how much power is dissipated by an rlc network if the current through it is i = 10 a sin(ωt 30°) and the voltage across it is v = 50 v sin(ωt – 20°)?

The time lapse between when the bat emits the sound and when it hears the echo is 0.05 s.

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

Time (t) =?

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

t = 0.05 s

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s.

A bat emits a sound wave and carefully listens to the echoes that return to it. The returning information is processed by the bat's brain in the same way that we processed our shouting sound with a stopwatch and calculator. The bat's brain determines the distance of an object by measuring how long it takes for a noise to return.

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Correction question:

A bat emits a sonar sound wave (343 m/s) that bounces off a mosquito 8.42 m away. How much time elapses between when the bat emits the sound and when it hears the echo? (Unit = s)

The reasons  for the discrepancy in the experimental density of the unknown liquid agree with the true value can be instrument not having same levels , Temperature Effects , Kind of scales used and  Shape of objects used for measure .

According to the question

Discrepancy:

The state or quality of being discrepant or in disagreement, as by displaying an unexpected or unacceptable difference; inconsistency.

Density:

Density is mass per unit volume, so when measuring density, you find the mass of the object and divide it by its measured volume.

All measurements include some uncertainty, however, and certain kinds of errors can increase the uncertainty in your calculation.

The reason of discrepancy in the experimental density of the unknown liquid agree with the true value can be:

1. Use of instrument not having same levels

2. Temperature Effects as Density varies with temperature .

3. Kind of scales used for measures

4. Shape of objects used for measure .

Hence, the reasons  for the discrepancy is instrument not having same levels , Temperature Effects , Kind of scales used and  Shape of objects used for measure .

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The required spring constant:

The spring constant of the spring is [tex]12\times 10^4 \text{ N/m}[/tex].

Calculation:

The mass of the car is m=1200 kg, the speed of the car is v=25 m/s, and after colliding the spring is brought to rest at a distance of x=2.5m. Let the spring constant of the spring is, k.

From the conservation of energy,

Total initial kinetic energy= Total final potential energy of the spring

Therefore,

[tex]\frac{1}{2}mv^2=\frac{1}{2}kx^2[/tex]

Now, substituting the values of the mass of the car, speed of the car, and displacement, we get:

[tex]$$\begin{aligned}1200\times(25)^2&=k\times (2.5)^2\\\Rightarrow k&=\frac{1200\times(25)^2}{(2.5)^2}\\&=12\times 10^4 \text{ N/m}\end{aligned}$$[/tex]

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As we adjust to low light, our cone becomes nonfunctional and it may take 20-30 min for rhodopsin to become regenerated sufficiently so that you can see well in low-light conditions.

The most prevalent protein in the retinal rod cells is rhodopsin, a G-protein coupled receptor. It consists of two components: an opsin molecule connected to an 11-cis-retinal chromophore, which serves as the main photoreceptor molecule of vision. When a photon of light excites 11-cis retinal, rhodopsin is linked to it. This isomerizes into an all-trans conformation.

Rhodopsin is crucial to our ability to see in low light because it enables the rods in our eyes to receive photons and detect light. As rhodopsin absorbs a photon, it separates into a retinal and an opsin molecule before slowly and at a constant rate recombining back into rhodopsin. But because this happens gradually, it takes some time for our eyes to get used to the dark. For humans, acclimating to the dark takes roughly 20 to 30 minutes.

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A vehicle that weights 400 n on the surface of the earth is traveling in outer space at a speed of 400 m/s. It can be stopped by applying a constant force of 20 n for 800 secs.

Newtons 3 law whilst one object exerts pressure on any other object, the second object exerts a force on the first item this is identical in significance, but opposite in course; for each movement, there is an identical, but opposite response; referred to as the law of action-reaction.

You can use the equal formulation d = rt because of this distance equals the price instance's time. To solve for speed or rate use the components for pace, s = d/t this means that pace equals distance divided by way of time. To clear up for time use the components for time, t = d/s this means that time equals distance divided by way of velocity.

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The accurate about the planet’s climate system is the wind

because heating near the equator blows the wind to drive the convection cells in the atmosphere, and the friction created by the rotation of the spherical planet in the atmosphere causes the wind to appear to bend left or right across the surface of the planet. ..

The climate system is a highly complex global system consisting of five major components: the atmosphere, the ocean, the cryosphere (cryosphere), the land surface, the biosphere, and the interactions between them.

Solar energy drives the climate by heating the surface of the earth unevenly. Ice also reflects incoming sunlight, further cooling the poles. Temperature differences move the ocean and atmosphere as they work together to disperse heat throughout the globe.

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Among the given objects, the largest one is dwarf elliptical, then ultra-compact dwarf and then globular clusters. Thus, option a is correct.

To find the correct answer, we need to know about the galaxies.

Thus, we can conclude that, option a is correct.

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1. The time taken to discharge to 2 V is 2×10⁻⁹ s

2. The time taken to discharge to 1 V is 5×10⁻¹⁰ s

The energy stored in a capacitor is given by

E = ½CV²

But

E = Pt

Thus,

Pt = ½CV²

Where

With the formula (Pt = ½CV²), we can determine the time in each case. Detail below:

Data obtained from the question include:

Pt = ½CV²

100 × t = ½ × 1×10⁻⁷ × 2²

Divide both sides by 100

t = (½ × 1×10⁻⁷ × 2²) / 100

t = 2×10⁻⁹ s

Thus, the time required to discharge to 2 V is 2×10⁻⁹ s

Data obtained from the question include:

Pt = ½CV²

100 × t = ½ × 1×10⁻⁷ × 1²

Divide both sides by 100

t = (½ × 1×10⁻⁷ × 1²) / 100

t = 5×10⁻¹⁰ s

Thus, the time required to discharge to 1 V is 5×10⁻¹⁰ s

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Answer:

The direction of the net force is at a tangent to the circle.

The distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n because:

In an atom, an electron is known to be attracted to a given nucleus by the use of "electromagnetic force".

Note that  similar to a baseball, the faster the electron is said to go, the farther away from the nucleus it is known to be seen. Therefore, the electrons in an atom are known to be in a state where they are moving a lot and very fast, so they are said to be far away from their nucleus.

Note also that energy difference between what we call consecutive levels tends to often decreases as well as increases.

Therefore, The distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n because:

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See full question below

Consider the hydrogen atom. How does the distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n?

The distance difference between adjacent orbit radii varies with increasing values of the principal quantum number.

The distance difference between adjacent orbit radii increases with increasing values of the principal quantum number.

The distance difference between adjacent orbit radii remains constant with increasing values of the principal quantum number.

The distance difference between adjacent orbit radii decreases with increasing values of the principal quantum number.

Answer:

5 years

Explanation:

[tex]\frac{1}{8}(40)\\\\= 5[/tex]

noob anyways I can't get u vape because first reason I lost ur money and second I felt bad for losing ur and I will not on yourself as I am thinking of a number my number is a multiple of 6.What other numbers must my number is a multiple of 6.What other numbers

While measuring , there are a lot of errors which can happen due to which ""true distances"" be different for different groups even though they are measuring the same distance.

While measuring , there are a lot of errors which can happen , to find the most correct value in order to make the result precise and accurate number of measurements needed to be done in order to reduce the error

As nothing can be measured with full precision and accuracy, different measurements for different groups even though they are measuring the same distance.

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Answer:

350x^2

Explanation:

I'm assuming you're saying you're using them together, like stacking them on top of each other, so if that's the case then this is a simple multiplication problem, which can be written as 10x(35x). Solve it and you get 350x^2.

Lamp Wattage is utilized with a CU of 0.75 and 80 percent of the available light reaches the work surface, the remaining 20 percent is absorbed by walls and other objects in the space, resulting in an illumination level of 50 f-c over a 100 ft2 area

The term "lumen" refers to the emission of "luminous flux," which is a measurement of the total amount of visible light emitted by a source in a certain amount of time. The illumination level over a 100 ft2 area will be 50 f-c Lamp Wattage with a CU of 0.75 used, with 80 percent of the available light reaching the work surface and the remaining 20 percent being absorbed by walls and other objects in the room.
Total Lamp Wattage = Number of Lamps X Wattage of Each Lamp.
The fixtures' total wattage is 2 x 32, or 64 watts.
Lumen per Fixtures equals Lumen Efficiency (Lumen per Watt) times the Watt of each Fixture
85x 64 = 5440 lumens per fixture.

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Answer:

F = K Q1 Q2 / R^2 = m g

Q1 = - Q2 = (4E12 * 1.60E-19) = 6.4E-7   coulombs

Q^2 = 4.10E-13

R^2 = 9.0E9 * 4.1E-13 / (.003 * 9.80) = 36.9E-4 / 2.94E-2

R^2 = .126

R = .35 m

F = K Q1 Q2 / R^2 = m g, Q1 = - Q2 = (4E12 * 1.60E-19) = 6.4E-7   coulombs Q^2 = 4.10E-13, R^2 = 9.0E9 * 4.1E-13 / (.003 * 9.80) = 36.9E-4 / 2.94E-2 R^2 = .126 and R = .35 m.

Due to their electric charges, particles can be attracted to or repelled by electrostatic forces. This force is also known as the Coulomb force or Coulomb contact, and it was first described in 1785 by French physicist Charles-Augustin de Coulomb.

Over a distance of 10-16 meters, or roughly one-tenth the diameter of an atomic nucleus, the electrostatic force is present. While opposite charges attract one another, like charges repel one another.

For instance, two positively charged protons, two negatively charged electrons, or two anions all repel one another. Cation and anions, as well as protons and electrons, are all attracted to one another.

Therefore, F = K Q1 Q2 / R^2 = m g, Q1 = - Q2 = (4E12 * 1.60E-19) = 6.4E-7   coulombs Q^2 = 4.10E-13, R^2 = 9.0E9 * 4.1E-13 / (.003 * 9.80) = 36.9E-4 / 2.94E-2 R^2 = .126 and R = .35 m.

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The period of a satellite, the time it takes for a complete revolution, depends on the satellite's mass of planet and the distance of satellite form center of the planet .

According to the question

The period of a satellite, the time it takes for a complete revolution, depends on the satellite's:

1. The mass of the planet being orbited

2. The distance of the satellite from the center of the planet.

Hence, The period of a satellite, the time it takes for a complete revolution, depends on the satellite's mass of planet and the distance of satellite form center of the planet .

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The efficiency of the machine is determined as 83.3 %.

M.A = load/Effort

M.A = 4500/900 = 5

V.R = distance moved by effort/distance moved by load

V.R = 6/1 = 6

E = M.A/V.R x 100%

E = (5/6) x 100%

E = 83.3 %

Thus, the efficiency of the machine is determined as 83.3 %.

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Frictional force provided by the teeth of the boots which are in contact with the grass in the soccer pitch enables the soccer player to start running and prevents him from slipping and falling.

Friction is the opposition to the relative motion of one object over another at their surface of contact.

Friction is a type of contact force as it requires between the two objects for its effect to be felt.

Friction has both advantages and disadvantages.

On of the advantages of friction is in the ability to walk or run. Friction between the ground and the foot or the boots of a person walking or running enables the person from slipping.

For example, when a soccer player runs with soccer boots, friction enables the runner to start running and prevents him from slipping and falling. The friction is provided by the teeth of the boots which are in contact with the grass in the soccer pitch.

In conclusion, friction enables a soccer player to start running and also prevents him from falling.

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The graphical representation of Tara is correct because of energy of the wave depends on the amplitude of the wave.

The energy of a wave due to the motion of a spring is calculated as follows;

E = ¹/₂KA²

where;

Thus, the graphical representation of Tara is correct because of energy of the wave depends on the amplitude of the wave.

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Answer:  No, it is not correct because as the amplitude of a wave increases, the energy it carries also increases. This graph shows that as the amplitude increases, the energy decreases.  

Explanation:

About 4.5 mol of water will be created when the platinum-based engine is run continuously at 300 K for an hour with 0.5 atm of H2 and 0.5 atm of O2 injected for each reaction.

For fuel cell engines' electrodes, platinum is a requirement. It acts as an electrocatalyst to speed up the electrochemical reactions needed to induce H2 to release electrons and form H2 ions when it is placed on porous electrodes.

Platinum is particularly well suited as a fuel cell catalyst because it makes it possible for the hydrogen and oxygen reactions to occur at an ideal rate and because it is stable enough to withstand both the intense electrical current density and the complex chemical environment found inside a fuel cell. This allows platinum to function effectively over an extended period of time.

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Clouds of gas in space

A protostar resembles a star, but its core is still too cool for fusion to occur. The protostar's heating as it contracts is the only source of brightness. The light that protostars release is typically blocked by dust, making them challenging to study in the visible spectrum.

By the time a protostar is produced, the cloud has flattened and a protostellar disk is spinning around it. The cloud starts spinning as it collapses. These disks occasionally form planetary systems and are thought to slow the protostar's rotation. The protostar produces a powerful magnetic field as it revolves.

Additionally, a strong protostellar wind—a movement of particles into space—is produced by the magnetic field. A lot of protostars also release gas into space in the form of fast-moving streams or jets.

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Voltage-gated calcium ion channels that function in neurotransmission are primarily found on the: excitable cells

A neurotransmitter is the body’s chemical messenger. They are molecules that transmit signals from neurons to muscles, or between different neurons. The transmission of signals between two neurons occurs in the synaptic cleft.

The electrical signals that travel along the axon are briefly converted into chemical signals through neurotransmitters.

Voltage-gated calcium (Ca2+) channels are key transducers of membrane potential changes into intracellular Ca2+ transients that initiate many physiological events. There are ten members of the voltage-gated Ca2+ channel family in mammals, and they serve distinct roles in cellular signal transduction.

They are found in excitable cells, not only in motor neurons but also in other types of excitable cells .

Voltage-gated calcium channels are important mediators of depolarization-evoked release of neurotransmitters. To ensure efficient coupling of calcium influx to rapid vesicle release, calcium channels must be localized within the active zones of presynaptic nerve terminals

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Answer: Speeding up the orbital speed of earth so it escapes the sun require the greater energy.

Explanation: To find the answer, we need to know more about the Orbital and escape velocities.

                   [tex]V_o=\sqrt{gR}[/tex]

                    [tex]V_e=\sqrt{2gR}[/tex]

Thus, we can conclude that, the speeding up the orbital speed of earth so it escapes the sun require the greater energy.

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Answer:

a = v^2 / R        where a is the centripetal acceleration and R the radius

v = 2 π R N / t        where (N / t) is the revolutions / sec giving distance / time

a = 4 g         horizontal acceleration

4 g = (2 π R N / t)^2 / R = 4 π^2 * R * (N / t)^2

(N / t)^2 = g / (π^2 * R)

N / t = 1 /  π * (g / R)^1/2 = .318 * (9.80 m / s^2 / 8 m)^1/2  = .352 / sec

The radial velocity method preferentially detects large planets close to the central star

The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.

This is due to the fact that low mass stars are more affected by the gravitational tug of planets.

When a planet orbits around a star, the star wobbles a little.

From this, we can determine the mass of the planet and its distance from the star.

hence we can say that,

option D is correct.

The radial velocity method preferentially detects large planets close to the central star

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Answer:

(-3, -3√3)

Explanation:

To convert from polar coordinate to rectangular coordinate, first you have to know these two equations:

[tex]\displaystyle{x=r\cos \theta}\\\displaystyle{y=r\sin \theta}[/tex]

We know that (x,y) is in rectangular coordinate form while (r,θ) is in polar coordinate form.

Therefore, substitute r = 6 and θ = 240° in both equations:

[tex]\displaystyle{x=6\cos 240^{\circ}}\\\displaystyle{y=6\sin 240^{\circ}}[/tex]

After evaluating, you'll get:

[tex]\displaystyle{x=-3}\\\displaystye{y=-3\sqrt{3}}[/tex]

Therefore, substitute x and y in rectangular coordinate form - hence, the answer is (-3, -3√3)

The magnetic field is responsible for levitating the hoverboard and rider as it traverses the half pipe.

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The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.

What is visual magnitude?

The brightness of a celestial body is determined by eye estimation with or without optical aid or by other instrumentation equivalent to the eye in spectral sensitivity.

Apparent magnitude:

Hence,

The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.

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The magnitude of the initial velocity of the ball relative to the ground is 9.3 m/s.

Relative velocity is the velocity of an object relative to another moving in the same plane. On frame of reference is used when measuring relative velocity.

The velocity of the ball relative to the ground  is the sum of the velocity of the ballistic cart and the velocity in which the ball is ejected.

The velocity of the ball relative to the ground = 6.5 m/s + 2.8 m/s = 9.3 m/s

In conclusion, relative velocity measures the velocity of an object from a reference point.

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