How many km are in a foot

Answers

Answer 1

Answer:

0.000305 km

Explanation:

1 foot = 0.000305 kilometers

Answer 2

Answer:

[\tex]\huge\bold\red{brainiest answer}[/tex]1 km =3,280.8398950131foot


Related Questions

Which group is the most reactive?
*
Alkaline Earth Metals
Alkali metals
Noble Gases
Lanthanides

Answers

Answer:

alkali metals- Group 1

Explanation:

they have less valence electrons and therefore are more reactive

Which of the following always combines in definite proportions?
a. compound
b. homogeneous mixture
c. element
d. heterogeneous mixture

Answers

Answer:

The answer is heterogeneous mixture

What do metalloids and non metals have in common

Answers

Answer:

Metalloids are brittle like Non-Metals

Explanation:

Why does water vapor
condense at higher
elevations?
A. cooling causes condensation
B. faster particle activity
C. due to a chemical change
D. due to a chemical reaction

Answers

Answer:

A. cooling causes condensation

Explanation:

air is cooler at higher altitude in the troposphere.

How are gases and liquids different from each other? O A. Liquids can change volume, and gases cannot. B. Gases can change shape, and liquids cannot. C. Liquids can change shape, and gases cannot. D. Gases can change volume, and liquids cannot.​

Answers

Answer:

d

Explanation:

d is the right answer since gases do not have definite shape and volume and liquids have definite volume. so liquid cannot change its volume but gas can

Can you determine the equation for density?

Answers

Answer:

YESBSJSKSSKEKEJRJRJER

Calculate the density of the football. Use the formula D = m/V where D is the density, m is the mass, and V is the volume. Record your calculations in Table B of your Student Guide. What is the density of the football while it is deflated? g/cm3

Answers

Answer:

0.84 g/cm3 EDGE 2020

Explanation:

Answer:

What is the density of the football while it is deflated?

⇒ 0.84 g/cm3

Concentration data is commonly monitored during a reaction to determine the order with respect to a reactant. Consider the types of observations listed, and determine which order is likely for that reactant. Assume all other factors are held constant.
An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially.
Choose...first order, second order, zero order
The reaction rate increases in direct proportion to the concentration of the reactant in solution.
Choose...first order, second order, zero order
The reaction rate is constant regardless of the amount of reactant in solution.
Choose...first order, second order, zero order

Answers

Answer:

An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially - first order

The reaction rate increases in direct proportion to the concentration of the reactant in solution -second order

The reaction rate is constant regardless of the amount of reactant in solution - zero order

Explanation:

The Order of Reaction refers to the power dependence of the rate on the concentration of each reactant. The order of reaction is determined experimentally and not necessarily by inspection.

Typically, in a second order reaction, the rate of reaction increases in proportion to increase in concentration.

For a first order reaction, the rate of reaction increases exponentially as the increase in concentration.

For a zero order reaction, the rate of reaction is independent of the concentration of the reactant.

Which of the following statements is/are correct? i. Principal energy levels are identified by the letters s, p, d, and f. ii. Principal energy levels appear in both the quantum mechanical model of the atom and the Bohr model of the atom. iii. In general, n = 1 is at lower energy than n = 2, and n = 2 is lower than n = 3, and so on. iv. The principal energy level is related to electron spin. a. i only b. iv only c. i and ii d. ii and iii e. iii and iv

Answers

Answer:

d. ii and iii

Explanation:

Both the Bohr model and the wave (quantum) mechanical  models of the atom recognize the principal quantum number n. The principal quantum number shows the shell or energy level where an electron may be found.

The energy levels are arranged in increasing order of magnitude. That is n=1 >n=2=n=3 etc

Explain the arrangement of the first 20 elements in the periodic table.
Please help! Will give brainliest!

Answers

Elements are arranged from left to right and top to bottom in order of increasing atomic number.

There are various kind of elements that are present in periodic table. Elements that are metals are kept on left side of periodic table and elements which are non metals are kept on right side of periodic table.

What is periodic table?

Periodic table is a table in which we find elements with properties like metals, non metals and metalloids element arranges in increasing atomic number.

The first 20 elements of periodic table are Hydrogen, Helium, Lithium, Beryllium, Boron, Carbon, Nitrogen, Oxygen, Fluorine, Neon, Sodium, Magnesium, Aluminum, Silicon, Phosphorus, Sulfur, Chlorine, Argon, Potassium and Calcium. Out of these Lithium, Beryllium, Sodium, Magnesium. Potassium and Calcium are metals so they are kept on the left side of the periodic table while others are non metals so they are kept on right side of periodic table.

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What is the speed of each vehicle? (Remember S=d/t)

A: 50 km/h, B: 40 km/h

A:5 km/h, B: 2 km/h

A: 10 km/h, B: 5 km/h

A: 20 km/h, B: 10 km/h

Answers

Answer : The correct option is A: 20 km/h, B: 10 km/h

Explanation :

Speed : It is defined as the distance traveled per unit time.

Formula used:

[tex]S=\frac{d}{t}[/tex]

where,

S = speed

d = distance

t = time

First we have to calculate the speed of vehicle A.

Given:

Distance of vehicle A = 50 km

Time of vehicle A = 2.5 hr

Now putting all the given values in the above formula, we get:

[tex]S=\frac{50km}{2.5hr}=20km/hr[/tex]

Now we have to calculate the speed of vehicle B.

Given:

Distance of vehicle B = 50 km

Time of vehicle B = 5 hr

Now putting all the given values in the above formula, we get:

[tex]S=\frac{50km}{5hr}=10km/hr[/tex]

Therefore, the speed of vehicle A and B is 20 km/hr and 10 km/hr respectively.

Mass is a unique property of any property.

Answers

Physical Properties of matter are characteristics of a substance that can be observed or measured without changing the makeup of the matter of the substance (NO chemical change needs to occur-meaning their particles stay the same). Characteristics such as mass, volume, color and temperatures are physical properties.
Extensive properties, such as mass and volume, depend on the amount of matter being measured. Intensive properties, such as density and color, do not depend on the amount of the substance present. Physical properties can be measured without changing a substance's chemical identity. measured, such as an object's density, color, mass, volume, length, malleability, melting point, hardness, odor, temperature, and more. without changing the composition of matter. Physical properties are used to observe and describe matter. Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others. Key Points
Matter can exist in one of three main states: solid, liquid, or gas.
Solid matter is composed of tightly packed particles. ...
Liquid matter is made of more loosely packed particles. ...
Gaseous matter is composed of particles packed so loosely that it has neither a defined shape nor a defined volume. the same whether the sample being observed is large or small. Examples of characteristic properties include freezing/melting point, boiling/condensing point, density, viscosity, and solubility.
Examples of chemical properties include flammability, toxicity, acidity, reactivity (many types), and heat of combustion.

If 65,000 J of energy were transferred to 450 g of water at 20˚C. What would have been the final temperature of the water?

Answers

Answer:

500g

Explanation:

Answer:Suppose that during the Icy Hot lab that 65 KJ of energy were transfered to 450 g of water at 20 degrees C. What would have been the final temerpatur

Explanation:

Fluorescent light bulbs, or CFLs, prevent the loss of energy from light bulbs as ________ energy.

Answers

Answer:

Compact fluorescent lamps, or CFLs, use 75 percent less energy than a traditional incandescent bulb, but they never quite caught on for home use.Feb

Is avocado a fruit or a vegetable?

(dont me with my question rn xD)​

Answers

Its a fruit, technically its a berry!! Avocados are considered a fruit because they fit all of the botanical criteria for a berry. They have a fleshy pulp and a seed after all.

For the equation 2 HCI + Zn ⇒ H₂ +ZnCI₂ suppose you had 2.00 g HCI and enough Zn.

a. What mass, in grams, would you have of Zn?

b. How many grams of H₂ would be produced?

Please show your work!!

Answers

Answer:

Zinc weighs 65.38 grams per mole, so we’ve got 0.994 moles of zinc (I’ll worry about sig figs at the end). HCl weighs 36.46 grams per mile, so we’ve got 1.78 moles of HCl. However, two moles of HCl react with one mole of zinc. So only 1.78/2 = 0.890 moles of Zinc are going to react.

One mole of zinc produces one mole of hydrogen, which weigh 2.02 grams per mole. So 0.890 moles * 2.02 grams/mole means 1.90 grams of hydrogen will be produced.

Since we have 2 sig figs in the weights given, the answer should have 2 sig figs, thus 1.9 grams.

This is just an example

Which of the following is NOT powered by alternating current?

A) household electrical outlets

B) power tools

C) toasters

D) batteries

Answers

It would be Batteries (D)

Answer:

batteries

Explanation:

bc they're powered by energy

What element has an atomic mass 4?

Answers

Answer:

Helium has atomic mass  4.002602.

So the answer to yr question is helium.

The answer is helium

Calculate the mass of a sample of fruit sugar, fructose,
C6H1206, containing 2.65 X 1020 molecules.

Answers

Answer:

, containing 2.65 X 1020 molecules.

Explanation:

The mass of a sample of fruit sugar (fructose) C₆H₁₂O₆, containing 2.65 ×10²⁰ is equal to 2.88 g.

What is Avogadro's number?

Avogadro’s number can be defined as the number of units in one mole of any chemical substance. Generally, these entities can be electrons, molecules, atoms, ions, or protons, depending upon the kind of chemical reaction or reactants and products.

The value of Avogadro’s constant is found approximately 6.022 × 10²³ mol⁻¹.

Given, the number of molecules of fructose = 2.65 ×10²⁰

The molar mass of the fructose = 180.16 g/mol

So 6.022 × 10²³ molecules of fructose have mass = 180.16 g

Then 2.65 × 10²⁰ fructose molecules will have mass = 2875.04 × 10⁻³ g

The mass of the  2.65 × 10²⁰ fructose molecules =  2.88 g

Therefore, the mass of  2.65 × 10²⁰ fructose molecules is equal to 2.88 g.

Learn more about Avogadro's number, here:

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How much heat is required to raise the temperature of 93.5 gg of water from its melting point to its boiling point

Answers

Answer:

39270 J

Explanation:

The quantity of heat required to raise the temperature of a substance from its initial temperature to its final temperature is given by:

Q = mCΔT

m = mass of substance, C = specific heat capacity of substance, ΔT = temperature change = final temperature - initial temperature

Melting point = 0°C, boiling point = 100°C, m = 93.5 g = 0.0935 g, ΔT = boiling point - melting point = 100 - 0 = 100°C, C = 4200 J/kg°C

Q = mCΔT

Q = 0.0935 × 4200 × 100 = 39270 J

What is gonna be the density of a block charger that is 22g and 210 cm3

Answers

Answer:

Control group

g The free energy change of the reaction A (g) ---> B(g) is zero under certain conditions. The STANDARD Free energy change of the reaction is -42.5 kJ. Which of the following statements must be true about the reaction described here? A) The concentration of the product is greater than the concentration of the reactant. B) The reaction is at equilibrium. C) The concentration of the reactant is greater than the concentration of the product.

Answers

Answer:

The reaction is at equilibrium.

Explanation:

In thermodynamics, the Gibbs free energy is a term used traditionally to refer to the available or  useful work that can be obtained from a thermodynamic system.

Gibbs free energy is a measure of the chemical potential that a reaction has left to do work. Hence, if the free energy is zero, then the reaction has attained equilibrium, and there is no more work to be done

The statement that should be true related to the reaction should be that it should be at equilibrium.

What is Gibbs free energy?

In terms of thermodynamics, this energy should be applied for the availability or the useful work that should be obtained via the system of thermodynamics.

Also, it determined the chemical potential where the reaction has left for doing the work. Also in the case when the free energy should be zero so here the reaction should be attained the equilibrium.

hence, the option b is correct.

Learn more about energy here:

. Give two everyday examples of the thermal energy of a substance being increased.

Answers

Answer:

• the warmth from the sun

• the heat from another a heater

• A cup of hot chocolate

•baking in an oven

Two everyday example that we say for the thermal energy of a substance being increased are, faster movement of the substances and boiling if liquids as well light absorption.

What is thermal energy?

Thermal energy is a form of energy generated by heating up a substance. It can also be generated by the movement of its particles.

Vibrating molecules increases the thermal energy of a substance. Similarly, when we heat a substance it acquires more thermal energy.

Another way of increasing thermal energy is light absorption by the substance. Thermal energy associated with light increases the temperature of of the system which is absorbed the light.

Hence, the two ways by which thermal energy of a substance is increased are heating or boiling and faster movement.

To learn more about thermal energy, refer the link below:

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What body of water is south of Constantinople? Atlantic Ocean Indus River Black Sea Mediterranean Sea​

Answers

Black sea
Hahahahhahahahahah

The diagram below shows a lithium atom. Which of the following correctly lists the particles in a lithium atom? *
Captionless Image
A. 3 protons, 4 neutrons, 3 electrons
B. 3 protons, 3 neutrons, 4 electrons
C. 4 protons, 4 neutrons, 3 electrons
D. 4 protons, 3 neutrons, 4 electrons

Answers

A—3 protons, 4 Neutrons, 3 electrons

how many seconds is in 1 year

Answers

Explanation:

hope it helps :)

step of the scientific method reviews your original question and your hypothesis.

results

observation

conclusion

experiment​

Answers

Answer: conclusion

Explanation:

It say reviews your original question and your hypothesis

Answer:

conclusion!

Explanation:

The rate of reaction in terms of the "rate law expression" includes the rate constant (kk), the concentration of the reactants, and the orders of the reaction with respect to the different reactants. Consider the following reaction: A+B→C+DA+B→C+D The initial concentrations of the reactants AA and BB are 0.200 MM and 0.350 MM, respectively. The rate of reaction is 0.060 M⋅s−1M⋅s−1, and the orders of the reaction, with respect to reactants AA and BB, are 1 and 2, respectively. Determine the rate constant (kk) for the reaction using the rate law. Express your answer in M−2⋅s−1M−2⋅s−1 to three significant figures.

Answers

Answer:

[tex]k=2.45M^{-2}s^{-1}[/tex]

Explanation:

Hello.

In this case, considering the given specific orders of reaction, we can write the rate law as:

[tex]r=k[A][B]^2[/tex]

Thus, considering the concentrations of A and B to be 0.200 M and 0.350 M respectively and a rate of 0.060 M/s, the rate constant turns out:

[tex]k=\frac{r}{[A][B]^2}\\ \\k=\frac{0.060M/s}{(0.200M)(0.350M)^2} \\\\k=2.45M^{-2}s^{-1}[/tex]

This is what we know as a third-order reaction since the specific orders both add to 3.

Best regards.

The salt copper(II) sulfate dissolves in water according to the reaction: CuSO4(s) Cu2+(aq) + SO42-(aq) (a) Calculate the standard enthalpy change ΔH° for this reaction, using the following data: CuSO4(s) = -771.4 kJ mol-1 Cu2+(aq) = 64.8 kJ mol-1 SO42-(aq) = -909.3 kJ mol-1 kJ (b) Calculate the temperature reached by the solution formed when 13.0 g of CuSO4 is dissolved in 0.109 L of water at 25.0 °C. Approximate the heat capacity of the solution by the heat capacity of 109 g of pure water (specific heat capacity = 4.18 J g-1 °C-1), ignoring the mass of the salt. °C (c) Heats of reaction find practical application in hot packs or cold packs. Would this dissolution reaction be appropriate for the preparation of a hot pack or a cold pack?

Answers

Answer:

(a) [tex]\Delta H=-73.1\frac{kJ}{mol}[/tex]

(b) [tex]T_2=38.1\°C[/tex]

(c) Yes, it is appropriated.

Explanation:

Hello.

(a) In this case, given the formation enthalpies for copper (II) sulfate, copper (II) ion and sulfate ion, we can compute the enthalpy change for such process as follows:

[tex]\Delta H=\Delta H_{Cu^{2+}}+\Delta H_{SO_4^{-2}}-\Delta H_{CuSO_4}\\\\\Delta H=64.8-909.3-(-771.4)\\\\\Delta H=-73.1\frac{kJ}{mol}[/tex]

(b) In this case, since 13.0 g of copper (II) sulfate (molar mass: 159.55 g/mol) we can compute the gained heat by water via:

[tex]Q_{water}=-n_{CuSO_4}\Delta H=-13.0g*\frac{1mol}{159.55g}* -73.1\frac{kJ}{mol}\\ \\Q_{water}=5.96kJ=5960J[/tex]

As the heat lost by the reaction is gained by the water, therefore, the final temperature is:

[tex]Q_{water}=m_{water}Cp_{water}(T_2-T_1)\\\\T_2=T_1+\frac{Q_{water}}{m_{water}Cp_{water}}\\ \\T_2=25.0\°C+\frac{5960J}{0.109L*\frac{1000g}{1L}*4.18\frac{J}{g\°C} } \\\\T_2=38.1\°C[/tex]

(c) In this case, since this dissolution reaction is exothermic as it increases the temperature when undergone, we can infer that yes, this dissolution would be appropriate for the preparation of a hot pack, because a cold pack would be with an endothermic dissolution reaction.

Best regards.

Which of the following can be broken down by chemical processes but not physical processes?

elements
compounds
all of these
mixtures​

Answers

Answer:

Elements and compounds

Explanation:

Elements and compounds, mixtures are not chemically bonded and can be physically seperated

Elements and compounds
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