How would this quadrilateral be best classified, and what is the measure of Angle B?

Answer:

Exfoliation

Step-by-step explanation:

Changes in temperature cause rock to expand (with heat) and contract (with cold). As this happens over and over again, the structure of the rock weakens. Over time, it crumbles.

Rocky desert landscapes are particularly vulnerable to thermal stress. The outer layer of desert rocks undergo repeated stress as the temperature changes from day to night. Eventually, outer layers flake off in thin sheets, a process called exfoliation.

Answer:

Mean = 6.66

Median = 7

Mode = 7.68

Step-by-step explanation:

According to the Question,

Class interval   frequency

  56-63                    1

  48-55                   10

  40-47                   12

  32-39                    6

  24-31                     3

  16-23                     8

1). Mean = (Sum of all Observation) / (number of observation)

Mean = 40/6 = 6.66

2) For Median, If there are two number in the middle then you need to find their mean.  1  3   6   8  10  12  middle numbers are 6 and 8.

Median = (6+8) / 2 = 7

3) Mode = 3 × Median - 2 × Mean

Mode = 3×7 - 2×6.66

Mode = 7.68

Answer:

silly question...I used technology to "cheat"

it is 11/23

34155 32775 33649 34485

72105 72105 72105 72105

Step-by-step explanation:

Answer:

Undefined

Step-by-step explanation:

Lim x - - > 1(1 /In(2-x) + 1/(x-1))

To find the limit as x tends to 1

Substitute x = 1 into the function ;

(1 / In(2 - 1) + 1 / (1 - 1))

(1 / In 1) + (1 / 0)

1 / 0 + 1 / 0

Undefined

Answer:

C) 8

Step-by-step explanation:

Consecutive angles are equal to 180. So 22x+4+180. Solve that to get x=8. Hope I helped and post more questions :)

Answer:

the answer for that is 61.

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

5-3=2 it's simple really

Answer:

5-3=2

Hope This Helps!!!

Answer:

270 coins

n + p

Step-by-step explanation:

Given that :

Number of nickels = 140

Number of pennies = 130

The total numbers coins had:

Number of Nickel + number of pennies

140 + 130 = 270 coins

If Number of nickels = n ; number of pennies = p

The total number of coins :

Number of Nickel + number of pennies

n + p

Answer:

[tex]{ \tt{let \: that \: unknown\: side \: be \: x}} \\ { \boxed{ \tt{perimeter = (8 \times side)}}} \\ 41.6 = (3.2 \times 2) + (5.9 \times 5) + x \\ x = 5.7 \:in \\ { \bf{answer : 5.7 \: inches}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}[/tex]

(√3 - i ) / (√3 + i ) × (√3 - i ) / (√3 - i ) = (√3 - i )² / ((√3)² - i ²)

… = ((√3)² - 2√3 i + i ²) / (3 - i ²)

… = (3 - 2√3 i - 1) / (3 - (-1))

… = (2 - 2√3 i ) / 4

… = 1/2 - √3/2 i

… = √((1/2)² + (-√3/2)²) exp(i arctan((-√3/2)/(1/2))

… = exp(i arctan(-√3))

… = exp(-i arctan(√3))

… = exp(-iπ/3)

By DeMoivre's theorem,

[(√3 - i ) / (√3 + i )]⁶ = exp(-6iπ/3) = exp(-2iπ) = 1

Answer:

Slope: -5/4

Step-by-step explanation:

Use slope (m) formula:

m = y2 - y1 / x2 - x1

m = 5 - 10 / 49 - 45

m = -5/4

Answer:

[tex]-\frac{5}{4}[/tex]

Step-by-step explanation:

Hi there!

Equation for the slope:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] where two given points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

To find the slope of the line, plug in any two points given in the table. For example, we can use the points (49,5) and (53,0):

[tex]=\frac{5-0}{49-53}\\=\frac{5}{-4}[/tex]

Therefore, the slope of the line is [tex]-\frac{5}{4}[/tex].

I hope this helps!

Answer:

Is the question original or you simply made it.

Answer:

0 or 1

Step-by-step explanation:

Given that Kelley  is tasked with having to use vertical line test to determine whether or not a curve is a function. Each vertical line that Kelly draws through her curve must intersect the curve at maximum one point only in order for thecurve to be a function

Answer is 0 or 1 point

Answer:

Step-by-step explanation:

If a point (x, y) is rotated 90° counterclockwise about the origin, rule for the rotation will be,

(x, y) → (-y, x)

Therefore, coordinates of the image point after the rotation will be (-y, x).

Following this rule,

Image points of the quadrilateral will be,

A(3, 3) → A'(-3, 3)

R(5, 7) → R'(-7, 5)

M(7, 5) → M'(-5, 7)

Y(5, 1) → Y'(-1, 5)

By graphing the image points we can get the graph of the image quadrilateral A'R'M'Y'.

Answer:

I got my answer on Khan Academy:

Given:

A quadrilateral DEFG inscribed in a circle.

[tex]m\angle D=60^\circ, m\angle E=m^\circ, m\angle F=2k^\circ, m\angle G=60^\circ[/tex]

To find:

The value of variables [tex]m[/tex] and [tex]k[/tex].

Solution:

If a quadrilateral is inscribed in a circle then it is a cyclic quadrilateral. The opposite angles of a cyclic quadrilateral angle supplementary angles.

Quadrilateral DEFG inscribed in a circle. So, quadrilateral DEFG is a cyclic quadrilateral.

[tex]m\angle D+m\angle F=180^\circ[/tex]                [Supplementary angle]

[tex]60^\circ+2k^\circ=180^\circ[/tex]

[tex]2k^\circ=180^\circ-60^\circ[/tex]

[tex]2k^\circ=120^\circ[/tex]

Divide both sides by 2.

[tex]k^\circ=\dfrac{120^\circ}{2}[/tex]

[tex]k^\circ=60^\circ[/tex]

[tex]k=60[/tex]

Similarly,

[tex]m\angle E+m\angle G=180^\circ[/tex]

[tex]m^\circ+60^\circ=180^\circ[/tex]

[tex]m^\circ=180^\circ-60^\circ[/tex]

[tex]m^\circ=120^\circ[/tex]

[tex]m=120[/tex]

Therefore, the values of the variables are [tex]m=120[/tex] and [tex]k=60[/tex].

Step-by-step explanation:

we cannot see anything, and you did not describe anything. so, there is nothing to calculate.