Answer:
62.7 gram
Explanation:
Molar mass = (6)(12)+(10)(1)+(1)(32)=114 g/mol
Mass = no of moles × molar mass
= 0.55 × 114 = 62.7 gram
The mass of 0.55 moles of compound C₆H₁₀S is equal to 62.7 g.
What is a mole?A mole is defined as a standard unit that is used to find a huge number of quantities such as atoms, molecules, ions, or other particles. The mass of the 1 mole of any chemical element is equal to the atomic mass of the element and that of any chemical compound is known as molar mass.
The number of entities in 1 mole was found to be equal to 6.023 × 10²³ which is known as Avogadro’s number or Avogadro's constant
Given, the number of moles of the given compound = 0.55 moles
The mass of 1 mole of given compound C₆H₁₀S = 114 g/mol
The mass of 0.350 moles of the given compound = 0.55 × 114 = 62.7 g
Therefore, 62.7 grams is the mass of 0.55 moles of C₆H₁₀S.
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A 0.205 g sample of CaCO3 (Mr = 100.1 g/mol) is added to a flask along with 7.50 mL of 2.00 M HCl. CaCO3(aq) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g) Enough water is then added to make a 125.0 mL solution. A 10.00 mL aliquot of this solution is taken and titrated with 0.058 M NaOH. NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq) How many mL of NaOH are used?
The required volume of sodium hydroxide is 15 mL.
What is concentration?The term concentration refers to the amount of substance present. It is the quotient of the number of moles and volume of solution.
We have the reaction; 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)
Number of moles of CaCO3 = 0.205 g / 100.1 g/mol = 0.0020 moles
Number of moles of HCl = 2.00 M * 7.50/1000 = 0.015 moles
Since 2 moles of HCl reacts with 1 mole of CaCO3
x moles of HCl reacts with 0.0020 moles
x = 0.004 moles of HCl
This means that HCl is in excess by the amount 0.011 moles.
Now consider the reaction; NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq)
Concentration of HCl = 0.011 moles/0.125L = 0.088 M
From;
CAVA/CBVB = na/nb
CAVAnb = CBVBna
VB = CAVAnb/CBna
VB = 0.088 M * 10mL * 1/0.058 M * 1
VB = 15 mL
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Calculate the molarity of solution of "sodium sulfate" that contains 5.2 grams sodiums sulfate diluted to 500mL
Taking into account the definition of molarity, the molarity of solution of sodium sulfate is 0.0732 [tex]\frac{moles}{liter}[/tex].
Definition of molarityMolar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
[tex]Molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
Molarity of solution of sodium sulfate.In this case, you have:
number of moles of sodium sulfate= [tex]5.2 grams\frac{1 mole}{142 grams} = 0.0366 moles[/tex] (being 142 g/mole the molar mass of sodiums sulfate)volume= 500 mL= 0.5 L (being 1000 mL= 1 L)Replacing in the definition of molarity:
[tex]Molarity=\frac{0.0366 moles}{0.5 L}[/tex]
Solving:
Molarity= 0.0732 [tex]\frac{moles}{liter}[/tex]
Finally, the molarity of solution of sodium sulfate is 0.0732 [tex]\frac{moles}{liter}[/tex].
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What happens to the electricity in a strand of Christmas lights if they are plugged in and not working? What happens if they are plugged in but the wires get cut
when a circuit is open the electricity fails to pass through any of the wire causing all the lights to go out. If the lights are in a straight line each light is on its own circuit to the power source.
Less massive molecules tend to escape from an atmosphere more often than more massive ones because:.
Since lighter molecules are moving faster, they escape from an atmosphere more often than more massive ones.
What is escape velocity?The escape velocity is the velocity that an object must be given in order to escape from the gravitational field of the earth. We must know that a less massive molecule moves faster than a more massive molecule.
Hence, less massive molecules tend to escape from an atmosphere more often than more massive ones because they are moving faster.
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What is the pH of a solution with [ht] = 2.3 * 10-3?
A. 3.00
B. -2.64
O C. -0.36
O D. 2.64
Answer:
The pH of a solution with [H+] = 2.3 x 10^-3 is 2.64.
Explanation:
if a gas is held in 3.60 L, 298 K AND 800. mmHg, what is the new pressure of the gas if the volume us decreased by half and the tempature is decreased to 250. K
Answer:
Explanation:
By Ideal Gas Law, P1*V1 / T1 = P2*V2 / T2
So new pressure = (P1*V1 / T1) / (V2 / T2)
= P1*V1*T2 / T1*V2
= 800*3.6*298 / 250*1.8
= 1907.2 mmHg
Apply combine gas law
[tex]\\ \rm\Rrightarrow \dfrac{P1V1}{T1}=\dfrac{P2V2}{T2}[/tex]
[tex]\\ \rm\Rrightarrow P2=\dfrac{P1V1T2}{V2T1}[/tex]
[tex]\\ \rm\Rrightarrow P2=\dfrac{800(3.6)(250)}{1.8(298)}[/tex]
[tex]\\ \rm\Rrightarrow P2=720000/536.4[/tex]
[tex]\\ \rm\Rrightarrow P2=1341.7 mmHg[/tex]
Volume is
A. The amount of space an object takes up
B. the amount of matter in an object
C. a measure of the pull of gravity on an object
D. a special state of matter
Answer:
the amount of matter in an object
wha is the specific heat of aluminum at 72.9 °C
Explain the structural relationship between amino acids and proteins
Answer:
A protein is just a long chain of amino acids. So, one could say that the monomer of a protein is an amino acid. Here is a diagram of a protein and amino acid for reference:
what is the purpose of shaking the petroleum ether-ethanol extract of the leaves with water in a separatort funnel
The purpose of shaking the petroleum ether-ethanol extract of the leaves with water in a separator funnel is that the shaking process will increase the surface area which is in contact between the two liquids and will allow the equilibrium to be established more rapidly.
This shaking process of petroleum ether-ethanol extract of the leaves with water in a separator funnel form layers of separation.
Shaking the separatory funnel allows the two solvents to mix and provides the opportunity for components dissolved in one of the solvents to be transferred to the other solvent.
Ether extraction is mainly used in the determination of Uranyl nitrate which is also known as Uranium.
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Cu + 2AgNO3
How many atoms of oxygen are mixed in the chemical equation above
An element that is considered to be unreactive
because it has a filled outer energy level is
1. silver.
2. hydrogen.
3. helium.
4. lithium.
Answer:
3
helium
Explanation:
Among all the given options, the correct option is option 3. An element that is considered to be unreactive because it has a filled outer energy level is helium.
What is element?Any compound that cannot be broken down into simpler chemicals by regular chemical processes is referred to as a chemical element or element. The building blocks of which every matter is made are called elements.
There are 118 chemical elements that are currently recognized. About 20% of them have only been created synthetically in the lab and are only known because they do never exist in nature or are only present in trace levels. An element that is considered to be unreactive because it has a filled outer energy level is helium.
Therefore, among all the given options, the correct option is option 3.
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At the same temperature, which of the following gases will effuse the slowest?
A) Hydrogen
B) Helium
C) Fluorine
D) Xenon
E) Bromine
Xenons at the same temperature, will effuse the slowest
The effusion rates is said to be inversely proportional to the square root of the molecular masses of the gases.
Hydrogen, helium, fluorine, and bromine effuses out of container earlier than Xenon because they have lower mass when compared to Xenon.At a set temperature, the average kinetic energy of all gaseous molecules is always equal.
Hydrogen gas has the lowest mass out of these gases, it will have the highest average velocity and as such, that it will exit out of the tiny hole at a rate faster than the other gases.
As the mass increases, the rate of effusion decreases. The gas with the lowest molecular weight will effuse the fastest.Conclusively, The rate of effusion for a gas is inversely proportional to the square-root of its molecular mass, this is Graham's Law.
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Answer: Bromine
Explanation: The rate of effusion is inversely proportional to the molar mass. Bromine (Br2) has a the highest molar mass of this group, and will therefore be the slowest
What is a strong electrolyte?
What is a weak electrolyte?
Provide examples of each one of these categories.
Answer:
An electrolyte is medium containing ions that is electrically conducting through the movement but not conducting electrons . Strong electrolytes are electrolytes that completely ionizes in a solution . Weak electrolytes that partially ionize in a solution .
Explanation:
Strong electrolytes fully dissociate In a solution such as NH4Cl , KOH(Potassium hydroxide) and HCl ( Hydrochloric acid)
Weak electrolytes partially dissociate In a solution such as HC2H3O2 (acetic acid), H2CO3 (carbonic acid), NH3 (ammonia), and H3PO4 (phosphoric acid) .
Number of electrons for all of these even the ones with a number by them ? Will give brainlist!!!!
Explanation:
s=2
p=6
d=10
f=14
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c) If nitrogen diffuses at a rate of 0.0069 m/s, how fast does carbon dioxide diffuse?
Answer:
it defuse at a rate of 0.0002 m/s
Which substance has a molar mass of 33.99 g/mol?
Answer:
PH₃.
Explanation:
Hello.
In this case, among the options:
PH₃, GaF₃, SF₂ and CO₂
We compute their molar masses by adding the atomic masses of the constituting elements by their subscripts:
[tex]M_{PH_3}=m_P+3*m_H=30.97+3*1.01=34.00g/mol\\\\M_{GaF_3}=m_{Ga}+3*m_F=69.72+3*19.00=126.72g/mol\\\\M_{SF_2}=m_{S}+2*m_F=32.07+2*19.00=70.07g/mol\\\\M_{CO_2}=m_{C}+2*m_O=12.01+2*16.00=44.01g/mol[/tex]
Thus, the answer is PH₃.
Best regards.
A benzene ring with two substituents, a bromo and chloro substituent. Each substituent is placed on a carbon two carbons away from the other. The parent name is benzene and there is a chloro and bromo substituent. Disubstituted benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor.
a. 1-bromo-3-chlorobenzene
b. 3-bromo-1-chlorobenzene
c. meta-bromochlorobenzene
d. o-bromochlorobenzene
e. ortho-bromochlorobenzene
f. m-bromochlorobenzene
The correct name of the structure given in the question is 1–bromo–3–chloro benzene (Option A)
How to name organic compoundsThe naming of organic compounds follows the standard of the international union of pure and applied chemistry (IUPAC).
To name a compound, we must
Locate the longest continuous carbon chain and determine the functional group of the compound. This gives the name of the compound. Locate the substituent groups attached Give the substitute group the lowest locate by naming alphabetically Combine the above to obtain the name of the compound. How name the compound The compound is a benzene ringThe substituent groups attached are bromo (Br) and Chloro (Cl) The Br is at carbon 1 while Cl is at carbon 3Therefore, the name of the compound is 1–bromo–3–chloro benzeneComplete question
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Polllination refers to the ___________
Explanation:
from internet
the act of transferring pollen grains from the male anther of a flower to the female stigma
Answer:
transfer of pollen from anther to stigma.
Explanation:
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What is the rate law for the following mechanism? Step 1: A + B = C (fast) Step 2: B + C=D (slow) Rate = k*
Answer:
The rate law is
rate
=k[A][B]^2
A sample is found to contain 66.5% NaHCO3 by mass. What is the mass of NaHCO3 in 4.25g of the sample?
Answer:
2.83 grams NaHCO₃ in the 4.25g Sample.
Explanation:
Given 4.25g Sample is 66.5% NaHCO₃
=> mass of NaHCO₃ = 0.665(4.25g) =2.83grams NaHCO₃.
The mass of NaHCO₃ in 4.25 g of the sample is 2.83 g
From the question given above, the following data were obtained:
Mass of sample = 4.25 g
Percentage by mass of NaHCO₃ = 66.5%
Mass of NaHCO₃ =?[tex]Percentage = \frac{mass of substance}{total mass} X 100[/tex]
66.5% = [tex]\frac{Mass of NaHCO_{3} }{4.25}\\\\[/tex]
Cross multiply
Mass of NaHCO₃ = 66.5% × 4.25
Mass of NaHCO₃ = 0.665 × 4.25
Mass of NaHCO₃ = 2.83 gTherefore, the mass of NaHCO₃ in 4.25 g of the sample is 2.83 g
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Can someone please help me? (Answer the question only if you are going to help). Thanks
Explanation:
a is the answer ok write it easily bye
Two bulbs are connected by a stopcock. The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.850 atm, and the small bulb, with a volume of 1.50 L, contains oxygen at a pressure of 2.50 atm. The temperature at the beginning and the end of the experiment is 22∘C .
After the stopcock is opened, the gases mix and react.
2NO(g)+O2(g)→2NO2(g)
1. Which gases are present at the end of the experiment?
2. What are the partial pressures of the gases? If the gas was consumed completely, put 0 for the answer.
Answer:
(I). The gases are present at the end of the experiment are O₂ and NO₂
(II). The pressure of O₂ is 0.158 atm.
The pressure of NO₂ is 0.681 atm
The Pressure of NO is zero.
Explanation:
Given that,
Volume of large bulb = 6.00 L
Pressure = 0.850 atm
Volume of small bulb = 1.50 L
Pressure = 2.50 atm
Temperature = 22°C = 295 K
We need to calculate the moles in NO
Using formula of moles
[tex]n=\dfrac{PV}{RT}[/tex]
Put the value into the formula
[tex]n=\dfrac{0.850\times6.00}{0.0821\times295}[/tex]
[tex]n=0.211\ moles[/tex]
We need to calculate the moles in O
Using formula of moles
[tex]n=\dfrac{PV}{RT}[/tex]
Put the value into the formula
[tex]n=\dfrac{2.50\times1.50}{0.0821\times295}[/tex]
[tex]n=0.155\ moles[/tex]
The balance equation for the reaction is
[tex]2NO+O_{2}\Rightarrow 2NO_{2}[/tex]
So, The gases are present at the end of the experiment are O₂ and NO₂
We need to calculate the remaining moles of O₂
Using formula for remaining moles
Moles of O₂ remaining = [tex]0.155-\dfrac{0.211}{2}[/tex]
[tex]Moles\ of \ O_{2}\ remaining =0.049\ moles[/tex]
Moles of NO₂ = 0.211 moles
Total volume [tex]V=V_{l}+V_{s}[/tex]
Put the value into the formula
[tex]V=6.00+1.50[/tex]
[tex]V=7.5\ V[/tex]
(2). If the gas was consumed completely
We need to calculate the pressure of O₂
Using formula of pressure
[tex]P=\dfrac{moles\times R\times T}{V}[/tex]
Put the value into the formula
[tex]P=\dfrac{0.049\times0.0821\times295}{7.5}[/tex]
[tex]P=0.158\ atm[/tex]
We need to calculate the pressure of NO₂
Using formula of pressure
[tex]P=\dfrac{moles\times R\times T}{V}[/tex]
Put the value into the formula
[tex]P=\dfrac{0.211\times0.0821\times295}{7.5}[/tex]
[tex]P=0.681\ atm[/tex]
If the gas was consumed completely
Then, Pressure of NO is zero.
Hence, (I). The gases are present at the end of the experiment are O₂ and NO₂
(II). The pressure of O₂ is 0.158 atm.
The pressure of NO₂ is 0.681 atm
The Pressure of NO is zero.
The gases that remained at the end of the experiment are nitrogen dioxide and nitric oxide. The partial pressure of nitric oxide has been 0.43 atm, nitrogen dioxide has been 1 atm, and oxygen has been 0 atm.
The balanced chemical equation has been given that, 2 moles of NO reacts completely with 1 mole of oxygen.
(1) According to the ideal gas equation:
PV nRT
n = [tex]\rm \dfrac{PV}{RT}[/tex]
The moles of NO;NO = [tex]\rm \dfrac{0.850\;atm\;\times\;6\;L}{0.0821\;L.atm/mol.K\;\times\;295\;K}[/tex]
Moles of NO = 0.211 moles
The moles of Oxygen:Oxygen = [tex]\rm \dfrac{2.50\;atm\;\times\;1.50\;L}{0.0821\;L.atm/mol.K\;\times\;295\;K}[/tex]
Moles of oxygen = 0.155 moles.
For 2 moles NO, 1 mole oxygen is used.
For 0.211 moles, Oxygen has been 0.422 moles.
The oxygen has been in a lesser quantity than requires, thus it has been the limiting reactant.
The gas that presents at the end of the reaction has been NO.
(2) The pressure of the gas has been calculated as:
After the complete consumption of the gas, NO remaining has been:
2 moles oxygen = 1 moles NO
0.155 moles oxygen = 0.0775 moles NO.
The moles of NO remaining = 0.211 - 0.0775 mol
The moles of NO remaining = 0.1335 mol.
The total volume of the solution will be 6 + 1.5 L = 7.5 L.
The moles of Nitrogen dioxide formed :
1 mole oxygen = 2 moles Nitric oxide
0.155 moles oxygen = 0.31 moles nitric oxide.
The partial pressure can be given by:
P = [tex]\rm \dfrac{nRT}{V}[/tex]
The pressure of NO:Pressure of NO = [tex]\rm \dfrac{0.1335\;\times\;0.08206\;\times\;295}{7.5}[/tex]
Pressure of NO = 0.43 atm.
The pressure of Oxygen = 0 atm.
The pressure of Nitrogen dioxide:
Pressure of nitrogen dioxide = [tex]\rm \dfrac{0.31\;\times\;0.08206\;\times\;295}{7.5}[/tex]
Pressure of nitrogen dioxide = 1.00 atm.
The gases that remained at the end of the experiment are nitrogen dioxide and nitric oxide. The partial pressure of nitric oxide has been 0.43 atm, nitrogen dioxide has been 1 atm, and oxygen has been 0 atm.
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What is chemical energy
If the molecular weight of horseradish peroxidase is about 44,000 g/mol, how many moles of enzyme are used per mole of vanillin?
What is when the molecular weight of horseradish peroxidase is about 44,000 g/mol, The number of moles of the enzyme used per mole of vanillin is
ME=289.188moles
What is the number of moles of the enzyme used per mole of vanillin?Generally, the equation for the moles of the enzyme is mathematically given as
[tex]ME=\frac{molecular weight}{vanilin MW}[/tex]
Therefore
ME=44000/152.15
ME=289.188moles
In conclusion, the number of moles of the enzyme is
ME=289.188moles
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A 5.0g sample of O2 is in a container at STP. What volume( liters) is the container? Round to the tenths place
(Need help asap)
A 5.0g sample of O₂ is in a container at STP, then the volume of the container is 3.49 L.
How do we calculate volume?Volume of oxygen sample at STP will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure = 1 atm
V = volume of gas = ?
R = universal gas constant = 0.082 L.atm/K.mol
T = temperature = 273K
n is the moles of oxygen sample and it will be calculated as:
n = W/M, where
W = given mass = 5g
M = molar mass of O₂ = 32g/mol
n = 5/32 = 0.156 moles
On putting all values on above equation, we get
V = (0.156)(0.082)(273) / (1)
V = 3.49 L
Hence required volume of gas sample is 3.49 L.
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What was the major organic product obtained when propanal was heated with a catalytic amount of KOH in water
Answer:
Commercially, 2-methylpentenal is synthesized by the aldol condensation of propanal in the presence of liquid base like KOH or NaOH in stoichiometric amount,,. Under optimum reaction conditions, 99% conversion of propanal is achieved with 86% selectivity of 2-methylpentenal using liquid base.
Explanation:
hope this helps
Answer:
HMM, what the person above said.
For the chemical reaction
2 NaOH + H2SO4 — Na2SO4 + 2H2O
how many moles of sodium sulfate will be produced from 28.3 g of sodium hydroxide?
The number of mole of sodium sulphate, Na₂SO₄ that will be produced from 28.3 g of sodium hydroxide, NaOH is 0.35 mole
How to determine the mole of NaOH Mass of NaOH = 28.3 gMolar mass of NaOH = 40 g/mol Mole of NaOH =?Mole = mass / molar mass
Mole of NaOH = 28.3 / 40
Mole of NaOH = 0.7075 mole
How to determine the mole of Na₂SO₄ produced2NaOH + H₂SO₄ —> Na₂SO₄ + H₂O
From the balanced equation above,
2 moles of NaOH reacted to produce 1 mole of Na₂SO₄.
Therefore,
0.7075 mole of NaOH will react to produce = (0.7075 × 1) / 2 = 0.35 mole of Na₂SO₄
Thus, 0.35 mole of Na₂SO₄ was obtained from the reaction
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What is the mass in grams of 381 mL of ethylene glycol?
Has a density of 1.11 grams/cm^3
Answer:
The answer is 422.91 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volumeFrom the question
volume = 381 mL = 381 cm³
density = 1.11 g/cm³
So we have
mass = 1.11 × 381
We have the final answer as
422.91 gHope this helps you
What is the name of the compound shown here
ethane is the compound of the answer you are asking help