I need help fast Estimate 81/4

Answer:

16

Step-by-step explanation:

8x2

Answer:

[tex]2[/tex][tex]z^{3}[/tex][tex]\sqrt{14z}[/tex]

Step-by-step explanation:

The simplified form of  √56z⁷  is 2z³√(14z⁴ ) in the given question.

To simplify √56z⁷, we can break down the number 56 into its prime factors and remove any perfect square factors from inside the square root.

When simplifying a square root expression, removing perfect square factors from inside the square root helps simplify the expression further. This is because the square root of a perfect square is a whole number.

First, let's factorize 56:

56 = 2 * 2 * 2 * 7

Since 2 is a perfect square, we can remove it from inside the square root:

√56z⁷  = √(2 * 2 * 2 * 7 * z⁷ )

Simplifying further:

√56z⁷ = 2z³√(2 * 7 * z)

Therefore, the simplified form of √56z⁷  is 2z³ √(14z⁴ ).

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Answer:

sphere

Step-by-step explanation:

sphere has a larger volume

Answer:

...... .................

Answer:

f(x) = a(x - 1) + 20

Step-by-step explanation:

Vertex form is written in this format: f(x) = a(x - h) + k. The vertex point is written in the form (h,k). To write the vertex in the equation, fill in the digits where they belong.

Hope it helps!

The ball's parabolic route is represented by the quadratic function's graph. The quadratic function is x²-2x+4=0.

Given that,

A thrown ball's height is a quadratic function of the amount of time it has been in the air. The ball's parabolic route is represented by the quadratic function's graph. The ball's route includes the location (1, 20), which is the graph's vertex (0,4).

We have to find what does the expression for this function look like? In vertex form, write the quadratic function.

Use y= a(x-h)² + k as the vertex form of a parabola.

(The parabola opens upward if "a" is positive and downward if "a" is negative.) Additionally, the vertex of the (h,k) is a parabola.

The vertex of the parabola (h,k) is (1,20)

The a value is 4 and y as 0.

y=a(x-h)²+k

0=4(x-1)²+20

0=4(x²-2x+1)+20

0=4x²-8x-4+20

0=4x²-8x+16

4x²-8x+16=0

x²-2x+4=0

Therefore, the quadratic function is x²-2x+4=0.

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Answer:

b

Step-by-step explanation:

Answer: 3

Step-by-step explanation: The number in front of your variable is called your coefficient so we say that 3 is the coeficient.

Make sure to understand that a variable

is just a letter that represents any number.

Answer:

Hey mate.....

Step-by-step explanation:

This is ur answer....

Hope it helps!

Mark me brainliest pls....

Follow me! ;)

Answer:

9.364 is the expected number of points.

we can approximate this to 10 points if we want a whole number

Step-by-step explanation:

We have these variables:

[0,5,10,15]

P(x= 0) = p(y>20)+p(y<-20) = 2p(y>20)

P(x=5) = p(-20<=y<=10)+p(10<=y<=20) = 2p(10<=y<=20)

P(x=10) = p(-10<=y<=-3)+p(3<=y<=10) = 2p(3<=y<=10)

P(x=15) = p(-3<=y<=3) = 2p(0<=y<=3)

Z = y/10

Therefore

P(x= 0) = 2(y>20)

= 2p(z>2) = 2(1-p<=2)

= 2(1-0.9772)

= 0.0456

P(x= 5)

= 2p(10<=y<=20)

= 2p(1<=z<=2)

= 2(0.9772-0.8413)

= 0.2718

P(x= 10)

= 2p(3<=y<=10)

= 2p(0.3<=z<=1)

= 2(0.8413-0.6179)

= 0.4468

P(x = 15)

= P(0.6179-0.3821)

= 0.2358

To get expected value of Y

0(0.0456)+5(0.2718)+10(0.4468)+15(0.2358)

= 1.359 + 4.468 + 3.537

= 9.364

E[Y] = 9.364

Answer:

d≈21.99

Step-by-step explanation:

Answer:

Me encanta el pollo, de todos modos, un día que es hoy, por cierto, fui a la tierra de los pollos y caminé en México, ¿sabías que es mi sueño? ¿Olvidé que mi nombre es jemma y me gusta caminar? párrafo así que nos vemos

Answer:

26 square feet

Step-by-step explanation:

I dont know if this is right

Answer:

C, 33 1/3%

Step-by-step explanation:

Because there are only two even number that follow this rule: 2<x≥6, and since there are only 6 possible outcomes, the probabilty is 2/6, which is 1/3. In a percent form, this is 100%*2/3, or 33 1/3%.

Answer: Hello the statement related to your question is missing attached below is the statement

answer : The statement is false

Step-by-step explanation:

The statement is false

This is because a confidence interval gives a range of values for an unknown parameter.

A 95% confidence interval is calculated and it gives a lower and upper limit in which the 58% of the voters can fall into i.e. The 58% of voters can fall within the upper and lower limit of the 95% confidence interval and not exactly 95% . Hence the statement is false.

Answer:

2/12 or 1/6

Step-by-step explanation:

12 games total

they have 2 games that are there favorite

Answer:

Step-by-step explanation:

i think that the equations might be y = x - 7

Answer:

x = 16

Step-by-step explanation:

[tex] \frac{2x - 5}{x + 8} = \frac{22.5}{20} [/tex]

Cross multiply

[tex] (2x - 5)*20 = (x + 8)*22.5 [/tex]

[tex] 40x - 100 = 22.5x + 180 [/tex]

Collect like terms

40x - 22.5x = 100 + 180

17.5x = 280

Divide both sides by 17.5

x = 280/17.5

x = 16

Answer:

The appropriate solution is "1.7109". A further explanation is provided below.

Step-by-step explanation:

The given values are:

Sample size,

n = 25

Degree of freedom,

[tex]df=n-1[/tex]

   [tex]=25-1[/tex]

   [tex]=24[/tex]

At 90% confidence level,

[tex]\alpha=1-90 \ percent[/tex]

  [tex]=1-0.9[/tex]

  [tex]=0.1[/tex]

and,

[tex]\frac{\alpha}{2}=\frac{0.1}{2}[/tex]

  [tex]=0.05[/tex]

Now,

The correct values of t will be:

=  [tex]t_{\frac{\alpha}{2}, df }[/tex]

=  [tex]t_{0.05,24}[/tex]

=  [tex]1.7109[/tex]

Answer:

x = -7

Step-by-step explanation:

4x - 2 = 3(x - 3)

use the distributive property

4x - 2 = 3x - 9

    +9         +9

4x + 7 = 3x

-4x        -4x

7 = -1x

x = -7

Hope I helped! Have a nice day! Plz mark as brainliest!!! :D

-XxDeathshotxX

5,0 is not a solution to the system of linear inequalities.

Answer:

21

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Answer:

1/10 = 4  

Step-by-step explanation:

Answer:

Ur answer is in attachment

Step-by-step explanation:

please mark me as brainliest

The probability that a student has both box and a console is 1/6 and the P(B/A) = 0.378

Probability is a measure of the likelihood of an event occurring. The probability formula is defined as the possibility of an event happening being equal to the ratio of the number of favorable outcomes and the total number of outcomes. Probability of event to happen P(E) = Number of favorable outcomes/Total Number of outcomes.

Given here, the number of students with both video games is 30 thus

The probability that a student has both box and a console is 30/180=1/6

And the conditional probability P(B/A) is = 1/6/0.44

                                                                    = 0.378

Hence, The probability that a student has both box and a console is 1/6, and the P(B/A) = 0.378

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Answer:

14

Step-by-step explanation:

[tex]x + 2 = 16 \\ x = 16 - 2 \\ x = 14[/tex]

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Answer:

16 = 2 + 14

Step-by-step explanation:

Sum means to add to numbers, so we are finding x + 2 = 16.

x + 2 - 2 = 16 - 2

x = 14

Answer:

48

Step-by-step explanation:

Cat = x

Dog = 8x

x + 8x = 54

9x = 54

x = 6, Dog = 8 * 6 = 48

Answer:

98%

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]T_j \sim exp ( \lambda j) \ \ \ j = 1 (1) n \\ \\ f_{Tj}(tj) = \lambda j e^{-\lambda j tj } , tj>0 \\ \\ P\Big[ Tj> x\Big] = \int \limits ^{\infty}_{x} \lambda j e^{-\lambda j tj}\ dtj \\ \\ = e^{-\lambda j x}, x > 0 \\ \\ \\ \\ a) F_x (x) \\ \\ = P[X \le x ] \\ \\ = 1 - P[X> x] \\ \\ = 1 - \pi \limits ^{n}_{j =1} \Big\{ P[T_j > x ] \Big \}[/tex]

[tex]\text{This is because the appliance has the capacity to work for more than (x) }[/tex][tex]\text{hours if and only if all the "n" components work more than (x) hours.}[/tex]

[tex]\text{Then:}[/tex]

[tex]= 1 - e \ \pi^{n}_{j=1} \ e^{-\lambda j x} \\ \\ = 1 - e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}[/tex]

∴

[tex]CDF = 1 - e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}\ , \ x>0[/tex]

[tex]PDF =\Big( \sum \limits ^{n}_{j =1} \lambda j\Big) e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}\ , \ x>0[/tex]

[tex]f_x(x) = \Big( \sum \limits ^{n}_{j =1} \lambda j\Big) e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}\ , \ x>0[/tex]

(b)

[tex]E(x) = \int \limits ^{\infty}_{o }x f_x (x) \ dx \\ \\ = \int \limits ^{\infty}_{o }x \ \Big( \sum \limits ^{n}_{j =1} \lambda j\Big) e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}\ , \ dx[/tex]

[tex]= \dfrac{1}{\sum \limits ^n_{j=1} \lambda j} \ \ \int \limits ^{\infty}_{o} \Big [(\sum \limits ^n_{j=1} \lambda j )x \Big] e ^{-\Big ( \sum \limits ^{n}_{j=1} \lambda j \Big)x} \ \ d \Big( x \sum \limits ^n_{j=1} \lambda j \Big)[/tex]

[tex]= \dfrac{1}{\sum \limits ^n_{j= 1} \lambda j} \int \llimits ^{\infty}_{o} t e^{-t} \ dt[/tex]

[tex]= \dfrac{1}{\sum \limits ^n_{j= 1} \lambda j} \int \llimits ^{\infty}_{o} t e^{-t} \ dt \ \ \ \ \text{\Big[By transformation }t =( \sum \limits ^n_{j=1} \lambda j )x \Big][/tex]

[tex]= \dfrac{1}{\sum \limits ^n_{j= 1} \lambda j}[/tex]

(c)

[tex]Let \ \ l_y_{\dfrac{1}{2}} \text{ be the median}[/tex]

∴

[tex]F(l_y_{\dfrac{1}{2}}) = \dfrac{1}{2} \\ \\ 1 - e ^{-\Big (\sum \limits ^{n}_{j=1} \lambda j \Big)} {l_y}_{\frac{1}{2}} = \dfrac{1}{2} \\ \\ \dfrac{1}{2} = e^{-\Big (\sum \limits ^{n}_{j=1} \lambda j \Big) } {l_y}_{\frac{1}{2}} \\ \\ - In 2 = {-\Big (\sum \limits ^{n}_{j=1} \lambda j \Big)} {l_y}_{\frac{1}{2}} \\ \\ \\ \\ \mathbf{ {l_y}_{\frac{1}{2}} = \dfrac{ In \ 2}{\sum \limits ^{n}_{j=1} \lambda j }}[/tex]