Answer:
Work = force * displacement
= 50 N * 20 Meter
=1000 Newton meter = 1000 joule .
Explanation:
A box of mass 7.7 - kg is accelerated from rest across a floor at a rate of 2.6 m/s2 for 18.5 s. Find the net work done on the box
Answer:
Explanation:
The net work will change the kinetic energy
W = ½mv² = ½m(at)² = ½ma²t²
W = ½(7.7)2.6²(18.5²) = 8907.3985 = 89 kJ
a car moves at a speed of 30m/s to the west of 3hr, what is its displacement of the car in km?
Answer:
Explanation:
30 m/s • 3 hr •3600 s/hr / 1000 m/km = 324 km west
A 1250 kg car is stopped at a traffic light. A 3550 kg truck moving at 8.33 m/s strikes the car from behind, causing the bumpers to lock together.
A) What is the momentum of the car-truck system before the collision?
B) What is the momentum of the car-truck system after the collision?
C) How fast do the car and truck move after the collision?
(Do NOT put any links or reproductions, I just need help with this.)
A) Before the collision, the total momentum is
(1250 kg) (0 m/s) + (3550 kg) (8.33 m/s) ≈ 29,600 kg•m/s
B) Momentum is conserved, so after the collision it is still approximately 29,600 kg•m/s.
C) If v is the speed of the locked car-truck system, then
(1250 kg) (0 m/s) + (3550 kg) (8.33 m/s) = (1250 kg + 3550 kg) v
Solve for v :
29,571.5 kg•m/s = (4800 kg) v
v ≈ 6.16 m/s
A wheel has a radius of r = 2.0 m and it rolls down a smooth incline. The height of the incline is h = 8.0 m . What is the angular velocity ω of the wheel at the bottom of the incline?
Express your answer in radians per second.
The angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec
The angular velocity (ω) of an object is the rate at which the object's angle position is changing in relation to time.
For a wheel attached to an incline angle, the angular velocity can be computed by considering the conservation of energy theorem.
As such the total kinetic energy (K.E) and rotational kinetic energy (R.K.E) at a point is equal to the total potential energy (P.E) at the other point.
i.e.
P.E = K.E + R.K.E
[tex]\mathbf{mgh = \dfrac{1}{2}m(r \times \omega)^2 + \dfrac{1}{2}\times I \times \omega^2}[/tex]
[tex]\mathbf{gh = \dfrac{1}{2}(r \times \omega)^2 + \dfrac{1}{2}\times r^2 \times \omega^2}[/tex]
[tex]\mathbf{2 \times \dfrac{gh}{r^2} =\omega^2 + \omega^2}[/tex]
[tex]\mathbf{2 \omega^2=2 \times \dfrac{9.81 \times 8 m }{2.0 ^2} }[/tex]
[tex]\mathbf{\omega^2=\dfrac{39.24 }{2}}[/tex]
[tex]\mathbf{\omega=\sqrt{19.62 } \ rad/sec}[/tex]
[tex]\mathbf{\omega=4.429 \ rad/sec}[/tex]
Therefore, we can conclude that the angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec
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The angular velocity of the wheel depends on the mass, radius and the
mode of rotation of the wheel (with or without slipping).
The angle velocity at the bottom of the incline, ω ≈ 4.43 rad/secReasons:
The given parameters are;
Radius of the wheel, r = 2.0 m
Height of the incline, h = 8.0 m
Required:
Angular velocity of the wheel at the bottom of the incline.
Solution:
The potential energy of the wheel at the top of the hill, P.E. = m·g·h
[tex]Sum \ of \ the \ kinetic \ energy \ of \ the \ wheel, \ K.E. = \mathbf{\displaystyle \frac{1}{2} \cdot m \cdot v^2 + \frac{1}{2} \cdot I \cdot \omega ^2}[/tex]
Where;
v = The translational velocity of the wheel = ω·r
I = The moment of inertia of the wheel = m·r²
Therefore'
[tex]Sum \ of \ K.E. = \displaystyle \frac{1}{2} \cdot m \cdot (\omega \cdot r)^2 + \frac{1}{2} \cdot m \cdot r^2 \cdot \omega ^2 = \mathbf{m \cdot r^2 \cdot \omega^2}[/tex]
At the bottom of the hill, the potential energy is converted to kinetic energy
Therefore;
P.E. = Sum of K.E.
m·g·h = m·r²·ω²
g·h = r²·ω²
[tex]\displaystyle \omega = \sqrt{ \frac{g \cdot h}{r^2} } = \mathbf{ \frac{\sqrt{g \cdot h} }{r}}[/tex]
Where;
g = Acceleration due to gravity ≈ 9.81 m/s²
Therefore;
[tex]\displaystyle \omega = \frac{\sqrt{9.81 \times 8} }{2} \approx \mathbf{ 4.43}[/tex]
The angular velocity of the of the wheel at the bottom of the incline, ω ≈ 4.43 rad/secLearn more about the law of conservation of energy here:
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if it takes a track runner 2.16 seconds to reach a speed of 5.31 m/s from the start of a race, what is the runners acceleration?
Answer:
Explanation:
Answer:
Explanation:
using dimensional analysis find the relation between the velocities of transverse waves produced from the vibration of thin homogeneous string and between the tension in the string and mass per unit length of it.
Answer:
[tex]v^2=\frac{T}{M}[/tex]
where v = transverse wave velocity, T = tension in the string, M = mass per unit length.
Explanation:
Dimensional analysis is where you just look at the units and see how they fit within each other.
In this case, all relationships are made using the MLT comparisons, where M stands for Mass, L stands for Length, and T stands for time.
For example, for velocity, we know the SI unit for velocity is [ms⁻¹] which is L¹T⁻¹, we can do the same thing for tension = [N = Kgms⁻²] = M¹L¹S⁻², and for the mass per unit length which we can think of as [Kgm⁻¹] = M¹L⁻¹.
If you play around a little with the powers, you can find a relationship:
[tex]v^2=\frac{T}{M}[/tex]
since:
[L¹T⁻¹]² = L²T⁻² = M¹L¹T⁻² ÷ M¹L⁻¹ = M¹⁻¹L¹⁻⁽⁻¹⁾T⁻² = M⁰L²T⁻² = L²T⁻²
That’s easy please tell me!
A baseball is hit with a speed of 27.0 m/s at an angle of 47.0 ∘ . It lands on the flat roof of a 10.0 m -tall nearby building. Part A If the ball was hit when it was 1.3 m above the ground, what horizontal distance does it travel before it lands on the building?
Answer:
H = Vy t - 1,2 g t^2 formula for height of ball after t sec
H = 10 - 1.3 = 8.7 m
Vy = 27 sin 47 = 19.7 m/s vertical speed of ball
8.7 = 19.7 t - 9.8/2 t^2 height of ball after t sec
4.9 t^2 - 19.7 + 8.7 = 0 rearranging
[19.7 ± (388 - 170)^1/2] / 2 *4.9 = [19.7 ± 14.7] / 9.8 = .51 ,3.5 sec
.51 sec would be on the way up and 3.5 sec on the way down
Sx = 27 * cos 47 * 3.5 = 64.4 m around 200 ft seems reasonable
A change
1. Ricardo has purchased a forklift for his business. The forklift can put out 4950 W of power. If the forklift is operating at full capacity, how much work can it do in 2.40 seconds?
O 2060)
O 4950)
O 6490)
O 11,900
The work done if the forklift is operating at full capacity is 11,900 J.
We have to recall that power is defined as the rate of doing work. The rate of doing work is defined as;
Power = Work done/time taken
When;
Power = 4950 W
Time taken = 2.40 s
Work done = Power × time taken
Work done = 4950 W × 2.40 s
Work done = 11,900 J
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How is the çhocolate shell on the outside of the bar different from the ice cream on the inside?
Answer:
Cake Crunch (Enriched Wheat Flour [Bleached Flour, Niacin, Reduced Iron, Thiamine Mononitrate, Riboflavin, Folic Acid]), Sugar, Vegetable Shortening [Partially Hydrogenated Soybean and Cottonseed Oil], Salt, Sodium Bicarbonate, Artificial Flavor, Soy Lecithin, Soybean Oil, Coconut Oil, Sugar, Chocolate Liquor, ...
imagine that you have an electric car and all of the recaptured energy is put back into the battery that powers your car what speed could your car cheat from rest by using only the recaptured energy from part B
Answer:
Moving vehicles have a lot of kinetic energy, and when brakes are applied to slow a vehicle, all of that kinetic energy has to go somewhere.
Explanation:
Oceanic crusts tend to be darker in color than continental crust. This is best explained by the fact that A) Oceanic crust is older than continental crust. B) Oceanic crust is denser than continental crust. C) Oceanic crust is thinner than continental crust. D) Oceanic crust is consist mostly of basalt while continental crust consist mainly of granite.
Answer:D
Explanation:USA test prep
Oceanic crusts tend to be darker in color than continental crust because
Oceanic crust consist mostly of basalt while continental crust consist mainly
of granite.
Oceanic crust are found under oceans while continental crust have most of
its parts above sea level. This explains why Oceanic crust is thinner than
continental crust due to the compression force from water.
Oceanic crust contains dark-colored rocks such as basalt while continental
crust contain light colored rocks such as granite which is why Oceanic
crusts tend to be darker in color than continental crust.
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Destination is your Destination
Answer:
woah awesome so cool
Explanation:
Answer:
woah excellent!
esse is swinging Miguel in a circle at a tangential speed of 3.50 m/s. If the radius of the circle is
0.600 m and Miguel has a mass of 11.0 kg, what is the centripetal force on Miguel? Round to the nearest whole number.
Answer:
Explanation:
F = mv²/R
F = 11.0(3.50²)/0.600 = 225 N
4. If a charged body is negatively charged, it has excess of _______
Answer:
Electrons
Explanation:
Electrons are negatively charged sub-atomic particles, therefore when a body's negatively charged, it means that there's more electrons than protons.
did the deadliest hurricanes happen recently or in the distant past
Answer:
Galveston hurricane of 1900
Explanation:
also called Great Galveston hurricane, hurricane (tropical cyclone) of September 1900, one of the deadliest natural disasters in U.S. history, claiming more than 8,000 lives.
Two forces act on a block as shown in the picture. What is the net force of the block?
30 N to the right
30 N to the left
10 N to the left 10
10 N to the right
Answer:
10 N to the left.
Explanation:
Since the forces are acting in opposite directions, you need to calculate the difference.
20 N - 10 N = 10 N
More force is being exerted to the left. Therefore, the net force is 10 N to the left.
What effect does the time taken to lift the mass have on power output?
How do we become children of Abraham and sons of God?
Answer:
we already are.
Explanation:
God created us, and we are the descendants of Abraham. if you want to choose to live against it, you'll be doing something similar to fighting a current. gods love is unfathomable. he is the only true God, and is our father in heaven.
Who actually asked Abraham to sacrifice his son?
Answer:
Allah asked Abraham(Ibrahim)
Anita Knapp needs to get hay to cows in a frozen field using an airplane flying 80.0 m/s, at a height of 300,m. If at the last minute, how far from the cow would she have to release the hay in order to hit the cow? *
Answer:
Explanation:
If we ignore wind resistance, the time needed for the hay to drop from vertical rest is
t = √(2h/g) = √(2(300)/9.81) = 7.82 s
d = vt = 80.0(7.82) = 626 m before passing over the cow.
A person is drinking a glass of soda with ice.
which option describes the relative kinetic energy of molecules in and above the soda in the glass?
A. in : least energy
above : intermediate and greatest energy
B. in : greatest energy
above : least energy
C. in : least energy
above : greatest energy
D. in least and intermediate energy
above : greatest energy
The relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.
The relative kinetic energy of gas molecules increases with increase in the mean distance between the gas molecules.
Also, relative kinetic energy of gas molecules increases with in the temperature of the gas molecules and decreases with a decrease in the temperature of the of the gas molecules;
ΔK.E ∝ T
The ice in the soda lowers the temperature of the gas molecules, thereby reducing their average speed which in turn reduces the average kinetic energy of the gas molecules in the soda.
Above the soda in the glass, the concentration of the gas molecules is less and their mean distance is greatest when compared to inside the soda. This results to an increase in the speed of the gas molecules which increases their average kinetic energy.
Thus, the relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.
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A common type of succession that occurs on a surface where an ecosystem has previously existed
As a truck rounds a curve, a box in the bed of the truck slides to the side farthest from the center of the curve. This movement of the box is a result of
Answer:
inertia .
because yes
This is physics and it says collision and elastic/inelastic i need help
The initial velocity of the 3250 Kg mass is 2.1 m/s. The distance covered by the larger mass in 5s is 4.7 cm.
In this problem, we have to apply the law of conservation of linear momentum. Note that;
Momentum before collision = Momentum after collision
m1u1 + m2u2 = m1v1 + m2v2
(2150 × 10) + (3250u1) = (2150 + 3250)5.22
21500 + 3250u1 = 5400 × 5.22
3250u1 = 28188 - 21500
u1 = 28188 - 21500/3250
u1 = 2.1 m/s
2) Again from the principle of conservation of linear momentum;
(0.40 × 3.5) + (0.60 × 0) = (0.40 × 0.70) + (0.60 × v2)
1.4 = 0.28 + 0.60v2
1.4 - 0.28 = 0.60v2
v2 = 1.87 cm/s
Using;
s = 1/2 ( u + v)t
s = 1/2(0 + 1.87) × 5
s = 4.7 cm
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please help me rn rn
Answer:
merry Christmas ⛄
Which of the following changes would decrease the force between two charged particles by a factor of 9? A. Decreasing the distance between the particles by a factor of 3 B. Increasing the distance between the particles by a factor of 3 C. Increasing the amount of charge on each particle by a factor of 9 D. Decreasing the amount of charge on one of the particles by a factor of 3
Option B is correct.Increasing the distance between the particles by a factor of 3 decrease the force between two charged particles by a factor of 9.
What is electric force?The electric force between the two charges is directly proportional to the product of the charge and inversely proportional to the square of the distance between them.
The electric force is found as;
[tex]\rm F = \frac{K q_1q_2}{r^2}[/tex]
The electric force between the two charges is directly proportional to the product of the charge.
The electric force is inversely proportional to the square of the distance between them.
Increasing the distance between the particles by a factor of 3 decreases the force between two charged particles by a factor of 9
Hence, option B is correct.
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(c) It is suggested that one side of the copper sheet cools to a lower temperature than the
other side.
Explain why this does not happen.
[2]
Answer:
Explanation:
The word "sheet" implies that the copper is quite thin.
Copper is also a very good conductor of heat.
Therefore, with a very short heat flow distance to cover and a high rate of heat transmission, temperature differences on either side of the sheet are almost instantaneously eliminated by heat flow.
During a car accident on the NJ Turnpike, the airbags deploy. A 79 kg passenger traveling at 32 m/s makes impact with the airbag over a time of 0.25 seconds. What
was the impact force experienced by the passenger?
Hi there!
Recall that:
Impulse = Δ in momentum = mΔv
Impulse = Force · time
Begin by calculating the change in momentum, or impulse.
I = mΔv = m(vf - vi)
I = (79)(0 - 32) = -2528 Ns
Now, we can use the equation relating force and time to impulse.
I = Ft
Rearrange for time:
I/F = t
-2528/0.25 = -10112 N
**OR, if magnitude ⇒ |-10112| = 10112 N
In a collision, a 30 kg ball moving at 3 m/s transfers all of its momentum to a 5kg ball. what is the velocity of the 3kg ball after the collision?
Answer:
Explanation:
Is it a 30 kg ball or a 3 kg ball?
Does not matter as we don't have to do actual calculations
If all of the momentum is transferred out of a mass, the velocity remaining must be ZERO