How much energy is required to melt 2 kg of gold? Use the table below and this equation.
a. 125.6 kJ
b. 1729 kJ
c. 10.4 kJ
d. 3440kJ
​

Answer:

carrying capacity

Explanation:

Thus, the carrying capacity is the maximum number of individuals of a species that an environment can support. Population size decreases above carrying capacity due to a range of factors depending on the species concerned, but can include insufficient space, food supply, or sunlight.

Answer:

The lipid bilayer made up of Palmitic acid will have a higher melting transition temperature

Explanation:

The one with a higher melting transition temperature is the lipid layer with a higher melting temperature

Melting temperature of palmitoleic acid = -0.5°C

Melting temperature of palmitic acid = 62.9°C

Hence the lipid bilayer made up of Palmitic acid will have a higher melting transition temperature

Answer:

D) caring capacity

Explanation:

Answer:

D)

Explanation:

The largest population that an environment can support is by definition a carrying capacity

Answer:

verdadero/a

falso/b

verdadero/c

Explanation:

Adding a catalyst would increase the rate of a reaction

Answer:

323.15 or just 323 depending on the teacher

Answer:

The more electronegative atom in a covalent bond

Answer:

pH = 4.71

Explanation:

We can find the pH of a buffer (Mixture of weak acid: CH3COOH, and its conjugate base: CH3COONa) using H-H equation:

pH = pKa + log [CH3COONa] / [CH3COOH]

Where pH is the pH of the buffere = 4.74, pKa the pka of the buffer and [] could be taken as the moles of each reactant.

As initially [CH3COONa] = [CH3COOH], [CH3COONa] / [CH3COOH] = 1:

pH = pKa + log 1

4.74 = pKa

To solve this question we need to find the initial moles of each species, The CH3COONa reacts with HCl to produce CH3COOH. That means the moles of CH3COOH after the reaction are: Initial CH3COOH + Moles HCl

Moles CH3COONa: Initial CH3COONa - Moles HCl.

Moles CH3COOH:

0.100L * (0.50mol / L) = 0.050 moles CH3COOH + 0.0020 moles HCl =

0.052 moles CH3COOH

Moles CH3COONa:

0.100L * (0.50mol / L) = 0.050 moles CH3COONa - 0.0020 moles HCl =

0.048 moles CH3COONa

Using H-H equation:

pH = 4.74 + log [0.048 moles] / [0.052 moles]

The pH be after 0.0020 mol of HCl has been added to 100.0 mL of the buffer is 4.71.

Buffer solution is a mixture of weak acid and its conjugate base or vice versa.

We can calculate the pH of buffer solution by using Henderson - Hasselbalch Equation:

pH = pKa + log[CH₃COONa] / [CH₃COOH]

Initially concentration of CH₃COONa is equal to the concentration of CH₃COOH and equal becomes:

4.74 = pKa + log(1)

pKa = 4.74

Given moles of added HCl moles = 0.002 mole

Given molarity of each CH₃COOH & CH₃COONa = 0.50M

Given Volume = 100mL

We can calculate the moles by using the formula:

n = M × V

Moles of CH₃COOH & CH₃COONa = 0.100 × 0.50 = 0.050 moles

Moles of CH₃COOH = 0.050moles CH₃COOH + 0.0020moles HCl =

0.052moles CH₃COOH

Moles of CH₃COONa = 0.050moles CH3COONa - 0.0020moles HCl =

0.048moles CH₃COONa

Now, resultant pH will be:

pH = 4.74 + log [0.048 moles] / [0.052 moles]

pH = 4.71

Hence, pH of resultant solution is 4.71.

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Answer:

yes is very possible to be

Answer:

1.56 mol H₂

Explanation:

Mg₃(Si₂O₅)₂(OH)₂

There are 4 Si moles per Mg₃(Si₂O₅)₂(OH)₂ mol. With that in mind we can calculate how many Mg₃(Si₂O₅)₂(OH)₂ moles are there in the sample, using the given number of silicon moles:

Then we can convert Mg₃(Si₂O₅)₂(OH)₂ moles into hydrogen moles, keeping in mind that there are 2 hydrogen moles per Mg₃(Si₂O₅)₂(OH)₂ mol:

Answer:

Close to the calculated endpoint of a titration - Partially open

At the beginning of a titration - Completely open

Filling the buret with titrant - Completely closed

Conditioning the buret with the titrant - Completely closed

Explanation:

'Titration' is depicted as the process under which the concentration of some substances in a solution is determined by adding measured amounts of some other substance until a rection is displayed to be complete.

As per the question, the stopcock would remain completely open when the process of titration starts. After the buret is successfully placed, the titrant is carefully put through the buret in the stopcock which is entirely closed. Thereafter, when the titrant and the buret are conditioned, the stopcock must remain closed for correct results. Then, when the process is near the estimated end-point and the solution begins to turn its color, the stopcock would be slightly open before the reading of the endpoint for adding the drops of titrant for final observation.

The various factors that impact the solubility of substances in water are - nature of solute and solvent, temperature, pressure and pH.

The solubility of substances in water is influenced by several factors:

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Answer:

(a) The potential near its surface is 45 * 10^6 V.

(b) The distance from which its center is the potential 1.00 MV is 45 m.

(c) Its energy in MeV when the atom is at the distance found in part b is 132 MeV.

Explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question.

A research Van de Graaff generator has a 2.00-m diameter metal sphere with a charge of 5.00 mC on it. (a) What is the potential near its surface?

(b) At what distance from its center is the potential 1.00 MV?

(c) An oxygen atom with three missing electrons is released near the Van de Graaff generator. What is its energy in MeV when the atom is at the distance found in part b?

The explanation of the answer is now provided as follows:

(a) What is the potential near its surface?

Q = Charge on the generator = 5 mC = 5 * 10^(-3)C

r = Sphere radius = 2 / 2 = 1 m

k = Constant of the electric force = 9 * 10^(9) N . m^2 / C^2

Therefore, the electric potential of a point charge can be calculated as follows:

V = kQ / r

V = (9 * 10^9 * 5 * 10^(-3)) / 1 = 45 * 10^6 V

Therefore, the potential near its surface is 45 * 10^6 V.

(b) At what distance from its center is the potential 1.00 MV?

This implies the distance where the potential is 1 MV.

Since the electric potential of a point charge is as follows:

V = kQ / r

Therefore, we can solve for r and estimate it as follows:

R = kQ / V = (9 * 10^9 * 5 * 10^(-3)) / 1 * 10^6 = 45 m

Therefore, the distance from which its center is the potential 1.00 MV is 45 m.

(c) An oxygen atom with three missing electrons is released near the Van de Graaff generator. What is its energy in MeV when the atom is at the distance found in part b?

The link between the potential difference and electrical potential energy can be stated as follows:

ΔV = ΔU / q

Therefore, we have:

ΔU = qΔV = q(Va - Vb) = 3 * (45 – 1) = 132 MeV

Therefore, its energy in MeV when the atom is at the distance found in part b is 132 MeV.

Answer:

See explanation

Explanation:

Since we have to fill five subshells in moving from Og to the next noble gas in the eight period, we have to know the maximum electrons contained in each of those subshells;

s= 2, p=6, d= 10, f= 14, g = 18

This means that we need a total of 50 electrons to fill all the five subshells.

Hence, the element just below Sg in the eight period will have an atomic number of 156.

Refer to the attachment.

Hope this helps you...

Answer:

The average mass of one atom of arsenic is 74.92 amu, and the mass of one mole of arsenic atoms is 74.92 grams.

The mass of one mole of arsenic atoms is 74.92 grams.

Calculation,

Mass of one mole of arsenic = Mass of 1 arsenic atom × [tex]N_{A}[/tex]

Where, [tex]N_{A}[/tex] = Avogadro's number = 6.022 × [tex]10^{23}[/tex]

Mass of one arsenic atom = 74.921 u

One u =  1.66 × [tex]10^{-27}[/tex] kg

And,

Mass of one mole of arsenic atom = 6.022 ×[tex]10^{23}[/tex] × 74.921 × 1.66 × [tex]10^{-27}[/tex]×[tex]10^{3}[/tex] kg

Mass of one mole of arsenic atom = 74.92 [tex]gmol^{-1}[/tex]

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Answer:

N 2 H4

Explanation:

Answer:

C2H3O3

Explanation:

Empirical formula is the simplest whole number ratio of moles of atoms that you can find in a molecule.

In combustion analysis all Carbon reacts producing CO2 and all hydrogen reacts producing H2O. With the differences in masses we can find the mass of oxygen and their moles:

Moles CO2 = Moles C:

14.08g * (1mol/44.01g) = 0.3199 moles C * (12.01g/mol) = 3.8423g C

Moles H2O:

4.32g H2O * (1mol/18.01g) = 0.2399 moles H2O * (2mol H / 1molH2O) = 0.4797moles H = 0.4797g H

Mass O:

12.01g = Mass O + 3.8423g C + 0.4797g H

Mass O = 7.688g O

Moles O:

7.688g O * (1mol/16g) = 0.48 moles O

The ratio of atoms (Dividing in the moles of C that are the lower number of moles):

O: 0.48moles O / 0.3199 moles C = 1.50

C: 0.3199 moles C / 0.3199 moles C = 1

H: 0.4797 moles H / 0.3199 moles C = 1.50

As empirical formula requires whole numbers:

O: 1.50* 2 = 3

C: 1*2 = 2

H: 1.50*2 = 3

The empirical formula is:

Answer:

n = 2.23 moles

Explanation:

Given the following data;

Standard temperature = 273 K

Standard pressure = 101.325 kPa

Volume = 50 liter

R = 8.314 J/mol·K  

To find the number of moles, we would use the ideal gas law formula;

PV = nRT

Where;

Making n the subject of formula, we have;

[tex] n = \frac {PV}{RT} [/tex]

Substituting into the formula, we have;

[tex] n = \frac {101.325*50}{8.314*273} [/tex]

[tex] n = \frac {5066.25}{2269.722} [/tex]

n = 2.23 moles

Therefore, 2.23 moles of carbon dioxide at STP will fit in a 50 liter container.

Answer:

2 lone pairs, bent

Explanation:

According to the Valence Shell Electron Pair Repulsion Theory, the number of electron pairs on the valence shell of the central atom in a molecule influences the shape of the molecule.

The presence of lone pairs on the valence shell of the central atom causes the observed molecular geometry to deviate from the ideal geometry predicted on the basis of the valence shell electron pair repulsion theory.

SCl2 has four regions of electron density. This means that its electron domain geometry is tetrahedral. However, there are two lone pairs on the valence shell of the central atom hence the observed molecular geometry is bent.

Answer:

1.714 M

Explanation:

We'll begin by calculating the number of mole in 46.8 g of NaHCO₃. This can be obtained as follow:

Mass of NaHCO₃ = 46.8 g

Molar mass of NaHCO₃ = 23 + 1 + 12 + (3×16)

= 23 + 1 + 12 + 48

= 84 g/mol

Mole of NaHCO₃ =?

Mole = mass / molar mass

Mole of NaHCO₃ = 46.8 / 84

Mole of NaHCO₃ = 0.557 mole

Next, we shall convert 325 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

325 mL = 325 mL × 1 L / 1000 mL

325 mL = 0.325 L

Thus, 325 mL is equivalent to 0.325 L.

Finally, we shall determine the molarity of the solution. This can be obtained as shown below:

Mole of NaHCO₃ = 0.557 mole

Volume = 0.325 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.557 / 0.325

Molarity = 1.714 M

Therefore the molarity of the solution is 1.714 M

Answer:

the discovery will always need to be tested more where if you're investigating you should already be in a more controlled environment

The difference between accidental discoveries and scientific investigations are as follows.

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Answer:

1) Greater than zero, and equal to the rate of the reverse reaction

2) Greater than zero, but less than the rate of the reverse reaction

3) Greater than zero, and equal to the rate of the reverse reaction

Explanation:

A reaction system is said to be in equilibrium when the rate of forward reaction is equal to the rate of reverse reaction.

Before we remove HCH3CO2 from the system, the system was in equilibrium. Recall that when a system is in equilibrium, the rate of forward reaction is equal to the rate of reverse reaction. The rate of reaction is greater than zero because products are being formed as the reactants interact with each other.

When HCH3CO2 is removed from the system, the equilibrium position shifts towards the left hand side hence the rate of reverse reaction is greater than the rate of forward reaction.

When the system attains equilibrium again, the rates of forward and reverse reaction become equal.

Answer:

none All have the same kinetic energy

Explanation:

0.152 moles

The mass of the oxygen gas produced = 4.87 g

Also, The molar mass of oxygen gas,  =  = 32 g/mol

The formula for the calculation of moles is shown below:

moles = [tex]\frac{Mass-taken}{Molar-mass}[/tex] *

Thus,

moles = [tex]\frac{4.87g}{32g/mol }[/tex]

Both given values and the answer is in 3 significant digits.

brainlist pls?

*i put a dash between mass and taken as formulas do no spaces

hope the picture above helps :)

Answer:

3KOH(aq) + FeCl3(aq) --------> Fe(OH)3 + 3KCl

Explanation:

The rule for balancing chemical equations is that the number of atoms of each element must be the same on both sides of the reaction equation.

Hence, the two reactants are potassium hydroxide and aqueous iron(III) chloride.

The balanced molecular reaction equation is;

3KOH(aq) + FeCl3(aq) --------> Fe(OH)3 + 3KCl

Answer:

F. When everyone is together it gets hotter

Explanation:

Answer:

c. it lies near the equator