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147.05 g/mol

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

CuClO₃

Step 2: Find MM

Molar Mass of Cu - 63.55 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CuClO₃ - 63.55 + 35.45 + 3(16.00) = 147.05 g/mol

Answer:

Mass = 63.19 g

Explanation:

Given data:

Number of moles = 0.89 mol

Mass of Cl₂ = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of Cl₂ = 71 g/mol

by putting values,

0.89 mol = mass/ 71 g/mol

Mass = 0.89 mol × 71 g/mol

Mass = 63.19 g

Answer:

NARUTOOOO

Explanation:

The molecular formula =C₆H₁₂O₆

Given

6.00 g of a certain compound X

The molecular molar mass of 180. g/mol

CO₂=8.8 g

H₂O=3.6 g

Required

The molecular formula

Solution

mass C in CO₂ :

= 1.12/44 x 8.8

= 2.4 g

mass H in H₂O :

= 2.1/18 x 3.6

= 0.4 g

Mass O in compound :

= 6-(2.4+0.4)

= 3.2 g

Mol ratio C : H : O

= 2.4/12 : 0.4/1 : 3.2/16

= 0.2 : 0.4 : 0.2

= 1 : 2 : 1

The empirical formula : CH₂O

(CH₂O)n=180 g/mol

(12+2+16)n=180

(30)n=180

n=6

(CH₂O)₆=C₆H₁₂O₆

Answer:

chlorine

Explanation:

hope this helps

5.40 mol N₂O₅

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

3.25 × 10²⁴ molecules N₂O₅

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

5.39688 mol N₂O₅ ≈ 5.40 mol N₂O₅

Answer:

whats zinc?

Explanation:

Answer:

I' really don't know I'm sorry

The locations with subatomic particles with the least mass are locations 1 and 4.

An atom is usually divided into two main regions:

The three sub-particles previously mentioned (neutrons, protons, and electrons) differ not only in their location but also in their mass. Indeed, electrons have a lower mass if compared to neutrons and protons.

Based on this, the outer region (locations 1 and 4) has sub particles with the least mass.

Learn more about atom in: https://brainly.com/question/13981855

Answer:

1 and 4

Explanation:

took the test

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Answer:

28 oc

Explanation:

Answer:

1. Partial pressure of H₂ = 2 atm

2. Partial pressure of He = 2 atm

Explanation:

The following data were obtained from the question:

Mole of H₂ = 3.50 moles

Mole of He = 3.50 moles

Total pressure (Pₜ) = 4 atm

Partial pressure of H₂ =?

Partial pressure of He =?

Next, we shall determine the mole fraction of each gas this can be obtained as follow:

Mole of H₂ = 3.50 moles

Mole of He = 3.50 moles

Total mole = Mole of H₂ + Mole of He

Total mole = 3.50 + 3.50

Total mole = 7 moles

Mole fraction of H₂ = mole of H₂ / Total mole

Mole fraction of H₂ = 3.5/7

Mole fraction of H₂ = 0.5

Mole fraction of He = mole of He / Total mole

Mole fraction of He = 3.5/7

Mole fraction of He = 0.5

1. Determination of the partial pressure of H₂.

Mole fraction of H₂ = 0.5

Total pressure (Pₜ) = 4 atm

Partial pressure of H₂ =?

Partial pressure of H₂ = Mole fraction of H₂ × Pₜ

Partial pressure of H₂ = 0.5 × 4

Partial pressure of H₂ = 2 atm

2. Determination of the partial pressure of He.

Total pressure (Pₜ) = 4 atm

Partial pressure of H₂ = 2 atm

Partial pressure of He =?

Total pressure (Pₜ) = Partial pressure of H₂ + Partial pressure of He

4 = 2 + Partial pressure of He

Collect like terms

Partial pressure of He = 4 – 2

Partial pressure of He = 2 atm

Answer:

m = 7.39 g.

Explanation:

Hello!

In this case, since the molar mass of iron (III) phosphate is 150.82 g/mol based on its molecular formula (FePO₄), we can compute the mass in grams of 0.0490 moles of this compound by setting up the following dimensional analysis:

[tex]m=0.0490mol*\frac{150.82g}{1mol} \\\\m=7.39 g[/tex]

Best regards!

Answer: d. Arrangement of grains

Explanation:

Edge:)))

Answer:

See explanation

Explanation:

The nitrate ion is a polyatomic ion. It means that the nitrate ion contains more than one atom. These atoms are one nitrogen atom and three oxygen atoms.

However, we can not fully describe the bonding in the nitrate ion using one structure. I have shown three resonance structures that describe the bonding in the nitrate ion in the image attached to this answer.

Answer:

C₃H₄O₄

Explanation:

In order to get the empirical formula of a compound, we have to follow a series of steps.

Step 1: Divide the percent by mass of each element by its atomic mass.

C: 34.6/12.01 = 2.88

H: 3.9/1.01 = 3.86

O: 61.5/16.00 = 3.84

Step 2: Divide all the numbers by the smallest one, i.e., 2.88

C: 2.88/2.88 = 1

H: 3.86/2.88 ≈ 1.34

O: 3.84/2.88 ≈ 1.33

Step 3: Multiply all the numbers by a number that makes all of them integer

C: 1 × 3 = 3

H: 1.34 × 3 = 4

O: 1.33 × 3 = 4

The empirical formula is C₃H₄O₄.

Answer: C9H16

Explanation:

molar mass C = 12.011, H = 1.008, O = 15.999, CO2 = 44.01, H2O = 18.00

9.9g CO2 = 0.225 mol, 3.55 g H2O = 0.200 mol

long way

molecules CO2 = 1.355x10^23 —> atoms of C

molecules H2O = 1.204x10^23 —> molecules H2

C:H2 = 1.355/1.204 = 1.125. —> C9H16

short way

molar massesCO2:H2O = 0.225:0.2 = 9:8

–> C9H16

verify

molar mass C9H16 =124

3.1g = 0.025 mol

oxidise C9H16 + 13O2 —> 9CO2 + 8H2O

0.025 mol + 13*0.025 mol (0.35mol) —> 9*0.025 + 8*0.025 —> 0.0.225 + 0.2

Answer:

The solution will be dilute

Explanation:

The concentration of a solution is defined as the ratio between an amount of solute (Glucose, in this case) and an amount of solvent (Water in this case).

As the student is adding some water (Solvent), the amount of solute per amount of solvent will decrease. That is, if the concentration decreases,

the solution will be dilute

Answer:

Strength of the bond

Masses of the bonded atoms.

Explanation:

The lack of such groups means that they are not endogenous in the concentrate. 1. A bond's spreading frequency relies on the frequency of the bond and the concentrations of the atoms that are bonded.

Answer:

Explanation:

The average atomic mass (sometimes called atomic weight) of an element is the weighted average mass of the atoms in a naturally occurring sample of the element. Average masses are generally expressed in unified atomic mass units (u), where 1 u is equal to exactly one-twelfth the mass of a neutral atom of carbon-12.

3.33 mol H₂O

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

60.0 g H₂O (Water)

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

Step 4: Convert

Follow sig fig rules and round. We are given 3 sig figs.

3.32963 mol H₂O ≈ 3.33 mol H₂O

Answer:

The correct answer would be - the easiest way is to wash with some polar solvent or salt solution or soap and water

Explanation:

Butyric acid is a carboxylic acid that has a putrid odor like rancid butter. If an individual touch this chemical will have the same odor on his hand and to get rid of it one should wash his hand with a polar solvent such as methanol, or salt solutions such as like NaHCO3, or soap and water that will form sodium butyrate that has no smell and easily dissolve and remove.

Thus, the easiest way is to wash with some polar solvent or salt solution or soap and water

Answer:

[tex]V_{HCl}=48.0 mL[/tex]

Explanation:

Hello!

In this case, since the reaction between calcium hydroxide and hydrochloric acid shows a 2:1 mole ratio between them:

[tex]2HCl+Ca(OH)_2\rightarrow CaCl_2+2H_2O[/tex]

We need to use the following mole ratio:

[tex]2n_{Ca(OH)_2}=n_{HCl}[/tex]

That can be written in volumes and concentrations:

[tex]2M_{Ca(OH)_2}V_{Ca(OH)_2}=M_{HCl}V_{HCl}[/tex]

Thus, we solve for the volume of HCl as it is the unknown:

[tex]V_{HCl}=\frac{2M_{Ca(OH)_2}V_{Ca(OH)_2}}{M_{HCl}}[/tex]

Therefore, we plug in to obtain:

[tex]V_{HCl}=\frac{2*0.120M*25.0mL}{0.150M} \\\\V_{HCl}=48.0 mL[/tex]

Best regards!

Answer:

10.56 g

Explanation:

C4H10(g) + 13/2O2 (g) -------> 4CO2(g) + 5H2O(l)

Number of moles of butane = 3.49g/ 58 g/mol = 0.06 moles

1 mole butane yields 4 moles of CO2

0.06 moles of butane = 0.06 × 4/1 = 0.24 moles of CO2

Number of moles of oxygen = 17.1g/32g/mol = 0.53 moles of oxygen

6.5 moles of oxygen yields 4 moles of CO2

0.53 moles of oxygen yields 0.53 × 4/6.5 =0.33 moles of CO2

Butane is the limiting reactant

Theoretical yield of CO2 = 0.24 moles × 44g/mol = 10.56 g

Answer:

SUBSTANCE

Explanation:

hope that help you thanx

Answer:

Density of the oil is lesser than that of the water

Explanation:

The density of water is given as 1.0g/cm³.

  Salad oil is found to float on water, this implies that the density of this salad oil is lesser than that of the water.

Density is the mass per unit volume of a substance.