Hey there! :)

Answer:

[tex]\huge\boxed{n = 25}[/tex]

-1/5n + 7 = 2

Start by subtracting 7 from both sides:

-1/5n + 7 - (7) = 2 - (7)

-1/5n = -5

Multiply both sides by the reciprocal of -1/5, or -5.

(-5) · (-1/5n) = (-5) · (-5)

n = 25

Answer:

1/3

Step-by-step explanation:

that does make sense

Answer:

1) The distance between the ends of the arch is approximately 98.6

2) The eight of the arc is approximately 12.3

Step-by-step explanation:

1) The function for the height of the arch, h(x) = -0.005061·x² + 0.499015·x

Where;

x = The distance from the ends of the arch = 0, which gives;

0 = -0.005061·x² + 0.499015·x

Factorizing the above equation, we get;

0 = x·(-0.005061·x + 0.499015)

Which gives;

x = 0 or (-0.005061·x + 0.499015) = 0

-0.005061·x + 0.499015 = 0 gives;

-0.005061·x = -0.499015

x = -0.499015/(-0.005061) ≈ 98.6

Therefore, the height of the arch is zero at distance x = 0 and x = 98.6

Which gives the distance between the ends of the arch = 98.6

2) The height of the arc function h(x) = -0.005061·x² + 0.499015·x, whereby the coefficient of x² is negative, shows that it is ∩-shaped, the coordinates height and therefore, the height, is given by equating the derivative of the function to zero as follows;

d(h(x))/dt = d(-0.005061·x² + 0.499015·x)/dt = 2×(-0.005061)×x + 0.499015

d(h(x))/dt = 0 gives;

2×(-0.005061)×x + 0.499015 = 0

x = -0.499015/(2×(-0.005061)) ≈ 49.3

Therefore, the height of the arc, is the height at the point where x = 49.3

Therefore, we find the height of the arc from the height equation as follows;

h(x) = -0.005061×(49.3)² + 0.499015×49.3 ≈ 12.3

The eight of the arc is approximately 12.3.

[tex] \Large{ \boxed{ \mathbb{ \pink{SOLUTION:}}}}[/tex]

The AP would be like:

Now,

➝ First term = 1

➝ Common difference = 2

➝ No. of terms = 50

By using formula,

[tex] \large{ \boxed{ \rm{S_n = \frac{n}{2} \bigg(2a + (n - 1)d \bigg)}}} [/tex]

Here,

Proceeding further,

➝ S50 = 50/2{ 2 × 1 + (50 - 1)2 }

➝ S50 = 25{ 2 + 49 × 2 }

➝ S50 = 25{ 100 }

➝ S50 = 2500

⛈️ Sum of 50 terms of AP = 2500

Shortcut trick:- n^2

Then, Sum of 50(n) terms = 50^2 = 2500

☘️ Hence, solved !!

━━━━━━━━━━━━━━━━━━━━

Answer:

2500

Step-by-step explanation:

The Sum of First 50 Odd Natural Numbers:

1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49+51+53+55+57+59+61+63+65+67+69+71+73+75+77+79+81+83+85+87+89+91+93+95+97+99

= 2500

Answer:

0.3

Step-by-step explanation:

Answer:

[tex]\huge\boxed{b=-8}[/tex]

Step-by-step explanation:

[tex]4b+8=3b\\\\4b+8-8=3b-8\\\\4b=3b-8\\\\4b-3b=3b-3b-8\\\\\boxed{b=-8}[/tex]

Answer:

b = -8

Step-by-step explanation:

4b+8=3b

Subtract 4b from each side

4b-4b+8=3b-4b

8 = -b

Multiply each side by -1

-8 = b

Answer:

The distance between these points is approximately is 9.198 units.

Step-by-step explanation:

Let be (5.5, 2.9) and (-3.5, 4.8) the location of the points in Cartesian plane. The straight line distance between both points ([tex]d[/tex]) is determined by the Pythagorean Theorem, which is described below:

[tex]d = \sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}}[/tex]

Where:

[tex]x_{A}[/tex], [tex]x_{B}[/tex] - Horizontal components of each point, dimensionless.

[tex]y_{A}[/tex], [tex]y_{B}[/tex] - Vertical components of each point, dimensionless.

If [tex]A = (5.5, 2.9)[/tex] and [tex]B = (-3.5,4.8)[/tex], the distance between these points is:

[tex]d = \sqrt{(-3.5-5.5)^{2}+(4.8-2.9)^{2}}[/tex]

[tex]d\approx 9.198[/tex]

The distance between these points is approximately is 9.198 units.

Consider first two digits and then the next two digits.If there are three digits in the given number then first consider the first digit and then the take two digits together

6 | 4489 | 6x

36

12x | 889 |

Now the number 889 has 9 in units place so take a share number which has 9 at the end (ex.3*3=9 and 7*7=49)

So put 7 in the place of x and multiply the x value with 12x(that is 127) u will get the remainder as 0

Therefore the square root of 4489 is 6x*6x i.e. 67*67=4489

Answer:

Find the attached file for the solution

Step-by-step explanation: To draw the multiplication table on the P=(3,5,7,9) in module 12, create the table where all the given parameters will be at the top of horizontal axis and vertical axis,

When multiply by each other, any value that is below 12 will be written down while the value greater than 12 will be divided by 12 and the remainder will be written down.

Find the attached file for the solution and table.

Answer:

Your answer will be 1.35

Answer:

D. 360 cubic cm.

Step-by-step explanation:

The volume = l * w * h

= 12 * 6 * 5

360 cu cm.

The  volume of the rectangular prism is  360 cubic cm

A rectangular prism is a three-dimensional shape. It also known as a cuboid.

Characteristics of a rectangular prism

Volume = length x width x height

12 x 6 x 5 =  360 cubic cm

A similar question was solved here: https://brainly.com/question/12449923?referrer=searchResults

Answer:

-2a + 3

Step-by-step explanation:

We can substitute a + 7 for x:

f(a + 7) = 17 - 2(a+7) = 17 - 2a - 14 = -2a + 3

Answer:

Cost of the pen = Rs.100

Step-by-step explanation:

Let the marked price = x

When the shopkeeper is selling for x, his gain = Rs. 20

Cost price = Marked price  - Gain = x - 20 --------(I)

After discount:

Discount = 10%

Marked price after discount = (100 - 10)% of x = 90% of x

                                               = 0.9 * x = 0.9x

When the shopkeeper is selling for 0.9x, his gain = Rs.8

Cost price = Marked price - gain = 0.9x - 8   -------(II)

From (I) and (II)

x - 20 = 0.9x - 8

x   = 0.9x - 8 + 20

x = 0.9x + 12

x - 0.9x = 12

0.1x = 12

x = 12/0.1

x = 120

Marked price of pen = Rs.120

Cost price = 120 - 20

Cost price  = Rs. 100

Answer:

654000 Rupees

Step-by-step explanation:

If we assume that the opera house was full every day then it would be 872 x 50 for the price of 1 day

872 x 50 = 43600

We multiple that number by the amount of days open so is would be 43600 x 15

43600 x 15 = 654000

Therefore it will make 654000 Rupees

Answer:

x = 10

Step-by-step explanation:

Step 1: Write out equation

16 = 9 + x - 3

Step 2: Combine like terms

16 = x + 6

Step 3: Subtract 6 on both sides

10 = x

Step 4: Rewrite

x = 10

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{x = 10}}}}}[/tex]

Step-by-step explanation:

[tex] \sf{16 = 9 + x - 3}[/tex]

Subtract 3 from

⇒[tex] \sf{16 = 6 + x}[/tex]

Swap the sides of the equation

⇒[tex] \sf{6 + x = 16}[/tex]

Move 6 to right hand side and change it's sign

⇒[tex] \sf{x = 16 - 6}[/tex]

Subtract 6 from 16

⇒[tex] \sf{x = 10}[/tex]

Hope I helped!

Best regards!!