how to find the hcf and the lcm of numbers using prime factorization.

lcm
30 and 12.

hcm
12 and 20​

Answer:

you do not have any numbers, only letters so I cannot answer your question. sorry...

Step-by-step explanation:

Select the correct answer.

Which number is an irrational number?

A.

B.

C.

D.

Answer:

As per Provided Information

Height of cone h is 3.25 cm

Diameter of cone is 2.2 cm

Radius = 2.2/2

Radius = 1.1 cm

We have been asked to determine the volume of the cone .

Using Formulae

[tex] \boxed{\bf \:Volume_{(Cone)} = \cfrac{1}{3} \pi {r}^{2}h}[/tex]

Substituting the given value and let's solve it

[tex]\sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times {1.1}^{2} \times 3.25 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times 1.21 \times 3.25 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times 3.9325 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 12.34805 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{12.34805}{3} \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = 4.11 {cm}^{3} [/tex]

Therefore,

Answer:

56

Step-by-step explanation:

Answer:

2929 1/3 [tex]\pi[/tex] in^3

Step-by-step explanation:

The equation for the volume of a sphere is [tex]\frac{4}{3} \pi r^3[/tex].

Insert 13 for r.  Then, simplify.

Answer:

it is A Scalene Triangle

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

As we know ~

Area of the circle is :

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 4.4\div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 2.2 \: mm[/tex]

Now find the Area ~

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {(2.2)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {4.84}^{} [/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 3.7 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 1.85 \: \: cm[/tex]

Bow, calculate the Area ~

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times (1.85) {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 3.4225 {}^{} [/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times (8.3) {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 68.89[/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx216.31 \: \: cm {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 5.8 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 2.9 \: \: yd[/tex]

now, let's calculate area ~

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {(2.9)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 8.41 [/tex]

[tex] \qquad \sf  \dashrightarrow \:area \approx26.41 \: \: yd {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 1 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 0.5 \: \: yd[/tex]

Now, let's calculate area ~

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times (0.5) {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 0.25[/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx0.785 \: \: yd {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {(8)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 64[/tex]

[tex]\qquad \sf  \dashrightarrow \:area = 200.96 \: \: yd {}^{2} [/tex]

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Answer:

the answer is -6.8°

Step-by-step explanation:

-36°+-25°+12°+-3°+18°/5°

-34°÷5°=-6.8°

Make as Braniliest!

Answer:

5.6

Step-by-step explanation:

4/5 = .8

so ? ÷ 7 = .8|
7 x .8 = 5.6
x= 5.6

x = 5.6

hope it helps...!!!!

Answer:

71.428571%

Step-by-step explanation:

You divide 5 by 7

Answer:

Step-by-step explanation:

you would multiply the fractions

then you would add the hole number

Answer:

2 14/15

Step-by-step explanation:

Answer:

hope it helps

also try to find out what 5power 10 is because I have no calculator with me

Answer:

C. 3000

Step-by-step explanation:

i took the quiz!

also 60 and 3000 line up

Answer:

C 3,000

Step-by-step explanation: It's right on Edge

Step-by-step explanation:

inscribed angles subtended by the same arc are equal.

the central angle of a circle is twice any inscribed angle subtended by the same arc.

the first statement tells us that the 53° angle as well as y stay the same size no matter where on their arcs (between the 2 points connected to O) they would be. so, we don't need to bother with any line lengths.

the 2nd statement tells us that x = 2×53 = 106°. the 53° and x angles refer to the short arc on the right of the 2 points connected to O.

and y and x refer to the larger arc on the left of the 2 line connected to O. that means according to the second statement : 360-x (the big angle around O) = 2y

so,

360 - 106 = 2y

254 = 2y

y = 127°

5,278 hope this helps good luck!

Answer:

50%

Step-by-step explanation:

Hope this helped

Maybe mark brainiest

Dime = 10 cents

Nickel = 5 cents

Total value of coins = 3(10) + 4(5) = 30 + 20 = 50

To find the percent, first create a fraction. The fraction will be the amount of money that Benjamin has over the total (one dollar).

50 / 100 = 5 / 10 = 0.5

0.5 x 100 = 50

50%

Answer: 50% of a dollar

Hope this helps!

Answer:

x= 12

Step-by-step explanation:

Hope u understood it

"PLEASE MARK ME THE BRAINLIEST"

Answer:

-13

Step-by-step explanation:

Answer:

4 boxes

Step-by-step explanation:

If she has 4 boxes that hold 5 cookies each, that will total 20 cookies.

4×5=20

20÷5=4

Answer:

13 C 14 D 15 A 16 B

Step-by-step explanation:

Sorry thats all i know hope you found this helpful

Answer:

a

Step-by-step explanation:

7(g-9)+12=26

7(g-9)+12-12=26-12

7(g-9)=14

7(g-9)/7=14/7

g-9=2

g-9+9=2+9

g=11

Answer:

Step-by-step explanation:

26=7(g-9)+12

(take 12 to 26)

so it will be 7(g-9)= 26-12

=> 7(g-9)= 14

(then take 7 to 14)

=> g-9= 14/2

=> g-9= 2

(then take 9 to 2)

g= 2 + 9

hope it is properly explained

STAY SAFE, HAVE A NICE DAY

Answer:

Pretty sure it's 2:30 P.M.

Step-by-step explanation:

If her track practice started at 12:00 P.M., and and ran relays for one hour, it would already be 1:00 P.M.

Then she practiced the long jump for an hour and thirty minutes. Add another hour to that and it would be 2:00 P.M. Add thirty minutes, and it would be 2:30 P.M.

Hopefully that makes sense to you

Answer:

[tex]P(A < 84)=\frac{4}{7}[/tex]

Step-by-step explanation:

[tex]Total\ numbers:\ 7\\Numbers\ less\ than\ 84:\ 4\\\\P(A < 84)=\frac{4}{7}[/tex]

Answer:

30.37

Step-by-step explanation:

Answer:

[tex]164 \div 5.40 ={\ 30.3704{}}[/tex]

The answer is 30.3704

Answer:

f(-6)= -41 923

Step-by-step explanation:

f(-6)= -( -6)⁶ +5(-6)⁴+8(-6)³+2(-6) -7 you substitute x with -6 the you use a calculator which will then give you - 41923

Answer:

[tex]\displaystyle 11,3[/tex]

Step-by-step explanation:

Use the Law of Cosines to find the length of the third edge:

Solving for Angles

[tex]\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos\angle{C} \\ \frac{a^2 - b^2 + c^2}{2ac} = cos\angle{B} \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos\angle{A}[/tex]

Use [tex]\displaystyle cos^{-1}[/tex]towards the end or you will throw your result off!

Solving for Edges

[tex]\displaystyle b^2 + a^2 - 2ba\:cos\angle{C} = c^2 \\ c^2 + a^2 - 2ca\:cos\angle{B} = b^2 \\ c^2 + b^2 - 2cb\:cos\angle{A} = a^2[/tex]

Take the square root of the final result or it will be thrown off!

Let us get to wourk:

[tex]\displaystyle 10^2 + 7,9^2 - 2[10][7,9]\:cos\:77,5 = a^2 \hookrightarrow 100 + 62,41 - 158\:cos\:77,5 = a^2 \hookrightarrow \sqrt{128,212541} = \sqrt{a^2}; 11,323097677... \\ \\ \boxed{11,3 \approx a}[/tex]

I am joyous to assist you at any time.

5 quarts I think 4 cups per quart has 5 quarts and 2 cups I think

Answer:

1 quart = 4 cups

8 × 4 = 32

32 - 6 = 26

26 - 18 = 8

he has 2 quarts left

[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer}}[/tex]

Let's solve ~ ☂

⧠ Here, I'm using middle term split method :

[tex] \qquad\rightarrowtail \sf {x}^{2} + 6x + 8[/tex]

[tex] \qquad\rightarrowtail \sf {x}^{2} + 4x + 2x+ 8[/tex]

[tex] \qquad\rightarrowtail \sf {x(x}^{} + 4) + 2(x+ 4)[/tex]

[tex] \qquad\rightarrowtail \sf (x + 2)(x+ 4)[/tex]

[tex]\\ \rm\rightarrowtail x^2+6x+8[/tex]

[tex]\\ \rm\rightarrowtail x^2+4x+2x+8[/tex]

[tex]\\ \rm\rightarrowtail x(x+4)+2(x+4)[/tex]

[tex]\\ \rm\rightarrowtail (x+2)(x+4)[/tex]

Done!