I have no idea how to solve this, please help with the answer

Answer

925 students brought their lunch.

Explanation

First let's rewrite the equation.

You know that "of" means multiply and "is" means equal.

Okay, so let's break it down.

The question says, "At your school, 74% of students brought their lunch at the cafeteria. There are 1250 students in the school."

This means that 74% of 1250 students brought their lunch at the cafeteria.

You are trying to find how many students brought their lunch. This will be x.

So the equation would be this.

74% × 1250 = x

74% is 0.74.

0.74 × 1250 = x

0.74 × 1250 = 925

So 925 students brought their lunch.

Answer:

50

Step-by-step explanation:

20/2=10

so this means 10 bottles per day

so there is 5 days

5 x 10 = 50

:)

Answer:

The answer to the  missing spot in the ratio is the number 50.

Step-by-step explanation:

10x5= 50

hope this helps :)

Answer:

That would be 38.4.

Answer:

The coordinates of the dillated vertices are [tex]A'(x,y) = (2,2)[/tex], [tex]B'(x,y) = (4,4)[/tex], [tex]C'(x,y) = (8,2)[/tex] and [tex]D'(x,y) = (4,-2)[/tex].

Step-by-step explanation:

From Linear Algebra, we define dilation by the following equation:

[tex]P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)][/tex] (1)

Where:

[tex]O(x,y)[/tex] - Center of dilation, dimensionless.

[tex]P(x,y)[/tex] - Original point, dimensionless.

[tex]k[/tex] - Scale factor, dimensionless.

[tex]P'(x,y)[/tex] - Dilated point, dimensionless.

If we know that [tex]O(x,y) = (0, 0)[/tex], [tex]k = 2[/tex], [tex]A(x,y) = (1,1)[/tex], [tex]B(x,y) = (2,2)[/tex], [tex]C(x,y) = (4,1)[/tex] and [tex]D(x,y) = (2,-1)[/tex], then the dilated points are, respectively:

Point A

[tex]A'(x,y) = O(x,y) + k\cdot [A(x,y)-O(x,y)][/tex] (2)

[tex]A'(x,y) = (0,0) + 2\cdot [(1,1)-(0,0)][/tex]

[tex]A'(x,y) = (2,2)[/tex]

Point B

[tex]B'(x,y) = O(x,y) + k\cdot [B(x,y)-O(x,y)][/tex] (3)

[tex]B'(x,y) = (0,0) + 2\cdot [(2,2)-(0,0)][/tex]

[tex]B'(x,y) = (4,4)[/tex]

Point C

[tex]C'(x,y) = O(x,y) + k\cdot [C(x,y)-O(x,y)][/tex]

[tex]C'(x,y) = (0,0) + 2\cdot [(4,1)-(0,0)][/tex]

[tex]C'(x,y) = (8,2)[/tex]

Point D

[tex]D'(x,y) = O(x,y) + k\cdot [D(x,y)-O(x,y)][/tex]

[tex]D'(x,y) = (0,0) + 2\cdot [(2,-1)-(0,0)][/tex]

[tex]D'(x,y) = (4,-2)[/tex]

The coordinates of the dillated vertices are [tex]A'(x,y) = (2,2)[/tex], [tex]B'(x,y) = (4,4)[/tex], [tex]C'(x,y) = (8,2)[/tex] and [tex]D'(x,y) = (4,-2)[/tex].

Answer:

[tex]\dfrac{5}{6}[/tex]

Step-by-step explanation:

The problem says Two-thirds divided by StartFraction 4 Over 5 EndFraction.

Two thirds means = 2/3

It means,

[tex]x=\dfrac{2}{3}\ \text{divided by}\ \dfrac{4}{5}[/tex]

or

[tex]x=\dfrac{\dfrac{2}{3}}{\dfrac{4}{5}}\\\\=\dfrac{2}{3}\times \dfrac{5}{4}\\\\=\dfrac{5}{6}[/tex]

Hence, the required answer is [tex]\dfrac{5}{6}[/tex].

Answer:

y=5x and y=40 when x=8

Answer:

y = 5x

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 10 when x = 2

10 = 2k ( divide both sides by 2 )

5 = k

y = 5x ← equation of variation

Answer:

136

Step-by-step explanation:

20% * 680

Cheers! :)

Answer:

I think option c is the best answer but i am not surely ok

Answer:here's the correct answer for this question

Step-by-step explanation:edge2023

Answer:7th

Step-by-step explanation:

I think it's B

Not 100% sure but I think

Proof (reasons are given in brackets):

Consider [tex]\triangle ABC[/tex], [tex]\triangle EDC[/tex]:

[tex]\overline B \overline C = \overline D \overline C[/tex] (given)

[tex]\angle BCA = \angle DCE[/tex] (vertically opposite angles are equal)

[tex]\overline A \overline C = \overline E \overline C[/tex] (given)

[tex]\therefore \triangle ABC \cong \triangle EDC[/tex] (SAS)

Hope this helps :)

Answer:

We obtained the two exponential functions:

Step-by-step explanation:

As we know that the exponential function is of the form

f(x) = abˣ

Given the points

We know these points belong to the exponential function.

so substituting the values (3, 7) and (5, 63) in the function

putting (3, 7)

y = abˣ  

7 = ab³

also putting (5, 63)

y = abˣ

63 = ab⁵

Considering the 2nd equation

63 = ab⁵

as

[tex]a^b\times \:a^c=a^{b+c}[/tex]

so

63 = ab³×b²  

substituting 7 = ab³ in 63 = ab³×b²  

63 = 7 × b²

b² = 63/7

b² = 9

b = ± 3

If b = 3

plug in b = 3 in the equation 7 = ab³ to find the value 'a'

7 = ab³

7 = a(3)³

7 = a × 27

a = 7/27

so, a = 7/27 and b = 3 would give us the function

y = abˣ

[tex]y\:=\:\frac{7}{27}\left(3\right)^x[/tex]

if b = -3

plug in b = -3 in the equation 7 = ab³ to find the value 'a'

[tex]\:7\:=\:a\left(-3\right)^3[/tex]

[tex]a\left(-27\right)=7[/tex]

[tex]a=-\frac{7}{27}[/tex]

so, a = -7/27 and b = -3 would give us the function

y = abˣ

[tex]y\:=-\:\frac{7}{27}\left(-3\right)^x[/tex]

Thus, we obtained the two exponential functions:

Answer:

true

Step-by-step explanation:

Answer:

8x +11y = 37 ---------(1)

_8x±y=_7 ----------(2)

-------------------

o+10y=30

Y=3

PUT  Y IN EQ 2

8X+3=7

8X=7-3=4

X=1/2

Ans

I hope this Ans is helpful for you

Step-by-step explanation:

Answer:

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Step-by-step explanation:

Answer:

d=0

d=0.5

d=1

d=1.5

d=2

d=2.5

Answer:

The magnitude of vector is:

[tex]\left|\begin{pmatrix}5&-6\end{pmatrix}\right|=\sqrt{61}[/tex]

v = <5, -6> means the vector has x-coordinate x = 5 and y-coordinate y = -6, so the vector v = <5, -6>  is heading towards SE.

Thus, option ( j ) is correct.

i.e.  [tex]\sqrt{61},\:SE[/tex]

Step-by-step explanation:

Given the vector

v = <5, -6>

Determining the magnitude of the vector

To find a magnitude of a vector v = (a, b) we use the formula

[tex]||v||\:=\:\sqrt{a^2+b^2}[/tex]

Magnitude of the vector is basically termed as the length of the vector, which is denoted by

[tex]|\left(5,\:-6\right)|=\sqrt{\left(5\right)^2+\left(-6\right)^2}[/tex]

            [tex]=\sqrt{5^2+6^2}[/tex]

             [tex]=\sqrt{25+36}[/tex]

             [tex]=\sqrt{61}[/tex]

Thus, the magnitude of vector is:

[tex]\left|\begin{pmatrix}5&-6\end{pmatrix}\right|=\sqrt{61}[/tex]

As the vector v = <5, -6> lies in 4th quadrant.

v = <5, -6> means the vector has x-coordinate x = 5 and y-coordinate y = -6, so the vector v = <5, -6>  is heading towards SE.

Thus, option ( j ) is correct.

i.e.  [tex]\sqrt{61},\:SE[/tex]

Answer:

Objects

Step-by-step explanation:

Normally, we make use of reciprocal pronouns in cases where each of two or more subjects are acting in the same manner towards one another. For example, X is talking to Y, and Y is talking to Z.

Thus, the subjects in question must be the same objects for them to be able to relate in the same way.

Answer:objects

Step-by-step explanation:

Answer:

2(x+3)(2x-1)

Step-by-step explanation:

Answer:

she did not get at least 2100 and definitely not 85% of the worth

Step-by-step explanation:

3000*0.85=2550

3000*0.7=2100

Answer:

Gia hoped to sell it for $2,550, but wanted at least $2,100. Because it sold for $1,800, she did not get what she hoped and/or wanted.

Step-by-step explanation:

85% of $3,000 can be solved by moving the decimal two places to the left and multiplying: 85.0% becomes 0.85. So, we multiply 0.85x3,000=$2,550.

We do the same thing to figure out 70% of $3,000. Again, solving it by moving the decimal two places to the left and multiplying: 70.0% becomes 0.70. So, we multiply 0.70x3,000=$2,100.

Answer:

i think adding heat to reaction will change the rate of the reaction

Step-by-step explanation:

When the inequality uses < or >, it is a broken line.

For the point (0, 0) it means that x = 0 and y = 0.

Since (0) < (0)² + 4(0) + 5 is true, the point is part of the solution.

Yes, the point (0,0) is part of the solution of y < - x² + 4x + 5.

Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.

A graph can be defined as a pictorial representation or a diagram that represents data or values.

To determine the border line of the graph of y < - x² + 4x + 5

A broken line results from the inequality using < or >.

x and y are both equal to zero at the coordinates (0, 0).

Substitute the values of x = 0 nad y = 0 in the inequality  y < - x² + 4x + 5

So, (0) < (0)² + 4(0) + 5

Since (0) < (0)² + 4(0) + 5 is valid,

Thus, the coordinates (0, 0) are part of the solution.

Learn more about inequalities here:

brainly.com/question/20383699

#SPJ2

Answer: 1/5

Step-by-step explanation:

Answer:

I'm pretty sure the answer is 48 minutes!

Answer:

that answer is 47/20

Step-by-step explanation:

52-5=47

20-20=20

52/20-5/20=47/20

Answer:

50/20-5÷20=2.35

Step-by-step explanation:

I used a calculator i hope it helps : )

Answer:

true

Step-by-step explanation:

True is the answer

i hope this helps you

Please mark me as brainliest

Thanks!!

minimum value: 1

lower quartile: 3

median of the data: 6

upper quartile: 8

maximum value: 14

Sorry for the late answer, i hope this will help you in the future and everyone else who reads this.

Answer:

36

Step-by-step explanation:

USE PYTHOGORAS THEOREM

A²=C²-B²

C²=3600

B²=2304

3600-2304=1296

√1296=36

hope it helps

Have a nice Day , I would appreciate it if you could mark my answer brainliest

Answer:

6800

Step-by-step explanation: