I didn't mean to click an answer but please help me out

Answer: B. [tex]12log(x)-4log(y)[/tex]

Step-by-step explanation:

Properties of logs:

[tex]log_{a} (\frac{B}{C} )=log_{A}B-log_{A} C[/tex]

[tex]logA^B = BlogA[/tex]

So, [tex]log\frac{x^{12} }{y^4} =logx^{12} -logy^4 =12log(x)-4log(y)[/tex]

It would be 12 log x - 4 log y (B)

Hi! ⋇

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The first digit of this number is 3², which is 9.

The Number is : 9xx

________

The second digit is: -2·(-4)=8.

The Number is : 98x.

________

The sum of all the digits is 18. This gives us an equation that we can solve in terms of x!

[tex]\multimap\sf{9+8+x=18}[/tex] (x is the digit we are looking for)

Now it takes a little arithmetic to find x :)

[tex]\multimap\sf{17+x=18}[/tex]. Just subtract 17 from both sides to find x!

[tex]\multimap\sf{x=1}[/tex]. And Now, can you see the number!

It's 981, of course :)

Hope this made sense to you!

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[tex]\large\it{\overbrace{Calligrxphy}}[/tex]

180-180=100

2+3=5

100÷5= 20

x = 20

Answer:

[tex]5x+80=180[/tex]
I hope this helps and that you can give a brainliest!

Step-by-step explanation:

This is a straight line which is always 180°.

Here there are 3 angles adding up to the total 180°.

So the initial equation is [tex]3x+80+2x =180[/tex].

But there are coefficients that share the same variable.
So by simplifying the equation, you end up with:

[tex]5x+80=180[/tex]

We conclude that the odds of hitting the ball are 0.158

The odds (like the probability) are given by the quotient between the number of attempts in which you hit the ball and the total number of attempts.

Here we know that out of 19 attempts, in 3 you hit the ball. Then the odds of hitting the ball are:

P = 3/19 = 0.158

We conclude that the odds of hitting the ball are 0.158

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Answer: A

Step-by-step explanation:

Each value of x maps onto only one value of y.

The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

Given the word:

ESTABROK

Then n = 8

p = 6

The formula for permutation without restrictions

P = n! ( n - p + 1)!

P = 8! ( 8 - 6 + 1) !

P = 8! (8 - 7)!

P = 8! (1)!

P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1

P = 40, 320 ways

Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

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The value of the probability P(A∪B) is 39/50

The given parameters are:

P(A)= 9/20

P(B) = 3/5

P(A∩B) = 27/100

To calculate the probability P(A∪B), we make use of the following equation

P(A∪B) = P(A) + P(B) - P(A∩B)

So, we have:

P(A∪B) = 9/20 + 3/5 - 27/100

Evaluate the expression

P(A∪B) = 78/100

Simplify

P(A∪B) = 39/50

Hence, the value of the probability P(A∪B) is 39/50

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Figure 1 was translated using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.

Translation is the movement of a point either up, down, left or right on the coordinate plane.

Figure 1 was translated 9 units left and 2 units up using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.

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Answer:

Step-by-step explanation:

plus all of them 5times 10

The probability of hitting the black circle inside the target is close to 0, and the probability of hitting the white portion is close to 1.

Given:

The square's length is 10 units.

The circle's diameter is equal to two units.

To Determine:

It is necessary to determine the probability that the target's white section and black circle will both be hit.

Solution:

The square's area is 10 x 10 or 100 units.

The shaded circle's area is given by  πr² = 3.14 (1)² = 3.14 units.

The white area has a surface area of (100 - 3.14) = 96.86 units.

Probability of an event = The number of favorable events /Total number of events

The probability that it will occur in the shaded area = 3.14/100 = 0.0314  (The probability is close to 0).

The probability of hitting the white section is equal = 96.86/100= 0.9686.

(The probability is quite near to 1)

Hence, the probability of hitting the black circle inside the target is close to 0, and the probability of hitting the white portion is close to 1.

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Answer:The inverse of the function y = 2x^2 –4 is;. y = √(x +4)/2To find the inverse of the function;We must first solve for x in the equation as follows;y = 2x² - 4y + 4 = 2x²x² = (y +4)/2x = √ (y +4)/2By swapping x and y; we then have;y = √(x +4)/2

The fill up of the missing points are:

Using the image attached, one can see that m<1 and m<2 creates a kind of  linear pair hence one can say they are both supplementary using the law of LINEAR POSTULATE THEOREM.

Based on the fact that the supplementary angles add up to 180 degrees, therefore:

m<1 + m<2 = 180   - will be equation 1

Since the interior angles m<2 and m<3 are known to be equal based on the CONGRUENCE POSTULATE THEOREM. Therefore

m<2 = m<3 ---  will be equation 2

Then place eqn. 2 into eqn. 2

m <1 + m <3 = 180

This connote that m<1 and m<3 are supplementary.

Hence, The fill up of the missing points are:

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Answer:

12.8 m.

Step-by-step explanation:

The length of the wire on the shorter pole (AC)

= √(6^2+8^2)

= √100

= 10 m.

The 2 triangles are similar so

10/16 = 8/x      where x is height of taller pole.

10x = 128

x = 12.8m

Answer:

El río mide:

300000 metros.

Step-by-step explanation:

1 km = 1000 metros

300 km = 300 * 1000 = 300000 metros

...

The probability of picking a red counter is therefore; 8/25.

Since the ratio of red to green is 2 :3 and there are 24 green counters, it follows that the number of red counters is;

x = (2/3)× 24 = 16 red.

The total of red and green is; 16 +24 = 40 which constitutes 80% of the total counters.

The total number of counters is therefore; 40/0.8 = 50 counters.

The probability of picking a red counter is therefore; 16/50 = 8/25.

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The equation which best represents the graph shows the amount of money that Janice saves each week from her summer job is option A which is  y=200x.

Given a graph showing the amount of money that Janice saves each week from her summer job.

Equation is relationship between two or more variables expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation, quadratic equation and cubic equation.

Equation can be formed from any two points present on the graph with the help of following formula:

[tex](y-y_{1})=(y_{2} -y_{1} ) /(x_{2} -x_{1} )*(x-x_{1} )[/tex] where [tex](x_{1} ,y_{1} ),(x_{2} ,y_{2} )[/tex]are the points.

So,we have to find points first which are (6,1200),(7,1400)

Put the values in the formula:

(y-1200)=(1400-1200)/(7-1)*(x-1200)

y-1200=200/1(x-6)

y-1200=200(x-6)

y-1200=200x-1200

y=200x-1200+1200

y=200x

Hence the equation shows the amount of monet that Janice saves each week from her summer job is option A which is y=200x.

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The interval where the function is negative is (–∞, –6)

The function is given as:

[tex]f(x) = \sqrt[3]{x + 6}[/tex]

Set the radicand to less than 0

x + 6 < 0

Subtract 6 from both sides

x < -6

Rewrite as an interval notation.

(–∞, –6)

Hence, the interval where the function is negative is (–∞, –6)

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Answer:

slope = [tex]-\frac{1}{2}[/tex]     if it were in an

Step-by-step explanation:

the graph is a negative and will therefore have a negative slope. to find the slope, pick a point on the graph and find the [tex]\frac{rise}{run}[/tex].

for instance, start with the point (0,1). Then go down 1 and left 2 to get to the next point on the graph (2,0). 1 is the "rise" and 2 is the "run" hence -1/2 being the slope.

you could also use the slope formula: [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

point 1: (0,1)    (x₁ ,y₁)

point 2: (2,0)    (x₂ , y₂)

[tex]\frac{0-1}{2-0} =-\frac{1}{2}[/tex]

Answer:

  (a)  3

Step-by-step explanation:

The fundamental theorem of algebra tells you a polynomial has a number of roots equal to its degree.

The degree of a polynomial is the largest exponent of the variable. Here, the degree is 3. That means there are three roots.

In general, the roots of a polynomial with real coefficients will be real or pairs of complex roots. The attached graph shows the roots of this cubic function are all real (and irrational).

This question is asking to create 5 of your own questions, so here are mine with the process on how I got each:

Question 1: Given c(x) = 8x + 32, find the range of c for the domain {1, 3, 5}.

Answer w/ Process:

For each equation, I am plugging in each domain value for x in the function, multiplying by 8, and adding by 32.

c(1) = 8(1) + 32 = 8 + 32 = 40

c(3) = 8(3) + 32 = 24 + 32 = 56

c(5) = 8(5) + 32 = 40 + 32 = 72

Range: {40, 56, 72}

Question 2: Given d(x) = x - 7, find the range of d for the domain {-2, 3}.

Answer w/ Process:

For each equation, I am plugging in each domain value for x in the function, and subtracting 7.

d(-2) = -2 - 7 = -9

d(3) = 3 - 7 = -4

Range: {-9. -4}

Question 3: Given f(x) = 7x + 738, find the range of f for the domain {1.5, 11}.

Answer w/ Process:

For each equation, I am plugging in each domain value for x in the function, multiplying by 7, and adding 738.

f(1.5) = 7(1.5) + 738 = 10.5 + 738 = 748.5

f(11) = 7(11) + 738 = 77 + 738 = 815

Range: {748.5, 815}

Question 4: Given g(x) = -2804x + 7268, find the range of g for the domain {50, 75, 256}.

Answer w/ Process:

For each equation, I am plugging in each domain value for x in the function, multiplying by -2804, and adding 7268.

g(50) = -2804(50) + 7268 = -140200 + 7268 = -132932

g(75) = -2804(75) + 7268 = -210300 + 7268 = -203032

g(256) = -2804(256) + 7268 = -717824 + 7268 = -710556

Range: {-132932, -203032, -710556}

Question 5: Given h(x) = -3x - 4, find the range of h for the domain {1, 2, 3}.

Answer w/ Process:

For each equation, I am plugging in each domain value for x in the function, multiplying by -3, and subtracting by 4.

h(1) = -3(1) - 4 = -3 - 4 = -7

h(2) = -3(2) - 4 = -6 - 4 = -10

h(3) - -3(3) - 4 = -9 - 4 = -13

Range: {-13, -10, -7}

b(-3)

b(5)

b(9)

Range

Rest questions

#1

k(x)=2x²-5

Find the range of k for domain {1,2,6}

#2

h(x)=9x³

Find the range of h for domain {9,0,8}

#3

o(x)=6x-7

find the range of o for domain {0,1,9}

#4

p(x)=23x²-5x

Find the range of p for domain {3,4,8}

Answer:

336 mangoes

Step-by-step explanation:

If 320 mangoes = 100%

Increasing them by 5% means that we will need to work out 105%

32 mangoes = 10%

3.2 mangoes = 1%

336 mangoes = 105%

Our final answer is 336 mangoes

Hope this helped and have a good day

Students who receive a grade of at least a C must have a minimum score of 50.38.

We may assume that the cut-off will be below 67.66 % because that percentage is more than 50%.

To get the value of 67.66 - 50 = 17.66, we must search in a regular normal table.

Hence, A z value of 0.458 will cause that value to occur.

Next, increase the standard deviation of 9 by 0.458.

The result is 4.122.

This indicates that the threshold for a student earning a C or higher is the mean minus 4.122.

So, the final result is 54.50-4.122 = 50.38.

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The Slope of the line :

[tex]m=-\frac{1}{5} \approx-0.2[/tex]

Using small, whole integer coordinates, it is simple to manually determine a line's slope. The formula becomes more effective if the coordinates are given greater or decimal values.

Because all horizontal lines have the same y-coordinates, it is important to note that all of them have a gradient of zero. In the slope formula's numerator, this will produce a zero. A vertical line, on the other hand, will have an arbitrary slope because the x-coordinates are constant. When applying the formula, this will lead to a division by zero error.

slope = (y₂ - y₁) / (x₂ - x₁)

Using the two points P=(2,3) and Q=(-3,4) as your input, determine the slope.

P=(x1,y1) and Q=(x2,y2) are two points on a line, and the slope of that line is given by :

                                 [tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

we have that:

                        [tex]x_{1}=2, y_{1}=3, x_{2}=-3, y_{2}=4[/tex]

Fill in the blanks in the slope calculation,

                                    [tex]m=\frac{(4)-(3)}{(-3)-(2)}\\\\=\frac{1}{-5}\\\\=-\frac{1}{5}[/tex]

Reaction:  the slope of the line is =[tex]m=-\frac{1}{5} \approx-0.2[/tex]

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Answer:

no solution

Step-by-step explanation:

y = (1/3)x - 4

3y - x = -7

put the first equation into the second

3(1/3)x - (3)4 - x = -7

x - 12 - x = -7

-12 = -7 can never be true so this is no solution

Answer:

[tex]x^2+7x-8-\frac{3}{x-7}[/tex]

Step-by-step explanation:

I think this question is a bit hard to explain by typing, so I'll add an image down below.  

I used long division for this question, and the final answer is: [tex]x^2+7x-8-\frac{3}{x-7}[/tex]

The package has a surface area of 4520cm². The area of the package is less than the area of the wrapping paper. So, dayson  can cover the package with the wrapping paper.

According to the question,

The first step is to determine the surface area of the package.

Total surface area of a cuboid = 2 (l w + w h + l h)

where:

• l = length

• w = width

• h = height

2[(50 x 20) + (50 x 18) + (20 x 18)] = 4520cm²

The second step is to convert 1 square meter to cm

1m² = 100 cm²

100 x 100 = 10,000

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The conditional probability that, when flipping a non-biased coin four times, there are at least two heads, given that the first flip is a head, is 3/4.

Calculating the Conditional Probability:

Let us assume that getting a head in the first flip of coin is event B

Also, let us assume that getting a head in on of the remaining three flips is A

Then we have to find the probability of A given B, that is, P(A|B).

The formula for conditional probability is given as follows,

P(A|B) = P (A∩B) / P(B)

The probability of getting two heads, P(A∩B) = 3/8

The probability of getting head in the first flip, P(B) = 1/2

∴ P(A|B) = (3/8) / (1/2)

P(A|B) = 3/4

Thus,  the conditional probability of getting at least two heads, given that the first flip is a head is 3/4.

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The first error in the proof is the fourth reason

Mathematical proofs are statements or collections of statements that are used to prove or disprove a statement, proof or theory

To determine the first error in the proof, we simply read through the statements and the given reason

From the table in the question, we have the following conclusions

Hence, the first error in the proof is the fourth reason

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