Answers
By decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.
To determine the number of moles of chlorine that could be produced by decomposing 157g of NaCl, we need to use the molar mass of NaCl and apply stoichiometry.
The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is approximately 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.
Now, we can calculate the number of moles of NaCl:
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
Moles of NaCl = 157 g / 58.44 g/mol
Moles of NaCl ≈ 2.69 mol
According to the balanced equation 2NaCl → 2Na + Cl₂, we can see that for every 2 moles of NaCl, we produce 1 mole of Cl₂.
Therefore, using the stoichiometric ratio, we can calculate the number of moles of chlorine produced:
Moles of Cl₂ = (Moles of NaCl / 2) × 1
Moles of Cl₂ = 2.69 mol / 2
Moles of Cl₂ ≈ 1.35 mol
Thus, by decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.
Learn more about chlorine from the link given below.
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Check all of the following below which describe experimental errors that would affect the percent chloride you report in your experimental results: ____________
a) The solid product was wet when you weighed the final mass
b) You added excess silver nitrate into the reaction mixture
c) The liquid collected from the filtration was cloudy
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Answers
The options that describe the experimental errors that would affect the percent of chloride reported are:
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when you added excess silver nitrate into the reaction mixture when the transfer from the reaction beaker to the filter funnel was imperfect due to lost of some of the reaction solution.Therefore, the options describe the experimental errors that would affect the percent of chloride reported are B and D.
Learn more about experimental errors here:
https://brainly.com/question/2764830