I need help in this (￣▽￣)

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Explanation:

The overall plank is 33 inches long. Subtract 2 copies of 2 inches off to represent those left and right 2 inches of space at each end.

33 - 2*2 = 33 - 4 = 29

So we have 29 inches to work with.

There are 4 plaques to hang up, and each is 5 inches wide. So that accounts for 4*5 = 20 inches of space just for the plaques themselves. We have 29-20 = 9 inches left for the gaps between plaques.

Since we have 4 plaques, there are 4-1 = 3 gaps between the adjacent plaques. The gap width is 9/3 = 3 inches.

See the diagram below. The values in black are the widths of each championship (5 inches each). The values in red are the gaps either between the plaques or between the plaque and the edge of the plank.

As a check, the values in that diagram should add to 33.

2+5+3+5+3+5+3+5+2 = 33

So the answer is confirmed.

Answer:

-2d + 2e - 2

Step-by-step explanation:

Combine like terms. Like terms are terms with the same variable as well as same amount of said variables. Set the expression:

4d - 6d + 6e - 4e + 4 - 6

(4d - 6d) = -2d

(6e - 4e) = 2e

(4 - 6) = -2

-2d + 2e - 2 is your answer.

~

Answer:

348468

Step-by-step explanation:

Answer:

348,468

Step-by-step explanation:

Hope it's help you !!!!:)

Answer:

He can put 7 cars together in 245,157 ways.

Step-by-step explanation:

The order in which the cars are put together is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

23 distinct train cars. How many ways can he put 7 cars together?

Combinations of 7 from a set of 23. So

[tex]C_{23,7} = \frac{23!}{7!(23-7)!} = \frac{23!}{7!16!} = 245157[/tex]

He can put 7 cars together in 245,157 ways.

Answer:

[tex]\frac{1}{243}\\[/tex]

Step-by-step explanation:

The expression of three power of five rational number with a negative exponent is;

Answer:

perimeter=a+b+c+d+e+f+g+h+I

x+13+3x+2+x+5+2+8+3x

CLT

x+x+3x+3x+13+2+5+2+8

8x+30

The function g(x) = x²/3

Given that graph of the function f(x) = x²,

Since, the graph of f(x) is transformed to form the g(x).

We see that g(x) is passing by (3, 3)

Here, the scale factor is 1/3,

So, we can say that the equation of the function g(x) is g(x) = x²/3

Therefore, the required function is g(x) = x²/3

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Answer:

the height of the triangle is 25

Answer:

height = 25 m

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the height )

Here A = 250 and b = 20 , then

[tex]\frac{1}{2}[/tex] × 20 × h = 250 , that is

10h = 250 ( divide both sides by 10 )

h = 25 m

Answer:

For a general quadratic equation like:

y = a*x^2 + b*x + c

a is the leading coefficient.

And we define the vertex of this as (h, k)

Where h is:

h = -b/(2*a)

and k is the y-value given when we use x = h.

Now, in this case we have:

f(x) = 5*x^2

We can see that the leading coefficient is 5, then a = 5.

To find the value of h we use:

h = -b/(2*a)

there is no lineal term, thus b = 0, then:

h = -0/(2*5) = -0/10 = 0

and k is given by

f(h) = f(0) = 5*0^2 = 0

then k = 0.

Concluding:

a = 5

h = 0

k = 0

Answer:

6 ^ 6

Step-by-step explanation:

hope this helps!

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: C. \:{6}^{5} }}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] {6}^{2} \times {6}^{3} [/tex]

➺[tex] \: {6}^{2 + 3} [/tex]

➺[tex] \: {6}^{5} [/tex]

[tex] {a}^{m} \times {a}^{n} = {a}^{m + n} [/tex]

[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♬}}}}}[/tex]

Answer:

82.9+38.6=121.5 miles far away.

7889 grams of jam

Step-by-step explanation:

In 5544 grams of jam, 1757 grams of sugar ==> 31.69%

let x be the grams of jam

2500 grams of sugar ==> 31.69%

x grams of jam ==> 100%

[tex]x \times 31.69\% = 2500 \\ x = 2500 \div 31.69\% \\ x = 7888.92 \: grams \\ x = 7889 \: grams \: (nearest \: whole \: number)[/tex]

Answer:

Step-by-step explanation:

x +(x+1500) = 9400

2x + 1500 = 9400

2x = 7900

x=3950 (men)

y = 5450 (woman)

5450 :3950

109:79

Answer: [tex]\$30,360[/tex]

Step-by-step explanation:

Given

Jed makes [tex]\$34,500[/tex] per year

After the loss of contract, a paycut of 12% is there

The amount after the paycut is

[tex]\Rightarrow 34,500(1-0.12)\\\Rightarrow 34,500\times 0.88\\\Rightarrow \$30,360[/tex]

Answer:

C

Step-by-step explanation:

i took the test

Answer:

D. y = -3/7 + 2

Step-by-step explanation:

Slope intercept form: y = mx + b

m = slope

b = intercept

Answer:

y - 4 = (9/4)(x - 4)

Step-by-step explanation:

Here we're given the slope (9/4) of a line and one point (4, 4) on the line.  The easiest form of the equation of a straight line to use here is the point-slope form:

y - k = m(x - h).

Here h = 4 and k = 4; the slope is m = 9/4.

Thus, the desired equation is

y - 4 = (9/4)(x - 4)

Answer:

2x(16)+16(16)

32x+256

32x/32=256/32

x=8

JL = x+16

JK+KL = x+16

2x+16+7 = x+16

2x+23 = x+16

2x-x = 16-23

x = 7

Answer:

19.42 ft.

Step-by-step explanation:

The diameter of the semicircle is 6, so 3.14 x 6 = 18.84. Since it is a semicircle, we divide that by 2 to get 9.42.

The hypotenuse of the right triangles only matter for the perimeter. 5 + 5 = 10, and 9.42 + 10 = 19.42 ft.

The outer perimeter is 19.42 ft.

Perimeter is the distance around the edge of a shape.

Given:

radius= 3 ft

height= 4 ft

slant height= 5 ft

diameter of the semicircle is 6 feet.

So,

= 3.14 x 6 = 18.84.

Since it is a semicircle,

=18.84/2

=9.42 feet

Now, the perimeter.

= 5 + 5 +9.42

= 19.42 ft.

Hence, the perimeter is 19.42 feet.

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Answer:

y=-2x+3

Step-by-step explanation:

for one, you can see that the y-intercept is at 3, so for y=m*x+b, b is 3

next, you can count to get the slope. it moves 2 units down and one unit to the left, so for slope, which is rise over run, you are -2/1= -2

so y = -2x + 3

Answer:

∡ c = 118°

Step-by-step explanation:

angle c is 118 degree (being vertically opposite angle)

∡ c = 118°

Answer:

118

Step-by-step explanation:

there is a property that i can't remember the name of that is dealing with angles across a flat line.

another way, is that 118+D=180, so D is 62

so that means D + C = 180, where D is 62 so C must be 118

Answer:

f(g(4)) = 213

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 8x + 5

g(x) = 7x - 2

Step 2: Find f(g(4))

[tex]\huge \qquad \boxed{\underline{\underbrace{\mathcal\color{gold}{Answer}}}}[/tex]

Here,

f(x) = 8x + 5 and g(x) = 7x - 2,

we have to find the f(g(4))

1st we have to solve the g(x)

Now substitute the functional value,

.°. The value of f(g(4)) is 213.

Answer:

The point you are rotating at (also called the centre of rotation)

The angle of rotation (usually in degrees but I don't know your school)

Direction of the turn

Step-by-step explanation:

Answer:

338

Step-by-step explanation:

X - 115  = 223

Add 115 to both the sides

X - 115 + 115 = 223 + 115

x = 338

Answer:

338

Step-by-step explanation:

x - 115 =223

Collect terms

x = 223 + 115

x = 338

Hope this helps you!

pls mark as brainlest ans

Bye!

Answer:

[tex]x=\frac{125}{6},\\y=11[/tex]

Step-by-step explanation:

The angles marked [tex]7x-15[/tex] and [tex]5x-5y[/tex] are co-interior angles. Since all co-interior angles are supplementary (add up to 180 degrees), we have the following equation:

[tex]7x-15+5x-5y=180[/tex]

The two angles marked [tex]4x+4y[/tex] and [tex]2x+y[/tex] are also co-interior angles, thus must also add to 180 degrees.

Therefore, we have the following system of equations:

[tex]\begin{cases}7x-15+5x-5y=180,\\4x+4y+2x+y=180\end{cases}[/tex]

Combine like terms:

[tex]\begin{cases}12x-5y-15=180,\\6x+5y=180\end{cases}[/tex]

Divide the first equation by -2 and add both equations to get rid of [tex]x[/tex]:

[tex]\begin{cases}-6x+2.5y=-97.5,\\6x+5y=180\end{cases},\\-6x+6x+2.5y+5y=82.5,\\7.5=82.5,\\y=\boxed{11}[/tex]

Now substitute [tex]y=11[/tex] into any equation with [tex]x[/tex]:

[tex]6x+5y=180,\\6x+5(11)=180,\\6x+55=180,\\6x=125,\\x=\boxed{\frac{125}{6}}[/tex]

Verify that these two solutions work:

[tex](7(\frac{125}{6})-15)+(5(\frac{125}{6})-5(11))=180\:\checkmark,\\\\(4(\frac{125}{6})+4(11))+(2(\frac{125}{6})+11)=180\:\checkmark[/tex]

Answer:

the answer is the intersection is a line