How to solve this please
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Answer:

h = 24 cm

Step-by-step explanation:

Let [tex]x[/tex] = height of ΔCBD

Let [tex]h[/tex] = height of ΔABE

As ΔABE ~ ΔCBD then AE : CD = [tex]h[/tex] : [tex]x[/tex]

Given:

[tex]\implies 20 : 10 = h : x[/tex]

[tex]\implies \dfrac{20}{10}=\dfrac{h}{x}[/tex]

Cross multiply:

[tex]\implies 20x=10h[/tex]

Simplify:

[tex]\implies 2x=h[/tex]

As we are told that [tex]x+h=36 \ \sf cm[/tex]

[tex]\implies h=36-x[/tex]

Equate the two equations for [tex]h[/tex] and solve for [tex]x[/tex]:

[tex]\implies 2x=36-x[/tex]

[tex]\implies 3x=36[/tex]

[tex]\implies x=12[/tex]

Since [tex]h=2x[/tex] then

[tex]\implies h=2 \cdot 12[/tex]

[tex]\implies h=24 \ \sf cm[/tex]

Answer: Square is a 17*17. Ok so its 121-25=96

Step-by-step explanation:

96

Let that be x

[tex]\\ \rm\rightarrowtail tan\theta=\dfrac{Perpendicular}{Base}[/tex]

[tex]\\ \rm\rightarrowtail tan20=\dfrac{x}{10}[/tex]

[tex]\\ \rm\rightarrowtail 0.364=\dfrac{x}{10}[/tex]

[tex]\\ \rm\rightarrowtail x=10(0.364)[/tex]

[tex]\\ \rm\rightarrowtail x=3.64mi[/tex]

Answer:

[tex]\displaystyle 4\:mi.[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{10}{h} = cot\:20 \hookrightarrow 10 = hcot\:20 \hookrightarrow \frac{10}{cot\:20} = h; 3,6397023427... \\ \\ \boxed{4 \approx h}[/tex]

OR

[tex]\displaystyle \frac{h}{10} = tan\:20 \hookrightarrow 10tan\:20 = h; 3,6397023427... \\ \\ \boxed{4 \approx h}[/tex]

I am joyous to assist you at any time.

2×+3y=6

-8×-3y=12

-6×=18

×=18/-6

×=-3

——————

2×+3y=6

2(3)+3y=6

6+3y=6

3y=6-6

3y=0

Y=0/3

Y=0

——————

×=3

Y=0

————

2×+3y=6

2(3)+3(0)=6

6=6

Answer:

a

Step-by-step explanation:

Answer:

256x^8

Step-by-step explanation:

Hope this helped

Maybe mark brainiest?

Step-by-step explanation:

percentage of green marbles=

(total green marbles÷ total marbles )×100

Answer:

he correct answer is D. 12 adult tickets, 4 child ticket

Step-by-step explanation:

Answer: B. K < 13. K is 12.5, 12.5 is less than 13

1. Its not D because at the ending points of the number line; 10-20, which is less than 30.

2 It is not C because K is not on 15

3 It is not A because 12.5 is less than 13.

Hope it helps!!

Answer:

Side A is 4

Step-by-step explanation:

Answer:

A.4

Step-by-step explanation:

a = √(c² - b²)

a= √(5² -3b²)=4

Answer:

58.58

Step-by-step explanation:

[tex] \frac{1}{2} \times 10 \times 3 \\ 5 \times 3 = 15.....(1)[/tex]

[tex] \frac{1}{2} \times 10 \times 10 \\ 5 \times 10 = 50...(2)[/tex]

Add one and two :- 15+ 50 = 65

Answer:

1,750

Step-by-step explanation:

35x50 that's the entire process

Answer:

Monica has 1 more card than Joey

Step-by-step explanation:

its simple math

Answer:

(n/4)-1

Step-by-step explanation:

Answer:

y = x - 5

Step-by-step explanation:

Line A

Equation

Answer:

Step-by-step explanation:

c

so you have to combine like terms so subtract 8 - 4 and the 4 disappears so it be like this

8 - 2x = 4 + x

-4 -2x = -4 + x

4 - 2x = x

next combine the like terms of the 2x so

4 - 2x = x

4 + 2x = +2x

4 = 2x

now you divide 4 by 2 so like this

4 = 2x

2   2

and your answer is x = 2 try to solve the other one if you need help ask me

a = 2, b = -18, c = 40

[tex]Given:\ Polynomial\ f(x)=ax^2+bx+c\ has\ zoroes\ 4\ aud\ 5[/tex]

[tex]and\ f(-1)=60[/tex]

[tex]Tofind:\ a,\ b,\ c[/tex]

[tex]Solution:\ As\ 4\ and\ 5\ are\ zeroes\ so\ f(4)=f(5)=0[/tex]

[tex]f(4)=a(4)^2+b(4)+c=0\Rightarrow16a+4b+c=0-(1)[/tex]

[tex]f(5)=a(5)^2+b(5)+c=0\Rightarrow25a+5b+c=0[/tex]

[tex]f(-1)=a(-1)^2+b(-1)+c=60\Rightarrowa-b+c=60-(3)[/tex]

[tex]subtracting\ (1)\ from\ (2)[/tex]

[tex]25a+5b+c-(16a+4b+c)=0\Rightarrow9a+b=0\Rightarrowb=-9a[/tex]

[tex]subtracting\ (3)\ from(2):[/tex]

[tex]25a+5b+c-(a-b+c)=0-60\Rightarrow24a+6b=-60[/tex]

[tex]putting\ b=-9a[/tex]

[tex]24a+6(-9a)=-60\Rightarrow24a-54a=-60\Rightarrow-30a=-60[/tex]

[tex]a=\frac{-60}{-30}=2[/tex] [tex]\Rightarrow[/tex] [tex]a=2[/tex]

[tex]b=-9a=-9\times2=-18[/tex]

[tex]c=-a+b\neq60=-2-18+60=-20+60=40[/tex]

I hope this helps you

:)

Answer:

8

Step-by-step explanation:

A=πr^2

64π=πr^2

since answer is in terms of pi, ignore the pi.

sqrt(64)=8

Answer:

Step-by-step explanation:

Anything going from lower left to upper right is a positive slope.

The lines are not easily seen. My best estimate is that one point is (2,5)

Use the two points you are sure of.

(0,-1) and (1,2)

Givens

Formula

m = (y2 - y1)/(x2 - x1)

Solution

m = (2 - - 1) / (1 - 0)

m = 3/1

m = 3

Answer:

8

Step-by-step explanation:

first multiple 12 by 12 then divide by 18 then you'll get 2 times 4 and that's how you get 8.

Answer: 10.62 irrational

Step-by-step explanation: You can divide 69.15 by 5.25 which equals 74.4 then divide by 7 which equals 10.62

Answer:

30000 simple interest ,50000 total repayment.

Step-by-step explanation:

sorry iam terrible at explaining,

Answer:

The coordinate of the image of a point is (2, +3) under the translation (x , y) → (x - 2),( y + 3). Find the coordinate of the preimage.

We are just looking for x and y and we know (2, +3) → (x - 2, y + 3)

2 = x - 2

x = 4

-3 = y + 3

y = -6

(x , y) = (4, -6)

How to find a 

The length of arc of the given circle, to the nearest hundreth, is: 2.41 units.

Length of arc = ∅/360 × 2πr, where the radius of the circle is r, and the reference angle is ∅.

We are given the following:

Radius (r) = 3 units

Reference angle (∅) = 46°

Plug in the values into the length of arc formula:

Length of arc = 46/360 × 2π(3)

Length of arc = 2.41 units.

Therefore, the length of arc of the given circle, to the nearest hundreth, is: 2.41 units.

Learn more about length of arc on:

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Answer:

The graph of g is translated down 5 units from the graph of f and stretched horizontally

Step-by-step explanation:

was correct on test :)

pls brainliest XD

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The value of the hypotenuse y will be equal to y = 2.8 inches.

The volume of the prism is equal to the product of the area of its base and the height of the prism.

[tex]\rm V=Area \ of\ triangular \ base\times Height \ of \ prism[/tex]

The volume oif the prism is =4 cubic inches

Height of the prism = x inches

Base of the right angle isosceles triangle will be =x inches

The hypotenuse is given = y

Now

[tex]\rm V=\dfrac{1}{2}\times Base\times Height \times height \ of \ prism[/tex]

[tex]V=\dfrac{1}{2} \times x \times x \times x[/tex]

[tex]x^3=8[/tex]

[tex]x=2[/tex]

Now by pythagorus theorem

[tex]y^2=h^2+b^2[/tex]

[tex]y^2=x^2+x^2[/tex]

[tex]y^2=2x^2=2\times 2^2[/tex]

[tex]y=2\sqrt{2}=2.82[/tex]

Thus the value of the hypotenuse y will be equal to y = 2.8 inches.

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Answer:

2.8 INCHES

Step-by-step explanation:

Answer:

c. 2x.

Step-by-step explanation:

16x2 - 14x

Common factor of 16 and 14 =  2'

for x2 and x it is x,

Answer: 2x.

The average squared distance between the points is their variance

The average squared distance is 8/3

The given parameters are:

R={(x,y): 0<=x<=2, 0<=y<=2}

The point = (2,2).

f(x,y) = (x-2)² + (y-2)²

The squared distance is calculated as:

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) is:

A = xy

Substitute the maximum values of x and y in A = xy

A = 2 * 2

A = 4

The minimum values of x and y are 0.

So, the limits for the integrals are 0 to 2

The integral becomes

[tex]D\² = \int \int (x-2)\² + (y-2)\² dx dy[/tex]

Expand

[tex]D\² = \int \int x\² -4x + 4 + (y-2)\² dx dy[/tex]

Evaluate the inner integral with respect to x from 0 to 2

[tex]D\² = \int \frac 13x^3 -2x^2 + 4x + x(y-2)\² |\limits^2_0 dy[/tex]

Expand

[tex]D\² = \int [\frac 13(2)^3 -2(2)^2 + 4(2) + (2)(y-2)\²] dy[/tex]

Simplify

[tex]D\² = \int \frac 83 + (2)(y-2)\² dy[/tex]

Expand

[tex]D\² = \int \frac 83 + 2y^2-8y + 8 \ dy[/tex]

Evaluate the integral with respect to y from 0 to 2

[tex]D\² = [\frac 83y + \frac 23y^3- 4y^2 + 8y ]|\limits^2_0[/tex]

Expand

[tex]D\² = \frac 83*2 + \frac 23*2^3- 4*2^2 + 8*2[/tex]

D² = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

So, we have:

AD² = 32/3 [tex]\div[/tex] 4

Evaluate the quotient

AD² = 32/12

Simplify

AD² = 8/3

Hence, the average squared distance is 8/3

Read more about average distance or variance at:

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The average squared distance between the points of R = {(x,y): 0<=x<= h, 0<=y<=k } is 8/3.

How do determine the average squared distance?

From the given parameters R = {(x,y): 0<=x<= h, 0<=y<=k }

The squared distance from point (h, k) is calculated as

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) will be

A = xy

Substitute the maximum values of x and y

A = 2 × 2 = 4

The minimum values of x and y are 0.

So, The integral becomes

[tex]D^{2} = \int \int(x-2)^2 +(y-2)^2 dx dy\\\\D^{2} = \int \int\limits^2_0 (x)^2 -4x + 4+(y-2)^2 dx dy\\\\D^{2} = \int1/3(x)^3-2x^{2} +4x + 4+x(y-2)^2 dy\\\\D^{2} = \int8/3+2y^{2} -8y +8 dy[/tex]

[tex]D^2 = {8/3y +2/3y^2 -4y^2+8y[/tex]

By expanding we get,

D^2 = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

AD² = 32/3  4

AD² = 32/12

AD² = 8/3

Hence, the average squared distance is 8/3

Read more about average distance;

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Perpendicular lines have slopes that are opposite reciprocals.

This means we take a number, flop it over, and change its sign.

In this case, we take [tex]\boxed{-3}[/tex], change its sign:

[tex]\boxed{3}[/tex]

3 can also be written as

[tex]\boxed{\frac{3}{1} }[/tex]

Now the numerator & denominator switch places:

[tex]\boxed{\frac{1}{3}}[/tex]

So that's the slope of the new line.

Now, let's write the equation in point-slope form:-

[tex]\bigstar{\underline{\boxed{\pmb{y-y_1=m(x-1)}}}[/tex]

Where

y₁  is the y-coordinate of the point (in this case, y₁ = 3)

m = slope (1/3)

x₁= the x-coordinate of the point (in this case, it's -2)

Plug in the values:-

[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x-(-2)}}[/tex]

[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x+2)} }\longleftarrow\sf{Point-Slope~Formula:)}}[/tex]

===============================================

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

Answer:

5x/1/2 = 1x



answer  1.12 <3


hope it helps


use brainly<3

Step-by-step explanation: