The required value of velocity 50 mi/h when converted to m/s is calculated to be 22.3 m/s.
mi/h is known as miles/hour. It is the unit of speed expressing number of miles travelled in one hour.
It is known that, 1 mi = 1609 m
And 1 hour = 60 min = 60 × 60 sec = 3600 sec
Now, let us convert 50 mi/h to m/s.
1 mi/h = 1609 m/3600 s = 0.446 m/s
Here, we are asked to convert 50 mi/h to m/s.
So, 50 mi/h = 50 × 0.446 m/s = 22.3 m/s
Thus, the required value of 50 mi/h when converted to m/s is 22.3 m/s.
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with what magnitude of velocity does it strike?
The velocity with which the sandbag strikes the ground is -28.44m/s (downward).
Given the initial velocity of balloon (u) = 5m/s
The height of balloon (h) = 40m
The acceleration is due to the gravity = g = 9.8m/s^2 acting downwards.
A sandbag is released from height h of the balloon.
The velocity of sandbag as it reaches the ground = v
We know that from Newtons laws of motion v = u + at
We know that the bag strikes the ground at y =0m,
then y = h + ut - 1/2gt^2
0 = 40 + 5t - 1/2 x 9.8 x t^2
t = 3.41s
As we know that v = u - gt
v = 5 - 9.8 x 3.41 = -28.44m/s
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complete question: A hot-air balloonist, rising vertically with a constant velocity of magnitude 5.00m/s releases a sandbag at an instant when the balloon is 40.0m above the ground. With what magnitude of velocity does it strike the ground?
what is the velocity when t=6 and the position when t=11 is?
The velocity of the particle when t = 6 s is 0 m/s, and its position when t = 11 s is 165 m.
What is the velocity function?To find the velocity of the particle when t = 6 s, we need to integrate the acceleration function with respect to time. The velocity function v(t) is the indefinite integral of the acceleration function a(t) with respect to time.
v(t) = ∫a(t) dt = ∫(2t - 6) dt = t² - 6t + C
where C is the constant of integration. To find the value of C, we need to use an initial condition, such as the velocity of the particle when t = 0. If the particle starts from rest, then v(0) = 0, so we can find the value of C:
0 = 0² - 6 × 0 + C
C = 0
Therefore, the velocity function is:
v(t) = t² - 6t
So the velocity of the particle when t = 6 s is:
v(6) = 6² - 6 × 6 = 0
To find the position of the particle when t = 11 s, we need to integrate the velocity function with respect to time. The position function x(t) is the indefinite integral of the velocity function v(t) with respect to time.
x(t) = ∫v(t) dt = ∫(t² - 6t) dt = (1/3)t³ - 6(1/2)t² + C
where C is the constant of integration. To find the value of C, we need to use an initial condition, such as the position of the particle when t = 0. If the particle starts from rest, then x(0) = 0, so we can find the value of C:
0 = (1/3) × 0³ - 6(1/2) × 0² + C
C = 0
Therefore, the position function is:
x(t) = (1/3)t³ - 6(1/2)t²
So the position of the particle when t = 11 s is:
x(11) = (1/3) × 11³ - 6(1/2) × 11² = 165 m.
Therefore, the velocity of the particle when t = 6 s is 0 m/s, and its position when t = 11 s is 165 m.
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The complete question is as follows:
The velocity of the particle when t = 6 s is 0 m/s, and its position when t = 11 s is 165 m.
What is the velocity function?
To find the velocity of the particle when t = 6 s, we need to integrate the acceleration function with respect to time. The velocity function v(t) is the indefinite integral of the acceleration function a(t) with respect to time.
v(t) = ∫a(t) dt = ∫(2t - 6) dt = t² - 6t + C
where C is the constant of integration. To find the value of C, we need to use an initial condition, such as the velocity of the particle when t = 0. If the particle starts from rest, then v(0) = 0, so we can find the value of C:
0 = 0² - 6 × 0 + C
C = 0
Therefore, the velocity function is:
v(t) = t² - 6t
So the velocity of the particle when t = 6 s is:
v(6) = 6² - 6 × 6 = 0
To find the position of the particle when t = 11 s, we need to integrate the velocity function with respect to time. The position function x(t) is the indefinite integral of the velocity function v(t) with respect to time.
x(t) = ∫v(t) dt = ∫(t² - 6t) dt = (1/3)t³ - 6(1/2)t² + C
where C is the constant of integration. To find the value of C, we need to use an initial condition, such as the position of the particle when t = 0. If the particle starts from rest, then x(0) = 0, so we can find the value of C:
0 = (1/3) × 0³ - 6(1/2) × 0² + C
C = 0
Therefore, the position function is:
x(t) = (1/3)t³ - 6(1/2)t²
So the position of the particle when t = 11 s is:
x(11) = (1/3) × 11³ - 6(1/2) × 11² = 165 m.
Therefore, the velocity of the particle when t = 6 s is 0 m/s, and its position when t = 11 s is 165 m.
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The complete question is as follows:
enter an expression for the total time of flight of the ball: the time from when it is launched to when it lands back on the ground. express this time in terms of vi and a.
"The expression for the total time of flight when the object is released from ground level is t = (2u sinθ)/(g)."
Applying the second kinematic equation yields the expression for the total duration of flight, as given below.
As the object is released from a height of h,
h = vt + ¹/₂ gt²
where;
h is said to be the height of fall of the object
v is the initial vertical velocity of the object
g is acceleration due to gravity
t is the time of flight
As the ball is elevated above the ground,
t = (2u sinθ)/(g)
where,
u is the initial velocity
θ is the direction of the velocity
g is acceleration due to gravity
The total amount of time an object spends in the air is hence it's time of flight.
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a load of 40 j 30 is connected to a source of 200 v with a phase angle of 30o, the total reactive power is:
A load of 40 j 30 is connected to a source of 200 v with a phase angle of 30o, The total reactive power is 640W.
We have given load ZL=40+j30
source voltage Vs= 200V
phase angle Ф= 30"
we have to calculate to total power delivered to load P.
so here circuit will be,
load Z - 40 +30
ZL=√(40) + (30)
ZL1600 900
ZL = √25,00
ZL = 50Ω
here angle cosΘ =R/Zl
by putting the values R=40 and Zl=50ohm
P=40*4*4=640W
A two-terminal device that can maintain a fixed voltage is a voltage source. An ideal voltage source can sustain the set voltage regardless of the output current or load resistance. The current that can be drawn from a voltage source in the real world is limited.
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A dart is thrown horizontally with an initial speed of 12m/s toward point P, the bulls-eye on a dart board. It hits at point Q on the rim, vertically below P,0.32s later. (a) What is the distance PQ? (b) How far away from the dart board is the dart released?
(a) To find the distance PQ, we can use the kinematic equation:
d = vi×t + 0.5×a×t².
where d is the distance, vi is the initial velocity (in this case 12 m/s horizontally), t is the time (0.32 s), and a is the acceleration due to gravity (9.8 m/s^2 downward).
Since the initial velocity is horizontal, the only acceleration acting on the dart is gravity, and we only need to consider the vertical displacement of the dart.
d = vi×t + 0.5×a×t² d = 0 + 0.59.8×0.32² d = 0.32 m
So the distance PQ is 0.32 m.
(b) To find the distance from the dart board where the dart was released, we need to find the horizontal displacement of the dart. We can use the same kinematic equation, but this time consider only the horizontal component of the initial velocity.
d = vi×t d = 12 m/s × 0.32 s d = 3.84 m
So the dart was released 3.84 m away from the dart board.
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The reverse of a spontaneous reaction is ......... .
The reverse of a spontaneous reaction is typically non-spontaneous, meaning it requires input of energy in the form of heat, light, or work to occur.
What is a spontaneous reaction?A spontaneous reaction is a chemical reaction that occurs on its own, without the input of external energy, and proceeds in a direction that increases the system's overall disorder, or entropy. This means that the reaction is thermodynamically favored and proceeds in the direction that leads to an increase in the randomness of the system. Spontaneous reactions can release energy in the form of heat or light, which can be harnessed in various applications.
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both the force that actos on an object and the time of impact are doubled, by how much is the impulse increased?
The impulse will be increased by 4 times, if the force acting on the object and the time of impact, both are doubled.
Impulse is defined as the change in momentum of an object. We know that time rate of change of momentum is equal to the exerted force.
Force = change in momentum(Δp)/time(t)
Also, Impulse = change in momentum(Δp)
So Impulse(I) = change in momentum = F × t
So impulse is also defined as the product of force and the time of the impact.
I = F × t
if force and time are doubled then,
I₂ = 2F × 2t
I₂ = 4 F × t
I₂ = 4 × I
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if an electron is located at the blue dot at t=0, would its subsequent path necessarily follow the electric field line on which the blue dot lies
Electrons are negatively charged particles that are affected by electric fields. The path followed by an electron under the influence of an electric field can be represented by electric field lines, which are lines that show the direction of the electric field at a particular point. It is often assumed that electrons will follow the path of the electric field lines on which they are located. However, this is not always the case and it depends on various factors.
The path followed by an electron depends on several factors, including its initial velocity, the strength of the electric field, and the presence of any other forces that may be acting on it. If an electron is initially at rest, it will start to move in the direction of the electric field. However, if the electron has an initial velocity, it may not follow the exact path of the electric field line on which it is located.
Another factor that affects the path of an electron is the presence of other forces, such as magnetic fields or collisions with other particles. These forces can cause the electron to deviate from the path of the electric field line. In some cases, the deviation can be significant enough to cause the electron to move in a completely different direction.
In conclusion, while the path followed by an electron under the influence of an electric field can be represented by electric field lines, the actual path that an electron follows may not always be the same as the field line on which it is located. The path of an electron depends on several factors, including its initial velocity, the strength of the electric field, and the presence of other forces.
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What do you think about replacing people with robots in some spheres of life? minimum 30 words
good luck ;)
Answer: good depending on what the robot is doing
Explanation:
Robots replacing people in some spheres of life would ensure that many dangerous jobs are taken over so that human casualties would significantly decrease such as mining.However, in a death to death situation leaving it up to a robot can be very one sided to some people and can cause two sides of an argument to arise. Some saying that the robot should have 'killed' one choice and some would say the other choice or the original choice the robot chose.
For example a self driving car, comes in path to either choose to drive into a innocent person on the side walk killing them, a brick wall killing the passengers in the car, the car in front killing the people in the front car or a harmless stray dog.
Humans have that choice as a quick decision to make at the spur of the moment as they deem fit. However if the robot decides to crash into the dog some may say that they would have crashed into the car in front. ect.
Overall, yes there are some places where robots can replace people and it will be a positive result, while there are other places where a robot taking over a persons 'job' could be a negative result.
a rotating rigid body has α = f t, where f > 0 is a constant. if for this body, θ(0) = ω(0) = 0 , what is θ(t) ?
Given the angular velocity α = f t and the initial conditions θ(0) = ω(0) = 0, the angle θ of the rotating rigid body at a given time t is given by θ(t) = 1/2 * f * t^2.
A rotating rigid body is an object that rotates about an axis with a constant angular velocity. If the angular velocity is a function of time, then the position of the body can be described by the angle it has rotated through at a given time. In this question, the angular velocity of the rotating rigid body is given by α = f t, where f > 0 is a constant.
Detailed Explanation:
The angular velocity α is the rate of change of the angle θ with respect to time. If we differentiate the equation α = f t with respect to time, we get dα/dt = f. Integrating both sides with respect to time, we get:
θ = 1/2 * f * t^2 + C
where C is an arbitrary constant of integration. Since θ(0) = 0 and ω(0) = 0, we can use these initial conditions to solve for C:
θ(0) = 1/2 * f * 0^2 + C = 0
C = 0
So, the equation for the angle θ becomes:
θ(t) = 1/2 * f * t^2
This equation represents the angle θ as a function of time, and shows that the angle is directly proportional to the square of the time elapsed.
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You observe a ball that moves (30.2 ± 0.1) cm in (19.58 ± 0.01) s. what is the observed speed of the ball (best estimate and most probable uncertainty)? (speed = distance / time)
A. (1.54 ±0.01) cm/s
B. (2.923 ± 0.008) cm/s
C. (1.739 ± 0.005) cm/s
D. (1.542 ± 0.005) cm/s
E. (2.92 ±0.02) cm/s
The required speed of the ball when distance and time are given is calculated to be (1.54 ± 0.01) cm/s.
The formula for speed is speed = distance/time. Using the given values, we can calculate the observed speed of the ball as follows:
Distance is given as (30.2 ± 0.1) cm.
Time is given as (19.58 ± 0.01) s.
Speed = distance / time = (30.2 ± 0.1)/(19.58 ± 0.01)
Using the most probable uncertainty (±0.5 times the smallest uncertainty), we can estimate the uncertainty in the speed calculation as follows:
Uncertainty in distance = 0.1 cm
Uncertainty in time = 0.01 s
Uncertainty in speed = (uncertainty in distance) / (time) ± 0.5 * (smallest uncertainty)
= (0.1) / (19.58) ± 0.5 * (0.01)
= 0.0051 ± 0.005 cm/s
Therefore, the observed speed of the ball is (1.54 ± 0.01) cm/s.
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Tarzan, who weighs 688 N, swings from a cliff at the end of a vine 18 m long. From the top of the cliff to the bottom of the swing,he descends by 3. 2 m. The vine will break if the force on it exceeds 950 N. (a) Does the vine break?(b) If no, what is the greatest force on it during the swing? If yes, at what angle with the vertical does it break?
From the given information about Tarzan,
a)No,the vine doesnot break.
b)The greatest force on it during the swing is 933N.
(a) To see if the vine breaks, it is adequate to inspect it right now Tarzan swings through the absolute bottom, which is the point at which the plant — in the event that it didn't break — would have the best strain. Picking a vertical positive, Newton's subsequent regulation prompts
T-mg=mv²/r
where r=18.0m and m=W/g=688/9.8=70.2kg. We see as the v²
from energy protection (where the reference position for the potential energy is at the absolute bottom).
mgh=(1/2)mv²
=>v²=2gh
where h=3.20m. Joining these outcomes, we have
T=mg+(m×2gh)/r=mg(1 + (2h/r))
=>T=70.2×9.8×[1+(2×3.2)/18]
=>T=687.96 × (1+ 6.4/18)
=>T=687.96 ×(1+0.355)
=>T=687.96×1.355
=>T=932.738N
Since,maximum force given is 950N ,therefore the vine doesn't break.
(b) Adjusting to a fitting number of huge figures, we see the greatest force is generally 9.3×10²N
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vector → has a magnitude of 25 units and makes 20° with the x-axis. vector → has a magnitude of 20 units and makes 60° with the x-axis. what is the magnitude of the vector → →?
vector → has a magnitude of 25 units and makes 20° with the x-axis. vector → has a magnitude of 20 units and makes 60° with the x-axis.The magnitude of the vector is 25 Units.
The magnitude of a vector is the absolute value of its length and is independent of its direction. In this case, the magnitude of the vector is 25 units, regardless of the angle it makes with the x-axis. Mathematically, this can be expressed as:
[tex]|vector| = √\sqrt(25^2) = 25[/tex]
Therefore ,The magnitude of the vector is 25 Units.
A vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity. A vector does not have location, while having magnitude and direction. In other words, a vector's shape remains unaltered if it is shifted parallel to itself as long as its length is unaltered.
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A psychologist who studies the differences between how men and women respond to situations is an example of which psychological approach?.
Answer:
Social-culture
Explanation:
on a two-leg trip, a car travels the first leg, a distance d1=40.6mi, in t1=1.18h. it travels the second leg, a distance d2=140.7mi, in t2=2.27h. refer to the figure.Part A) In miles per hour, what is the average speed of the car during the first leg?Part B) In miles per hour, what is the average speed of the car over the entire trip?Part C) What is the average speed for the whole trip in meters per second?
A) the average speed of the car during the first leg is 34.4 miles/hr
B)the average speed of the car over the entire trip is 61miles/hr
We know, the average speed =Total distance/Total time then at a we convert mites/nour to m/s. [ 1 mile = 1600. 344 meter]
During,
1st lag, Distance (BI) = 40.6 miles time (+1) = 1.18 hours.
Average speed the car during the first v avg =40.6/1.18=34.4 miles/hr
During, 2nd leg,
Distance (D₂) = 140.7 miles Time (+ 2 )=2.27 hours
Average speed of the car during second. 140 miles/hour
v avg * 2 = 140.7/2.27 =61 miles/hr.
How is average speed determined?
It is calculated by dividing the overall distance traveled by the overall journey time. Consider the older automobile as an illustration. The car's average speed would be 70 / 2 = 35 miles per hour if it covered 70 miles in two hours.
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A baseball is thrown straight up. The drag force is proportional to v2. The positive y direction is upward.
The acceleration when the ball is moving upward is -5g/4.
The complete question:
A baseball is thrown straight up. The drag force is proportional to v².
-In terms of g, what is the y-component of the ball's acceleration when its speed is half its terminal speed and it is moving up?
If 'g' is the acceleration due to gravity
V' is the terminal velocity of the ball
The Drage force can be determined as,
F = (K × v²)
v=√g/K
where k is the drag force
Acceleration when the ball is half terminal while moving upward can be calculated as,
Acceleration F= k× (v/2)²
Acceleration= -k×(g/(k/2²)) -g
Acceleration= -k×(g/(k/4)) -g
Acceleration = -5g/4
Hence, acceleration when the ball is moving upward is -5g/4.
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A car headlamp when connected to a 12 V battery converts energy at a rate f 50 W. How much energy is converted when it is switched on for 5 minutes?
Energy (E) is given by the product of power (P) and time (t), so
E = P * t.If the car headlamp converts energy at a rate of 50 W.
E = 50 W * (5 minutes / 60 minutes/hour) = 50 W * (5/60) hours = 50 * (5/60) Wh
5 minutes = 5 minutes / 60 minutes/hour = 5/60 hours
Next, we'll use the formula for energy:
Energy (E) = Power (P) * Time (t)
Plugging in the values we have:
E = 50 W * (5/60) hours = 50 * (5/60) Wh
So the car headlamp converts 50 * (5/60) watt-hours of energy when it's switched on for 5 minutes.
In other words, 50 watts of power multiplied by 5/60 hours of time results in 50 * (5/60) watt-hours of energy.
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under what circumstances is the car’s instantaneous velocity component different than the instantaneous speed? does this have anything to do with the direction the car moves?
Instantaneous velocity and instantaneous speed are related but distinct concepts in physics. Understanding the difference between these two measures is important for understanding the motion of objects, including cars.
Instantaneous velocity refers to the velocity of an object at a specific point in time. It is a vector quantity that includes both the magnitude (speed) and direction of the object's motion. This means that if an object is moving, its instantaneous velocity will be different at different points in time as its speed or direction may change.
On the other hand, instantaneous speed refers to the magnitude of an object's velocity at a specific point in time, without takinin time, without taking into account the direction of motion. This meang into account the direction of motion. This mean that the instantaneous speed will always be a positive scalar value, regardless of the direction of motion.
So, to answer the question, the car's instantaneous velocity component can be different from its instantaneous speed when the car changes direction. If the car is turning, its direction of motion is changing, so its instantaneous velocity will change as well, even if its speed remains constant. However, the instantaneous speed will not change in this case, as it only takes into account the magnitude of velocity, not its direction.
To summarize, the difference between instantaneous velocity and instantaneous speed has to do with the direction of motion. Instantaneous velocity includes information about the direction of motion, while instantaneous speed only includes information about the magnitude of velocity.
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(a) How much charge is on each plate of a 3.00-µF capacitor when it is connected to a 16.0-V battery?
µC
(b) If this same capacitor is connected to a 2.50-V battery, what charge is stored?
µC
a. 4.80 C is the charge on each plate of a 3.00-F capacitor linked to a 16.0-V battery.
b. The charge stored is 0.75 C if the identical capacitor is linked to a 2.50-V battery.
Capacitors store electrical energy on their plates by building an electric charge. The quantity of charge held on each plate is determined by the capacitance and voltage of the battery to which it is attached.
(a) To calculate the charge on each capacitor plate, use the formula Q = CV, where C is the capacitance (3.00 F) and V is the voltage (16.0 V).
Q = CV = (3.00 x [tex]10^{-6}[/tex])(16.0) = 48 x [tex]10^{-6}[/tex] C = 48 µC
(b) If the same capacitor is connected to a 2.50-V battery, the charge stored can be calculated using the same formula:
Q = CV = (3.00 x [tex]10^{-6}[/tex])(2.50) = 7.5 x [tex]10^{-6}[/tex] C = 7.5 µC
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Calculate the area of cro ection of a wire i length 2 m and it reitance i 25 ohm and the reitivity of material wire i 1. 84 multiply 10 to the power 6 ohm
The area of a cross-section of a wire is 1.472 × 10⁻⁷ m².
The complete question is in the attachment. The formula to calculate the resistance of an object
R = ρ × L ÷ A
L = object length (m)R = ρ × L ÷ A
R × A = ρ × L
A = ρ × L ÷ R
A = 1.84 × 10⁻⁶ × 2 ÷ 25
A = 3.68 × 10⁻⁶ ÷ 25
A = 0.1472 × 10⁻⁶
A = 1.472 × 10⁻⁷ m²
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What is 28 degrees Celsius in Fahrenheit?
The formula for converting temperature, Celsius to Fahrenheit is °F = °C (9/5) + 32. As a result, 28° C is equivalent to 82.4° F.
What is temperature, exactly?
Like all other physical quantities, temperature is defined as the comparison of a substance's or object's warmth or coldness to some reference point. Even though it can be used to describe hot and cold circumstances, temperature is often measured using a thermometer with markings in several different temperature scales, the most popular of which are Celsius and Fahrenheit. There are numerous additional temperature units.
The SI Temperature Unit: What Is It?
The International System of Units (SI) uses the Kelvin (K) sign to denote the temperature unit. In science and engineering, the Kelvin scale is commonly acknowledged or utilised. In much of the world, temperature is typically expressed in degrees Celsius or Fahrenheit.
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compared to red light, blue light has higher frequency and
Compared to red light, blue light has a higher frequency and energy.
Visible light is made up of electromagnetic wavelengths that are visible to human vision. Infrared waves and ultraviolet light fall outside of this spectrum.
The colours we perceive are determined by the wavelengths and frequencies that an item reflects.
Light exists as a particle as well as a wave. It possesses wave qualities, such as amplitude, period, wavelength, and frequency, among others.
A wave's frequency is the number of times it completes a cycle every second. It is measured in cycles per second, or hertz (Hz).
The frequencies for visible light vary from 4*10^14 to 8*10^14 Hz.
The greater the frequency, the more energy there is in the light. Its wavelength becomes shorter as a result.
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To maintain a higher temperature (in a thermostat), which way should the control knob be moved?-to the right so that it moves towards the contacts, or to the left? Explain why?
Turn the dial either clockwise to make the unit colder or anticlockwise to make the unit warmer to set the thermostat to any temperature.
What is thermostat?A thermostat is a part of a regulating mechanism that senses the temperature of a physical system and takes action to keep it close to a desired setpoint.
Any system or gadget that heats or cools to a setpoint temperature uses a thermostat. Examples include central heating systems for buildings, air conditioners, HVAC systems, water heaters, kitchen appliances like refrigerators and ovens, and incubators for use in science and medicine.
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How do you determine the direction of force in Coulomb's law?
The direction of force in Coulomb's law is determined by the direction of the electric field created by the charges.
Coulomb's law states that the force between two charged particles is proportional to the product of their charges and inversely proportional to the square of the distance between them. The direction of this force is determined by the direction of the electric field created by the charges.
The electric field is defined as the force per unit charge and can be visualized as the field lines that emanate from a charged particle. The direction of the electric field is always away from a positive charge and towards a negative charge, and the force between two charges will be in the same direction as the electric field at the point where they are located.
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Which of the following is one of the products formed when 4-bromo-3-methyloctane is treated with NaOCH3 then O3 followed by dimethyl sulfide? Br NaOCH 1) Og ? 2) DMS о о
A series of reactions occur when 4-bromo-3-methyloctane is treated with NaOCH3 followed by O3.
The NaOCH3 reacts with the 4-bromo-3-methyloctane to form an intermediate that is electrophilically substituted with ozone (O3) to form an alkoxy radical, which is then unimolecularly degraded to form a ketone and an aldehyde.
The reaction is completed by treating the products with dimethyl sulfide (DMS). As a nucleophile, dimethyl sulfide reacts with the carbonyl groups of the ketone and aldehyde to form hemiacetal and dimethyl sulfoxide. This is a common method for converting carbonyl groups into alcohols and is known as nucleophilic addition.
Thus, the products formed when 4-bromo-3-methyloctane is treated with NaOCH3, then O3, , and then with dimethyl sulfide, are a ketone and an alcohol. The exact identity of the products will depend on the specific conditions of the reaction, including the reaction temperature, solvent, and reactant ratios.
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a speeding car is traveling at a constant speed of 39.5 m/s when it passes a stationary police car. if the police car delays for 7.79 seconds before starting off, what must be the magnitude of the (assumed constant) acceleration of the police car to catch the speeding car just at the border of the jurisdiction, a distance 715 away from the original position of the police car?
23.59m/s^2 is the magnitude of the (assumed constant) acceleration of the police car to catch the speeding car.
What is acceleration?
The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not necessarily. An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.
A vehicle is said to be accelerating in the direction of travel when it begins at rest (zero velocity in an inertial frame of reference) and moves straight ahead at increasing speeds. When a vehicle turns, its velocity vector is altered by an acceleration in the new direction. A vehicle's acceleration in its present direction of motion is referred to as a linear acceleration (or a tangential acceleration in circular motions).
s = ut +1/2 at^2
s = 715
u = 0
t = 7.79
a = ?
715 = 0 + 1/2 a 7.79^2
715= a *0.5* 7.79*7.79
a = 715/(30.3)
a = 23.59m/s^2
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A student makes the claim that the space around a charged particle will exert a force on any other charged particle that is placed within this space. If an object is placed between two charged metal plates, one plate that is positively charged and one plate that is negatively charged, which argument best supports the student's claim?.
The argument that best supports the student's claim is that a charged particle creates an electric field around it, which can exert a force on other charged particles within its space.
An electric field is a field of force that surrounds a charged particle and extends through the space around it. The strength of the electric field at a given point is proportional to the amount of charge at the source and decreases as the distance from the source increases. When a charged particle is placed within the electric field created by another charged particle, it experiences a force due to the interaction between its charge and the electric field. This force is proportional to the strength of the electric field and the charge on the particle.
Therefore, if an object is placed between two charged metal plates, one positively charged and one negatively charged, the electric field created by each plate will exert a force on the object. The magnitude and direction of the force will depend on the strength and direction of the electric fields created by the two plates and the charge on the object. This supports the student's claim that the space around a charged particle will exert a force on any other charged particle that is placed within this space.
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a 1.0kg box on a frictionless surface is attached to a 1.5 kg box as shown. what is the acceleration of the 1.0 kg box?
The acceleration of the 1.0 kg box would be 4.9 m/s²
The rate at which velocity changes with reference to both speed and direction over a period of time is referred to as acceleration. If a point or an object that is moving in a straight line speeds up or slows down, then the point or object is accelerating.
To find the acceleration, we can use this following formula:
a = ((m₂ – m₁) × g)) ÷ m1
Where:
a = acceleration
m₁ = the mass of the object 1
m₂ = the mass of the object 2
g = acceleration due to gravitation (9.8 m/s²)
Thus, the acceleration of a 1.0 kg box would be:
A = ((1.5 kg – 1 kg) × 9.8 m/s²) ÷ 1 kg
A = 4.9 m/s²
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experiment 1: where did the extra mass come from? (hint: the final product is magnesium oxide.)
The extra mass of the magnesium oxide comes from then magnesium nitride that is also formed.
What causes the extra mass?If we look at the law of the conservation of mass, we know from that very law that the masses of the substances at the beginning of the reaction must be the same as the masses of the substances at the end of the reaction and this is because the mass of the reaction is conserved.
Given the fact that magnesium does combine with nitrogen to give magnesium nitride in the reaction then the mass of the product would be higher.
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what is the purpose of a portable filtration cart in a hydraulic system?
An easy-to-handle portable filtration system that reliably purifies oil on operations involving transit up and down stairs and ladders is the hydraulic filter cart. It is straightforward and simple to use, and it can reach places that larger oil filtering systems can't, making it ideal for gearboxes and other difficult-to-reach areas.
Oil filter carts are intended to offer a portable method of fluid transfer, flushing, and off-line kidney loop filtration. Our industrial systems for usage where oil cleanliness is crucial include kidney loop filtration and oil filter carts. These oil filtering systems use Adsorptive Ion Exchange Resin Media Filters for Varnish Removal and micro-glass filter components that are BETA 1000 Absolute rated.
For any industrial system and to satisfy the standards of ISO 4406 Cleanliness Code, there are numerous micron retention ratings for particulate filters.
Gearbox filtration, phosphate ester EHC systems, Skydrol filtration, governor speed control hydraulic systems, and mobile equipment hydraulics are a few examples of common applications.
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