how many percent closer object in water looks?

Answers

Answer 1

Object appears 33% closer in water, this is due to the refractive index of water.

When a ray of light passes through an optically denser medium from an optically rarer medium, it gets bent towards the normal. This is called the refraction of light. This is due to the different speeds of light in different mediums of different optical densities.

Refractive index of a substance is the ratio of the speed of light in a vacuum to the speed of light in the substance. Mathematically

Refractive index = speed of light in vacuum/speed of light in substance

Refractive index of water is 1.33. It means the distance travelled by the light in a vacuum is 1.33 times more than that of in water.

So object appears (1.33d × 100)/d = 33% closer

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Related Questions

repeated reference is made in ewr and the nec® to limit the length of ""fixture whips"" to 6 feet. what is the significance of this 6-foot limitation?

Answers

A “fixture whips” longer than 6 feet are required to be supported and grounded per the NEC ®for that wiring method.

What is Length ?

Length is a term used to describe the distance between two points on an object or the dimension of an object along a particular axis.  Length is usually measured in units of distance, such as meters, centimeters, inches, or feet .

In physics, length is an important concept used to describe the size of objects, the distance between two points, or the dimensions of a space. In engineering and construction, length is used to design and build structures, such as bridges and buildings, to ensure they are safe and fit for their intended purpose.

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earth carries a net charge of about -5.0× 105 c . how many more electrons are there than protons on earth?

Answers

The net charge of the Earth is [tex]-5.0 x 10^5[/tex] coulombs, which means that the Earth has a net negative charge. This net negative charge is due to the presence of more electrons than protons on the Earth.

A coulomb is the unit of electric charge and is used to measure the amount of electric charge in an object. The charge of an electron is [tex]-1.6 x 10^-19[/tex]coulombs, and the charge of a proton is[tex]+1.6 x 10^-19[/tex]coulombs. These charges are equal in magnitude but opposite in sign, meaning that the charge of an electron is the exact opposite of the charge of a proton.

Since the Earth has a net negative charge, this means that there are more electrons than protons on the Earth. To calculate the exact number of extra electrons, we would need to know the magnitudes of the individual charges of electrons and protons. However, as a rough estimate, we can assume that the charges of electrons and protons are equal in magnitude and opposite in sign, so the number of extra electrons would be approximately equal to the net charge of Earth divided by the charge of a single electron.

Therefore, the estimated number of extra electrons is:

[tex](-5.0 x 10^5) / (-1.6 x 10^-19) = 3.125 x 10^24[/tex]

So, there are approximately [tex]3.125 x 10^24[/tex] more electrons than protons on Earth.

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This problem is designed to illustrate the superposition principle and the concepts of modulated and modulating functions in a wave packet. Consider two wave functions ψ1(y, t) = 5y cos 7t and ψ2(y, t) = −5y cos 9t, where y and t are in meters and seconds, respectively. Show that their superposition generates a wave packet. Plot it and identify the modulated and modulating functions.

Answers

The modulated function is A(y) = 5y and the modulating function is ω = -2.

The superposition of the two given wave functions is given by:

ψ(y, t) = ψ1(y, t) + ψ2(y, t)

 = (5y cos 7t) +(- 5y cos 9t)

The wave packet generated by the superposition of the two wave functions is given by:

ψ(y, t) = A(y)cosωt

 = 5y(cos7t - cos9t)

Where A(y) = 5y is the modulated function and ω = (7 - 9) = -2 is the modulating function.

The wave packet is as shown:Wave packet plot

The  wave packet generated by the superposition of the two given wave functions.

Therefore,The modulated function is A(y) = 5y and the modulating function is ω = -2.

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a sine wave has a frequency of 50 khz. how many cycles does it complete in 10ms

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The sine wave completes 500 cycles in 10 ms.

To calculate the number of cycles completed by a sine wave, we need to know its frequency and the time interval.

Given:

Frequency = 50 kHz

Time interval = 10 ms

First, we need to convert the frequency to cycles per second (Hz) since the time interval is given in seconds. We know that 1 kHz = 1000 Hz.

Frequency = 50 kHz

Frequency = 50,000 Hz

Next, we can calculate the number of cycles using the formula:

Number of cycles = Frequency x Time interval

Number of cycles = 50,000 Hz x 10 ms

Number of cycles = 500 cycles

Therefore, the sine wave completes 500 cycles in 10 ms.

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What is a valid Lewis dot structure?

Answers

Answer: A valid Lewis dot structure shows all the non-zero formal charges, satisfies the octet rule for each atom, and contains the correct number of atoms and valence electrons

Explanation:

Answer:

shows all non-zero formal charges, satisfies the octet rule for each atom, and contains the correct number of atoms and valence electrons.

Explanation:

An object has a kinetic energy of 12750 J and a mass of 268 kg, how fast is the object
moving?

Answers

Put the values into kinetic energy multiplication now. The V-shape has a value of 25 when divided by 500 jewels. 25, or 5 squared. Now, 1000 divided by 25 results in a weight of 40 kg. Therefore, the item will have a 40 kg mass.

A 478 kilogram object moving at a 15 m/s speed has how much kinetic energy?

53775 joule We calculate the kinetic energy to be 53775 joules. This is the necessary response.

What is kinetic energy's mathematical equation?

Kinetic energy has the following formula: K.E. = 1/2 m v2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kilograms-meters squared per second squared if the mass is measured in kilograms and the velocity is measured in meters per second.

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What information is needed to calculate the gravitational force of an object?

Answers

By applying the known acceleration caused by gravity and this rule, we may determine the effects of gravity of any item on the surface of the planet.

What determines an object's gravitational pull?

The size of this force is determined by the weight of each item and the separation of their centers. According to mathematics, the gravity force is proportional to the square of the distance between both the objects and directly related to the masses of the items.

How can you figure out an object's gravitational acceleration?

An object is drawn toward the earth's core by the force of gravity. The acceleration brought on by gravity is 9.8 m/s2 on earth. The formula used to determine.

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